JEE Chemistry Amines MCQs Set 12

Download JEE MCQs for JEE Chemistry: Amines

Review structured MCQ sets for JEE Chemistry Amines. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.

Chapter-wise Objective Questions: Amines

Navigate directly to the 50 objective questions for Amines using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.

Multiple Choice Questions

Question 1: Hinsberg's method is used for
(a) preparation of primary amines
(b) preparation of secondary amines
(c) preparation of tertiary amines
(d) separation of amine mixtures
Show Answer & Explanation

Answer: (d) separation of amine mixtures

Explanation:
1. Benzenesulphonyl chloride converts primary and secondary amines to sulphonamides with different solubility in alkali and leaves tertiary amines unreacted, so a mixture can be separated.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 2: Which one of the following compounds gives a secondary amine on reduction?
(a) nitromethane
(b) nitrobenzene
(c) methyl isocyanide
(d) methyl cyanide
Show Answer & Explanation

Answer: (c) methyl isocyanide

Explanation:
1. CH3NC + 4[H] → CH3NHCH3.
2. Nitro compounds and nitriles give primary amines.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 3: Chloropicrin is manufactured by the reaction between Cl2, NaOH and
(a) nitromethane
(b) nitroethane
(c) nitrophenol
(d) nitrostyrene
Show Answer & Explanation

Answer: (a) nitromethane

Explanation:
1. All three hydrogens of CH3NO2 are replaced by Cl, giving CCl3NO2, chloropicrin.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 4: In the reaction R-COOH ← (H3O+) X → ([H]) RCH2NH2, X is
(a) isonitrile
(b) nitrile
(c) nitrite
(d) oxime
Show Answer & Explanation

Answer: (b) nitrile

Explanation:
1. RCN hydrolyses to RCOOH and is reduced to RCH2NH2.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 5: When ethanol is mixed with ammonia and passed over alumina, the compound formed is
(a) C2H5NH2
(b) C2H4
(c) C2H5OC2H5
(d) CH3OCH3
Show Answer & Explanation

Answer: (a) C2H5NH2

Explanation:
1. Ammonolysis of ethanol over heated alumina gives ethylamine (with some di- and triethylamine).

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 6: Which of the following reactions does not yield an amine?
(a) RX + NH3
(b) RCH=NOH + [H] (Na/C2H5OH)
(c) RCN + H2O (H+)
(d) RCONH2 + 4H (LiAlH4)
Show Answer & Explanation

Answer: (c) RCN + H2O (H+)

Explanation:
1. Acid hydrolysis of a nitrile gives a carboxylic acid.
2. The other reactions form amines.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 7: Acetamide → (P2O5, heat) A → (4H) B. Identify B.
(a) CH3NH2
(b) CH3CH2NH2
(c) CH3CN
(d) CH3COONH4
Show Answer & Explanation

Answer: (b) CH3CH2NH2

Explanation:
1. P2O5 dehydrates the amide to CH3CN (A).
2. Reduction of CH3CN gives CH3CH2NH2.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 8: Which of the following gives a primary amine on reduction?
(a) CH3-CH2-N→O (nitroso-type oxide)
(b) CH3-CH2-O-N=O
(c) CH3CH2NO2
(d) none of these
Show Answer & Explanation

Answer: (c) CH3CH2NO2

Explanation:
1. Nitroethane is reduced to ethylamine, CH3CH2NH2.
2. An alkyl nitrite is reduced to the alcohol.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 9: Which of the following is converted into an alcohol on treatment with HNO2?
(a) methylamine
(b) aniline
(c) dimethylamine
(d) triethylamine
Show Answer & Explanation

Answer: (a) methylamine

Explanation:
1. A primary aliphatic amine gives a diazonium ion that is replaced by water: CH3NH2 + HNO2 → CH3OH + N2 + H2O.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 10: Which of the following gives RNC when reacted with CHCl3 and KOH?
(a) RNH2
(b) R2NH
(c) R3N
(d) R4N+Cl-
Show Answer & Explanation

Answer: (a) RNH2

Explanation:
1. Only primary amines give the foul-smelling isocyanide (carbylamine reaction).

