Download JEE MCQs for JEE Chemistry: Aldehydes Ketones and Carboxylic Acids
Review structured MCQ sets for JEE Chemistry Aldehydes Ketones and Carboxylic Acids. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Chapter-wise Objective Questions: Aldehydes Ketones and Carboxylic Acids
Navigate directly to the 50 objective questions for Aldehydes Ketones and Carboxylic Acids using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) \( \ce{sp^3} \) hybridised
(b) \( \ce{sp^2} \) hybridised
(c) \( \ce{sp} \) hybridised
(d) Unhybridised
Show Answer & Explanation
Answer: (b) \( \ce{sp^2} \) hybridised
Explanation:
1. The carbonyl carbon forms three sigma bonds (two to substituents, one to O) and one pi bond, so it is sp2 hybridised and trigonal planar.
Teacher's Note:
1. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
2. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
(a) 1-Hydroxy-4-methylpentan-3-one
(b) 2-Methyl-5-hydroxypentan-3-one
(c) 4-Methyl-3-oxopentan-1-ol
(d) Hexanol-1-one-3
Show Answer & Explanation
Answer: (a) 1-Hydroxy-4-methylpentan-3-one
Explanation:
1. The longest chain has five carbons: HOCH2-CH2-CO-CH(CH3)-CH3.
2. Number from the OH end so the ketone is C3: 1-hydroxy-4-methylpentan-3-one.
Teacher's Note:
1. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
2. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
(a) \( \ce{CH2-CH2O} \) (cyclic oxide)
(b) Ethane-1,2-diol
(c) \( \ce{OHC-CHO} \)
(d) Hydroxyethanal
Show Answer & Explanation
Answer: (c) \( \ce{OHC-CHO} \)
Explanation:
1. Glyoxal is ethanedial, \( \ce{OHC-CHO} \), the simplest dialdehyde.
Teacher's Note:
1. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
2. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
(a) Ketones
(b) Ethers
(c) Alcohols
(d) Fatty acids
Show Answer & Explanation
Answer: (a) Ketones
Explanation:
1. An aldehyde RCHO and a ketone with the same number of carbons share the formula, for example propanal and propanone, \( \ce{C3H6O} \).
Teacher's Note:
1. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
2. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
(a) Phenol
(b) Carboxylic acid
(c) Aldehydes
(d) Alcohols
Show Answer & Explanation
Answer: (c) Aldehydes
Explanation:
1. Aldehydes contain the -CHO group and have no hydroxyl group.
Teacher's Note:
1. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
2. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
(a) Acetone
(b) Propanone
(c) Dimethyl ketone
(d) Propanal
Show Answer & Explanation
Answer: (b) Propanone
Explanation:
1. Three carbons with the carbonyl on the middle one give propanone.
Teacher's Note:
1. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
2. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
(a) Aldehyde
(b) Ketone
(c) Acid
(d) Acid chloride
Show Answer & Explanation
Answer: (b) Ketone
Explanation:
1. R-CO-R' with two alkyl groups on the carbonyl carbon is a ketone.
Teacher's Note:
1. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
2. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
(a) One ketonic
(b) Two aldehydic
(c) One double bond
(d) Two double bonds
Show Answer & Explanation
Answer: (b) Two aldehydic
Explanation:
1. Ethanedial is \( \ce{OHC-CHO} \) and carries two -CHO groups.
Teacher's Note:
1. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
2. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
(a) Two sigma and one pi bonds
(b) Three sigma and one pi bonds
(c) One sigma and two pi bonds
(d) Two sigma and two pi bonds
Show Answer & Explanation
Answer: (b) Three sigma and one pi bonds
Explanation:
1. The carbonyl carbon has one sigma and one pi bond to oxygen plus two sigma bonds to R and R', i.e. three sigma and one pi.
Teacher's Note:
1. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
2. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
(a) Chain isomerism
(b) Position isomerism
(c) Functional isomerism
(d) All of these
Show Answer & Explanation
Answer: (d) All of these
Explanation:
1. Pentanone shows position isomerism (pentan-2-one and pentan-3-one), chain isomerism (3-methylbutanone) and functional isomerism (pentanal).
Teacher's Note:
1. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
2. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
(a) Chloral
(b) Trichloroacetaldehyde
(c) 1,1,1-Trichloroethanal
(d) 2,2,2-Trichloroethanal
Show Answer & Explanation
Answer: (d) 2,2,2-Trichloroethanal
Explanation:
1. The CHO carbon is C1 and the three chlorines are on C2, so the name is 2,2,2-trichloroethanal.
Teacher's Note:
1. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
2. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
(a) Pentanone
(b) Acetophenone
(c) Benzophenone
(d) Butanone
Show Answer & Explanation
Answer: (b) Acetophenone
Explanation:
1. A mixed ketone has two different groups on the carbonyl, here methyl and phenyl in acetophenone.
Teacher's Note:
1. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
2. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
(a) \( \ce{CCl3CHO} \)
(b) \( \ce{CCl3COCH3} \)
(c) \( \ce{CCl3COCCl3} \)
(d) \( \ce{CCl3CH2OH} \)
Show Answer & Explanation
Answer: (a) \( \ce{CCl3CHO} \)
Explanation:
