JEE Chemistry Isomerism MCQs Set 04

Multiple Choice Questions (MCQs) for JEE Chemistry: Isomerism

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Multiple Choice Questions

Question 1: d-Tartaric acid and l-tartaric acid are
(a) Enantiomers
(b) Tautomers
(c) Diastereoisomers
(d) Structural isomers
Show Answer & Explanation

Answer: (a) Enantiomers

Explanation:
1. They are non-superimposable mirror images
2. Such pairs are enantiomers

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 2: Minimum resistance to bond rotation will be observed in the compound
(a) Hexachloroethane
(b) Ethylene
(c) Acetylene
(d) Ethane
Show Answer & Explanation

Answer: (d) Ethane

Explanation:
1. Ethane has the smallest torsional barrier (about 12 kJ/mol)
2. Hexachloroethane is hindered by bulky Cl, and ethylene and acetylene have pi bonds

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 3: Which pair shows cis-trans isomerism?
(a) Maleic and fumaric acid
(b) Lactic and tartaric acid
(c) Malonic and succinic acid
(d) Crotonic and acrylic acid
Show Answer & Explanation

Answer: (a) Maleic and fumaric acid

Explanation:
1. Maleic acid is the cis and fumaric acid the trans form of butenedioic acid
2. The other pairs are different compounds

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 4: Which compound is optically active?
(a) 4-Chloro-1-hydroxybutane
(b) tert-Butyl alcohol
(c) sec-Butylamine
(d) n-Butyl alcohol
Show Answer & Explanation

Answer: (c) sec-Butylamine

Explanation:
1. sec-Butylamine \( \ce{CH3CH2-CH(NH2)-CH3} \) has a carbon with four different groups
2. The others have none

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 5: Choose the pair of chain isomers.
(a) \( \ce{CH3CHBr2} \) and \( \ce{CH2BrCH2Br} \)
(b) 1-Propanol and 2-propanol
(c) Neopentane and isopentane
(d) Diethyl ether and methyl n-propyl ether
Show Answer & Explanation

Answer: (c) Neopentane and isopentane

Explanation:
1. Both are \( \ce{C5H12} \) with different carbon skeletons
2. The other pairs are position isomers, position isomers and metamers

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 6: Optical isomerism arises due to the presence of
(a) An asymmetric carbon atom
(b) Centre of symmetry
(c) Axis of symmetry
(d) Plane of symmetry
Show Answer & Explanation

Answer: (a) An asymmetric carbon atom

Explanation:
1. A carbon with four different groups makes the molecule chiral
2. Symmetry elements make a molecule achiral

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 7: Which pair represents chain isomers?
(a) \( \ce{CH3CHCl2} \) and \( \ce{ClCH2CH2Cl} \)
(b) n-Propyl alcohol and isopropyl alcohol
(c) 2-Methylpropan-1-ol and 2-methylpropan-2-ol
(d) 2-Methylbutane and neopentane
Show Answer & Explanation

Answer: (d) 2-Methylbutane and neopentane

Explanation:
1. Both are \( \ce{C5H12} \) with different carbon skeletons
2. The other pairs are position isomers

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 8: On bromination, propionic acid yields two isomeric 2-bromopropionic acids. This pair is an important example of
(a) Chain isomers
(b) Optical isomers
(c) Cis-trans isomers
(d) Position isomers
Show Answer & Explanation

Answer: (b) Optical isomers

Explanation:
1. 2-Bromopropanoic acid has one stereocentre, so both enantiomers form
2. The pair is optical isomers

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 9: Geometrical isomerism is NOT possible in
(a) Propene
(b) 3-Hexene
(c) Butenedioic acid
(d) A cyclic compound such as 1,2-dimethylcyclopropane
Show Answer & Explanation

Answer: (a) Propene

Explanation:
1. Propene has two H atoms on one C=C carbon
2. Its two groups on that carbon are identical, so no cis-trans form exists

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 10: Only two isomeric monochloro derivatives are possible for
(a) 2-Methylpropane
(b) n-Pentane
(c) Benzene
(d) 2,4-Dimethylpentane
Show Answer & Explanation

Answer: (a) 2-Methylpropane

Explanation:
1. 2-Methylpropane gives 1-chloro-2-methylpropane and 2-chloro-2-methylpropane
2. n-Pentane gives 3, benzene 1 and 2,4-dimethylpentane 3

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 11: Lactic acid, in which a methyl group, a hydroxyl group, a carboxylic acid group and a hydrogen atom are attached to a central carbon atom, shows optical isomerism due to the molecular geometry at the
(a) Central carbon atom
(b) Carbon atom of the methyl group
(c) Carbon atom of the carboxylic acid group
(d) Oxygen of the hydroxyl group
Show Answer & Explanation

Answer: (a) Central carbon atom

Explanation:
1. The central carbon holds four different groups in a tetrahedral arrangement
2. It is the stereocentre

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 12: The reason for geometrical isomerism in 2-butene is
(a) Chiral carbon
(b) Free rotation about a single bond
(c) Free rotation about a double bond
(d) Restricted rotation about a double bond
Show Answer & Explanation

