Multiple Choice Questions (MCQs) for JEE Chemistry: Isomerism
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Multiple Choice Questions
(a) Enantiomers
(b) Tautomers
(c) Diastereoisomers
(d) Structural isomers
Show Answer & Explanation
Answer: (a) Enantiomers
Explanation:
1. They are non-superimposable mirror images
2. Such pairs are enantiomers
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) Hexachloroethane
(b) Ethylene
(c) Acetylene
(d) Ethane
Show Answer & Explanation
Answer: (d) Ethane
Explanation:
1. Ethane has the smallest torsional barrier (about 12 kJ/mol)
2. Hexachloroethane is hindered by bulky Cl, and ethylene and acetylene have pi bonds
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) Maleic and fumaric acid
(b) Lactic and tartaric acid
(c) Malonic and succinic acid
(d) Crotonic and acrylic acid
Show Answer & Explanation
Answer: (a) Maleic and fumaric acid
Explanation:
1. Maleic acid is the cis and fumaric acid the trans form of butenedioic acid
2. The other pairs are different compounds
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) 4-Chloro-1-hydroxybutane
(b) tert-Butyl alcohol
(c) sec-Butylamine
(d) n-Butyl alcohol
Show Answer & Explanation
Answer: (c) sec-Butylamine
Explanation:
1. sec-Butylamine \( \ce{CH3CH2-CH(NH2)-CH3} \) has a carbon with four different groups
2. The others have none
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) \( \ce{CH3CHBr2} \) and \( \ce{CH2BrCH2Br} \)
(b) 1-Propanol and 2-propanol
(c) Neopentane and isopentane
(d) Diethyl ether and methyl n-propyl ether
Show Answer & Explanation
Answer: (c) Neopentane and isopentane
Explanation:
1. Both are \( \ce{C5H12} \) with different carbon skeletons
2. The other pairs are position isomers, position isomers and metamers
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) An asymmetric carbon atom
(b) Centre of symmetry
(c) Axis of symmetry
(d) Plane of symmetry
Show Answer & Explanation
Answer: (a) An asymmetric carbon atom
Explanation:
1. A carbon with four different groups makes the molecule chiral
2. Symmetry elements make a molecule achiral
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) \( \ce{CH3CHCl2} \) and \( \ce{ClCH2CH2Cl} \)
(b) n-Propyl alcohol and isopropyl alcohol
(c) 2-Methylpropan-1-ol and 2-methylpropan-2-ol
(d) 2-Methylbutane and neopentane
Show Answer & Explanation
Answer: (d) 2-Methylbutane and neopentane
Explanation:
1. Both are \( \ce{C5H12} \) with different carbon skeletons
2. The other pairs are position isomers
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) Chain isomers
(b) Optical isomers
(c) Cis-trans isomers
(d) Position isomers
Show Answer & Explanation
Answer: (b) Optical isomers
Explanation:
1. 2-Bromopropanoic acid has one stereocentre, so both enantiomers form
2. The pair is optical isomers
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) Propene
(b) 3-Hexene
(c) Butenedioic acid
(d) A cyclic compound such as 1,2-dimethylcyclopropane
Show Answer & Explanation
Answer: (a) Propene
Explanation:
1. Propene has two H atoms on one C=C carbon
2. Its two groups on that carbon are identical, so no cis-trans form exists
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) 2-Methylpropane
(b) n-Pentane
(c) Benzene
(d) 2,4-Dimethylpentane
Show Answer & Explanation
Answer: (a) 2-Methylpropane
Explanation:
1. 2-Methylpropane gives 1-chloro-2-methylpropane and 2-chloro-2-methylpropane
2. n-Pentane gives 3, benzene 1 and 2,4-dimethylpentane 3
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) Central carbon atom
(b) Carbon atom of the methyl group
(c) Carbon atom of the carboxylic acid group
(d) Oxygen of the hydroxyl group
Show Answer & Explanation
Answer: (a) Central carbon atom
Explanation:
1. The central carbon holds four different groups in a tetrahedral arrangement
2. It is the stereocentre
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) Chiral carbon
