JEE Chemistry Isomerism MCQs Set 03

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Chapter-wise Objective Questions: Isomerism

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Multiple Choice Questions

Question 1: The number of geometrical isomers of \( \ce{CH3-CH=CH-CH=CH-C2H5} \) is
(a) 4
(b) 3
(c) 2
(d) 5
Show Answer & Explanation

Answer: (a) 4

Explanation:
1. Each of the two double bonds has different groups on its carbons
2. So each can be cis or trans, giving 2 x 2 = 4 isomers

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 2: The property by virtue of which a compound can turn the plane of polarised light is known as
(a) Photolysis
(b) Phosphorescence
(c) Optical activity
(d) Polarisation
Show Answer & Explanation

Answer: (c) Optical activity

Explanation:
1. Optical activity is the ability to rotate plane-polarised light
2. The other terms describe different phenomena

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 3: Which of the following compounds exhibits optical isomerism?
(a) \( \ce{CH3CH2COOH} \)
(b) \( \ce{CH3CHOHCOOH} \)
(c) \( \ce{CH3CH2CH2OH} \)
(d) \( \ce{CH3CHOHCH3} \)
Show Answer & Explanation

Answer: (b) \( \ce{CH3CHOHCOOH} \)

Explanation:
1. Only lactic acid has a carbon bonded to four different groups
2. The others have no stereocentre

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 4: The maximum number of stereoisomers possible for 2-hydroxy-2-methylbutanoic acid is
(a) 1
(b) 2
(c) 3
(d) 4
Show Answer & Explanation

Answer: (b) 2

Explanation:
1. The compound \( \ce{CH3CH2-C(OH)(CH3)-COOH} \) has one stereocentre (C-2)
2. So there are two stereoisomers

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 5: Which one of the following pairs represents stereoisomerism?
(a) Geometrical isomerism, position isomerism
(b) Geometrical isomerism, conformational isomerism
(c) Optical isomerism, geometrical isomerism
(d) Optical isomerism, metamerism
Show Answer & Explanation

Answer: (c) Optical isomerism, geometrical isomerism

Explanation:
1. Stereoisomers have the same connectivity but different spatial arrangement
2. Optical and geometrical isomerism are both stereoisomerism (position isomerism and metamerism are structural)

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 6: Diethyl ether and methyl n-propyl ether are
(a) Position isomers
(b) Functional isomers
(c) Metamers
(d) Chain isomers
Show Answer & Explanation

Answer: (c) Metamers

Explanation:
1. Both are \( \ce{C4H10O} \) ethers with different alkyl groups on oxygen
2. Such isomers are metamers

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 7: It is possible to distinguish between optical isomers by
(a) Infrared spectroscopy
(b) Mass spectrometry
(c) Melting point determination
(d) Polarimetry
Show Answer & Explanation

Answer: (d) Polarimetry

Explanation:
1. Enantiomers have identical IR spectra, mass spectra and melting points
2. They differ only in the direction in which they rotate plane-polarised light, measured by a polarimeter

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 8: The isomerism exhibited by alkyl cyanide and alkyl isocyanide is
(a) Functional
(b) Positional
(c) Tautomerism
(d) Metamerism
Show Answer & Explanation

Answer: (a) Functional

Explanation:
1. \( \ce{R-CN} \) and \( \ce{R-NC} \) have the same formula but different functional groups
2. The relation is functional isomerism

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 9: Which compound is NOT an isomer of diethyl ether?
(a) n-Propyl methyl ether
(b) Butan-1-ol
(c) 2-Methylpropan-2-ol
(d) Butanone
Show Answer & Explanation

Answer: (d) Butanone

Explanation:
1. Diethyl ether is \( \ce{C4H10O} \), as are the first three options
2. Butanone is \( \ce{C4H8O} \)

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 10: \( \ce{CH3-O-CH2CH3} \) and \( \ce{CH3-CH2-CH2OH} \) are an example of
(a) Metamerism
(b) Functional isomerism
(c) Chain isomerism
(d) Positional isomerism
Show Answer & Explanation

Answer: (b) Functional isomerism

Explanation:
1. Both are \( \ce{C3H8O} \), one an ether and the other an alcohol
2. Different functional groups mean functional isomerism

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 11: Functional isomerism is exhibited by the pair
(a) Acetone and propionaldehyde
(b) Diethyl ether and methyl propyl ether
(c) Butane and isobutane
(d) 1-Butene and 2-butene
Show Answer & Explanation

Answer: (a) Acetone and propionaldehyde

Explanation:
1. Acetone and propanal are both \( \ce{C3H6O} \) but one is a ketone and the other an aldehyde
2. The others are metamers, chain isomers and position isomers

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 12: The total number of possible isomeric trimethylbenzenes is
(a) 2
(b) 3
(c) 4
(d) 6
Show Answer & Explanation

Answer: (b) 3

Explanation:
1. The isomers are 1,2,3-, 1,2,4- and 1,3,5-trimethylbenzene
2. Three in all

