Download JEE MCQs for JEE Chemistry: Basic Inorganic Nomenclature
Review structured MCQ sets for JEE Chemistry Basic Inorganic Nomenclature. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Chapter-wise Objective Questions: Basic Inorganic Nomenclature
Navigate directly to the 50 objective questions for Basic Inorganic Nomenclature using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) \( \ce{NaClO2} \)
(b) \( \ce{NaClO3} \)
(c) \( \ce{NaClO} \)
(d) \( \ce{NaClO4} \)
Show Answer & Explanation
Answer: (a) \( \ce{NaClO2} \)
Explanation:
1. Chlorous acid \( \ce{HClO2} \) gives chlorite \( \ce{ClO2^-} \) (-ous gives -ite).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{AlP3} \)
(b) \( \ce{AlP} \)
(c) \( \ce{Al2P3} \)
(d) \( \ce{Al3P2} \)
Show Answer & Explanation
Answer: (b) \( \ce{AlP} \)
Explanation:
1. Al is +3 and phosphide is \( \ce{P^3-} \), so the ratio is 1:1.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.
(a) \( \ce{Ba(N3)2} \)
(b) \( \ce{BaN} \)
(c) \( \ce{Ba2N3} \)
(d) \( \ce{Ba3N2} \)
Show Answer & Explanation
Answer: (a) \( \ce{Ba(N3)2} \)
Explanation:
1. Azide is \( \ce{N3^-} \) and barium is \( \ce{Ba^2+} \), so two azide ions are needed. (\( \ce{Ba3N2} \) would be barium nitride.)
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.
(a) \( \ce{SiF} \)
(b) \( \ce{SiF3} \)
(c) \( \ce{SiF4} \)
(d) \( \ce{SiF6} \)
Show Answer & Explanation
Answer: (c) \( \ce{SiF4} \)
Explanation:
1. Silicon has valency 4 with fluorine -1, so \( \ce{SiF4} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.
(a) \( \ce{Al2C} \)
(b) \( \ce{AlC3} \)
(c) \( \ce{AlC} \)
(d) \( \ce{Al4C3} \)
Show Answer & Explanation
Answer: (d) \( \ce{Al4C3} \)
Explanation:
1. Al is +3 and carbide is \( \ce{C^4-} \): cross-multiplying gives \( \ce{Al4C3} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.
(a) \( \ce{H3PO4} \) only
(b) All of these
(c) \( \ce{H3BO3} \) only
(d) \( \ce{H2SO4} \) only
Show Answer & Explanation
Answer: (b) All of these
Explanation:
1. \( \ce{2H3PO4} \) - \( \ce{H2O} \) = \( \ce{H4P2O7} \), \( \ce{2H3BO3} \) - \( \ce{H2O} \) = \( \ce{H4B2O5} \) and \( \ce{2H2SO4} \) - \( \ce{H2O} \) = \( \ce{H2S2O7} \) all exist.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) Cl, S, P
(b) Si, B, C
(c) Cl, S, N
(d) C, Si, P
Show Answer & Explanation
Answer: (c) Cl, S, N
Explanation:
1. Meta acids are formed by Si, P and B (e.g. \( \ce{H2SiO3} \), \( \ce{HPO3} \), \( \ce{HBO2} \)); Cl, S and N do not form them. In the options, only the set Cl, S, N contains no such element.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) (i) and (ii) only
(b) All of these
(c) (ii) and (iii) only
(d) (iii) and (iv) only
Show Answer & Explanation
Answer: (b) All of these
Explanation:
1. All four names follow the -ate rule and are correct.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{Na3S} \)
(b) \( \ce{Na3S2} \)
(c) \( \ce{Na2S} \)
(d) \( \ce{Na2S3} \)
Show Answer & Explanation
Answer: (d) \( \ce{Na2S3} \)
Explanation:
1. Trisulphide is \( \ce{S3^2-} \) and sodium is +1, so \( \ce{Na2S3} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.
