JEE Chemistry Qualitative Salt Analysis MCQs Set 02

Multiple Choice Questions (MCQs) for JEE Chemistry: Qualitative Salt Analysis

Review structured MCQ sets for JEE Chemistry Qualitative Salt Analysis. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Practice Qualitative Salt Analysis MCQs for JEE Chemistry

View or download the dedicated Qualitative Salt Analysis MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Chemistry evaluations.

Multiple Choice Questions

Question 1: On passing \( \ce{H2S} \) gas through acidified \( \ce{KMnO4} \) solution, we get
(a) \( \ce{K2S} \)
(b) \( \ce{K2SO3} \)
(c) S
(d) \( \ce{MnO2} \)
Show Answer & Explanation

Answer: (c) S

Explanation:
1. \( \ce{H2S} \) is oxidised to sulphur, and \( \ce{MnO4^-} \) is reduced to \( \ce{Mn^{2+}} \).

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 2: Which of the following precipitates does not dissolve even in a large excess of \( \ce{NH4OH} \)?
(a) \( \ce{AgCl} \)
(b) \( \ce{AgBr} \)
(c) \( \ce{AgI} \)
(d) none of these
Show Answer & Explanation

Answer: (c) \( \ce{AgI} \)

Explanation:
1. AgCl dissolves readily, AgBr slightly, and AgI is insoluble even in concentrated ammonia.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 3: Concentrated sodium hydroxide can separate a mixture of
(a) \( \ce{Cr^{3+}} \) and \( \ce{Fe^{3+}} \)
(b) \( \ce{Zn^{2+}} \) and \( \ce{Pb^{2+}} \)
(c) \( \ce{Al^{3+}} \) and \( \ce{Cr^{3+}} \)
(d) \( \ce{Al^{3+}} \) and \( \ce{Zn^{2+}} \)
Show Answer & Explanation

Answer: (a) \( \ce{Cr^{3+}} \) and \( \ce{Fe^{3+}} \)

Explanation:
1. Cr(OH)3 dissolves in excess alkali (as chromite) while Fe(OH)3 does not, so they can be separated.
2. The other pairs are both amphoteric and dissolve.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 4: Conc. \( \ce{HNO3} \) is added before proceeding to test for group III members. This is to
(a) oxidise any remaining \( \ce{H2S} \)
(b) increase ionisation of ammonium hydroxide
(c) convert ferrous ion into ferric ion
(d) form nitrates which give granular precipitates
Show Answer & Explanation

Answer: (c) convert ferrous ion into ferric ion

Explanation:
1. Group III tests need iron as Fe(III), so ferrous ions are oxidised by boiling with conc. nitric acid.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 5: The colour of \( \ce{CuCr2O7} \) solution in water is green because
(a) \( \ce{Cr2O7^{2-}} \) ions are green
(b) \( \ce{Cu^{2+}} \) ions are green
(c) both ions are green
(d) \( \ce{Cu^{2+}} \) ions are blue and \( \ce{Cr2O7^{2-}} \) ions are yellow
Show Answer & Explanation

Answer: (d) \( \ce{Cu^{2+}} \) ions are blue and \( \ce{Cr2O7^{2-}} \) ions are yellow

Explanation:
1. Blue \( \ce{Cu^{2+}} \) and yellow-orange dichromate together appear green.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 6: AgCl dissolves in ammonia solution giving
(a) \( \ce{Ag(NH3)^+} \) and \( \ce{Cl^-} \)
(b) \( \ce{Ag^+, NH4^+} \) and \( \ce{Cl^-} \)
(c) \( \ce{Ag2(NH3)^+} \) and \( \ce{Cl^-} \)
(d) \( \ce{[Ag(NH3)2]^+} \) and \( \ce{Cl^-} \)
Show Answer & Explanation

Answer: (d) \( \ce{[Ag(NH3)2]^+} \) and \( \ce{Cl^-} \)

Explanation:
1. \( \ce{AgCl + 2NH3 -> [Ag(NH3)2]^+ + Cl^-} \).

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 7: In the borax bead test, which of the following compounds is formed?
(a) tetraborate
(b) orthoborate
(c) double oxide
(d) metaborate
Show Answer & Explanation

Answer: (d) metaborate

Explanation:
1. On heating, borax gives sodium metaborate and boric anhydride: \( \ce{Na2B4O7 -> 2NaBO2 + B2O3} \).
2. The boric anhydride combines with the metal oxide to give a coloured metaborate.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 8: The reagent used in the qualitative analysis of group IV is
(a) HCl
(b) \( \ce{H2S} \) (alkaline)
(c) \( \ce{(NH4)2S} \)
(d) none of these
Show Answer & Explanation

Answer: (b) \( \ce{H2S} \) (alkaline)

Explanation:
1. Group IV (Zn, Mn, Ni, Co) is precipitated by \( \ce{H2S} \) in the presence of \( \ce{NH4Cl} \) and \( \ce{NH4OH} \).

