Download JEE MCQs for JEE Physics: Wave Optics
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Chapter-wise Objective Questions: Wave Optics
View or download the dedicated Wave Optics MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.
Multiple Choice Questions
(a) reflection
(b) diffraction
(c) refraction
(d) origin of spectra
Show Answer & Explanation
Answer: (d) origin of spectra
Explanation:
1. Huygens' construction explains reflection, refraction and diffraction but not the origin of spectra.
Teacher's Note:
1. Recall the basic fact.
(a) refraction of light
(b) diffraction of light
(c) dispersion of light
(d) polarization of light
Show Answer & Explanation
Answer: (d) polarization of light
Explanation:
1. Only transverse waves can be polarised, so polarisation proves the transverse nature of light.
Teacher's Note:
1. Recall the basic fact.
(a) The intensity decreases in inverse proportion to the square of the distance.
(b) The wavefront is parabolic.
(c) The intensity does not depend on the distance.
(d) None of these.
Show Answer & Explanation
Answer: (a) The intensity decreases in inverse proportion to the square of the distance.
Explanation:
1. Light from a point source spreads over a sphere of area 4πr².
2. So intensity falls as 1/r² and the wavefront is spherical.
Teacher's Note:
1. Recall the basic fact.
Assertion (A): No interference pattern is detected when two coherent sources are infinitely close to each other.
Reason (R): The fringe width is inversely proportional to the distance between the two sources.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. β = λD/d becomes infinitely large as d → 0.
2. So a single fringe would cover the whole screen and no pattern is seen.
Teacher's Note:
1. Think about what happens to β when d tends to zero.
(a) 32 W m⁻²
(b) 16 W m⁻²
(c) 8 W m⁻²
(d) 4 W m⁻²
Show Answer & Explanation
Answer: (b) 16 W m⁻²
Explanation:
1. The first polarizer transmits half of the unpolarised light: 32/2 = 16 W m⁻².
2. (Check: with the middle polarizer at θ, 16cos²θ sin²θ = 4sin²2θ = 3 is possible.)
Teacher's Note:
1. Recall the basic fact.
(a) Only I
(b) II and III
(c) I and II
(d) I, II and III
Show Answer & Explanation
Answer: (c) I and II
Explanation:
1. Diffraction needs a slit comparable to the wavelength, which is common for sound but not for light.
2. It is observed in all waves, so III is false.
Teacher's Note:
1. Recall the basic fact.
(a) 30°
(b) 60°
(c) 45°
(d) 75°
Show Answer & Explanation
Answer: (a) 30°
Explanation:
1. Brewster's law: tan i = 1/√3.
2. So i = 30°.
Teacher's Note:
1. Recall the basic fact.
(a) produce polarised light
(b) produce double refraction
(c) rotate the plane of polarisation of polarised light
(d) convert a plane polarised light into circularly polarised light
Show Answer & Explanation
Answer: (c) rotate the plane of polarisation of polarised light
Explanation:
1. Optically active substances rotate the plane of polarisation, for example sugar solution.
Teacher's Note:
1. Recall the basic fact.
(a) Lloyd's mirror
(b) Fresnel biprism
(c) Young's double slit
(d) Prism
Show Answer & Explanation
Answer: (d) Prism
Explanation:
1. Lloyd's mirror, biprism and double slit all derive two coherent sources from one source. A simple prism does not.
Teacher's Note:
1. Recall the basic fact.
(a) a hyperbola
(b) a straight line
(c) an ellipse
(d) a parabola
Show Answer & Explanation
Answer: (a) a hyperbola
Explanation:
1. The points whose distances from two fixed points differ by a constant lie on a hyperbola.
Teacher's Note:
1. Recall the basic fact.
(a) much greater than the wavelength of light used
(b) much less than the wavelength of light used
(c) comparable to the wavelength of light used
(d) independent of the wavelength of light used
Show Answer & Explanation
Answer: (c) comparable to the wavelength of light used
Explanation:
1. Diffraction effects become noticeable when the size or separation is comparable to the wavelength.
Teacher's Note:
1. Recall the basic fact.
Assertion (A): In YDSE, if I₁ = 9I₀ and I₂ = 4I₀ then Imax/Imin = 25.
Reason (R): In YDSE Imax = (√I₁ + √I₂)² and Imin = (√I₁ − √I₂)².
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Imax = (3 + 2)² I₀ = 25 I₀ and Imin = (3 − 2)² I₀ = I₀.
2. So the ratio is 25, using the formulae of the reason.
Teacher's Note:
1. Apply the formulae for Imax and Imin directly.
(a) 6.5 × 10⁻⁴ mm
(b) 1.3 micron
(c) 3250 Å
(d) 2.6 × 10⁻⁴ cm
Show Answer & Explanation
Answer: (b) 1.3 micron
Explanation:
1. a sinθ = λ gives a = 6500 Å/sin30° = 13000 Å = 1.3 micron.