(a) phosphate ion
(b) phosphite ion
(c) hypophosphite ion
(d) pyrophosphite ion
Show Answer & Explanation
Answer: (a) phosphate ion
Explanation:
1. It comes from the -ic acid \( \ce{H3PO4} \) so it is a phosphate.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{H3PO4} \)
(b) \( \ce{H4P2O5} \)
(c) \( \ce{H4P2O7} \)
(d) \( \ce{H3PO3} \)
Show Answer & Explanation
Answer: (c) \( \ce{H4P2O7} \)
Explanation:
1. \( \ce{2H3PO4} \) - \( \ce{H2O} \) = \( \ce{H4P2O7} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) 1-s, 2-q, 3-r, 4-s
(b) 1-q, 2-r, 3-p, 4-q
(c) 1-s, 2-r, 3-q, 4-p
(d) 1-r, 2-p, 3-s, 4-q
Show Answer & Explanation
Answer: (d) 1-r, 2-p, 3-s, 4-q
Explanation:
1. \( \ce{H3PO4} \) is (ortho)phosphoric, \( \ce{HPO3} \) metaphosphoric, \( \ce{H2SO4} \) sulphuric and \( \ce{H2S2O3} \) thiosulphuric (one O replaced by S).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) \( \ce{H2S2O8} \)
(b) \( \ce{H2S2O3} \)
(c) \( \ce{H2S2O7} \)
(d) \( \ce{H2SO3} \)
Show Answer & Explanation
Answer: (c) \( \ce{H2S2O7} \)
Explanation:
1. \( \ce{2H2SO4} \) - \( \ce{H2O} \) = \( \ce{H2S2O7} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) \( \ce{H2SO3} \)
(b) \( \ce{H2S2O7} \)
(c) \( \ce{H2S2O8} \)
(d) \( \ce{H2S2O3} \)
Show Answer & Explanation
Answer: (a) \( \ce{H2SO3} \)
Explanation:
1. The -ous acid has fewer oxygens than sulphuric acid: \( \ce{H2SO3} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{H2S2O7} \)
(b) \( \ce{H2SO5} \)
(c) \( \ce{H2SO4} \)
(d) \( \ce{H2S2O8} \)
Show Answer & Explanation
Answer: (b) \( \ce{H2SO5} \)
Explanation:
1. One -O- of sulphuric acid is replaced by -O-O-, giving \( \ce{H2SO5} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) hypoiodous acid
(b) iodic acid
(c) periodic acid
(d) iodous acid
Show Answer & Explanation
Answer: (d) iodous acid
Explanation:
1. HIO is hypoiodous, \( \ce{HIO2} \) iodous, \( \ce{HIO3} \) iodic, \( \ce{HIO4} \) periodic acid.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) magnesium hypoiodite
(b) magnesium iodite
(c) magnesium iodate
(d) magnesium periodate
Show Answer & Explanation
Answer: (a) magnesium hypoiodite
Explanation:
1. IO^- comes from hypoiodous acid, so it is hypoiodite.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{CdF3} \) is a correct formula
(b) Zn can show only the +3 state
(c) The element of atomic number 29 lies in the p-block
(d) The name of \( \ce{SeO3^2-} \) is selenite
Show Answer & Explanation
Answer: (d) The name of \( \ce{SeO3^2-} \) is selenite
Explanation:
1. Selenium(IV) oxoanion is selenite. Cd is +2 so \( \ce{CdF2} \) is right, Zn is only +2 and Z = 29 (Cu) is a d-block element.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{SiI2} \)
(b) \( \ce{Na2C8H4O4} \)
(c) \( \ce{Cr2O7} \)
(d) \( \ce{Ti2O5} \)
Show Answer & Explanation
Answer: (b) \( \ce{Na2C8H4O4} \)
Explanation:
1. Sodium phthalate \( \ce{Na2C8H4O4} \) is a real salt; \( \ce{CrO3} \) or \( \ce{Cr2O3} \) (not \( \ce{Cr2O7} \)) and \( \ce{TiO2} \) are the common oxides.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.
(a) \( \ce{H2SnO3} \)
(b) \( \ce{Sb2O5} \)
(c) \( \ce{H3PO5} \)
(d) \( \ce{HNO2} \)
Show Answer & Explanation
Answer: (c) \( \ce{H3PO5} \)
Explanation:
1. \( \ce{H3PO5} \) has one O-O link and is peroxomonophosphoric acid; the others have no peroxide link.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) carbonate, azide, peroxide, acetate
(b) carbonate, azide, acetate, peroxide
(c) azide, carbonate, peroxide, acetate
(d) carbonate, nitride, peroxide, acetate
Show Answer & Explanation
Answer: (a) carbonate, azide, peroxide, acetate
Explanation:
1. The names are the standard ones: \( \ce{N3^-} \) is azide (nitride is \( \ce{N^3-} \)).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) \( \ce{CrO4^2-} \)
(b) \( \ce{Cr2O7^2-} \)
(c) \( \ce{CrO3} \)
(d) \( \ce{Cr2O4} \)
Show Answer & Explanation
Answer: (b) \( \ce{Cr2O7^2-} \)
Explanation:
1. Two chromate ions condense with loss of one oxide to give \( \ce{Cr2O7^2-} \).
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) 3
(b) 2
(c) 4
(d) 5
Show Answer & Explanation
Answer: (a) 3
Explanation:
1. \( \ce{H4P2O7} \) (pyrophosphoric), \( \ce{H4P2O5} \) (pyrophosphorous) and \( \ce{H6Si2O7} \) (pyrosilicic) are pyro acids; \( \ce{H2S2O3} \) is thiosulphuric.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Prefixes ortho, meta and pyro describe the water content of the acid; per/peroxo means an O-O link is present.
(a) 2
(b) 4
(c) 3
(d) 5
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. Correct: nitride, zincate and plumbite. Wrong: \( \ce{O^2-} \) is oxide, \( \ce{SO4^2-} \) sulphate, \( \ce{NO2^-} \) nitrite, \( \ce{Fe^2+} \) ferrous.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) 3
(b) 4
(c) 6
(d) 5
Show Answer & Explanation
Answer: (d) 5
Explanation:
1. True: (i), (iv), (v), (vi), (vii). False: alkaline earth metals are +2, and \( \ce{HClO3} \) is chloric (not perchloric) acid.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.
(a) 4
(b) 5
(c) 6
(d) 7
Show Answer & Explanation
Answer: (b) 5
Explanation:
1. \( \ce{N2O} \) (+1), \( \ce{NF3} \) (+3), \( \ce{HNO2} \) (+3), \( \ce{N2O3} \) (+3), \( \ce{NaNO3} \) (+5) are positive; the rest are -3 or -1/3.
2. Only this option agrees with the working above, so it is the correct choice.
Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.
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Multiple Choice Questions (MCQs) for JEE Chemistry Basic Inorganic Nomenclature
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FAQs
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