Chemistry Objective Questions and Answers: Hydrocarbons
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Multiple Choice Questions
(a) Branched hydrocarbons
(b) Straight-chain hydrocarbons
(c) Linear unsaturated hydrocarbons
(d) Toluene
Show Answer & Explanation
Answer: (a) Branched hydrocarbons
Explanation:
1. Branched alkanes burn smoothly and have a high octane number
2. Straight chains cause knocking
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) \( \ce{CHCl3} \)
(b) \( \ce{CH3Cl} \)
(c) \( \ce{CH3CH3} \)
(d) \( \ce{CH3CH2CH3} \)
Show Answer & Explanation
Answer: (d) \( \ce{CH3CH2CH3} \)
Explanation:
1. Chlorination gives \( \ce{CH3Cl} \), \( \ce{CH2Cl2} \), \( \ce{CHCl3} \) and \( \ce{CCl4} \)
2. Two methyl radicals can combine to give a little ethane in the radical chain, but propane cannot form
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Neopentane
(b) n-Butane
(c) n-Heptane
(d) Isobutane
Show Answer & Explanation
Answer: (c) n-Heptane
Explanation:
1. Boiling point rises with molecular mass and with the length of the chain
2. n-Heptane (98 degrees C) is far above the butanes and neopentane
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Silicon carbide
(b) Calcium carbide
(c) Aluminium carbide
(d) Iron carbide
Show Answer & Explanation
Answer: (c) Aluminium carbide
Explanation:
1. \( \ce{Al4C3 + 12 H2O -> 4 Al(OH)3 + 3 CH4} \)
2. Calcium carbide gives acetylene instead
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) \( \ce{CH3OH} \)
(b) \( \ce{CH3COOH} \)
(c) \( \ce{CH3CHO} \)
(d) \( \ce{C2H6} \)
Show Answer & Explanation
Answer: (d) \( \ce{C2H6} \)
Explanation:
1. \( \ce{PCl5} \) replaces OH of alcohols and acids and the carbonyl oxygen of aldehydes
2. Alkanes have no such reactive group
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Ethylene
(b) Benzene
(c) Hexane
(d) Aniline
Show Answer & Explanation
Answer: (c) Hexane
Explanation:
1. Alkanes are saturated and non-polar, so they do not dissolve or react
2. Alkenes, benzene (sulphonation) and aniline (salt formation) do
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Methane
(b) Ethane
(c) Propane
(d) Butane
Show Answer & Explanation
Answer: (a) Methane
Explanation:
1. The Grignard reagent is a strong base and removes the acidic OH hydrogen
2. \( \ce{CH3MgBr + C2H5OH -> CH4 + C2H5OMgBr} \)
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) \( \ce{CH3I} \)
(b) \( \ce{C2H5I} \)
(c) \( \ce{CH3OH} \)
(d) \( \ce{C2H5OH} \)
Show Answer & Explanation
Answer: (a) \( \ce{CH3I} \)
Explanation:
1. Reduction of \( \ce{CH3I} \) (Zn/HCl) gives methane
2. Wurtz coupling of \( \ce{CH3I} \) with Na gives ethane
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Ester
(b) Alcohol
(c) Unsaturated hydrocarbon
(d) Saturated hydrocarbon
Show Answer & Explanation
Answer: (d) Saturated hydrocarbon
Explanation:
1. Paraffin wax is a mixture of higher alkanes, \( \ce{C20-C30} \)
2. It is a saturated hydrocarbon
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) 2
(b) 3
(c) 4
(d) 1
Show Answer & Explanation
Answer: (a) 2
Explanation:
1. The four monochloro products include two chiral ones, 1-chloro-2-methylbutane and 2-chloro-3-methylbutane
2. Each exists as one enantiomeric pair, so there are 2 pairs
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Aliphatic hydrocarbons
(b) Aromatic hydrocarbons
(c) Aliphatic alcohols
(d) None of these
Show Answer & Explanation
Answer: (a) Aliphatic hydrocarbons
Explanation:
1. Petroleum is mostly a mixture of alkanes and cycloalkanes
2. Aromatic compounds are minor constituents
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) A solvent for fats, oils, varnish and rubber
(b) A fuel
(c) Both (a) and (b)
(d) None of these
Show Answer & Explanation
Answer: (a) A solvent for fats, oils, varnish and rubber
