JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01

Multiple Choice Questions (MCQs) for JEE Chemistry: Basic Inorganic Nomenclature

Explore reliable objective questions for Basic Inorganic Nomenclature tailored for JEE learners. Utilizing these Chemistry multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Practice Basic Inorganic Nomenclature MCQs for JEE Chemistry

Access the complete set of multiple-choice questions for Basic Inorganic Nomenclature below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.

Multiple Choice Questions

Question 1: The oxidation number that iron does not exhibit in its common compounds or in the elemental state is
(a) 0
(b) +1
(c) +2
(d) +3
Show Answer & Explanation

Answer: (b) +1

Explanation:
1. Iron is 0 in the element and +2 and +3 in common compounds; +1 is not shown.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 2: The oxidation state of nitrogen varies from
(a) 0 to +5
(b) -3 to +1
(c) +3 to +5
(d) -3 to +5
Show Answer & Explanation

Answer: (d) -3 to +5

Explanation:
1. Nitrogen is in group 15 (n = 15), so its range is (n-18) to (n-10) = -3 to +5, as in \( \ce{NH3} \) and \( \ce{N2O5} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 3: When \( \ce{H2SO3} \) is converted into \( \ce{H2SO4} \), the change in oxidation state of sulphur is from
(a) +4 to +6
(b) 0 to +2
(c) +2 to +4
(d) +4 to +2
Show Answer & Explanation

Answer: (a) +4 to +6

Explanation:
1. In \( \ce{H2SO3} \): 2 + x - 6 = 0 gives x = +4. In \( \ce{H2SO4} \): 2 + x - 8 = 0 gives x = +6.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 4: The most stable oxidation state of chromium is
(a) +5
(b) +2
(c) +4
(d) +3
Show Answer & Explanation

Answer: (d) +3

Explanation:
1. Cr(III) has a half-filled \( t_{2g}^3 \) set and is the most stable state of chromium.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 5: Which of the following can have both positive and negative oxidation states?
(a) F
(b) I
(c) Na
(d) He
Show Answer & Explanation

Answer: (b) I

Explanation:
1. Iodine is -1 in iodides and positive (+1, +3, +5, +7) with more electronegative atoms; F is only -1, Na only +1, He is 0.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 6: Which of the following metals exhibits more than one oxidation state?
(a) Na
(b) Mg
(c) Fe
(d) Al
Show Answer & Explanation

Answer: (c) Fe

Explanation:
1. Fe shows +2 and +3; Na is +1, Mg is +2 and Al is +3 only.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 7: The most common oxidation state of an element is -2. The number of electrons in its outermost shell is
(a) 6
(b) 2
(c) 4
(d) 8
Show Answer & Explanation

Answer: (a) 6

Explanation:
1. An element that gains two electrons to reach an octet must have 8 - 2 = 6 valence electrons.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 8: In the conversion of \( \ce{PbSO4} \) to PbS, the oxidation number of sulphur in PbS is
(a) +6
(b) -2
(c) +4
(d) -1
Show Answer & Explanation

Answer: (b) -2

Explanation:
1. Lead is +2 and the compound is neutral, so sulphur is -2.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 9: The oxidation number of phosphorus in \( \ce{Mg2P2O7} \) is
(a) +5
(b) -5
(c) +6
(d) -7
Show Answer & Explanation

Answer: (a) +5

Explanation:
1. 2(+2) + 2x + 7(-2) = 0 gives 2x = +10, so x = +5.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 10: In the conversion of \( \ce{Br2} \) to \( \ce{BrO3^-} \), the oxidation state of bromine changes from
(a) -1 to +5
(b) 0 to -3
(c) 0 to +5
(d) +2 to +5
Show Answer & Explanation

Answer: (c) 0 to +5

Explanation:
1. Br2 is 0; in \( \ce{BrO3^-} \): x - 6 = -1 gives x = +5.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 11: The oxidation number of sulphur in \( \ce{S2Cl2} \) is
(a) +6
(b) 0
(c) -1
(d) +1
Show Answer & Explanation

Answer: (d) +1

Explanation:
1. Chlorine is -1, so 2x + 2(-1) = 0 and x = +1.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 12: Which of the following elements shows only the -1 oxidation number in the combined state?
(a) Cl
(b) F
(c) Br
(d) I
Show Answer & Explanation

Answer: (b) F

Explanation:
1. Only fluorine, the most electronegative element, never shows a positive state in compounds.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 13: The oxidation number of Fe in \( \ce{FeS2} \) is
(a) +4
(b) +1
(c) +2
(d) 0
Show Answer & Explanation

Answer: (c) +2

Explanation:
1. Iron pyrite contains the disulphide ion \( \ce{S2^2-} \) (S is -1 each), so Fe = +2.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 14: The oxidation number of carbon in \( \ce{H2C2O4} \) is
(a) +2
(b) +3
(c) +4
(d) +1
Show Answer & Explanation

Answer: (b) +3

Explanation:
1. 2(+1) + 2x + 4(-2) = 0 gives 2x = +6, so x = +3.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 15: The oxidation number of N in \( \ce{H2N2O2} \) (hyponitrous acid) is
(a) +2
(b) +3
(c) -1
(d) +1
Show Answer & Explanation