Teacher's Note:
1. Recall the basic fact.
(a) \( I_0/2 \)
(b) \( I_0/\sqrt{2} \)
(c) \( I_0\sqrt{2} \)
(d) \( 2I_0 \)
Show Answer & Explanation
Answer: (a) \( I_0/2 \)
Explanation:
1. I = I₀cos²45° = I₀/2.
Teacher's Note:
1. Recall the basic fact.
(a) 4 mm
(b) 5.6 mm
(c) 14 mm
(d) 28 mm
Show Answer & Explanation
Answer: (d) 28 mm
Explanation:
1. Dark fringe positions: y = (2m + 1)λD/2d = (2m + 1) × 2 mm for 400 nm and (2n + 1) × 2.8 mm for 560 nm.
2. They coincide when 5(2m + 1) = 7(2n + 1), the first at 14 mm and the next at 42 mm.
3. Spacing of the totally dark areas = 28 mm.
Teacher's Note:
1. Recall the basic fact.
(a) zero
(b) (2n − 1)π
(c) nπ
(d) (n + 1)π
Show Answer & Explanation
Answer: (b) (2n − 1)π
Explanation:
1. Destructive interference occurs for a phase difference of an odd multiple of π, that is (2n − 1)π.
Teacher's Note:
1. Recall the basic fact.
Assertion (A): A thin film such as a soap bubble or a thin layer of oil on water shows beautiful colours when illuminated by white light.
Reason (R): It happens due to the interference of light reflected from the upper and lower face of the thin film.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. The two reflected beams interfere.
2. Different wavelengths interfere constructively at different thicknesses, giving colours.
Teacher's Note:
1. Thin film colours are an interference effect.
(a) \( \tan(1.5) \)
(b) \( \sin(1.5) \)
(c) \( \sin^{-1}(1.5) \)
(d) \( \tan^{-1}(1.5) \)
Show Answer & Explanation
Answer: (d) \( \tan^{-1}(1.5) \)
Explanation:
1. tan iB = μ = 1.5.
2. So iB = tan⁻¹(1.5).
Teacher's Note:
1. Recall the basic fact.
(a) \( (2n+1)\frac{\lambda}{2} \)
(b) \( (2n+1)\frac{\lambda}{4} \)
(c) \( (2n+1)\frac{\lambda}{8} \)
(d) \( (2n+1)\frac{\lambda}{16} \)
Show Answer & Explanation
Answer: (b) \( (2n+1)\frac{\lambda}{4} \)
Explanation:
1. cos²(φ/2) = 1/2 gives φ/2 = π/4 (odd multiples), so φ = (2n + 1)π/2.
2. Path difference = φλ/2π = (2n + 1)λ/4.
Teacher's Note:
1. Recall the basic fact.
(a) is parallel to the direction of propagation
(b) does not change with time
(c) increases linearly with time
(d) varies periodically with time
Show Answer & Explanation
Answer: (d) varies periodically with time
Explanation:
1. The electric vector of a wave oscillates periodically, perpendicular to the direction of propagation.
Teacher's Note:
1. Recall the basic fact.
(a) 6 mm
(b) 4 mm
(c) 3 mm
(d) 8 mm
Show Answer & Explanation
Answer: (a) 6 mm
Explanation:
1. β₁ = λ₁D/d = 1.2 mm and β₂ = 1.0 mm.
2. n₁β₁ = n₂β₂ gives 12n₁ = 10n₂, so n₁ = 5, n₂ = 6.
3. y = 5 × 1.2 = 6 mm.
Teacher's Note:
1. Recall the basic fact.
(a) points
(b) straight lines
(c) semi-circles
(d) concentric circles
Show Answer & Explanation
Answer: (d) concentric circles
Explanation:
1. Points with the same path difference lie on a hyperboloid of revolution about the line S₁S₂.
2. Its intersection with the screen perpendicular to this line is a set of concentric circles.
Teacher's Note:
1. Recall the basic fact.
(a) Reflected and refracted rays are completely polarised with their planes of polarization parallel to each other
(b) Reflected and refracted rays are completely polarised with their planes of polarization perpendicular to each other
(c) Reflected light is plane polarised but transmitted light is partially polarised
(d) Reflected light is partially polarised but refracted light is plane polarised
Show Answer & Explanation
Answer: (c) Reflected light is plane polarised but transmitted light is partially polarised
Explanation:
1. At Brewster's angle the reflected light is completely plane polarised.
2. The refracted light is only partially polarised.
Teacher's Note:
1. Recall the basic fact.
(a) 1.75
(b) 1.50
(c) 1.25
(d) 1.00
Show Answer & Explanation
Answer: (a) 1.75
Explanation:
1. Shift is proportional to (μ − 1).
2. (μ' − 1)/(1.5 − 1) = 3/2, so μ' − 1 = 0.75 and μ' = 1.75.
Teacher's Note:
1. Recall the basic fact.
(a) \( I_0\cos\left(\frac{x}{\beta}\right) \)
(b) \( I_0\cos^2\left(\frac{x}{\beta}\right) \)
(c) \( I_0\cos^2\left(\frac{\pi x}{\beta}\right) \)
(d) \( \frac{I_0}{4}\cos^2\left(\frac{\pi x}{\beta}\right) \)
Show Answer & Explanation
Answer: (c) \( I_0\cos^2\left(\frac{\pi x}{\beta}\right) \)
Explanation:
1. Phase difference φ = 2πx/β.
2. I = I₀cos²(φ/2) = I₀cos²(πx/β).
Teacher's Note:
1. Recall the basic fact.
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Multiple Choice Questions (MCQs) for JEE Physics Wave Optics
JEE Physics Wave Optics Objective Test Questions
Test your conceptual understanding of Wave Optics with these targeted multiple-choice questions. Designed in alignment with the latest JEE curriculum for JEE Physics, these problem sets build accuracy and prepare students for objective exams.
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FAQs
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