Practice MCQs for JEE Physics Vectors and Calculus
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Access Vectors and Calculus Questions and Solutions
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Multiple Choice Questions
(a) \( 42\hat i+30\hat j-6\hat k \)
(b) \( 42\hat i+30\hat j+6\hat k \)
(c) \( 42\hat i-30\hat j+6\hat k \)
(d) zero
Show Answer & Explanation
Answer: (a) \( 42\hat i+30\hat j-6\hat k \)
Explanation:
1. The position of the force relative to the point is \( \vec r=\vec r_1-\vec r_2=-2\hat i+4\hat j+6\hat k \).
2. \( \vec\tau=\vec r\times\vec F=\begin{vmatrix}\hat i&\hat j&\hat k\\-2&4&6\\4&-5&3\end{vmatrix} \).
3. \( =(12+30)\hat i-(-6-24)\hat j+(10-16)\hat k=42\hat i+30\hat j-6\hat k \).
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(a) 64
(b) \( 8\sqrt3 \)
(c) 32
(d) \( \sqrt3 \)
Show Answer & Explanation
Answer: (b) \( 8\sqrt3 \)
Explanation:
1. \( \vec A\times\vec B=(2+6)\hat i-(1-9)\hat j+(-2-6)\hat k=8\hat i+8\hat j-8\hat k \).
2. Area \( =|\vec A\times\vec B|=8\sqrt{1+1+1}=8\sqrt3 \) units.
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121. .
(a) \( \vec A\times\vec B=\vec A\cdot\vec B \)
(b) \( \vec A\times\vec B=0 \)
(c) \( \vec A\cdot\vec B=0 \)
(d) \( \vec A\cdot\vec B=|\vec A||\vec B| \)
Show Answer & Explanation
Answer: (c) \( \vec A\cdot\vec B=0 \)
Explanation:
1. \( \vec A\cdot\vec B=AB\cos90^\circ=0 \).
2. The cross product has magnitude \( AB\sin90^\circ=AB \), not zero, and a dot product is a scalar while a cross product is a vector.
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(a) 10 N, 11 N
(b) 5 N, 12 N
(c) 6.5 N, 6.5 N
(d) 9 N, 12 N
Show Answer & Explanation
Answer: (b) 5 N, 12 N
Explanation:
1. Rectangular components satisfy \( F_x^2+F_y^2=F^2=169 \).
2. \( 5^2+12^2=169 \) works. \( 10^2+11^2=221,\ 6.5^2+6.5^2=84.5,\ 9^2+12^2=225 \) do not.
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(a) -2
(b) -7
(c) 8
(d) -8
Show Answer & Explanation
Answer: (c) 8
Explanation:
1. Perpendicular vectors have \( \vec A\cdot\vec B=0 \).
2. \( 10+14-3a=0 \), so \( a=8 \).
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(a) \( \dfrac{5\hat i+3\hat j+7\hat k}{\sqrt{83}} \)
(b) \( \dfrac{5\hat i+3\hat j-7\hat k}{\sqrt{83}} \)
(c) \( \dfrac{3\hat i-5\hat j+7\hat k}{\sqrt{83}} \)
(d) \( \dfrac{3\hat i+5\hat j+7\hat k}{\sqrt{83}} \)
Show Answer & Explanation
Answer: (d) \( \dfrac{3\hat i+5\hat j+7\hat k}{\sqrt{83}} \)
Explanation:
1. The cross product is perpendicular to both: \( (4-1)\hat i-(-2-3)\hat j+(1+6)\hat k=3\hat i+5\hat j+7\hat k \).
2. Its magnitude is \( \sqrt{9+25+49}=\sqrt{83} \).
3. The unit vector is \( (3\hat i+5\hat j+7\hat k)/\sqrt{83} \).
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(a) \( \left(A^2+B^2+\sqrt2\,AB\right)^{1/2} \)
(b) \( \sqrt{A^2+B^2} \)
(c) A + B
(d) \( \left(A^2+B^2+\dfrac{AB}{\sqrt2}\right)^{1/2} \)
Show Answer & Explanation
Answer: (a) \( \left(A^2+B^2+\sqrt2\,AB\right)^{1/2} \)
Explanation:
1. \( AB\cos\theta=AB\sin\theta \), so \( \theta=45^\circ \).
