Practice MCQs for JEE Physics Waves
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Multiple Choice Questions
(a) I and III
(b) II and III
(c) I, II and III
(d) I and II
Show Answer & Explanation
Answer: (a) I and III
Explanation:
1. The ripples spread outward (I) and no bulk water moves with them (III).
2. A cork only bobs up and down and does not move outward, so II is false.
Teacher's Note:
1. Waves move, medium does not.
(a) diffraction
(b) destructive interference
(c) constructive and destructive interference
(d) superposition of two waves of nearly equal frequency
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Answer: (d) superposition of two waves of nearly equal frequency
Explanation:
1. Beats arise when two waves of slightly different frequencies are superposed.
2. The amplitude then rises and falls periodically.
Teacher's Note:
1. Beat frequency = f₁ − f₂.
Assertion (A): Particle velocity and wave velocity are both independent of time.
Reason (R): For the propagation of wave motion, the medium must have the properties of elasticity and inertia.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
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Answer: (d) A is false, but R is true.
Explanation:
1. The wave velocity is constant but the particle velocity changes with time, so the assertion is false.
2. The reason is a true statement.
Teacher's Note:
1. Particle velocity is periodic.
(a) 1 : 2
(b) 1 : 4
(c) 2 : 1
(d) 4 : 1
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Answer: (c) 2 : 1
Explanation:
1. f_A = v/2L and f_B = v/4L.
2. The ratio is 2 : 1.
Teacher's Note:
1. Open: v/2L; closed: v/4L.
(a) longitudinal elastic waves only
(b) transverse elastic waves only
(c) both longitudinal and transverse elastic waves
(d) non-elastic waves
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Answer: (c) both longitudinal and transverse elastic waves
Explanation:
1. Solids have both bulk and shear moduli.
2. So both longitudinal and transverse waves can travel.
Teacher's Note:
1. Solids support both types.
| Column I | Column II |
|---|---|
| (A) A region of low pressure and low density | (1) Particles oscillate at right angle to the direction of propagation |
| (B) A region of high pressure and high density | (2) Particles oscillate in the same direction as propagation |
| (C) Longitudinal wave | (3) Compression |
| (D) Transverse wave | (4) Rarefaction |
(a) A-4, B-2, C-3, D-1
(b) A-3, B-4, C-2, D-1
(c) A-4, B-3, C-2, D-1
(d) A-4, B-1, C-2, D-3
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Answer: (c) A-4, B-3, C-2, D-1
Explanation:
1. Low pressure and density is a rarefaction (A-4).
2. High pressure and density is a compression (B-3).
3. In a longitudinal wave the particles oscillate along the direction of propagation (C-2).
4. In a transverse wave they oscillate at right angles (D-1).
Teacher's Note:
1. Compressions and rarefactions.
(a) \( y=\sin(2\pi x-2\pi t) \)
(b) \( y=\sin(10\pi x-20\pi t) \)
(c) \( y=\sin(2\pi x+2\pi t) \)
(d) \( y=\sin(x-2t) \)
Show Answer & Explanation
Answer: (d) \( y=\sin(x-2t) \)
Explanation:
1. k = 2π/λ = 1 rad/m and ω = 2πf = 2 rad/s.
2. A wave in the +x direction is y = sin(kx − ωt) = sin(x − 2t).
Teacher's Note:
1. Find k and ω.
(a) I and III
(b) II and III
(c) I and II
(d) I, II and III
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Answer: (c) I and II
Explanation:
1. Steel has both moduli and carries longitudinal and transverse waves at different speeds.
2. Air has no shear modulus and carries only longitudinal waves, so III is false.
Teacher's Note:
1. Fluids lack shear modulus.
Assertion (A): Two waves moving in a uniform string having uniform tension cannot have different velocities.
Reason (R): The elastic and inertial properties of the string are the same for all waves in the same string. Moreover, the speed of a wave in a string depends on its elastic and inertial properties only.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
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Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. v = √(T/μ) depends only on the tension and the mass per unit length.
2. These are the same for both waves, so their speeds are equal.
Teacher's Note:
1. Speed depends on the medium only.
(a) 205 Hz
(b) 10.5 Hz
(c) 105 Hz
(d) 155 Hz
Show Answer & Explanation
Answer: (c) 105 Hz
Explanation:
1. Consecutive harmonics differ by the fundamental frequency.
2. f₁ = 420 − 315 = 105 Hz.
Teacher's Note:
1. Harmonics are n f₁.
(a) the frequency of the wave produced
(b) the velocity of the source
(c) the velocity of the observer
(d) the distance from the source to the listener
Show Answer & Explanation
Answer: (d) the distance from the source to the listener
Explanation:
1. f′ depends on f, v_s and v_o.
