Download JEE MCQs for JEE Chemistry: Hydrocarbons
Explore reliable objective questions for Hydrocarbons tailored for JEE learners. Utilizing these Chemistry multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Chapter-wise Objective Questions: Hydrocarbons
Navigate directly to the 50 objective questions for Hydrocarbons using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) \( \ce{C5H8} \)
(b) \( \ce{C8H6} \)
(c) \( \ce{C9H10} \)
(d) \( \ce{C7H16} \)
Show Answer & Explanation
Answer: (d) \( \ce{C7H16} \)
Explanation:
1. An alkane follows \( \ce{CnH2n+2} \)
2. For n = 7 this gives \( \ce{C7H16} \)
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) n-Pentane > iso-pentane > neo-pentane
(b) iso-Pentane > n-pentane > neo-pentane
(c) neo-Pentane > iso-pentane > n-pentane
(d) n-Pentane > neo-pentane > iso-pentane
Show Answer & Explanation
Answer: (a) n-Pentane > iso-pentane > neo-pentane
Explanation:
1. Branching reduces surface area and so van der Waals forces
2. The straight chain n-pentane boils highest and the compact neopentane lowest
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) n-Propyl bromide
(b) Ethyl bromide and n-butyl bromide
(c) Ethyl chloride and n-butyl chloride
(d) Methyl bromide and n-pentyl chloride
Show Answer & Explanation
Answer: (a) n-Propyl bromide
Explanation:
1. By the Wurtz reaction, \( \ce{2 CH3CH2CH2Br + 2 Na -> CH3(CH2)4CH3 + 2 NaBr} \)
2. Using one alkyl halide avoids a mixture of alkanes
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Mg
(b) Zn
(c) Li
(d) K
Show Answer & Explanation
Answer: (a) Mg
Explanation:
1. Alkyl halides react with magnesium in dry ether to give \( \ce{RMgX} \)
2. Zn gives Frankland reagents and Li gives organolithiums
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Heating with \( \ce{LiAlH4} \)
(b) Electrolysing its aqueous solution
(c) Heating with soda lime
(d) Heating with calcium acetate
Show Answer & Explanation
Answer: (b) Electrolysing its aqueous solution
Explanation:
1. Kolbe electrolysis of \( \ce{CH3COONa} \) gives \( \ce{CH3-CH3} \) at the anode with \( \ce{CO2} \)
2. Heating with soda lime gives methane instead
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Glycerol
(b) Glycol
(c) 1,2-Dibromoethane
(d) Benzene
Show Answer & Explanation
Answer: (c) 1,2-Dibromoethane
Explanation:
1. Tetraethyl lead leaves lead and lead oxides in the engine
2. 1,2-Dibromoethane converts them into volatile \( \ce{PbBr2} \), which leaves with the exhaust
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) \( \ce{C15-C18} \)
(b) \( \ce{C10-C12} \)
(c) \( \ce{C5-C9} \)
(d) \( \ce{C1-C9} \)
Show Answer & Explanation
Answer: (b) \( \ce{C10-C12} \)
Explanation:
1. Kerosene boils at about 175-275 degrees C
2. It contains hydrocarbons of roughly \( \ce{C10-C12} \)
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Wurtz reaction
(b) Aldol condensation
(c) Perkin's reaction
(d) Levit reaction
Show Answer & Explanation
Answer: (a) Wurtz reaction
Explanation:
1. Two alkyl halides couple on treatment with sodium in dry ether to form a higher alkane, ethane here
2. This is the Wurtz reaction
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Pentane
(b) Propane
(c) Butene
(d) Butane
Show Answer & Explanation
Answer: (d) Butane
Explanation:
1. \( \ce{2 C2H5I + 2 Na -> C2H5-C2H5 + 2 NaI} \)
2. The two ethyl groups join to give butane
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Methane
(b) Pentane
(c) Isobutane
(d) Neopentane
Show Answer & Explanation
Answer: (c) Isobutane
Explanation:
1. \( \ce{KMnO4} \) oxidises a tertiary C-H bond of an alkane to give the tertiary alcohol, \( \ce{(CH3)3C-OH} \)
2. Isobutane has a tertiary hydrogen, while the others do not react easily
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) \( \ce{CH3^+} \)
(b) \( \ce{CH3-C^+H2} \)
(c) \( \ce{CH3-C^+H-CH3} \)
(d) \( \ce{(CH3)3C^+} \)
Show Answer & Explanation
Answer: (d) \( \ce{(CH3)3C^+} \)
Explanation:
1. The tertiary carbocation has the most alkyl groups for +I and hyperconjugation
2. Order: tertiary > secondary > primary > methyl
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) 2,2-Dimethylpropane
(b) 2-Methylbutane
(c) Isobutane
(d) n-Pentane
Show Answer & Explanation
Answer: (a) 2,2-Dimethylpropane
Explanation:
1. Volatility rises as intermolecular forces fall
2. Neopentane is the most compact of the pentanes (b.p. 9.5 degrees C), so it is the most volatile of the options
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Na
(b) Na/liquid \( \ce{NH3} \)
