JEE Physics Units and Dimensions MCQs Set 10

Practice MCQs for JEE Physics Units and Dimensions

Access targeted multiple-choice questions for Units and Dimensions designed to align with the latest JEE academic syllabus for JEE Physics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

Access Units and Dimensions Questions and Solutions

View or download the dedicated Units and Dimensions MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Physics evaluations.

Multiple Choice Questions

Question 1: Which of the following is a possible dimensionless quantity?
(a) Velocity gradient
(b) Pressure gradient
(c) Displacement gradient
(d) Force gradient
Show Answer & Explanation

Answer: (c) Displacement gradient

Explanation:
1. A gradient is a quantity divided by a length.
2. Displacement divided by length has dimensions \( L/L \), which is dimensionless.
3. Velocity gradient has \( T^{-1} \), pressure gradient \( ML^{-2}T^{-2} \) and force gradient \( MT^{-2} \), all non-zero.

Teacher's Note:
1. D
2. i
3. v
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5. d
6. e
7.
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11.
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82.
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109. o
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115. i
116. m
117. e
118. n
119. s
120. i
121. o
122. n
123. l
124. e
125. s
126. s
127. .

Question 2: The unit of power is
(a) kilowatt
(b) kilowatt hour
(c) joule
(d) dyne
Show Answer & Explanation

Answer: (a) kilowatt

Explanation:
1. Power is the rate of doing work, with unit joule per second (watt).
2. Kilowatt is a multiple of watt.
3. Kilowatt hour and joule are units of energy and dyne is a unit of force.

Teacher's Note:
1. K
2. i
3. l
4. o
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6. a
7. t
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9.
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14.
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20. c
21. o
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31.
32. b
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39.
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42.
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70.
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72. u
73. t
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80.
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82. n
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84. r
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88.
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90. l
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95.
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98. e
99. c
100. k
101.
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103. h
104. e
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106. h
107. e
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109.
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111. i
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119. u
120. l
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124. l
125. i
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127. d
128.
129. o
130. r
131.
132. d
133. i
134. v
135. i
136. d
137. e
138. d
139. .

Question 3: The dimensional formula of Planck's constant is identical to that of
(a) torque
(b) work
(c) stress
(d) angular momentum
Show Answer & Explanation

Answer: (d) angular momentum

Explanation:
1. From \( E = h\nu \), \( [h] = [E]/[\nu] = ML^2T^{-2}\cdot T = ML^2T^{-1} \).
2. Angular momentum \( mvr \) has \( M\cdot LT^{-1}\cdot L = ML^2T^{-1} \).
3. Torque and work are \( ML^2T^{-2} \), stress is \( ML^{-1}T^{-2} \).

Teacher's Note:
1. P
2. l
3. a
4. n
5. c
6. k
7. '
8. s
9.
10. c
11. o
12. n
13. s
14. t
15. a
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18.
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60. g
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67. o
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75.
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77. h
78. i
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80.
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83.
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87.
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89. n
90. g
91. u
92. l
93. a
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95.
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100. n
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102. u
103. m
104.
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113. i
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117.
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122. n
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126.
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129.
130. \
131. (
132.
133. h
134. /
135. 2
136. \
137. p
138. i
139.
140. \
141. )
142. .

Question 4: Which of the following is a fundamental (base) quantity?
(a) volume
(b) velocity
(c) time
(d) force
Show Answer & Explanation

Answer: (c) time

Explanation:
1. Base quantities are those chosen independently in the SI system: length, mass, time, current, temperature, amount of substance and luminous intensity.
2. Volume, velocity and force are derived from them.

Teacher's Note:
1. L
2. e
3. a
4. r
5. n
6.
7. t
8. h
9. e
10.
11. s
12. e
13. v
14. e
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18. I
19.
20. b
21. a
22. s
23. e
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26. u
27. a
28. n
29. t
30. i
31. t
32. i
33. e
34. s
35. ;
36.
37. e
38. v
39. e
40. r
41. y
42. t
43. h
44. i
45. n
46. g
47.
48. e
49. l
50. s
51. e
52.
53. i
54. n
55.
56. m
57. e
58. c
59. h
60. a
61. n
62. i
63. c
64. s
65.
66. i
67. s
68.
69. a
70.
71. c
72. o
73. m
74. b
75. i
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77. a
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79. i
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81. n
82.
83. o
84. f
85.
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90. t
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95. a
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98.
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100. n
101. d
102.
103. t
104. i
105. m
106. e
107. .