1. Chloral is trichloroethanal, \( \ce{CCl3CHO} \).
Teacher's Note:
1. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
2. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
(a) Ethers, aldehydes, ketones and carboxylic acids
(b) Aldehydes, ketones and carboxylic acids
(c) Aldehydes and ketones
(d) Carboxylic acids
Show Answer & Explanation
Answer: (c) Aldehydes and ketones
Explanation:
1. The name carbonyl compounds is used for aldehydes and ketones.
Teacher's Note:
1. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
2. Remember common names: formaldehyde, acetaldehyde, chloral, glyoxal, acetone, acetophenone, benzophenone.
(a) \( \ce{C6H5CHO} \)
(b) \( \ce{CH3CHO} \)
(c) \( \ce{HCHO} \)
(d) All are equally reactive
Show Answer & Explanation
Answer: (c) \( \ce{HCHO} \)
Explanation:
1. Formaldehyde has two hydrogens and no electron-donating group, so its carbonyl carbon is the most electrophilic and least hindered.
Teacher's Note:
1. The carbonyl carbon is sp2 with one pi bond, which is why nucleophilic addition is the typical reaction.
2. Name carbonyl compounds by choosing the longest chain that contains the C=O; aldehydes end in -al, ketones in -one.
(a) Acetic acid
(b) Isopropyl alcohol
(c) Acetone
(d) Ethanol
Show Answer & Explanation
Answer: (c) Acetone
Explanation:
1. Ethyne is hydrated to acetaldehyde (A)
2. Acetaldehyde with \( \ce{CH3MgBr} \) gives propan-2-ol (B) after hydrolysis, and oxidation of this secondary alcohol gives acetone.
Teacher's Note:
1. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
(a) \( \ce{RCH2OH} \)
(b) \( \ce{RCOOH} \)
(c) \( \ce{RCHO} \)
(d) \( \ce{RCH3} \)
Show Answer & Explanation
Answer: (c) \( \ce{RCHO} \)
Explanation:
1. This is Rosenmund reduction: the poisoned catalyst stops reduction at the aldehyde stage.
Teacher's Note:
1. Aldehyde syntheses: Rosenmund (acid chloride, H2, Pd/BaSO4), Stephen (nitrile, SnCl2/HCl), Etard (toluene, CrO2Cl2), Gattermann-Koch (benzene, CO/HCl, AlCl3).
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
(a) Rosenmund reaction
(b) Sandmeyer reaction
(c) Wurtz reaction
(d) Friedel-Crafts reaction
Show Answer & Explanation
Answer: (d) Friedel-Crafts reaction
Explanation:
1. Benzene with acetyl chloride and anhydrous AlCl3 gives acetophenone by Friedel-Crafts acylation.
Teacher's Note:
1. Check each reagent for whether it stops at the carbonyl stage or goes on to the acid.
2. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
(a) \( \ce{CH3CH=CHCH3} \)
(b) \( \ce{(CH3)2C=C(CH3)2} \)
(c) \( \ce{C6H5CH=CH2} \)
(d) \( \ce{CH3CH=CH2} \)
Show Answer & Explanation
Answer: (b) \( \ce{(CH3)2C=C(CH3)2} \)
Explanation:
1. Each carbon of the double bond in tetramethylethene carries two methyl groups, so cleavage gives two molecules of acetone.
2. The others give aldehydes.
Teacher's Note:
1. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
(a) Glyoxal
(b) Cyclohexane
(c) Acetophenone
(d) Hexabromocyclohexane
Show Answer & Explanation
Answer: (c) Acetophenone
Explanation:
1. Friedel-Crafts acylation of benzene is a substitution giving acetophenone.
2. Cyclohexane and hexabromocyclohexane need addition reactions.
Teacher's Note:
1. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
2. Check each reagent for whether it stops at the carbonyl stage or goes on to the acid.
(a) Hydrolysis of esters
(b) Oxidation of primary alcohols
(c) Oxidation of secondary alcohols
(d) Reaction of acid halide with alcohols
Show Answer & Explanation
Answer: (c) Oxidation of secondary alcohols
Explanation:
1. A secondary alcohol is oxidised directly to a ketone.
2. Primary alcohols give aldehydes or acids, and the other two give acids or esters.
Teacher's Note:
1. Check each reagent for whether it stops at the carbonyl stage or goes on to the acid.
2. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
(a) Reimer-Tiemann reaction
(b) Cannizzaro reaction
(c) Rosenmund reaction
(d) Reformatsky reaction
Show Answer & Explanation
Answer: (c) Rosenmund reaction
Explanation:
1. Reduction of an acid chloride to an aldehyde with poisoned palladium is the Rosenmund reduction.
Teacher's Note:
1. Aldehyde syntheses: Rosenmund (acid chloride, H2, Pd/BaSO4), Stephen (nitrile, SnCl2/HCl), Etard (toluene, CrO2Cl2), Gattermann-Koch (benzene, CO/HCl, AlCl3).
