JEE Chemistry Amines MCQs Set 11

Practice MCQs for JEE Chemistry Amines

Explore reliable objective questions for Amines tailored for JEE learners. Utilizing these Chemistry multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

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Multiple Choice Questions

Question 1: The cyanide ion is
(a) nucleophilic
(b) electrophilic
(c) strongly acidic
(d) non-reactive and neutral
Show Answer & Explanation

Answer: (a) nucleophilic

Explanation:
1. CN- has a lone pair on carbon and attacks electron-poor centres, so it is a nucleophile.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 2: Compounds containing both -NH2 and -COOH groups are known as
(a) diamines
(b) unknown
(c) amino acids
(d) enzymes
Show Answer & Explanation

Answer: (c) amino acids

Explanation:
1. An amino acid carries an amino group and a carboxyl group, as in glycine H2NCH2COOH.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 3: Which of the following is a primary amine?
(a) ethylenediamine
(b) dimethylamine
(c) trimethylamine
(d) N-methylaniline
Show Answer & Explanation

Answer: (a) ethylenediamine

Explanation:
1. In H2N-CH2CH2-NH2 each nitrogen is attached to one carbon, so both are primary amino groups.
2. The others are secondary or tertiary.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 4: C3H9N represents
(a) a primary amine
(b) a secondary amine
(c) a tertiary amine
(d) all of these
Show Answer & Explanation

Answer: (d) all of these

Explanation:
1. Propylamine and isopropylamine are primary, ethylmethylamine is secondary and trimethylamine is tertiary, all with the formula C3H9N.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 5: (CH3)2C(NH2)CH2COCH3 is known as
(a) diacetone
(b) acetoneamine
(c) diacetoneamine
(d) aminoacetone
Show Answer & Explanation

Answer: (c) diacetoneamine

Explanation:
1. This 4-amino-4-methylpentan-2-one is obtained from acetone (two acetone units) and ammonia, and is called diacetoneamine.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 6: A secondary amine is
(a) an organic compound with two -NH2 groups
(b) a compound with two carbon atoms and an -NH2 group
(c) a compound with an -NH2 group on carbon number 2
(d) a compound in which two of the hydrogens of NH3 have been replaced by organic groups
Show Answer & Explanation

Answer: (d) a compound in which two of the hydrogens of NH3 have been replaced by organic groups

Explanation:
1. Replacing one H of ammonia gives a primary amine, two H give a secondary amine and three H a tertiary amine.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 7: The structural formula of methyl aminomethane is
(a) (CH3)2CHNH2
(b) (CH3)3N
(c) (CH3)2NH
(d) CH3NH2
Show Answer & Explanation

Answer: (c) (CH3)2NH

Explanation:
1. Aminomethane is CH3NH2, and a methyl group on its nitrogen gives CH3NHCH3, dimethylamine.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 8: Allyl isocyanide, CH2=CH-CH2-N≡C, has
(a) 9 sigma bonds and 4 pi bonds
(b) 9 sigma bonds and 5 pi bonds
(c) 8 sigma bonds, 3 pi bonds and 4 non-bonding electrons
(d) 9 sigma bonds, 3 pi bonds and 2 non-bonding electrons
Show Answer & Explanation

Answer: (d) 9 sigma bonds, 3 pi bonds and 2 non-bonding electrons

Explanation:
1. Sigma bonds: 5 C-H, 2 C-C (including the sigma of C=C), 1 C-N and 1 N-C of the triple bond, a total of 9.
2. Pi bonds: 1 in C=C and 2 in N≡C, a total of 3.
3. The terminal carbon of the isocyanide carries one lone pair (2 electrons).

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 9: Triaminobenzene is a
(a) secondary amine
(b) tertiary amine
(c) primary amine
(d) quaternary salt
Show Answer & Explanation

Answer: (c) primary amine

Explanation:
1. Each NH2 group is attached to a ring carbon and has two hydrogens, so the compound is a primary aromatic amine.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 10: CH2=CH-CH2-NH-CH3 is a
(a) secondary amine
(b) primary amine
(c) tertiary amine
(d) none of these
Show Answer & Explanation

Answer: (a) secondary amine

Explanation:
1. The nitrogen carries two carbon groups (allyl and methyl) and one hydrogen.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 11: The leakage of which gas was responsible for the 1984 Bhopal tragedy?
(a) CH3-N=C=O
(b) CH3-C-N=S
(c) CHCl3
(d) C6H5COCl
Show Answer & Explanation

Answer: (a) CH3-N=C=O

Explanation:
1. Methyl isocyanate, CH3NCO, leaked from the storage tank.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 12: Which of the following is not a nitro derivative?
(a) C6H5NO2
(b) CH3CH2ONO
(c) CH3CH(CH3)NO2
(d) C6H4(OH)NO2
Show Answer & Explanation

Answer: (b) CH3CH2ONO

Explanation:
1. A nitro compound has the carbon bonded to nitrogen, C-NO2.
2. CH3CH2ONO has C-O-N=O, so it is an alkyl nitrite.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 13: Acetonitrile is
(a) C2H5CN
(b) CH3CN
(c) CH3COCN
(d) C6H5CH2CN
Show Answer & Explanation

Answer: (b) CH3CN

Explanation:
1. Acetonitrile (methyl cyanide) is CH3CN, the nitrile of acetic acid.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 14: In an alkyl cyanide, the alkyl group is attached to
(a) the C of the CN group
(b) the N of the CN group
(c) either C or N of the CN group
(d) both C and N of the CN group
Show Answer & Explanation