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 11: When aniline reacts with NaNO2 and dil. HCl at 0-5°C, the product formed is
(a) nitroaniline
(b) benzenediazonium chloride
(c) benzene
(d) trinitroaniline
Show Answer & Explanation

Answer: (b) benzenediazonium chloride

Explanation:
1. Primary aromatic amines are diazotised at low temperature to C6H5N2+Cl-.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 12: Starting from propanoic acid: propanoic acid → (SOCl2) X → (NH3) Y → (Br2 + KOH) Z. What is Z?
(a) CH3CH2Br
(b) CH3CH2NH2
(c) CH3CH2COBr
(d) CH3CH2CH2NH2
Show Answer & Explanation

Answer: (b) CH3CH2NH2

Explanation:
1. X = propanoyl chloride; Y = propanamide.
2. Hofmann degradation removes one carbon, so Z is ethylamine.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 13: CH3COOH → (PCl5) A → (NH3) B → (NaBrO) C. The final product C is
(a) ammonium acetate
(b) acetamide
(c) aminomethane
(d) ethanal
Show Answer & Explanation

Answer: (c) aminomethane

Explanation:
1. A = acetyl chloride and B = acetamide.
2. Hofmann bromamide reaction gives methylamine (aminomethane).

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 14: In the reaction X (bromination) Y (NaNO2 + HCl) Z (boiling with C2H5OH) gives tribromobenzene. X is
(a) benzoic acid
(b) salicylic acid
(c) phenol
(d) aniline
Show Answer & Explanation

Answer: (d) aniline

Explanation:
1. Aniline brominates to 2,4,6-tribromoaniline (Y), which is diazotised.
2. Boiling the diazonium salt with ethanol replaces N2+ by H, giving 1,3,5-tribromobenzene.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 15: Which of the following reactions will not give a primary amine?
(a) CH3CONH2 + KOH + Br2
(b) CH3CN + LiAlH4
(c) CH3NC + LiAlH4
(d) CH3CONH2 + LiAlH4
Show Answer & Explanation

Answer: (c) CH3NC + LiAlH4

Explanation:
1. An isocyanide is reduced to a secondary amine, CH3NHCH3.
2. The other three give CH3NH2, CH3CH2NH2 and CH3CH2NH2.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 16: The carbylamine reaction is given by
(a) primary amines
(b) tertiary amines
(c) secondary amines
(d) quaternary salts
Show Answer & Explanation

Answer: (a) primary amines

Explanation:
1. Only RNH2 reacts with chloroform and KOH to form an isocyanide.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 17: C6H5NH2 + CHCl3 + 3KOH → C6H5NC + 3KCl + 3H2O is known as
(a) the carbylamine reaction
(b) the Reimer-Tiemann reaction
(c) the Kolbe reaction
(d) Hofmann's degradation
Show Answer & Explanation

Answer: (a) the carbylamine reaction

Explanation:
1. Formation of the isocyanide from a primary amine, chloroform and alkali is the carbylamine reaction.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 18: CH3CONH2 → (Na + ROH) Z + H2O. What is Z?
(a) CH3CH2NH2
(b) CH3CH2NC
(c) CH3CH2CH3
(d) NH2CONH2
Show Answer & Explanation

Answer: (a) CH3CH2NH2

Explanation:
1. Reduction of the amide group by sodium and alcohol gives the amine with the same carbon number, ethylamine.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 19: Which of the following reacts with chloroform and a base to form phenyl isocyanide?
(a) aniline
(b) benzene
(c) phenol
(d) nitrobenzene
Show Answer & Explanation

