JEE Chemistry Qualitative Salt Analysis MCQs Set 04

Chemistry Objective Questions and Answers: Qualitative Salt Analysis

Access targeted multiple-choice questions for Qualitative Salt Analysis designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

Download Qualitative Salt Analysis MCQs with Answers

Access the complete set of multiple-choice questions for Qualitative Salt Analysis below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.

Multiple Choice Questions

Question 1: Assertion (A): Addition of \( \ce{NH4OH} \) to an aqueous solution of \( \ce{BaCl2} \) in the presence of \( \ce{NH4Cl} \) (excess) precipitates \( \ce{Ba(OH)2} \).
Reason (R): \( \ce{Ba(OH)2} \) is insoluble in water.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (d) A is false

Explanation:
1. Barium hydroxide is soluble in water, so it does not precipitate.
2. A is false.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 2: An aqueous solution of \( \ce{FeSO4} \), \( \ce{Al2(SO4)3} \) and chrome alum is heated with excess of \( \ce{Na2O2} \) and filtered. The materials obtained are
(a) a colourless filtrate and a green residue
(b) a yellow filtrate and a green residue
(c) a yellow filtrate and a brown residue
(d) a green filtrate and a brown residue
Show Answer & Explanation

Answer: (c) a yellow filtrate and a brown residue

Explanation:
1. Sodium peroxide is a strong oxidant and alkali: Fe(II) goes to brown \( \ce{Fe(OH)3} \) (residue), Cr(III) to yellow chromate and Al to soluble aluminate (both in the filtrate).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 3: The best reason for the solubility of MnS in dil. HCl is that
(a) concentration of Mn is lowered by the formation of complex ions with chloride ions
(b) solubility product of \( \ce{MnCl2} \) is less than that of MnS
(c) concentration of sulphide ions is lowered by oxidation to free sulphur
(d) concentration of sulphide ions is lowered by formation of the weak acid \( \ce{H2S} \)
Show Answer & Explanation

Answer: (d) concentration of sulphide ions is lowered by formation of the weak acid \( \ce{H2S} \)

Explanation:
1. MnS has a relatively high \( K_{sp} \).
2. Sulphide ions combine with \( \ce{H^+} \) from HCl to form weakly ionised \( \ce{H2S} \), so the ionic product falls below \( K_{sp} \) and MnS dissolves.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 4: A mixture is heated with dil. \( \ce{H2SO4} \) and the lead acetate paper turns black by the evolved gases. The mixture contains
(a) sulphite
(b) thiosulphate
(c) sulphate
(d) sulphide
Show Answer & Explanation

Answer: (d) sulphide

Explanation:
1. Sulphide evolves \( \ce{H2S} \) with dilute acid, which blackens lead acetate paper (PbS).
2. Sulphite and thiosulphate give \( \ce{SO2} \) with dilute acid, which does not blacken lead acetate paper.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 5: A chemistry student trying to detect the metallic ion in a salt makes a paste on a clean platinum wire loop of the salt with concentrated HCl. When he takes a small amount of this paste and keeps it in a non-luminous Bunsen flame, the colour of the flame changes to grassy green. He should, therefore, conclude that the metal is
(a) potassium
(b) strontium
(c) barium
(d) calcium
Show Answer & Explanation

Answer: (c) barium

Explanation:
1. Barium gives a grassy (apple) green flame; calcium is brick red, strontium crimson and potassium lilac.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 6: A salt on treatment with dil. HCl gives a pungent smelling gas and a yellow precipitate. The salt gives a green flame when tested. The salt solution gives a yellow precipitate with potassium chromate. The salt is
(a) \( \ce{BaS2O3} \)
(b) \( \ce{CuSO4} \)
(c) \( \ce{NiSO4} \)
(d) \( \ce{PbS2O3} \)
Show Answer & Explanation

Answer: (a) \( \ce{BaS2O3} \)

Explanation:
1. Thiosulphate with dilute HCl gives \( \ce{SO2} \) (pungent) and yellow sulphur.
2. The green flame and yellow \( \ce{BaCrO4} \) with chromate show barium.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 7: Assertion (A): \( \ce{ZnCO3} \) will not give any gas when treated with conc. \( \ce{H2SO4} \).
Reason (R): \( CO3^{2-} \) can only be detected in the dil. acid test.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (d) A is false

Explanation:
1. \( \ce{ZnCO3 + H2SO4 -> ZnSO4 + H2O + CO2} \): carbonate gives \( \ce{CO2} \) with conc. sulphuric acid as well.
2. A is false.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 8: The brown ring test for nitrite and nitrate is due to the formation of a complex ion with the formula
(a) \( \ce{[Fe(H2O)5(NO)]^{2+}} \)
(b) \( \ce{[Fe(NO)(CN)5]^{2-}} \)
(c) \( \ce{[Fe(H2O)4(NO)2]^{2+}} \)
(d) \( \ce{[Fe(H2O)6]^{2+}} \)
Show Answer & Explanation