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 9: When \( \ce{CO2} \) is passed into lime water it turns milky. When excess of \( \ce{CO2} \) is passed, the milkiness disappears because
(a) the reaction is reversed
(b) water soluble \( \ce{Ca(HCO3)2} \) is formed
(c) vaporisable calcium derivative is formed
(d) none of these
Show Answer & Explanation

Answer: (b) water soluble \( \ce{Ca(HCO3)2} \) is formed

Explanation:
1. \( \ce{CaCO3 + H2O + CO2 -> Ca(HCO3)2} \) is soluble in water.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 10: A mixture of two salts is not water soluble but dissolves completely in dilute hydrochloric acid to form a colourless solution. The mixture could be
(a) \( \ce{FeCl3} \) and \( \ce{CaCO3} \)
(b) \( \ce{AgNO3} \) and KBr
(c) \( \ce{BaCO3} \) and ZnS
(d) \( \ce{Mn(NO3)2} \) and \( \ce{MgSO4} \)
Show Answer & Explanation

Answer: (c) \( \ce{BaCO3} \) and ZnS

Explanation:
1. Both \( \ce{BaCO3} \) and ZnS are insoluble in water but dissolve in dilute HCl to give colourless chlorides.
2. The other mixtures are partly soluble in water or give a coloured solution.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 11: When \( \ce{Cl2} \) water is added to a salt solution containing chloroform, the chloroform layer turns violet. The salt contains
(a) \( \ce{I^-} \)
(b) \( \ce{S^{2-}} \)
(c) \( \ce{Cl^-} \)
(d) \( \ce{NO3^-} \)
Show Answer & Explanation

Answer: (a) \( \ce{I^-} \)

Explanation:
1. Chlorine oxidises iodide to iodine, which dissolves in chloroform to give a violet layer.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 12: Addition of a solution of oxalate to an aqueous mixture of \( \ce{Ba^{2+}} \), \( \ce{Sr^{2+}} \) and \( \ce{Ca^{2+}} \) will precipitate
(a) \( \ce{Ca^{2+}} \)
(b) \( \ce{Ca^{2+}} \) and \( \ce{Sr^{2+}} \)
(c) \( \ce{Ba^{2+}} \) and \( \ce{Sr^{2+}} \)
(d) all the three
Show Answer & Explanation

Answer: (d) all the three

Explanation:
1. Barium, strontium and calcium oxalates are all sparingly soluble in water.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 13: Which of the following will not produce a precipitate with \( \ce{AgNO3} \) solution?
(a) \( \ce{CO3^{2-}} \)
(b) \( \ce{PO4^{3-}} \)
(c) \( \ce{F^-} \)
(d) \( \ce{Br^-} \)
Show Answer & Explanation

Answer: (c) \( \ce{F^-} \)

Explanation:
1. Silver fluoride is soluble in water.
2. Silver bromide, carbonate and phosphate are precipitated.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 14: A light greenish coloured salt was soluble in water. On passing \( \ce{H2S} \) into the solution (made ammoniacal) a black precipitate was obtained which dissolved readily in HCl. The metal ion present is
(a) \( \ce{Fe^{2+}} \)
(b) \( \ce{Ni^{2+}} \)
(c) \( \ce{Co^{2+}} \)
(d) \( \ce{Mn^{2+}} \)
Show Answer & Explanation

Answer: (a) \( \ce{Fe^{2+}} \)

Explanation:
1. Fe(II) salts are light green and FeS is black but dissolves readily in dilute HCl.
2. CoS and NiS do not dissolve in dilute HCl.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 15: Lead sulphate is soluble
(a) in conc. hydrochloric acid
(b) in water
(c) in a solution of ammonium acetate
(d) in conc. nitric acid
Show Answer & Explanation

Answer: (c) in a solution of ammonium acetate

Explanation:
1. Acetate forms the weakly ionised \( \ce{Pb(CH3COO)2} \), so ammonium acetate dissolves \( \ce{PbSO4} \).