2. \( |\vec C|=\sqrt{A^2+B^2+2AB\cos45^\circ}=(A^2+B^2+\sqrt2AB)^{1/2} \).
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(a) \( 18\hat i+13\hat j-2\hat k \)
(b) \( 6\hat i+2\hat j-3\hat k \)
(c) \( -18\hat i-13\hat j+2\hat k \)
(d) \( 6\hat i-2\hat j+8\hat k \)
Show Answer & Explanation
Answer: (c) \( -18\hat i-13\hat j+2\hat k \)
Explanation:
1. \( \vec\omega\times\vec r=\begin{vmatrix}\hat i&\hat j&\hat k\\3&-4&1\\5&-6&6\end{vmatrix} \).
2. \( =(-24+6)\hat i-(18-5)\hat j+(-18+20)\hat k=-18\hat i-13\hat j+2\hat k \).
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155. .
(a) \( \hat i+\hat j\ \text{and}\ \hat i-\hat j\ \text{are mutually perpendicular} \)
(b) A vector of zero length can have a unique direction
(c) \( \text{If }\vec A\times\vec B=0\text{, then both }\vec A\text{ and }\vec B\text{ must be zero} \)
(d) \( \text{If }\vec A\cdot\vec B=0\text{, then }\vec A=0\text{ or }\vec B=0 \)
Show Answer & Explanation
Answer: (a) \( \hat i+\hat j\ \text{and}\ \hat i-\hat j\ \text{are mutually perpendicular} \)
Explanation:
1. \( (\hat i+\hat j)\cdot(\hat i-\hat j)=1-1=0 \), so they are perpendicular.
2. A null vector has no direction; a zero cross product only means the vectors are parallel; a zero dot product only means they are perpendicular (or one is null).
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144. .
(a) 6
(b) \( 2\sqrt{10} \)
(c) \( 5\sqrt6 \)
(d) 4
Show Answer & Explanation
Answer: (b) \( 2\sqrt{10} \)
Explanation:
1. Components: \( \Delta x=6,\ \Delta y=-2,\ \Delta z=0 \).
2. Magnitude \( =\sqrt{36+4}=\sqrt{40}=2\sqrt{10} \).
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90. .
(a) \( \pi/2 \)
(b) zero
(c) \( \pi \)
(d) \( \pi/4 \)
Show Answer & Explanation
Answer: (a) \( \pi/2 \)
Explanation:
1. \( 13^2=12^2+5^2+2(12)(5)\cos\theta \).
2. \( 169=169+120\cos\theta \), so \( \cos\theta=0 \) and \( \theta=\pi/2 \).
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36. r
37. i
38. g
39. h
40. t
41.
42. t
43. r
44. i
45. a
46. n
47. g
48. l
49. e
50. ,
51.
52. s
53. o
54.
55. t
56. h
57. e
58.
59. t
60. w
61. o
62.
63. c
64. o
65. m
66. p
67. o
68. n
69. e
70. n
71. t
72.
73. v
74. e
75. c
76. t
77. o
78. r
79. s
80.
81. a
82. r
83. e
84.
85. p
86. e
87. r
88. p
89. e
90. n
91. d
92. i
93. c
94. u
95. l
96. a
97. r
98. .
(a) 12
(b) 8
(c) 16
(d) 0
Show Answer & Explanation
Answer: (d) 0
Explanation:
1. \( \vec A\cdot\vec B=(2)(3)+(3)(-2)+(1)(0)=6-6+0=0 \).
Teacher's Note:
1. A
2.
3. z
4. e
5. r
6. o
7.
8. d
9. o
10. t
11.
12. p
13. r
14. o
15. d
16. u
17. c
18. t
19.
20. t
21. e
22. l
23. l
24. s
25.
26. y
27. o
28. u
29.
30. t
31. h
32. e
33.
34. t
35. w
36. o
37.
38. v
39. e
40. c
41. t
42. o
43. r
44. s
45.
46. a
47. r
48. e
49.
50. a
51. t
52.
53. r
54. i
55. g
56. h
57. t
58.
59. a
60. n
61. g
62. l
63. e
64. s
65. .
66.
67. R
68. e
69. m
70. e
71. m
72. b
73. e
74. r
75.
76. t
77. o
78.