Answer: (a) \( \ce{[Fe(H2O)5(NO)]^{2+}} \)

Explanation:
1. \( \ce{[Fe(H2O)6]^{2+} + NO -> [Fe(H2O)5(NO)]^{2+} + H2O} \).
2. The brown ring is pentaaquanitrosyliron(II).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 9: Assertion (A): All soluble sulphides give a white precipitate with \( \ce{BaCl2} \) solution.
Reason (R): BaS is insoluble in water.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (d) A is false

Explanation:
1. Sulphides do not give a precipitate with barium chloride because BaS is soluble in water; a white precipitate is formed with sulphates.
2. Both A and R are false (A is false).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 10: Assertion (A): Lime water becomes turbid on passing \( \ce{CO2} \) but becomes clear on passing more \( \ce{CO2} \).
Reason (R): Lime water is calcium hydroxide, \( \ce{Ca(OH)2} \).
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (b) Both A and R are true but R is not the correct explanation of A

Explanation:
1. \( \ce{Ca(OH)2 + CO2 -> CaCO3 + H2O} \) (turbid) and \( \ce{CaCO3 + CO2 + H2O -> Ca(HCO3)2} \) (clear).
2. R is true but does not explain the clearing on excess \( \ce{CO2} \).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 11: Assertion (A): White precipitate of AgCl is soluble in \( \ce{NH4OH} \).
Reason (R): It is due to the formation of a soluble complex.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (a) Both A and R are true and R is the correct explanation of A

Explanation:
1. \( \ce{AgCl + 2NH3 -> [Ag(NH3)2]Cl} \): complex formation explains the dissolution.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 12: Assertion (A): \( \ce{PbCl2} \) will give HCl in the conc. \( \ce{H2SO4} \) test.
Reason (R): All chlorides react with conc. \( \ce{H2SO4} \), on heating, to give HCl.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (a) Both A and R are true and R is the correct explanation of A

Explanation:
1. \( \ce{PbCl2 + H2SO4 -> PbSO4 + 2HCl} \).
2. The general reaction of chlorides with conc. sulphuric acid explains the assertion.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 13: Assertion (A): CuS is blue in colour.
Reason (R): All \( Cu^{2+} \) salts are blue in colour.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (d) A is false

Explanation:
1. CuS is a black precipitate.
2. A is false.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 14: Assertion (A): A brown gas which intensifies on adding Cu-turnings in the conc. \( \ce{H2SO4} \) test is \( \ce{NO2} \).
Reason (R): Copper reacts with conc. \( \ce{HNO3} \) to give \( \ce{NO2} \).
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (a) Both A and R are true and R is the correct explanation of A

Explanation:
1. Nitrate with conc. \( \ce{H2SO4} \) gives \( \ce{HNO3} \), and copper reduces it to brown \( \ce{NO2} \): \( \ce{Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O} \).
2. R explains why the brown fumes intensify.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 15: On performing a borax-bead test with a given inorganic mixture, the colour of the bead was found to be emerald green both in oxidising and reducing flame. It indicates the possibility of the presence of
(a) \( \ce{Ni} \)
(b) \( \ce{Co} \)
(c) \( \ce{Cu} \)
(d) \( \ce{Cr} \)
Show Answer & Explanation

Answer: (d) \( \ce{Cr} \)

Explanation:
1. Chromium gives an emerald green bead in both flames; cobalt is blue, nickel brown and copper blue (oxidising) or red (reducing).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 16: Assertion (A): Acidified \( \ce{K2Cr2O7} \) is turned green when \( \ce{SO2} \) is passed through it.
Reason (R): In this reaction \( \ce{SO2} \) acts as a reducing agent.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (a) Both A and R are true and R is the correct explanation of A

Explanation:
1. \( \ce{Cr2O7^{2-} + 3SO2 + 2H^+ -> 2Cr^{3+} + 3SO4^{2-} + H2O} \).
2. Orange Cr(VI) is reduced to green Cr(III) because \( \ce{SO2} \) reduces it.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 17: A white solid 'A' on heating gives off a gas which turns lime water milky. The residue is yellow when hot but turns white on cooling. The solid 'A' is
(a) zinc carbonate
(b) lead carbonate
(c) lead sulphate
(d) zinc sulphate
Show Answer & Explanation

Answer: (a) zinc carbonate

Explanation:
1. \( \ce{ZnCO3 -> ZnO + CO2} \).
2. ZnO is yellow when hot and white when cold.
3. Lead carbonate would leave PbO, which is yellow when cold; sulphates do not give \( \ce{CO2} \).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 18: Assertion (A): \( \ce{CdS} \) is yellow in colour.
Reason (R): Cd salts are yellow in colour.
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (c) A is true but R is false