Answer: (a) aniline

Explanation:
1. Aniline is a primary aromatic amine and gives the carbylamine reaction.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 20: An aromatic primary amine, when treated with cold HNO2, gives
(a) benzyl alcohol
(b) nitrobenzene
(c) a diazonium salt
(d) aniline
Show Answer & Explanation

Answer: (c) a diazonium salt

Explanation:
1. ArNH2 + HNO2 + HCl → ArN2+Cl- + 2H2O at 0-5°C.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 21: Which of the following compounds is the strongest base?
(a) ammonia
(b) aniline
(c) methylamine
(d) N-methylaniline
Show Answer & Explanation

Answer: (c) methylamine

Explanation:
1. The methyl group donates electrons and raises basicity above ammonia.
2. The aniline types are weaker because the lone pair is delocalised in the ring.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 22: Nitrobenzene combines with hydrogen in the presence of platinum to produce
(a) toluene
(b) benzene
(c) aniline
(d) azobenzene
Show Answer & Explanation

Answer: (c) aniline

Explanation:
1. Catalytic hydrogenation reduces C6H5NO2 to C6H5NH2.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 23: Aryl diazonium chloride from 4-methylaniline is treated with CuCN. The product is
(a) 4-methylaniline
(b) 4-methylbenzonitrile
(c) 3-methylbenzonitrile
(d) 2-methylbenzonitrile
Show Answer & Explanation

Answer: (b) 4-methylbenzonitrile

Explanation:
1. The Sandmeyer reaction replaces N2+ with CN at the same ring position.
2. So the product is 4-CH3-C6H4-CN.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 24: Ethylamine, on heating with CS2 in the presence of HgCl2, forms
(a) C2H5NCS
(b) (C2H5)2S
(c) (C2H5)2CS
(d) C2H5(CS)2
Show Answer & Explanation

Answer: (a) C2H5NCS

Explanation:
1. Primary amines give ethyl isothiocyanate (mustard oil reaction).
2. The dithiocarbamate first formed loses H2S with HgCl2.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 25: Which of the following reacts with NaNO2 + HCl to give phenol?
(a) C6H5CH2NHCH3
(b) (CH3)2NH
(c) CH3NH2
(d) C6H5NH2
Show Answer & Explanation

Answer: (d) C6H5NH2

Explanation:
1. Aniline gives the diazonium salt, which on warming with water gives phenol.
2. Aliphatic primary amines give alcohols, not phenol.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 26: When chlorobenzene is treated with NH3 in the presence of Cu2O in xylene at 570 K, the product obtained is
(a) benzylamine
(b) diazonium salt
(c) Schiff's base
(d) aniline
Show Answer & Explanation

Answer: (d) aniline

Explanation:
1. Copper-catalysed ammonolysis under forcing conditions replaces the aryl chlorine by NH2.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 27: Nitrobenzene can be prepared from benzene using a mixture of conc. HNO3 and conc. H2SO4. In the nitrating mixture, HNO3 acts as
(a) a base
(b) a catalyst
(c) an acid
(d) a reducing agent
Show Answer & Explanation

Answer: (a) a base

Explanation:
1. Sulphuric acid is the stronger acid and protonates HNO3, which then loses water to form the nitronium ion NO2+.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 28: When C6H5NH2 + HCl + NaNO2 react, the product X is
(a) aniline hydrochloride
(b) nitroaniline
(c) benzenediazonium chloride
(d) none of these
Show Answer & Explanation

Answer: (c) benzenediazonium chloride

Explanation:
1. Diazotisation at 0-5°C gives C6H5N2+Cl-.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 29: The diazonium salts are the reaction products in the presence of excess mineral acid and nitrous acid with
(a) a primary aliphatic amine
(b) a secondary aromatic amine
(c) a primary aromatic amine
(d) a tertiary aliphatic amine
Show Answer & Explanation

Answer: (c) a primary aromatic amine

Explanation:
1. Only primary aromatic amines give stable diazonium salts at low temperature.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

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