Explanation:
1. Petroleum ether is a low-boiling mixture of pentanes and hexanes
2. It is a non-polar solvent for fats, oils and rubber, but it is far too volatile to be used as a fuel
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Synthetic dyes
(b) Drugs
(c) Perfumes
(d) All the three
Show Answer & Explanation
Answer: (d) All the three
Explanation:
1. Coal tar is a source of benzene, toluene, phenol and naphthalene
2. These are raw materials for dyes, drugs and perfumes
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) 109.5 degrees
(b) 109 degrees
(c) 120 degrees
(d) 180 degrees
Show Answer & Explanation
Answer: (a) 109.5 degrees
Explanation:
1. The carbon is sp3 hybridised
2. So the bond angle is the tetrahedral angle, 109.5 degrees
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Hydrolysis
(b) Oxidation
(c) Hydrogenation
(d) Electrolysis
Show Answer & Explanation
Answer: (d) Electrolysis
Explanation:
1. This is Kolbe's electrolytic method
2. Two carboxylate ions lose \( \ce{CO2} \) at the anode and the alkyl radicals join to give an alkane
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Electrophilic substitution
(b) Nucleophilic substitution
(c) Free-radical substitution
(d) Oxidation
Show Answer & Explanation
Answer: (c) Free-radical substitution
Explanation:
1. Light splits \( \ce{X2} \) into radicals which abstract H from the alkane
2. A halogen atom replaces hydrogen by a chain reaction
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Ethane
(b) Propane
(c) Butane
(d) None of these
Show Answer & Explanation
Answer: (b) Propane
Explanation:
1. HI/red P reduces \( \ce{-COOH} \) to \( \ce{-CH3} \)
2. \( \ce{CH3CH2COOH + 6HI -> CH3CH2CH3 + 2H2O + 3I2} \)
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) One alkane
(b) Two alkanes
(c) Four alkanes
(d) Three alkanes
Show Answer & Explanation
Answer: (d) Three alkanes
Explanation:
1. Cross coupling gives pentane (ethyl + propyl)
2. Self coupling gives butane and hexane, so three alkanes form
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Neopentane
(b) Ethane
(c) Methane
(d) Propane
Show Answer & Explanation
Answer: (d) Propane
Explanation:
1. Propane has two kinds of hydrogen, on C-1 and on C-2
2. So it gives 1-bromopropane and 2-bromopropane
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Alkanes
(b) Aromatic compounds
(c) Alcohols
(d) Aliphatic acids
Show Answer & Explanation
Answer: (a) Alkanes
Explanation:
1. Kerosene is a fraction of petroleum with about 10 to 16 carbon atoms
2. It is mainly alkanes
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Kerosene
(b) Petroleum ether
(c) Diesel
(d) Machine oil
Show Answer & Explanation
Answer: (b) Petroleum ether
Explanation:
1. Fractions come off in order of boiling point
2. Petroleum ether (40-70 degrees C) is the most volatile of the four
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) To precipitate inorganic substances
(b) To prevent freezing of petrol
(c) To increase the boiling point of petrol
(d) As an antiknock
Show Answer & Explanation
Answer: (d) As an antiknock
Explanation:
1. Iso-octane has an octane number of 100
2. Adding it raises the antiknock quality of the fuel
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) A fire extinguisher
(b) A pain reliever
(c) A petroleum additive
(d) A mosquito repellent
Show Answer & Explanation
Answer: (c) A petroleum additive
Explanation:
1. Tetraethyl lead is added to petrol to raise the octane number
2. It is an antiknock additive
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
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Hydrocarbons Objective Questions & Solutions for JEE Chemistry
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FAQs
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