79. i
80. n
81. c
82. l
83. u
84. d
85. e
86.
87. t
88. h
89. e
90.
91. m
92. i
93. s
94. s
95. i
96. n
97. g
98.
99. k
100.
101. c
102. o
103. m
104. p
105. o
106. n
107. e
108. n
109. t
110.
111. a
112. s
113.
114. z
115. e
116. r
117. o
118. .
(a) The resultant is 7 N
(b) The resultant is 1 N
(c) The resultant lies between 1 N and 7 N
(d) The resultant is 4 N
Show Answer & Explanation
Answer: (c) The resultant lies between 1 N and 7 N
Explanation:
1. The resultant is largest when the forces are parallel: \( 3+4=7 \) N.
2. It is smallest when they are opposite: \( 4-3=1 \) N.
3. For any other angle the resultant lies between 1 N and 7 N.
Teacher's Note:
1. F
2. o
3. r
4.
5. t
6. w
7. o
8.
9. v
10. e
11. c
12. t
13. o
14. r
15. s
16.
17. t
18. h
19. e
20.
21. r
22. e
23. s
24. u
25. l
26. t
27. a
28. n
29. t
30.
31. l
32. i
33. e
34. s
35.
36. b
37. e
38. t
39. w
40. e
41. e
42. n
43.
44. t
45. h
46. e
47.
48. d
49. i
50. f
51. f
52. e
53. r
54. e
55. n
56. c
57. e
58.
59. a
60. n
61. d
62.
63. t
64. h
65. e
66.
67. s
68. u
69. m
70.
71. o
72. f
73.
74. t
75. h
76. e
77.
78. m
79. a
80. g
81. n
82. i
83. t
84. u
85. d
86. e
87. s
88. .
89.
90. N
91. e
92. v
93. e
94. r
95.
96. a
97. s
98. s
99. u
100. m
101. e
102.
103. t
104. h
105. e
106.
107. a
108. n
109. g
110. l
111. e
112.
113. u
114. n
115. l
116. e
117. s
118. s
119.
120. t
121. h
122. e
123.
124. q
125. u
126. e
127. s
128. t
129. i
130. o
131. n
132.
133. g
134. i
135. v
136. e
137. s
138.
139. i
140. t
141. .
(a) \( \sqrt{0.75} \)
(b) 0.5
(c) 1
(d) none of these
Show Answer & Explanation
Answer: (a) \( \sqrt{0.75} \)
Explanation:
1. \( |\vec A|^2=0.16+0.09+c^2=1 \).
2. \( c^2=0.75 \), so \( c=\sqrt{0.75} \) (about 0.87).
Teacher's Note:
1. S
2. e
3. t
4.
5. t
6. h
7. e
8.
9. m
10. a
11. g
12. n
13. i
14. t
15. u
16. d
17. e
18.
19. e
20. q
21. u
22. a
23. l
24.
25. t
26. o
27.
28. o
29. n
30. e
31.
32. a
33. n
34. d
35.
36. s
37. o
38. l
39. v
40. e
41.
42. f
43. o
44. r
45.
46. t
47. h
48. e
49.
50. u
51. n
52. k
53. n
54. o
55. w
56. n
57.
58. c
59. o
60. m
61. p
62. o
63. n
64. e
65. n
66. t
67. .
68.
69. T
70. h
71. e
72.
73. v
74. a
75. l
76. u
77. e
78.
79. 0
80. .
81. 5
82.
83. w
84. o
85. u
86. l
87. d
88.
89. g
90. i
91. v
92. e
93.
94. a
95.
96. m
97. a
98. g
99. n
100. i
101. t
102. u
103. d
104. e
105.
106. b
107. e
108. l
109. o
110. w
111.
112. o
113. n
114. e
115. .
(a) \( \vec B \)
(b) \( \vec C \)
(c) \( \vec B\times\vec C \)
(d) \( \vec B\cdot\vec C \)
Show Answer & Explanation
Answer: (c) \( \vec B\times\vec C \)
Explanation:
1. A is perpendicular to both B and C.
2. \( \vec B\times\vec C \) is also perpendicular to both, so A is parallel to it.
3. \( \vec B\cdot\vec C \) is a scalar and cannot be parallel to a vector.
Teacher's Note:
1. A
2.
3. v
4. e
5. c
6. t
7. o
8. r
9.