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 16: A precipitate of the following would be obtained when HCl is added to a solution of stannous sulphide (\( \ce{SnS} \)) in yellow ammonium sulphide
(a) \( \ce{(NH4)2SnS3} \)
(b) \( \ce{Sn2S2} \)
(c) \( \ce{SnS2} \)
(d) \( \ce{SnS} \)
Show Answer & Explanation

Answer: (c) \( \ce{SnS2} \)

Explanation:
1. Yellow ammonium sulphide oxidises SnS to the thiostannate \( \ce{(NH4)2SnS3} \); acid then precipitates yellow \( \ce{SnS2} \).

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 17: ........ is formed when potassium iodide is heated with conc. \( \ce{H2SO4} \).
(a) \( \ce{KIO3} \)
(b) \( \ce{I2} \)
(c) \( \ce{HIO3} \)
(d) \( \ce{HI} \)
Show Answer & Explanation

Answer: (b) \( \ce{I2} \)

Explanation:
1. Conc. sulphuric acid oxidises the HI formed, liberating violet iodine.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 18: A salt gives a bright red colour to the flame. This colour indicates the presence of
(a) \( \ce{Ba^{2+}} \)
(b) \( \ce{Cr^{3+}} \)
(c) \( \ce{Ca^{2+}} \)
(d) \( \ce{Sr^{2+}} \)
Show Answer & Explanation

Answer: (d) \( \ce{Sr^{2+}} \)

Explanation:
1. Strontium gives a crimson/bright red flame.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 19: Which compound does not dissolve in hot dilute \( \ce{HNO3} \)?
(a) \( \ce{CdS} \)
(b) \( \ce{HgS} \)
(c) \( \ce{CuS} \)
(d) \( \ce{PbS} \)
Show Answer & Explanation

Answer: (b) \( \ce{HgS} \)

Explanation:
1. HgS has an extremely low solubility product and dissolves only in aqua regia.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 20: The composition of 'golden spangles' is
(a) \( \ce{BaCrO4} \)
(b) \( \ce{PbCrO4} \)
(c) \( \ce{As2S3} \)
(d) \( \ce{PbI2} \)
Show Answer & Explanation

Answer: (d) \( \ce{PbI2} \)

Explanation:
1. Lead iodide dissolves in hot water and crystallises on cooling as shining golden-yellow flakes called golden spangles.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 21: Which one of the following sulphides is yellow?
(a) zinc sulphide
(b) cadmium sulphide
(c) nickel sulphide
(d) lead sulphide
Show Answer & Explanation

Answer: (b) cadmium sulphide

Explanation:
1. CdS is yellow, ZnS white, NiS black and PbS black.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 22: A salt is heated first with dil. \( \ce{H2SO4} \) and then with conc. \( \ce{H2SO4} \). No reaction takes place. It may be
(a) nitrate
(b) oxalate
(c) sulphide
(d) sulphate
Show Answer & Explanation

Answer: (d) sulphate

Explanation:
1. Sulphate does not react with either dilute or concentrated sulphuric acid.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 23: A mixture containing \( \ce{Cu^{2+}} \) and \( \ce{Ni^{2+}} \) can be separated for identification by
(a) passing \( \ce{H2S} \) in alkaline medium
(b) passing \( \ce{H2S} \) in dry mixture
(c) passing \( \ce{H2S} \) in neutral medium
(d) passing \( \ce{H2S} \) in acid medium
Show Answer & Explanation

Answer: (d) passing \( \ce{H2S} \) in acid medium

Explanation:
1. In acid, only CuS precipitates; NiS remains in solution.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 24: Ferrous and ferric ions in solution may be distinguished by using
(a) silver nitrate solution
(b) sodium chloride solution
(c) acidified solution of potassium permanganate
(d) lead acetate solution
Show Answer & Explanation

Answer: (c) acidified solution of potassium permanganate

Explanation:
1. Only ferrous ions decolourise acidified permanganate; ferric ions do not.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Question 25: The alkaline earth metal that imparts an apple green colour to the Bunsen flame when introduced as its chloride is
(a) barium
(b) magnesium
(c) strontium
(d) calcium
Show Answer & Explanation

Answer: (a) barium

Explanation:
1. Ba gives an apple-green flame, Sr crimson red and Ca brick red; Mg gives none.

Teacher's Note:
1. Link each observation to its reagent: colour, gas evolved and precipitate are the usual clues in salt analysis.
2. Memorise the confirmatory test for each ion; they are asked repeatedly.

Qualitative Salt Analysis Objective Questions & Solutions for JEE Chemistry

Download Multiple Choice Questions: Qualitative Salt Analysis (JEE Chemistry)

Review structured objective questions for JEE Chemistry Qualitative Salt Analysis. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.

Concept Clarification for Qualitative Salt Analysis

Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.

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FAQs

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