Answer: (d) Restricted rotation about a double bond

Explanation:
1. The pi bond prevents rotation about the C=C bond
2. The groups are locked on the same or opposite sides

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 13: Stereoisomers which are not mirror images of one another are called
(a) Enantiomers
(b) Tautomers
(c) Mesomers
(d) Diastereoisomers
Show Answer & Explanation

Answer: (d) Diastereoisomers

Explanation:
1. Diastereoisomers are stereoisomers that are not mirror images
2. Enantiomers are mirror images

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 14: The isomerism shown by n-butyl alcohol and isobutyl alcohol is
(a) Metamerism
(b) Chain
(c) Position
(d) Stereo
Show Answer & Explanation

Answer: (b) Chain

Explanation:
1. n-Butanol and isobutanol are \( \ce{C4H9OH} \) with different carbon chains
2. This is chain isomerism

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 15: Which of the following will show geometrical isomerism?
(a) \( \ce{CH3CH=CHCH3} \)
(b) \( \ce{(CH3)2C=C(CH3)2} \)
(c) \( \ce{(CH3)2C=CH-CH3} \)
(d) \( \ce{CH3-CH=C(CH3)2} \)
Show Answer & Explanation

Answer: (a) \( \ce{CH3CH=CHCH3} \)

Explanation:
1. 2-Butene has two different groups on each doubly bonded carbon
2. In the others a doubly bonded carbon has two identical methyl groups

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 16: The maximum number of open-chain structural isomers possible for \( \ce{C4H8} \) is
(a) 2
(b) 3
(c) 5
(d) 1
Show Answer & Explanation

Answer: (b) 3

Explanation:
1. But-1-ene, but-2-ene and 2-methylpropene
2. Three open-chain structures (but-2-ene's cis and trans forms are stereoisomers, not structural)

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 17: The number of optical isomers of glucose is
(a) 8
(b) 12
(c) 16
(d) Cannot be predicted
Show Answer & Explanation

Answer: (c) 16

Explanation:
1. Open-chain glucose has four stereocentres
2. The number of stereoisomers is 2^4 = 16

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 18: An organic compound is \( \ce{CH3-CH2-CH2-CH2-CH2-CH2-CH3} \) (heptane). To make it chiral, the attack (substitution) should be on carbon number
(a) 1
(b) 3
(c) 4
(d) 7
Show Answer & Explanation

Answer: (b) 3

Explanation:
1. Substituting at C-3 gives \( \ce{CH3CH2-CH(X)-C4H9} \), which has four different groups
2. At C-1 and C-7 the carbon keeps three identical H, and at C-4 the two chains are the same, so the product is achiral

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 19: The number of possible structural isomers for a compound with molecular formula \( \ce{C7H16} \) is
(a) 8
(b) 9
(c) 10
(d) 12
Show Answer & Explanation

Answer: (b) 9

Explanation:
1. Heptane, two methylhexanes, four dimethylpentanes, 3-ethylpentane and 2,2,3-trimethylbutane
2. In total 1 + 2 + 4 + 1 + 1 = 9

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 20: Which of the following molecules contains an asymmetric carbon atom?
(a) \( \ce{CH3-CHCl-COOH} \)
(b) \( \ce{CH3CH2COOH} \)
(c) \( \ce{ClCH2CH2COOH} \)
(d) \( \ce{Cl2CH-COOH} \)
Show Answer & Explanation

Answer: (a) \( \ce{CH3-CHCl-COOH} \)

Explanation:
1. \( \ce{CH3-CHCl-COOH} \) has a carbon bonded to H, Cl, \( \ce{CH3} \) and COOH
2. The others have no such carbon

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 21: A similarity between optical and geometrical isomerism is that
(a) Each forms an equal number of isomers for a given compound
(b) If a compound has one, it also has the other
(c) Both are included in stereoisomerism
(d) They have no similarity
Show Answer & Explanation

Answer: (c) Both are included in stereoisomerism

Explanation:
1. In both types the atoms are connected in the same order but arranged differently in space
2. Both come under stereoisomerism

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 22: If light waves pass through a Nicol prism so that all oscillations occur in only one plane, the beam of light is called
(a) Non-polarised light
(b) Plane polarised light
(c) Polarised light
(d) Optical light
Show Answer & Explanation

Answer: (b) Plane polarised light

Explanation:
1. A Nicol prism allows vibrations in only one plane to pass
2. The emerging beam is plane-polarised light

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 23: Which compound is chiral?
(a) Butane
(b) 1-Chloro-2-methylbutane
(c) 2-Methylbutane
(d) 2-Methylpropane
Show Answer & Explanation

Answer: (b) 1-Chloro-2-methylbutane

Explanation:
1. In \( \ce{ClCH2-CH(CH3)-CH2CH3} \) C-2 has H, \( \ce{CH3} \), \( \ce{C2H5} \) and \( \ce{CH2Cl} \)
2. The others have no stereocentre

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

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