10. p
11. e
12. r
13. p
14. e
15. n
16. d
17. i
18. c
19. u
20. l
21. a
22. r
23.
24. t
25. o
26.
27. t
28. w
29. o
30.
31. n
32. o
33. n
34. -
35. p
36. a
37. r
38. a
39. l
40. l
41. e
42. l
43.
44. v
45. e
46. c
47. t
48. o
49. r
50. s
51.
52. m
53. u
54. s
55. t
56.
57. l
58. i
59. e
60.
61. a
62. l
63. o
64. n
65. g
66.
67. t
68. h
69. e
70. i
71. r
72.
73. c
74. r
75. o
76. s
77. s
78.
79. p
80. r
81. o
82. d
83. u
84. c
85. t
86. .
87.
88. A
89.
90. s
91. c
92. a
93. l
94. a
95. r
96.
97. c
98. a
99. n
100.
101. n
102. e
103. v
104. e
105. r
106.
107. b
108. e
109.
110. a
111. n
112.
113. o
114. p
115. t
116. i
117. o
118. n
119.
120. f
121. o
122. r
123.
124. a
125.
126. d
127. i
128. r
129. e
130. c
131. t
132. i
133. o
134. n
135. .
(a) an axial vector
(b) a scalar
(c) a polar vector
(d) a null vector
Show Answer & Explanation
Answer: (a) an axial vector
Explanation:
1. \( \vec L=\vec r\times\vec p \) is a cross product of two polar vectors.
2. Its direction is along the axis of rotation by the right-hand rule, so it is an axial (pseudo) vector.
Teacher's Note:
1. T
2. o
3. r
4. q
5. u
6. e
7. ,
8.
9. a
10. n
11. g
12. u
13. l
14. a
15. r
16.
17. v
18. e
19. l
20. o
21. c
22. i
23. t
24. y
25.
26. a
27. n
28. d
29.
30. a
31. n
32. g
33. u
34. l
35. a
36. r
37.
38. m
39. o
40. m
41. e
42. n
43. t
44. u
45. m
46.
47. a
48. r
49. e
50.
51. a
52. l
53. l
54.
55. a
56. x
57. i
58. a
59. l
60.
61. v
62. e
63. c
64. t
65. o
66. r
67. s
68. .
69.
70. P
71. o
72. s
73. i
74. t
75. i
76. o
77. n
78. ,
79.
80. v
81. e
82. l
83. o
84. c
85. i
86. t
87. y
88.
89. a
90. n
91. d
92.
93. f
94. o
95. r
96. c
97. e
98.
99. a
100. r
101. e
102.
103. p
104. o
105. l
106. a
107. r
108.
109. v
110. e
111. c
112. t
113. o
114. r
115. s
116. .
(a) 4
(b) 2
(c) 3
(d) 1
Show Answer & Explanation
Answer: (b) 2
Explanation:
1. Two forces of equal magnitude acting in exactly opposite directions cancel.
2. A single force cannot give zero resultant.
Teacher's Note:
1. T
2. h
3. e
4.
5. w
6. o
7. r
8. d
9.
10. m
11. i
12. n
13. i
14. m
15. u
16. m
17.
18. i
19. s
20.
21. i
22. m
23. p
24. o
25. r
26. t
27. a
28. n
29. t
30. .
31.
32. T
33. w
34. o
35.
36. e
37. q
38. u
39. a
40. l
41.
42. o
43. p
44. p
45. o
46. s
47. i
48. t
49. e
50.
51. f
52. o
53. r
54. c
55. e
56. s
57.
58. a
59. r
60. e
61.
62. e
63. n
64. o
65. u
66. g
67. h
68. ,
69.
70. e
71. v
72. e
73. n
74.
75. t
76. h
77. o
78. u
79. g
80. h
81.
82. t
83. h
84. r
85. e
86. e
87.
88. a
89. t
90.
91. 1
92. 2
93. 0
94.
95. d
96. e
97. g
98. r
99. e
100. e
101. s
102.
103. a
104. l
105. s
106. o
107.
108. w
109. o
110. r
111. k
112. .
(a) a zero vector
(b) \( \hat i+\hat j+\hat k \)
(c) \( -\hat i-\hat j-\hat k \)
(d) a unit vector
Show Answer & Explanation
Answer: (a) a zero vector
Explanation:
1. \( \hat j\times\hat k=\hat i \).