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
(a) Cannizzaro reaction
(b) Wurtz reaction
(c) Etard reaction
(d) Reimer-Tiemann reaction
Show Answer & Explanation
Answer: (c) Etard reaction
Explanation:
1. Chromyl chloride, \( \ce{CrO2Cl2} \), converts the methyl group of toluene to an aldehyde in the Etard reaction.
Teacher's Note:
1. Aldehyde syntheses: Rosenmund (acid chloride, H2, Pd/BaSO4), Stephen (nitrile, SnCl2/HCl), Etard (toluene, CrO2Cl2), Gattermann-Koch (benzene, CO/HCl, AlCl3).
2. Check each reagent for whether it stops at the carbonyl stage or goes on to the acid.
(a) \( \ce{HCHO} \)
(b) \( \ce{CH3CHO} \)
(c) \( \ce{CH3COCH3} \)
(d) \( \ce{CO2} \)
Show Answer & Explanation
Answer: (c) \( \ce{CH3COCH3} \)
Explanation:
1. A ketone with a Grignard reagent gives a tertiary alcohol.
2. \( \ce{CH3MgI} \) adds to acetone to give \( \ce{(CH3)3COH} \).
Teacher's Note:
1. Grignard reagents give a secondary alcohol with aldehydes (primary with HCHO) and a tertiary alcohol with ketones.
2. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
(a) Pd/BaSO4
(b) Zn-Hg couple
(c) \( \ce{LiAlH4} \)
(d) \( \ce{Ni/H2} \)
Show Answer & Explanation
Answer: (a) Pd/BaSO4
Explanation:
1. Rosenmund reduction uses palladium on barium sulphate, partially poisoned.
Teacher's Note:
1. Aldehyde syntheses: Rosenmund (acid chloride, H2, Pd/BaSO4), Stephen (nitrile, SnCl2/HCl), Etard (toluene, CrO2Cl2), Gattermann-Koch (benzene, CO/HCl, AlCl3).
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
(a) \( Hg^{2+} \)
(b) \( \ce{KMnO4} \)
(c) \( \ce{KClO3} \)
(d) \( \ce{K2Cr2O7} \)
Show Answer & Explanation
Answer: (a) \( Hg^{2+} \)
Explanation:
1. Hydration of a terminal alkyne with Hg2+ and dilute H2SO4 follows Markovnikov addition, giving the methyl ketone butanone.
Teacher's Note:
1. Check each reagent for whether it stops at the carbonyl stage or goes on to the acid.
2. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
(a) Acetaldehyde
(b) Ethane
(c) Acetic acid
(d) Acetone
Show Answer & Explanation
Answer: (d) Acetone
Explanation:
1. \( \ce{(CH3COO)2Ca} \) on heating gives acetone and calcium carbonate.
Teacher's Note:
1. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
(a) Phenol and acetic acid
(b) Benzene and acetone
(c) Benzene and acetyl chloride
(d) Phenol and acetone
Show Answer & Explanation
Answer: (c) Benzene and acetyl chloride
Explanation:
1. Friedel-Crafts acylation uses benzene and an acyl chloride with AlCl3.
Teacher's Note:
1. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
2. Check each reagent for whether it stops at the carbonyl stage or goes on to the acid.
(a) \( \ce{CH3COCH3} \)
(b) \( \ce{CH3CHO} \)
(c) \( \ce{HCHO + CaCO3} \)
(d) \( \ce{CH3CHO + CaCO3} \)
Show Answer & Explanation
Answer: (d) \( \ce{CH3CHO + CaCO3} \)
Explanation:
1. A mixed calcium salt of formic and acetic acids gives acetaldehyde and calcium carbonate on dry heating.
Teacher's Note:
1. List the standard preparations: oxidation of alcohols, ozonolysis, hydration of alkynes, Rosenmund, Stephen, Etard, Gattermann-Koch and Friedel-Crafts acylation.
2. Decide whether the product should be an aldehyde or a ketone from the type of alcohol or alkene given.
Free study material for Chemistry
Practice MCQs for JEE Chemistry Aldehydes Ketones and Carboxylic Acids
JEE Chemistry Aldehydes Ketones and Carboxylic Acids Objective Test Questions
Test your conceptual understanding of Aldehydes Ketones and Carboxylic Acids with these targeted multiple-choice questions. Designed in alignment with the latest JEE curriculum for JEE Chemistry, these problem sets build accuracy and prepare students for objective exams.
NCERT-Aligned Objective Questions and Solutions
Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
Next Steps in Your Exam Preparation
Explore our broader library of printable assignments, chapter notes, and mock tests designed to support continuous revision and secure higher marks in JEE assessments.
FAQs
You can get most exhaustive JEE Chemistry Aldehydes Ketones and Carboxylic Acids MCQs Set 22 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.
Yes, our JEE Chemistry Aldehydes Ketones and Carboxylic Acids MCQs Set 22 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Chemistry Aldehydes Ketones and Carboxylic Acids MCQs Set 22, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.
Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Chemistry Aldehydes Ketones and Carboxylic Acids MCQs Set 22 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.