Multiple Choice Questions (MCQs) for JEE Chemistry: Biomolecules
Review structured MCQ sets for JEE Chemistry Biomolecules. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Practice Biomolecules MCQs for JEE Chemistry
Navigate directly to the 50 objective questions for Biomolecules using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) glycerine
(b) cellulose
(c) glycol
(d) starch
Show Answer & Explanation
Answer: (b) cellulose
Explanation:
1. Nitration of cellulose gives cellulose nitrate.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) C and O
(b) C, H and O
(c) C, H, N and O
(d) C and H
Show Answer & Explanation
Answer: (b) C, H and O
Explanation:
1. Carbohydrates are made of carbon, hydrogen and oxygen only.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) the same osazone
(b) the same acid on oxidation
(c) the same alcohol when reduced
(d) different osazones
Show Answer & Explanation
Answer: (a) the same osazone
Explanation:
1. Only C1 and C2 react with phenylhydrazine, and these two sugars have the same configuration at C3 to C5, so the osazone is the same.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) CO and CO2
(b) CO and SO2
(c) CO, CO2 and SO2
(d) none of these
Show Answer & Explanation
Answer: (c) CO, CO2 and SO2
Explanation:
1. Sucrose is dehydrated to carbon, which is then oxidised by the acid to CO, CO2 with SO2.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) its direct synthesis
(b) its dextrorotation
(c) its mutarotation
(d) its configuration
Show Answer & Explanation
Answer: (d) its configuration
Explanation:
1. D means that the configuration at the highest-numbered chiral carbon matches D-glyceraldehyde, and it says nothing about the sign of rotation.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) glucose in aqueous solution
(b) protein in blood
(c) iodine in aqueous solution
(d) urea in blood
Show Answer & Explanation
Answer: (c) iodine in aqueous solution
Explanation:
1. Starch gives a deep blue colour with iodine.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) fructose
(b) starch
(c) glucose
(d) cellulose
Show Answer & Explanation
Answer: (d) cellulose
Explanation:
1. Cellulose is the main structural material of plants and the most abundant organic compound.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) cellulose
(b) sucrose
(c) vitamins
(d) starch
Show Answer & Explanation
Answer: (a) cellulose
Explanation:
1. Cellulose forms the cell wall.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) Molisch's test
(b) Dunstan's test
(c) Benedict's test
(d) Legal's test
Show Answer & Explanation
Answer: (c) Benedict's test
Explanation:
1. Benedict's reagent gives a red precipitate with glucose in urine.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) sucrose nitrate
(b) formic acid
(c) oxalic acid
(d) citric acid
Show Answer & Explanation
Answer: (c) oxalic acid
Explanation:
1. Strong oxidation of sugars with nitric acid cleaves them to oxalic acid.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) it is a polyhydroxy compound
(b) it is an aldehyde sugar
(c) it has six carbon atoms
(d) it exhibits optical activity
Show Answer & Explanation
Answer: (c) it has six carbon atoms
Explanation:
1. Ribose is an aldopentose with five carbon atoms.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) 6
(b) 10
(c) 11
(d) 22
Show Answer & Explanation
Answer: (c) 11
Explanation:
1. Maltose is C12H22O11.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) alpha-D-glucopyranosyl-beta-D-fructofuranoside
(b) beta-D-glucopyranosyl-beta-D-fructofuranoside
(c) alpha-D-glucopyranosyl-alpha-D-fructofuranoside
(d) beta-D-glucopyranosyl-alpha-L-fructofuranoside
Show Answer & Explanation
Answer: (a) alpha-D-glucopyranosyl-beta-D-fructofuranoside
Explanation:
1. Sucrose is linked from C1 of alpha-glucose to C2 of beta-fructose through both anomeric carbons.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) laevorotatory
(b) dextrorotatory
(c) a racemic mixture
(d) optically inactive
Show Answer & Explanation
Answer: (b) dextrorotatory
Explanation:
1. Sucrose has a specific rotation of +66.5 degrees.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) laevorotatory
(b) dextrorotatory
(c) equally both (+) and (-) rotatory
(d) optically inactive
Show Answer & Explanation
Answer: (a) laevorotatory
Explanation:
1. The product (invert sugar) has net rotation about -20 degrees, because fructose (-92 degrees) outweighs glucose (+52.5 degrees).