Explanation:
1. CdS is a yellow precipitate (group II test for cadmium).
2. Cadmium salts such as \( \ce{CdSO4} \) and \( \ce{CdCl2} \) are colourless or white, so R is false.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 19: The salt used for performing the 'bead' test in qualitative inorganic analysis is
(a) \( \ce{FeSO4.(NH4)2SO4.6H2O} \)
(b) \( \ce{Na(NH4)HPO4.4H2O} \)
(c) \( \ce{CaSO4.2H2O} \)
(d) \( \ce{K2SO4.Al2(SO4)3.24H2O} \)
Show Answer & Explanation

Answer: (b) \( \ce{Na(NH4)HPO4.4H2O} \)

Explanation:
1. Microcosmic salt, sodium ammonium hydrogen phosphate, gives a glassy bead of \( \ce{NaPO3} \) with which coloured metaphosphates are formed.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 20: To an acid solution of an anion a few drops of \( \ce{KMnO4} \) solution were added. Which of the following, if present, will not decolourise the \( \ce{KMnO4} \) solution?
(a) \( \ce{CO3^{2-}} \)
(b) \( \ce{NO2^-} \)
(c) \( \ce{Cl^-} \)
(d) \( \ce{S^{2-}} \)
Show Answer & Explanation

Answer: (a) \( \ce{CO3^{2-}} \)

Explanation:
1. Nitrite, sulphide and (in strongly acidic solution) chloride are reducing and decolourise permanganate.
2. Carbonate only gives \( \ce{CO2} \) with acid and cannot reduce permanganate.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 21: Assertion (A): \( \ce{CuS} \) will give \( \ce{H2S} \) in the dilute acid test.
Reason (R): All sulphides react with dil. \( \ce{H2SO4} \), on heating, to give \( \ce{H2S} \).
Select the correct option.
(a) Both A and R are true and R is the correct explanation of A
(b) Both A and R are true but R is not the correct explanation of A
(c) A is true but R is false
(d) A is false
Show Answer & Explanation

Answer: (d) A is false

Explanation:
1. CuS has a very small solubility product and does not dissolve in dilute acids, so no \( \ce{H2S} \) is evolved.
2. A is false (and R is also false).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 22: A white crystalline substance dissolves in water. On passing \( \ce{H2S} \) in this solution, a black precipitate is obtained. The black precipitate dissolves completely in hot \( \ce{HNO3} \). On adding a few drops of conc. \( \ce{H2SO4} \) a white precipitate is obtained. This precipitate is that of
(a) \( \ce{BaSO4} \)
(b) \( \ce{PbSO4} \)
(c) \( \ce{SrSO4} \)
(d) \( \ce{CdSO4} \)
Show Answer & Explanation

Answer: (b) \( \ce{PbSO4} \)

Explanation:
1. Black PbS dissolves in hot nitric acid to give \( \ce{Pb(NO3)2} \), and sulphuric acid precipitates white \( \ce{PbSO4} \).
2. Barium and strontium are not precipitated by \( \ce{H2S} \), and CdS is yellow.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 23: Upon the addition of a solution A to a strongly acidified solution of barium nitrate, a white precipitate was obtained which did not dissolve even after a large addition of water. Solution A contained
(a) sodium chloride
(b) sodium phosphate
(c) sodium sulphate
(d) sodium carbonate
Show Answer & Explanation

Answer: (c) sodium sulphate

Explanation:
1. Barium phosphate and carbonate dissolve in strong acid.
2. Only \( \ce{BaSO4} \) is insoluble in acids.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 24: A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube. The red solid is
(a) \( \ce{Pb3O4} \)
(b) \( \ce{(NH4)2Cr2O7} \)
(c) \( \ce{HgI2} \)
(d) \( \ce{HgO} \)
Show Answer & Explanation

Answer: (c) \( \ce{HgI2} \)

Explanation:
1. \( \ce{HgI2 + 2KI -> K2[HgI4]} \) dissolves it.
2. On heating \( \ce{HgI2 -> Hg + I2} \): violet iodine vapour and mercury droplets.

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Question 25: If NaOH is added to an aqueous solution of zinc ions, a white precipitate appears and on adding excess NaOH, the precipitate dissolves. In this solution zinc exists in the
(a) cationic part
(b) anionic part
(c) both in cationic and anionic parts
(d) there is no zinc in the solution
Show Answer & Explanation

Answer: (b) anionic part

Explanation:
1. \( \ce{Zn(OH)2 + 2OH^- -> [Zn(OH)4]^{2-}} \): zinc is present in the anion (zincate).

Teacher's Note:
1. Learn the colour of each precipitate, gas and flame test; they identify the ion directly.
2. Write the equation of the test reaction; the explanation usually follows from it.

Practice MCQs for JEE Chemistry Qualitative Salt Analysis

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