Answer: (d) +1

Explanation:
1. 2(+1) + 2x + 2(-2) = 0 gives x = +1.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 16: The oxidation number of Fe in \( \ce{Fe3O4} \) is
(a) +8/3
(b) +3
(c) +2
(d) +4
Show Answer & Explanation

Answer: (a) +8/3

Explanation:
1. 3x + 4(-2) = 0 gives x = +8/3 (average of two Fe(III) and one Fe(II)).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 17: The oxidation number of Cr in \( \ce{K2Cr2O7} \) is
(a) +3
(b) +7
(c) +6
(d) +12
Show Answer & Explanation

Answer: (c) +6

Explanation:
1. 2(+1) + 2x + 7(-2) = 0 gives x = +6.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 18: The oxidation number of Xe in \( \ce{H4XeO6} \) is
(a) +6
(b) +4
(c) +7
(d) +8
Show Answer & Explanation

Answer: (d) +8

Explanation:
1. 4(+1) + x + 6(-2) = 0 gives x = +8.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 19: The oxidation number of oxygen in \( \ce{OF2} \) is
(a) -2
(b) -1
(c) +2
(d) +1
Show Answer & Explanation

Answer: (c) +2

Explanation:
1. Fluorine is -1 each, so O must be +2 to balance.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 20: The oxidation number of oxygen in \( \ce{O2F2} \) is
(a) +1
(b) +2
(c) -1
(d) 0
Show Answer & Explanation

Answer: (a) +1

Explanation:
1. Two F atoms are -1 each, so the two O atoms share +2, i.e. +1 each.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 21: The oxidation number of manganese in \( \ce{HMnO4} \) is
(a) +6
(b) +7
(c) +4
(d) +5
Show Answer & Explanation

Answer: (b) +7

Explanation:
1. 1 + x - 8 = 0 gives x = +7.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 22: The oxidation number of manganese in \( \ce{H2MnO4} \) is
(a) +7
(b) +4
(c) +2
(d) +6
Show Answer & Explanation

Answer: (d) +6

Explanation:
1. 2 + x - 8 = 0 gives x = +6.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 23: The oxidation number of sulphur in \( \ce{H2SO5} \) (peroxomonosulphuric acid) is
(a) +6
(b) +4
(c) +8
(d) +5
Show Answer & Explanation

Answer: (a) +6

Explanation:
1. It has three normal O (-2) and two peroxide O (-1): 2 + x - 6 - 2 = 0 gives x = +6.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 24: The oxidation number of nitrogen in \( \ce{Ca(N3)2} \) is
(a) -3
(b) +1
(c) -1
(d) -1/3
Show Answer & Explanation

Answer: (d) -1/3

Explanation:
1. Ca is +2, so each azide ion is -1: 3x = -1 and x = -1/3.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 25: The oxidation number of Mn in \( \ce{MnSO4} \) and in \( \ce{Mn2O3} \) respectively is
(a) +2 and +2
(b) +2 and +3
(c) +3 and +3
(d) +4 and +3
Show Answer & Explanation

Answer: (b) +2 and +3

Explanation:
1. In \( \ce{MnSO4} \) sulphate is -2 so Mn = +2; in \( \ce{Mn2O3} \) 2x = +6 so Mn = +3.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Oxidation number is a bookkeeping charge: fix F = -1, O = -2 (exceptions in peroxides, superoxides, OF2), H = +1 and then make the total equal the charge on the species.

Question 26: The correct formula of aluminium perchlorate is
(a) \( \ce{Al(ClO)3} \)
(b) \( \ce{Al(ClO2)3} \)
(c) \( \ce{Al(ClO4)3} \)
(d) \( \ce{Al2(ClO3)3} \)
Show Answer & Explanation

Answer: (c) \( \ce{Al(ClO4)3} \)

Explanation:
1. Perchlorate is \( \ce{ClO4^-} \) and aluminium is \( \ce{Al^3+} \), so three perchlorate ions are needed.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Free study material for Chemistry

Basic Inorganic Nomenclature Objective Questions & Solutions for JEE Chemistry

About Basic Inorganic Nomenclature MCQs for JEE Chemistry

Test your conceptual understanding of Basic Inorganic Nomenclature with these targeted multiple-choice questions. Designed in alignment with the latest JEE curriculum for JEE Chemistry, these problem sets build accuracy and prepare students for objective exams.

How to Verify Your MCQ Answers

Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.

Enhance Speed with Online MCQ Tests

Follow up your worksheet practice by attempting the interactive online Chemistry MCQ test for this chapter to evaluate your execution speed. All platform resources are free to access.

FAQs

Where can I access latest JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01?

You can get most exhaustive JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Chemistry JEE material?

Yes, our JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.

How do practicing Chemistry MCQs help in scoring full marks in JEE exams?

By solving our JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.

Do you provide answers and explanations for JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01?

Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.

Can I practice these Chemistry JEE MCQs online?

Yes, you can also access online interactive tests for JEE Chemistry Basic Inorganic Nomenclature MCQs Set 01 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.