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) a reducing sugar
(b) not a reducing sugar
(c) a partial reducing sugar
(d) a mixed sugar
Show Answer & Explanation
Answer: (b) not a reducing sugar
Explanation:
1. Both anomeric carbons are tied up in the glycosidic link, so it has no free aldehyde or ketone group.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) -CHO
(b) >C=O
(c) both (a) and (b)
(d) none of these
Show Answer & Explanation
Answer: (d) none of these
Explanation:
1. Neither carbonyl group is free in sucrose.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) furanose
(b) pyranose
(c) open chain
(d) all of these
Show Answer & Explanation
Answer: (a) furanose
Explanation:
1. Fructose in sucrose is a five-membered furanose ring.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) glucose
(b) sucrose
(c) fructose
(d) none of these
Show Answer & Explanation
Answer: (c) fructose
Explanation:
1. Fructose is called laevulose, with [alpha]D = -92 degrees.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) hydrolysis
(b) change in bacteria
(c) hydrogenation
(d) dehydration
Show Answer & Explanation
Answer: (a) hydrolysis
Explanation:
1. Enzymes hydrolyse large food molecules into small ones.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) neutral ferric chloride
(b) chloroform and alcoholic KOH
(c) ammoniacal silver nitrate
(d) sodium ethoxide
Show Answer & Explanation
Answer: (c) ammoniacal silver nitrate
Explanation:
1. Tollens' reagent gives a silver mirror with glucose.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) two molecules of glucose
(b) two molecules of fructose
(c) one molecule each of glucose and fructose
(d) one molecule each of glucose and mannose
Show Answer & Explanation
Answer: (c) one molecule each of glucose and fructose
Explanation:
1. C12H22O11 + H2O -> C6H12O6 + C6H12O6, glucose plus fructose.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) lactose
(b) starch
(c) cellulose
(d) glucose
Show Answer & Explanation
Answer: (a) lactose
Explanation:
1. Lactose is glucose plus galactose.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) a hexose
(b) a carbohydrate
(c) an oligosaccharide
(d) an aldose
Show Answer & Explanation
Answer: (c) an oligosaccharide
Explanation:
1. Glucose is a monosaccharide, so it is not an oligosaccharide.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) Fehling solution
(b) phenylhydrazine
(c) Benedict solution
(d) hydroxylamine
Show Answer & Explanation
Answer: (b) phenylhydrazine
Explanation:
1. Excess phenylhydrazine gives a yellow crystalline phenylosazone.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) maltase
(b) zymase
(c) invertase
(d) diastase
Show Answer & Explanation
Answer: (d) diastase
Explanation:
1. Diastase (amylase) hydrolyses starch to maltose.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) glucose and maltose
(b) glucose and lactose
(c) glucose and fructose
(d) only glucose
Show Answer & Explanation
Answer: (c) glucose and fructose
Explanation:
1. Cane sugar is sucrose.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
Free study material for Chemistry
Biomolecules Objective Questions & Solutions for JEE Chemistry
JEE Chemistry Biomolecules Objective Test Questions
Test your conceptual understanding of Biomolecules with these targeted multiple-choice questions. Designed in alignment with the latest JEE curriculum for JEE Chemistry, these problem sets build accuracy and prepare students for objective exams.
NCERT-Aligned Objective Questions and Solutions
Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
Next Steps in Your Exam Preparation
Wrap up your chapter revision by testing your knowledge against standard question formats. Everything on our platform is provided free of charge.
FAQs
You can get most exhaustive JEE Chemistry Biomolecules MCQs Set 11 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.
Yes, our JEE Chemistry Biomolecules MCQs Set 11 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Chemistry Biomolecules MCQs Set 11, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.
Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Chemistry Biomolecules MCQs Set 11 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.