2. The distance between source and listener does not enter.
Teacher's Note:
1. No distance in the formula.
| Column I | Column II |
|---|---|
| (A) Pitch | (1) Waveform |
| (B) Quality | (2) Frequency |
| (C) Loudness | (3) Intensity |
| (D) Nodes | (4) Position of zero amplitude |
(a) A-3, B-1, C-2, D-4
(b) A-2, B-4, C-3, D-1
(c) A-1, B-2, C-3, D-4
(d) A-2, B-1, C-3, D-4
Show Answer & Explanation
Answer: (d) A-2, B-1, C-3, D-4
Explanation:
1. Pitch is related to frequency (A-2).
2. Quality (timbre) depends on the waveform (B-1).
3. Loudness depends on intensity (C-3).
4. Nodes are points of zero amplitude (D-4).
Teacher's Note:
1. Characteristics of sound.
(a) carrying electric charge and vibrating
(b) vibrating with a frequency greater than 20000 Hz
(c) vibrating with a very large amplitude
(d) moving with a speed greater than that of sound in the medium
Show Answer & Explanation
Answer: (d) moving with a speed greater than that of sound in the medium
Explanation:
1. A source moving faster than sound produces a conical shock wave.
Teacher's Note:
1. Supersonic motion.
(a) \( y=r\sin\omega t \)
(b) \( y=r\sin(\omega t-kx) \)
(c) \( y=\frac{a}{\sqrt r}\sin(\omega t-kx) \)
(d) \( y=\frac ar\sin(\omega t-kr) \)
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Answer: (b) \( y=r\sin(\omega t-kx) \)
Explanation:
1. A plane wave has a constant amplitude and travels along one direction.
2. y = r sin(ωt − kx) is of this form; the others are not plane waves.
Teacher's Note:
1. Plane wave: constant amplitude.
(a) \( \pi \)
(b) 0
(c) \( \pi/2 \)
(d) \( \pi/3 \)
Show Answer & Explanation
Answer: (b) 0
Explanation:
1. An open (free) boundary reflects the wave with no phase change.
Teacher's Note:
1. Open end: 0.
(a) \( \frac1n=\frac1{n_1}+\frac1{n_2}+\frac1{n_3} \)
(b) \( \frac1{\sqrt n}=\frac1{\sqrt{n_1}}+\frac1{\sqrt{n_2}}+\frac1{\sqrt{n_3}} \)
(c) \( \sqrt n=\sqrt{n_1}+\sqrt{n_2}+\sqrt{n_3} \)
(d) \( n=n_1+n_2+n_3 \)
Show Answer & Explanation
Answer: (a) \( \frac1n=\frac1{n_1}+\frac1{n_2}+\frac1{n_3} \)
Explanation:
1. At fixed tension and mass per length, n ∝ 1/L.
2. Since L = L₁ + L₂ + L₃, 1/n = 1/n₁ + 1/n₂ + 1/n₃.
Teacher's Note:
1. n ∝ 1/L.
(a) \( 15\sqrt2\ \text{m/s} \)
(b) \( \frac{15}{\sqrt2}\ \text{m/s} \)
(c) \( 15\ \text{m/s} \)
(d) \( 30\ \text{m/s} \)
Show Answer & Explanation
Answer: (c) \( 15\ \text{m/s} \)
Explanation:
1. f′ = 9500 × 300/(300 − v) ≤ 10000.
2. So 300 − v ≥ 285 and v ≤ 15 m/s.
Teacher's Note:
1. Doppler for an approaching source.
(a) wavelength
(b) loudness
(c) frequency
(d) intensity
Show Answer & Explanation
Answer: (b) loudness
Explanation:
1. The phon is a unit of loudness level.
Teacher's Note:
1. Phon measures loudness.
(a) only the fundamental note
(b) only even harmonics
(c) only odd harmonics
(d) even and odd harmonics
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Answer: (d) even and odd harmonics
Explanation:
1. An open pipe produces f, 2f, 3f, ….
2. So both even and odd harmonics are present.
Teacher's Note:
1. All harmonics.
(a) 0
(b) \( \pi \)
(c) \( 2\pi \)
(d) \( 3\pi \)
Show Answer & Explanation
Answer: (b) \( \pi \)
Explanation:
1. Reflection at a denser medium (fixed end) reverses the displacement.
2. This is a phase change of π.
Teacher's Note:
1. Denser medium: phase change π.
(a) If the source and the listener both move in the same direction with the same speed
(b) If one of the source/listener is at the centre of a circle while the other is moving on it
(c) When both the source and the listener are at rest
(d) all of these
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Answer: (d) all of these
Explanation:
1. The Doppler effect needs relative motion along the line joining source and listener.
2. There is none in any of the three cases.
Teacher's Note:
1. No relative radial motion, no shift.
(a) \( y=A\sin(kx+\omega t) \)
(b) \( y=A\cos(kx+\omega t) \)
(c) \( y=-A\sin(kx-\omega t) \)
(d) \( y=-A\sin(kx+\omega t) \)
Show Answer & Explanation
Answer: (a) \( y=A\sin(kx+\omega t) \)
Explanation:
1. The reflected wave travels in the −x direction and has a phase change of π: y_r = −A sin(−kx − ωt) = A sin(kx + ωt).
2. At x = 0 the total displacement −A sin ωt + A sin ωt = 0, as required at a rigid wall.
Teacher's Note:
1. Boundary condition y = 0 at x = 0.
(a) an open pipe
(b) a closed pipe
(c) any of them
(d) none
Show Answer & Explanation
Answer: (a) an open pipe
Explanation:
1. A closed pipe produces only odd harmonics.
2. The tenth (even) harmonic can only appear in an open pipe.
Teacher's Note:
1. Even harmonics need an open pipe.
(a) vary from 0 to a
(b) vary from 0 to −a
(c) vary from −a to a
(d) none of these
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Answer: (c) vary from −a to a
Explanation:
1. The sine function takes all values between −1 and 1.
2. The displacement therefore varies from −a to a.
Teacher's Note:
1. Range of sine.
(a) I only
(b) II only
(c) III only
(d) I, II and III
Show Answer & Explanation
Answer: (c) III only
Explanation:
1. v = √(T/μ) depends on tension and linear mass density only.
2. It does not depend on the frequency.
Teacher's Note:
1. v = √(T/μ).
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