2. \( \hat i\times\hat i=0 \), so the result is the zero vector.
Teacher's Note:
1. W
2. o
3. r
4. k
5.
6. f
7. r
8. o
9. m
10.
11. t
12. h
13. e
14.
15. i
16. n
17. s
18. i
19. d
20. e
21.
22. b
23. r
24. a
25. c
26. k
27. e
28. t
29.
30. o
31. u
32. t
33. w
34. a
35. r
36. d
37. s
38. .
39.
40. T
41. h
42. e
43.
44. c
45. r
46. o
47. s
48. s
49.
50. p
51. r
52. o
53. d
54. u
55. c
56. t
57.
58. o
59. f
60.
61. a
62.
63. v
64. e
65. c
66. t
67. o
68. r
69.
70. w
71. i
72. t
73. h
74.
75. i
76. t
77. s
78. e
79. l
80. f
81.
82. i
83. s
84.
85. a
86. l
87. w
88. a
89. y
90. s
91.
92. z
93. e
94. r
95. o
96. .
(a) \( \dfrac{2\hat i+3\hat j}{\sqrt{59}} \)
(b) \( \dfrac{3\hat i+7\hat j+\hat k}{\sqrt{59}} \)
(c) \( \dfrac{\hat i+4\hat j+\hat k}{\sqrt{18}} \)
(d) \( \dfrac{2\hat i+3\hat j}{\sqrt{13}} \)
Show Answer & Explanation
Answer: (b) \( \dfrac{3\hat i+7\hat j+\hat k}{\sqrt{59}} \)
Explanation:
1. \( \vec A+\vec B=3\hat i+7\hat j+\hat k \).
2. Magnitude \( =\sqrt{9+49+1}=\sqrt{59} \).
Teacher's Note:
1. A
2. d
3. d
4.
5. t
6. h
7. e
8.
9. v
10. e
11. c
12. t
13. o
14. r
15. s
16.
17. c
18. o
19. m
20. p
21. o
22. n
23. e
24. n
25. t
26.
27. b
28. y
29.
30. c
31. o
32. m
33. p
34. o
35. n
36. e
37. n
38. t
39. ,
40.
41. t
42. h
43. e
44. n
45.
46. d
47. i
48. v
49. i
50. d
51. e
52.
53. b
54. y
55.
56. t
57. h
58. e
59.
60. m
61. a
62. g
63. n
64. i
65. t
66. u
67. d
68. e
69.
70. o
71. f
72.
73. t
74. h
75. e
76.
77. s
78. u
79. m
80. ,
81.
82. n
83. o
84. t
85.
86. o
87. f
88.
89. t
90. h
91. e
92.
93. i
94. n
95. d
96. i
97. v
98. i
99. d
100. u
101. a
102. l
103.
104. v
105. e
106. c
107. t
108. o
109. r
110. s
111. .
(a) 16 W
(b) 8 W
(c) zero
(d) \( 8\sqrt2\ \text{W} \)
Show Answer & Explanation
Answer: (c) zero
Explanation:
1. \( P=\vec F\cdot\vec v=(2)(4)+(4)(-2)=8-8=0 \).
Teacher's Note:
1. P
2. o
3. w
4. e
5. r
6.
7. i
8. s
9.
10. t
11. h
12. e
13.
14. d
15. o
16. t
17.
18. p
19. r
20. o
21. d
22. u
23. c
24. t
25.
26. o
27. f
28.
29. f
30. o
31. r
32. c
33. e
34.
35. a
36. n
37. d
38.
39. v
40. e
41. l
42. o
43. c
44. i
45. t
46. y
47. .
48.
49. Z
50. e
51. r
52. o
53.
54. p
55. o
56. w
57. e
58. r
59.
60. m
61. e
62. a
63. n
64. s
65.
66. t
67. h
68. e
69.
70. f
71. o
72. r
73. c
74. e
75.
76. i
77. s
78.
79. p
80. e
81. r
82. p
83. e
84. n
85. d
86. i
87. c
88. u
89. l
90. a
91. r
92.
93. t
94. o
95.
96. t
97. h
98. e
99.
100. m
101. o
102. t
103. i
104. o
105. n
106. .
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