Practice MCQs for JEE Chemistry Biomolecules
Review structured MCQ sets for JEE Chemistry Biomolecules. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
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Access the complete set of multiple-choice questions for Biomolecules below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) rotatory motion
(b) inversion
(c) specific rotation
(d) mutarotation
Show Answer & Explanation
Answer: (d) mutarotation
Explanation:
1. A fresh solution of one anomer changes in rotation as it equilibrates with the other anomer, which is mutarotation.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) nitrosucrose
(b) nitrocellulose
(c) nitroglucose
(d) nitropicrin
Show Answer & Explanation
Answer: (b) nitrocellulose
Explanation:
1. Cellulose treated with conc. HNO3 and conc. H2SO4 gives cellulose trinitrate, gun-cotton.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) galactose
(b) fructose
(c) glucose
(d) arabinose
Show Answer & Explanation
Answer: (d) arabinose
Explanation:
1. Arabinose is an aldopentose, HOCH2(CHOH)3CHO.
2. The other three are hexoses.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) lipids
(b) carbohydrates
(c) amino acids
(d) proteins
Show Answer & Explanation
Answer: (d) proteins
Explanation:
1. Proteins are polyamides joined by peptide (amide) bonds.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) leucine
(b) albumin
(c) inulin
(d) maltase
Show Answer & Explanation
Answer: (c) inulin
Explanation:
1. Inulin is a polysaccharide of fructose.
2. Leucine is an amino acid and albumin and maltase are proteins.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) CnH2nO2n+2
(b) Cx(H2O)2x
(c) Cx(H2O)y
(d) none of these
Show Answer & Explanation
Answer: (c) Cx(H2O)y
Explanation:
1. Carbohydrates were named hydrates of carbon, Cx(H2O)y, though some compounds fitting the formula are not carbohydrates.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) Ag+
(b) Li+
(c) Cu2+
(d) Ba2+
Show Answer & Explanation
Answer: (c) Cu2+
Explanation:
1. Benedict's reagent is alkaline CuSO4 with citrate.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) an acidic group
(b) an alcoholic group
(c) a ketonic group
(d) an aldehydic group
Show Answer & Explanation
Answer: (d) an aldehydic group
Explanation:
1. Tollens' reagent oxidises an aldehyde group to the acid and is itself reduced to silver.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) a protein
(b) a monosaccharide
(c) a lipid
(d) an amino acid
Show Answer & Explanation
Answer: (b) a monosaccharide
Explanation:
1. Ninhydrin detects amino acids and proteins, and Benedict's solution detects reducing sugars.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) sucrose
(b) a protein
(c) fructose
(d) maltose
Show Answer & Explanation
Answer: (d) maltose
Explanation:
1. Positive Molisch means a carbohydrate and positive Benedict means a reducing sugar, so sucrose is excluded.
2. Fructose, a ketose, gives Seliwanoff's test, while maltose, an aldose-type reducing sugar, does not.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) an aldehyde group
(b) a -CH2OH group
(c) a ring structure
(d) five hydroxyl groups
Show Answer & Explanation
Answer: (c) a ring structure
Explanation:
1. The cyclic hemiacetal form is converted into two anomeric acetals (glycosides).
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) glucose
(b) xylose
(c) fructose
(d) sucrose
Show Answer & Explanation
Answer: (d) sucrose
Explanation:
1. Sucrose splits into one glucose and one fructose.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) glucose
(b) fructose
(c) both glucose and fructose
(d) none of these
Show Answer & Explanation
Answer: (c) both glucose and fructose
Explanation:
1. Glucose and fructose are isomers.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) esterification
(b) saponification
(c) inversion
(d) hydration
Show Answer & Explanation
Answer: (c) inversion
Explanation:
1. The dextrorotatory sucrose gives a laevorotatory mixture, so the rotation is inverted.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) fructose
(b) lactose
(c) galactose
(d) sucrose
Show Answer & Explanation
Answer: (c) galactose
Explanation:
1. Glycolipids contain glucose or galactose.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) change of configuration
(b) addition of one more carbon
(c) substitution of a carbon
(d) conversion of -CHO to -C=O
Show Answer & Explanation
Answer: (a) change of configuration
Explanation:
1. Epimers differ in configuration at one carbon atom, and epimerisation inverts it.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) glycolaldehyde
(b) glyceraldehyde
(c) glucose
(d) galactose
Show Answer & Explanation
Answer: (a) glycolaldehyde
Explanation:
1. HOCH2CHO has no carbon bearing four different groups.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) -
(b) +
(c) R-
(d) all of these
Show Answer & Explanation
Answer: (b) +
Explanation:
1. The (+) sign denotes dextrorotation.
2. R/S describes configuration and (-) is laevorotation.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) glycolaldehyde
(b) glyceraldehyde
(c) glucose
(d) fructose
Show Answer & Explanation
Answer: (b) glyceraldehyde
Explanation:
1. D- and L- are assigned by comparison with glyceraldehyde.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) optically active polyhydroxy aldehydes
(b) optically active polyhydroxy ketones
(c) optically active polyhydroxy aldehydes or ketones
(d) polyhydroxy aldehydes or ketones which may or may not be optically active
Show Answer & Explanation
Answer: (d) polyhydroxy aldehydes or ketones which may or may not be optically active
Explanation:
1. Simple sugars such as dihydroxyacetone are optically inactive, so only the last statement covers all sugars.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) C6H12O7
(b) C6H12O8
(c) C6H12O6
(d) C6H10O6
Show Answer & Explanation
Answer: (a) C6H12O7
Explanation:
1. Br2 water oxidises only the -CHO group to -COOH, giving gluconic acid, C6H12O7.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) the brain and the spinal cord
(b) nails and hairs
(c) oils and fats
(d) waxes
Show Answer & Explanation
Answer: (a) the brain and the spinal cord
Explanation:
1. Phospholipids are abundant in nerve tissue.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) monosaccharide
(b) disaccharide
(c) trisaccharide
(d) polysaccharide
Show Answer & Explanation
Answer: (b) disaccharide
Explanation:
1. It is made of glucose and fructose.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) C10H18O9
(b) C10H20O10
(c) C18H22O11
(d) C12H22O11
Show Answer & Explanation
Answer: (d) C12H22O11
Explanation:
1. Two C6H12O6 units less H2O gives C12H22O11.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) glucose
(b) glucose and fructose
(c) fructose
(d) sucrose
Show Answer & Explanation
Answer: (a) glucose
Explanation:
1. Starch is a polymer of glucose.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) glucose
(b) fructose
(c) galactose
(d) all of these
Show Answer & Explanation
Answer: (d) all of these
Explanation:
1. None can be hydrolysed further.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) starch
(b) glycogen
(c) cellulose
(d) all of these
Show Answer & Explanation
Answer: (d) all of these
Explanation:
1. Each is a polymer of glucose units.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
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FAQs
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