Answer: (a) the C of the CN group

Explanation:
1. In R-C≡N the alkyl group is bonded to carbon.
2. Attachment through nitrogen gives isocyanide, R-N≡C.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 15: The number of isomeric primary amines obtained from C4H11N is
(a) 3
(b) 4
(c) 5
(d) 6
Show Answer & Explanation

Answer: (b) 4

Explanation:
1. Butan-1-amine, butan-2-amine, 2-methylpropan-1-amine and 2-methylpropan-2-amine.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 16: Amides may be converted into amines by a reaction named after
(a) Perkin
(b) Hofmann
(c) Claisen
(d) Kolbe
Show Answer & Explanation

Answer: (b) Hofmann

Explanation:
1. The Hofmann bromamide (degradation) reaction converts an amide into a primary amine with one carbon fewer.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 17: CH3CONH2 → (NaOBr) gives
(a) CH3Br
(b) CH4
(c) CH3COBr
(d) CH3NH2
Show Answer & Explanation

Answer: (d) CH3NH2

Explanation:
1. Hofmann degradation removes the carbonyl carbon, so acetamide gives methylamine.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 18: Acetamide is treated separately with the following reagents. Which would give methylamine?
(a) PCl5
(b) NaOH + Br2
(c) sodalime
(d) hot conc. H2SO4
Show Answer & Explanation

Answer: (b) NaOH + Br2

Explanation:
1. NaOH + Br2 (that is NaOBr) carries out Hofmann bromamide degradation to CH3NH2.
2. PCl5 gives CH3CN (via dehydration).

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 19: The amine formed from an amide by means of bromine and alkali has
(a) the same number of C atoms as that of amide
(b) one less C atom than that of amide
(c) one more C atom than that of amide
(d) two more C atoms than that of amide
Show Answer & Explanation

Answer: (b) one less C atom than that of amide

Explanation:
1. One carbon is lost as carbonate in the Hofmann bromamide reaction.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 20: CH3CN → (Na + C2H5OH) X. The compound X is
(a) CH3CONH2
(b) CH3CH2NH2
(c) C2H6
(d) CH3NHCH3
Show Answer & Explanation

Answer: (b) CH3CH2NH2

Explanation:
1. Nascent hydrogen from sodium and ethanol reduces the nitrile to the primary amine CH3CH2NH2.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 21: Ethylamine can be made by the action of bromine and caustic potash on
(a) acetamide
(b) propionamide
(c) formamide
(d) methyl cyanide
Show Answer & Explanation

Answer: (b) propionamide

Explanation:
1. Hofmann degradation shortens the chain by one carbon, so propionamide (3 C) gives ethylamine (2 C).

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 22: Ethylamine can be obtained by the
(a) action of NH3 on ethyl iodide
(b) action of NH3 on ethyl alcohol (over alumina, heated)
(c) both (a) and (b)
(d) none of the above
Show Answer & Explanation

Answer: (c) both (a) and (b)

Explanation:
1. Alkyl halides are ammonolysed to amines.
2. Alcohols passed with ammonia over alumina at high temperature also give amines.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 23: Aniline is usually purified by
(a) steam distillation
(b) simple distillation
(c) vacuum distillation
(d) extraction with a solvent
Show Answer & Explanation

Answer: (a) steam distillation

Explanation:
1. Aniline is immiscible with water and volatile in steam, so steam distillation separates it from non-volatile impurities.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Question 24: Reduction of nitroalkanes yields
(a) acid
(b) alcohol
(c) amine
(d) diazo compounds
Show Answer & Explanation

Answer: (c) amine

Explanation:
1. RNO2 + 6[H] → RNH2 + 2H2O.

Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.

Question 25: Acetamide changes into methylamine by
(a) Hofmann bromamide reaction
(b) Hofmann reaction
(c) Friedel-Crafts reaction
(d) Hinsberg reaction
Show Answer & Explanation

Answer: (a) Hofmann bromamide reaction

Explanation:
1. The Hofmann bromamide reaction steps down the chain by one carbon.

Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.

Question 26: When methyl iodide is heated with ammonia, the product obtained is
(a) methylamine
(b) dimethylamine
(c) trimethylamine
(d) a mixture of the above three amines
Show Answer & Explanation

Answer: (d) a mixture of the above three amines

Explanation:
1. The product amine is itself nucleophilic and reacts further, giving a mixture of primary, secondary, tertiary amines and the quaternary salt.

Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.

Question 27: Acetanilide can be prepared from aniline and which of the following?
(a) ethanol
(b) acetaldehyde
(c) acetone
(d) acetic anhydride
Show Answer & Explanation

Answer: (d) acetic anhydride

Explanation:
1. Acylation of aniline with acetic anhydride (or acetyl chloride) gives C6H5NHCOCH3.

Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.

Question 28: Reduction of nitroalkanes in neutral medium (for example Zn/NH4Cl) forms mainly
(a) R-NH2
(b) R-NHOH
(c) R-N=N-Cl
(d) all of these
Show Answer & Explanation

Answer: (b) R-NHOH

Explanation:
1. In neutral medium reduction stops at the hydroxylamine stage.
2. Strongly acidic medium gives the amine.

Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.

Question 29: Nitrosobenzene can be made by oxidising aniline with
(a) H2SO4
(b) H2SO5
(c) H2SO3
(d) K2Cr2O7
Show Answer & Explanation

Answer: (b) H2SO5

Explanation:
1. Peroxomonosulphuric acid (Caro's acid) oxidises aniline partly, to nitrosobenzene.

Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.

Practice MCQs for JEE Chemistry Amines

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FAQs

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