JEE Physics Magnetism and Matter MCQs Set 06

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Chapter-wise Objective Questions: Magnetism and Matter

View or download the dedicated Magnetism and Matter MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.

Multiple Choice Questions

Question 1: For a paramagnetic substance kept in a magnetic field, consider: (a) if the magnetic field increases, the magnetisation increases; (b) if the temperature rises, the magnetisation increases. Then:
(a) both (a) and (b) are true
(b) (b) is true but (a) is false
(c) (a) is true but (b) is false
(d) both (a) and (b) are false
Show Answer & Explanation

Answer: (c) (a) is true but (b) is false

Explanation:
1. Magnetisation is proportional to \( \frac BT \) (Curie's law) in the unsaturated region.
2. A stronger field aligns more dipoles, so (a) is true.
3. Higher temperature increases thermal randomisation, reducing magnetisation, so (b) is false.

Teacher's Note:
1. Think of competition between alignment by the field and thermal randomising.
2. Saturation occurs only at very high B and very low T.

Question 2: Which of the following relations is not correct?
(a) \( B=\mu_0(H+I) \)
(b) \( B=\mu_0H(1+\chi_m) \)
(c) \( \mu_r=1+\chi_m \)
(d) \( \mu_0=\mu(1+\chi_m) \)
Show Answer & Explanation

Answer: (d) \( \mu_0=\mu(1+\chi_m) \)

Explanation:
1. The standard relations are \( B=\mu_0(H+I) \), \( B=\mu_0H(1+\chi_m) \) and \( \mu_r=1+\chi_m \).
2. Since \( \mu=\mu_0\mu_r=\mu_0(1+\chi_m) \), the correct statement is \( \mu=\mu_0(1+\chi_m) \).
3. So \( \mu_0=\mu(1+\chi_m) \) is wrong.

Teacher's Note:
1. Memorise: \( \mu=\mu_0(1+\chi_m) \).
2. The other three are consistent with it.

Question 3: The hysteresis loop for the material of a permanent magnet is:
(a) tall and wide
(b) short and wide
(c) tall and narrow
(d) short and narrow
Show Answer & Explanation

Answer: (a) tall and wide

Explanation:
1. A permanent magnet needs large retentivity (tall loop) so it keeps a strong magnetisation.
2. It needs large coercivity (wide loop) so that it is not easily demagnetised.
3. So the loop is tall and wide.

Teacher's Note:
1. Soft iron has the opposite requirement: small area loop.
2. Loop area represents energy lost per cycle.

Question 4: The material for making permanent magnets should have:
(a) high retentivity and low coercivity
(b) high retentivity and high coercivity
(c) low retentivity and high coercivity
(d) low retentivity and low coercivity
Show Answer & Explanation

Answer: (b) high retentivity and high coercivity

Explanation:
1. High retentivity gives a strong residual magnetisation.
2. High coercivity makes the magnetisation hard to remove.
3. Steel and alnico are suitable.

Teacher's Note:
1. Soft iron is the opposite case.
2. Both properties are needed together.

Question 5: About soft iron, consider: (a) it is a conductor of electricity; (b) it is a magnetic material; (c) it is an alloy of iron; (d) it is used for making permanent magnets. Which of the following is correct?
(a) (a) and (c) are true
(b) (c) and (d) are true
(c) (a) and (b) are true
(d) (b) and (d) are true
Show Answer & Explanation

Answer: (c) (a) and (b) are true

Explanation:
1. Soft iron is almost pure iron, a metal, so it conducts electricity: (a) is true, and it is a magnetic material (ferromagnetic): (b) is true.
2. It is nearly pure iron, not an alloy: (c) is false.
3. Its coercivity is low, so it is unsuitable for permanent magnets: (d) is false.

Teacher's Note:
1. Soft iron is used in electromagnets and transformer cores.
2. Permanent magnets use steel or alloys.

Question 6: Soft iron is used in many electrical machines because it has:
(a) low hysteresis loss and low permeability
(b) high hysteresis loss and low permeability
(c) high hysteresis loss and high permeability
(d) low hysteresis loss and high permeability
Show Answer & Explanation

Answer: (d) low hysteresis loss and high permeability

Explanation:
1. Soft iron has a narrow hysteresis loop, so energy loss per cycle is small.
2. It has high permeability, so it gives a strong field for a given current.
3. These are the properties needed for transformer cores and electromagnets.

Teacher's Note:
1. Loop area gives hysteresis loss.
2. Reversing the magnetisation thousands of times per second makes low loss essential.

Question 7: A magnetic dipole in a uniform magnetic field has potential energy \( -\mu B\cos\theta \). The torque on a magnetic needle of moment 0.5 A m\( ^2 \) at 30 degrees to a field of 0.04 T is:
(a) 0.01 N m
(b) 0.02 N m
(c) 0.0173 N m
(d) 0.04 N m
Show Answer & Explanation

Answer: (a) 0.01 N m

Explanation:
1. Torque: \( \tau=\mu B\sin\theta \).
2. Substitute: \( 0.5\times0.04\times\sin30^\circ=0.5\times0.04\times0.5 \).
3. This gives \( \tau=0.01 \) N m.

Teacher's Note:
1. Maximum torque occurs at 90 degrees.
2. The torque tries to align the needle with the field.

Multiple Choice Questions (MCQs) for JEE Physics Magnetism and Matter

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FAQs

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