Download JEE MCQs for JEE Physics: Magnetism and Matter
Explore reliable objective questions for Magnetism and Matter tailored for JEE learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Chapter-wise Objective Questions: Magnetism and Matter
View or download the dedicated Magnetism and Matter MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.
Multiple Choice Questions
(a) both (a) and (b) are true
(b) (b) is true but (a) is false
(c) (a) is true but (b) is false
(d) both (a) and (b) are false
Show Answer & Explanation
Answer: (c) (a) is true but (b) is false
Explanation:
1. Magnetisation is proportional to \( \frac BT \) (Curie's law) in the unsaturated region.
2. A stronger field aligns more dipoles, so (a) is true.
3. Higher temperature increases thermal randomisation, reducing magnetisation, so (b) is false.
Teacher's Note:
1. Think of competition between alignment by the field and thermal randomising.
2. Saturation occurs only at very high B and very low T.
(a) \( B=\mu_0(H+I) \)
(b) \( B=\mu_0H(1+\chi_m) \)
(c) \( \mu_r=1+\chi_m \)
(d) \( \mu_0=\mu(1+\chi_m) \)
Show Answer & Explanation
Answer: (d) \( \mu_0=\mu(1+\chi_m) \)
Explanation:
1. The standard relations are \( B=\mu_0(H+I) \), \( B=\mu_0H(1+\chi_m) \) and \( \mu_r=1+\chi_m \).
2. Since \( \mu=\mu_0\mu_r=\mu_0(1+\chi_m) \), the correct statement is \( \mu=\mu_0(1+\chi_m) \).
3. So \( \mu_0=\mu(1+\chi_m) \) is wrong.
Teacher's Note:
1. Memorise: \( \mu=\mu_0(1+\chi_m) \).
2. The other three are consistent with it.
(a) tall and wide
(b) short and wide
(c) tall and narrow
(d) short and narrow
Show Answer & Explanation
Answer: (a) tall and wide
Explanation:
1. A permanent magnet needs large retentivity (tall loop) so it keeps a strong magnetisation.
2. It needs large coercivity (wide loop) so that it is not easily demagnetised.
3. So the loop is tall and wide.
Teacher's Note:
1. Soft iron has the opposite requirement: small area loop.
2. Loop area represents energy lost per cycle.
(a) high retentivity and low coercivity
(b) high retentivity and high coercivity
(c) low retentivity and high coercivity
(d) low retentivity and low coercivity
Show Answer & Explanation
Answer: (b) high retentivity and high coercivity
Explanation:
1. High retentivity gives a strong residual magnetisation.
2. High coercivity makes the magnetisation hard to remove.
3. Steel and alnico are suitable.
Teacher's Note:
1. Soft iron is the opposite case.
2. Both properties are needed together.
(a) (a) and (c) are true
(b) (c) and (d) are true
(c) (a) and (b) are true
(d) (b) and (d) are true
Show Answer & Explanation
Answer: (c) (a) and (b) are true
Explanation:
1. Soft iron is almost pure iron, a metal, so it conducts electricity: (a) is true, and it is a magnetic material (ferromagnetic): (b) is true.
2. It is nearly pure iron, not an alloy: (c) is false.
3. Its coercivity is low, so it is unsuitable for permanent magnets: (d) is false.
Teacher's Note:
1. Soft iron is used in electromagnets and transformer cores.
2. Permanent magnets use steel or alloys.
(a) low hysteresis loss and low permeability
(b) high hysteresis loss and low permeability
(c) high hysteresis loss and high permeability
(d) low hysteresis loss and high permeability
Show Answer & Explanation
Answer: (d) low hysteresis loss and high permeability
Explanation:
1. Soft iron has a narrow hysteresis loop, so energy loss per cycle is small.
2. It has high permeability, so it gives a strong field for a given current.
3. These are the properties needed for transformer cores and electromagnets.
Teacher's Note:
1. Loop area gives hysteresis loss.
2. Reversing the magnetisation thousands of times per second makes low loss essential.
(a) 0.01 N m
(b) 0.02 N m
(c) 0.0173 N m
(d) 0.04 N m
Show Answer & Explanation
Answer: (a) 0.01 N m
Explanation:
1. Torque: \( \tau=\mu B\sin\theta \).
2. Substitute: \( 0.5\times0.04\times\sin30^\circ=0.5\times0.04\times0.5 \).
3. This gives \( \tau=0.01 \) N m.
Teacher's Note:
1. Maximum torque occurs at 90 degrees.
2. The torque tries to align the needle with the field.
Free study material for Physics
Multiple Choice Questions (MCQs) for JEE Physics Magnetism and Matter
Chapter MCQs with Answers for JEE Physics
Explore reliable practice questions for Magnetism and Matter tailored for JEE Physics learners. Use these multiple-choice formats to evaluate preparedness and strengthen problem-solving skills.
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FAQs
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By solving our JEE Physics Magnetism and Matter MCQs Set 06, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.
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