(c) Na/dry ether
(d) Na/dry alcohol
Show Answer & Explanation
Answer: (c) Na/dry ether
Explanation:
1. Alkyl halides couple with sodium in dry ether
2. Water or alcohol would react with sodium, so dryness is essential
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) n-Hexane
(b) n-Heptane
(c) n-Pentane
(d) 2,2,4-Trimethylpentane
Show Answer & Explanation
Answer: (d) 2,2,4-Trimethylpentane
Explanation:
1. Iso-octane (2,2,4-trimethylpentane) is the reference fuel with an octane number of 100
2. Straight-chain alkanes knock much more and have low octane numbers
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Pesticide
(b) Refrigerant
(c) Solvent
(d) Lubricant
Show Answer & Explanation
Answer: (b) Refrigerant
Explanation:
1. Freon-12 is \( \ce{CCl2F2} \)
2. It is non-flammable and easily liquefied, so it was used as a refrigerant
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) 20% normal heptane + 80% iso-octane
(b) 80% normal heptane + 20% iso-octane
(c) 20% normal heptane + 80% normal octane
(d) 80% normal heptane + 20% normal octane
Show Answer & Explanation
Answer: (a) 20% normal heptane + 80% iso-octane
Explanation:
1. Octane number is the percentage by volume of iso-octane in a mixture with n-heptane
2. An octane number of 80 means 80% iso-octane and 20% n-heptane
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) \( \ce{CH3CH2CH2Cl} \) with Mg/ether, then \( \ce{H2O} \)
(b) \( \ce{CH3COCl} \) with \( \ce{CH3MgX} \), then \( \ce{H2O} \)
(c) \( \ce{CH3CH=CH2} \) with \( \ce{B2H6} \), then \( \ce{CH3COOH} \)
(d) \( \ce{CH3CH(OH)CH3} \) with P/HI
Show Answer & Explanation
Answer: (b) \( \ce{CH3COCl} \) with \( \ce{CH3MgX} \), then \( \ce{H2O} \)
Explanation:
1. (a) The Grignard reagent is hydrolysed to propane, (c) hydroboration then protonolysis gives propane, (d) HI/P reduces the alcohol to propane
2. (b) gives acetone (\( \ce{CH3COCH3} \))
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) Linear
(b) Trigonal planar
(c) Square planar
(d) Tetrahedral
Show Answer & Explanation
Answer: (d) Tetrahedral
Explanation:
1. Carbon in methane is sp3 hybridised
2. The four C-H bonds point to the corners of a tetrahedron
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) But-2-ene
(b) 2,2-Dimethylpropane
(c) But-1-yne
(d) Butan-2-ol
Show Answer & Explanation
Answer: (b) 2,2-Dimethylpropane
Explanation:
1. All twelve hydrogens of neopentane are equivalent
2. Only one monobromo derivative is possible
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) 2-Bromobutane
(b) 2-Methylpropane
(c) 1-Bromobutane
(d) All of these
Show Answer & Explanation
Answer: (b) 2-Methylpropane
Explanation:
1. \( \ce{AlCl3} \) with HCl or HBr isomerises n-alkanes to branched alkanes
2. Butane gives isobutane (2-methylpropane)
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
(a) It can be chlorinated with chlorine
(b) It can be catalytically hydrogenated
(c) When oxidised it produces \( \ce{CO2} \) and \( \ce{H2O} \)
(d) It is a saturated hydrocarbon
Show Answer & Explanation
Answer: (b) It can be catalytically hydrogenated
Explanation:
1. Ethane has no multiple bond, so it cannot add hydrogen
2. The other statements are correct
Teacher's Note:
1. Trends such as boiling point and stability depend on molecular size, branching and substituent effects.
2. Apply the trend directly to rank the options.
(a) Distillation of petroleum to give different fractions
(b) Obtaining aromatic compounds from aliphatic compounds present in petroleum
(c) Cracking of petroleum to get gaseous hydrocarbons
(d) Purification of petroleum
Show Answer & Explanation
Answer: (a) Distillation of petroleum to give different fractions
Explanation:
1. Refining separates crude oil by fractional distillation into gasoline, kerosene, diesel and so on
2. Cracking and reforming are separate processes
Teacher's Note:
1. Recall the key fact or reaction first, then eliminate options that contradict it.
2. Link each answer to the underlying bonding or mechanism rather than memorising it.
(a) Iso-octane
(b) Ethylene dibromide
(c) Tetraethyl lead
(d) Mercaptan
Show Answer & Explanation
Answer: (b) Ethylene dibromide
Explanation:
1. Ethylene dibromide converts lead into volatile \( \ce{PbBr2} \)
2. The vapour leaves with the exhaust gases
Teacher's Note:
1. Check the type of reaction involved and what it does to the carbon skeleton.
2. Compare the options one by one against that.
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FAQs
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