(b) Free rotation about a single bond
(c) Free rotation about a double bond
(d) Restricted rotation about a double bond
Show Answer & Explanation
Answer: (d) Restricted rotation about a double bond
Explanation:
1. The pi bond prevents rotation about the C=C bond
2. The groups are locked on the same or opposite sides
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) Enantiomers
(b) Tautomers
(c) Mesomers
(d) Diastereoisomers
Show Answer & Explanation
Answer: (d) Diastereoisomers
Explanation:
1. Diastereoisomers are stereoisomers that are not mirror images
2. Enantiomers are mirror images
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) Metamerism
(b) Chain
(c) Position
(d) Stereo
Show Answer & Explanation
Answer: (b) Chain
Explanation:
1. n-Butanol and isobutanol are \( \ce{C4H9OH} \) with different carbon chains
2. This is chain isomerism
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) \( \ce{CH3CH=CHCH3} \)
(b) \( \ce{(CH3)2C=C(CH3)2} \)
(c) \( \ce{(CH3)2C=CH-CH3} \)
(d) \( \ce{CH3-CH=C(CH3)2} \)
Show Answer & Explanation
Answer: (a) \( \ce{CH3CH=CHCH3} \)
Explanation:
1. 2-Butene has two different groups on each doubly bonded carbon
2. In the others a doubly bonded carbon has two identical methyl groups
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) 2
(b) 3
(c) 5
(d) 1
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. But-1-ene, but-2-ene and 2-methylpropene
2. Three open-chain structures (but-2-ene's cis and trans forms are stereoisomers, not structural)
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) 8
(b) 12
(c) 16
(d) Cannot be predicted
Show Answer & Explanation
Answer: (c) 16
Explanation:
1. Open-chain glucose has four stereocentres
2. The number of stereoisomers is 2^4 = 16
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) 1
(b) 3
(c) 4
(d) 7
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. Substituting at C-3 gives \( \ce{CH3CH2-CH(X)-C4H9} \), which has four different groups
2. At C-1 and C-7 the carbon keeps three identical H, and at C-4 the two chains are the same, so the product is achiral
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) 8
(b) 9
(c) 10
(d) 12
Show Answer & Explanation
Answer: (b) 9
Explanation:
1. Heptane, two methylhexanes, four dimethylpentanes, 3-ethylpentane and 2,2,3-trimethylbutane
2. In total 1 + 2 + 4 + 1 + 1 = 9
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) \( \ce{CH3-CHCl-COOH} \)
(b) \( \ce{CH3CH2COOH} \)
(c) \( \ce{ClCH2CH2COOH} \)
(d) \( \ce{Cl2CH-COOH} \)
Show Answer & Explanation
Answer: (a) \( \ce{CH3-CHCl-COOH} \)
Explanation:
1. \( \ce{CH3-CHCl-COOH} \) has a carbon bonded to H, Cl, \( \ce{CH3} \) and COOH
2. The others have no such carbon
Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.
(a) Each forms an equal number of isomers for a given compound
(b) If a compound has one, it also has the other
(c) Both are included in stereoisomerism
(d) They have no similarity
Show Answer & Explanation
Answer: (c) Both are included in stereoisomerism
Explanation:
1. In both types the atoms are connected in the same order but arranged differently in space
2. Both come under stereoisomerism
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
(a) Non-polarised light
(b) Plane polarised light
(c) Polarised light
(d) Optical light
Show Answer & Explanation
Answer: (b) Plane polarised light
Explanation:
1. A Nicol prism allows vibrations in only one plane to pass
2. The emerging beam is plane-polarised light
Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.
(a) Butane
(b) 1-Chloro-2-methylbutane
(c) 2-Methylbutane
(d) 2-Methylpropane
Show Answer & Explanation
Answer: (b) 1-Chloro-2-methylbutane
Explanation:
1. In \( \ce{ClCH2-CH(CH3)-CH2CH3} \) C-2 has H, \( \ce{CH3} \), \( \ce{C2H5} \) and \( \ce{CH2Cl} \)
2. The others have no stereocentre
Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.
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