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 13: Optically active isomers that are not mirror images are called
(a) Enantiomers
(b) Tautomers
(c) Mesomers
(d) Diastereoisomers
Show Answer & Explanation

Answer: (d) Diastereoisomers

Explanation:
1. Stereoisomers that are not mirror images of each other are diastereoisomers
2. Enantiomers are mirror images

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 14: \( \ce{C7H9N} \) has how many isomeric forms that contain a benzene ring?
(a) 4
(b) 5
(c) 6
(d) 7
Show Answer & Explanation

Answer: (b) 5

Explanation:
1. Benzylamine, N-methylaniline and o-, m- and p-toluidine
2. Five isomers

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 15: Which of the following is expected to be optically active?
(a) \( \ce{(CH3)4C} \)
(b) \( \ce{C2H5-CH(CH3)-C3H7} \)
(c) \( \ce{(C2H5)2CH-CH3} \)
(d) \( \ce{CH3CH=CHCH3} \)
Show Answer & Explanation

Answer: (b) \( \ce{C2H5-CH(CH3)-C3H7} \)

Explanation:
1. 3-Methylhexane has a carbon with H, \( \ce{CH3} \), \( \ce{C2H5} \) and \( \ce{C3H7} \)
2. None of the other options has a stereocentre

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 16: Which compound does NOT show geometrical isomerism?
(a) 2-Butene
(b) 2-Pentene
(c) 2,3-Dibromo-2-butene
(d) 2-Methylpropene
Show Answer & Explanation

Answer: (d) 2-Methylpropene

Explanation:
1. In 2-methylpropene one doubly bonded carbon has two identical methyl groups
2. The other three have different groups on each C=C carbon

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 17: The isomers that can be converted into one another by rotation about a single bond are
(a) Geometrical isomers
(b) Conformers
(c) Enantiomers
(d) Diastereomers
Show Answer & Explanation

Answer: (b) Conformers

Explanation:
1. Conformers differ by rotation about single bonds only
2. The other isomers need bond breaking

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 18: The number of enantiomers of the compound \( \ce{CH3-CHBr-CHBr-COOH} \) is
(a) 0
(b) 1
(c) 3
(d) 4
Show Answer & Explanation

Answer: (d) 4

Explanation:
1. The compound has two different stereocentres, so 2^2 = 4 stereoisomers
2. These form two pairs of enantiomers, i.e. four optically active forms

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 19: Which of the following compounds is not chiral?
(a) \( \ce{DCH2CH2CH2Cl} \)
(b) \( \ce{CH3CH2CHDCl} \)
(c) \( \ce{CH3CHDCH2CH2Cl} \)
(d) \( \ce{CH2ClCHClCH2D} \)
Show Answer & Explanation

Answer: (a) \( \ce{DCH2CH2CH2Cl} \)

Explanation:
1. In (a) no carbon has four different groups
2. In (b), (c) and (d) one carbon carries four different groups (H, D and two different carbon chains or Cl)

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 20: cis- and trans-2-Butene are
(a) Conformational isomers
(b) Optical isomers
(c) Position isomers
(d) Geometrical isomers
Show Answer & Explanation

Answer: (d) Geometrical isomers

Explanation:
1. They differ in the arrangement of groups about the double bond
2. This is geometrical (cis-trans) isomerism

Teacher's Note:
1. Enantiomers differ only in optical rotation; diastereomers differ in all physical properties.
2. Meso compounds have stereocentres but are optically inactive because of internal symmetry.

Question 21: Which one of the following is the chiral molecule?
(a) \( \ce{CH3Cl} \)
(b) \( \ce{CH2Cl2} \)
(c) \( \ce{CHBr3} \)
(d) \( \ce{CHClBrI} \)
Show Answer & Explanation

Answer: (d) \( \ce{CHClBrI} \)

Explanation:
1. \( \ce{CHClBrI} \) has a carbon bonded to H, Cl, Br and I
2. All four groups are different

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Question 22: Cyanide and isocyanide are isomers of the type
(a) Positional
(b) Functional
(c) Tautomer
(d) Structural
Show Answer & Explanation

Answer: (b) Functional

Explanation:
1. \( \ce{R-CN} \) and \( \ce{R-NC} \) have different functional groups
2. They are functional isomers

Teacher's Note:
1. Write out the structures of all isomers systematically (skeleton first, then position of groups) when counting.
2. Remember that the number of stereoisomers is 2^n only when the stereocentres are all different.

Question 23: Which of the following compounds is optically active?
(a) 1-Butanol
(b) 2-Butanol
(c) 3-Butanol
(d) 4-Heptanol
Show Answer & Explanation

Answer: (b) 2-Butanol

Explanation:
1. 2-Butanol has a carbon with H, OH, \( \ce{CH3} \) and \( \ce{C2H5} \)
2. The others have no stereocentre (and 3-butanol is not a valid name)

Teacher's Note:
1. Look for a carbon with four different groups to spot chirality, and for two different groups on each doubly bonded carbon to spot geometrical isomerism.
2. Check that the isomers have the same molecular formula before naming the type.

Practice MCQs for JEE Chemistry Isomerism

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