Question 5: A unitless quantity
(a) may have nonzero dimensions
(b) never has a nonzero dimension
(c) always has nonzero dimensions
(d) does not exist
Show Answer & Explanation

Answer: (b) never has a nonzero dimension

Explanation:
1. A unitless quantity such as a pure number, a ratio or an angle in radian carries no unit.
2. If it had a non-zero dimension it would need a unit to express its magnitude.
3. Hence it can never have non-zero dimensions.

Teacher's Note:
1. D
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3.
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7.
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20. n
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24. n
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31. i
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34.
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36. n
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56.
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61.
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128. l
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130. s
131. s
132. .

Question 6: The unit joule second is the unit of
(a) angular momentum
(b) energy
(c) momentum
(d) power
Show Answer & Explanation

Answer: (a) angular momentum

Explanation:
1. Joule second = \( ML^2T^{-2}\cdot T = ML^2T^{-1} \).
2. This is the dimension of angular momentum \( mvr \) and of Planck's constant.

Teacher's Note:
1. M
2. u
3. l
4. t
5. i
6. p
7. l
8. y
9. i
10. n
11. g
12.
13. e
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21. y
22.
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24. i
25. m
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27.
28. g
29. i
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31. e
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79. o
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81. e
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83. t
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86. .
87.
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89. e
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94. e
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98. h
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101.
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122. .

Question 7: Given that v is speed, r is radius and g is gravitational acceleration, which of the following expressions is dimensionless?
(a) \( \dfrac{v^2 r}{g} \)
(b) \( \dfrac{v^2 g}{r} \)
(c) \( v^2 r g \)
(d) \( \dfrac{v^2}{rg} \)
Show Answer & Explanation

Answer: (d) \( \dfrac{v^2}{rg} \)

Explanation:
1. \( v^2 = L^2T^{-2} \) and \( rg = L\cdot LT^{-2} = L^2T^{-2} \).
2. So \( v^2/(rg) \) has dimension \( L^0T^0 \).

Teacher's Note:
1. T
2. h
3. i
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103.
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131. o
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175. i
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177. g
178. .

Question 8: The dimensional formula for modulus of rigidity is
(a) \( [ML^{2}T^{-2}] \)
(b) \( [ML^{-1}T^{-3}] \)
(c) \( [ML^{-2}T^{-2}] \)
(d) \( [ML^{-1}T^{-2}] \)
Show Answer & Explanation

Answer: (d) \( [ML^{-1}T^{-2}] \)

Explanation:
1. Modulus of rigidity = shear stress / shear strain.
2. Shear strain is dimensionless, so the dimensions are those of stress (force/area).
3. \( [F/A] = MLT^{-2}/L^2 = ML^{-1}T^{-2} \).

Teacher's Note:
1. A
2. l
3. l
4.
5. t
6. h
7. r
8. e
9. e
10.
11. e
12. l
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20. o
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22. u
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24. i
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27. Y
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35. u
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37. k
38. ,
39.
40. r
41. i
42. g
43. i
44. d
45. i
46. t
47. y
48. )
49.
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52. v
53. e
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56. h
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60. i
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107. o
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115. e
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130. d
131. i
132. m
133. e
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136. i
137. o
138. n
139. s
140. .

Question 9: A highly rigid cubical block A of mass m and side L is rigidly fixed on a similar cubical block B of low modulus of rigidity \( \eta \). The lower face of B is fixed to a horizontal surface. A small force is applied to a side face of A and then withdrawn, so that A executes simple harmonic motion. Its time period is
(a) \( 2\pi\sqrt{m\eta L} \)
(b) \( 2\pi\sqrt{\dfrac{m\eta}{L}} \)
(c) \( 2\pi\sqrt{\dfrac{m}{\eta L}} \)
(d) \( 2\pi\sqrt{\dfrac{mL}{\eta}} \)
Show Answer & Explanation

Answer: (c) \( 2\pi\sqrt{\dfrac{m}{\eta L}} \)

Explanation:
1. Check dimensions: the period must have dimension \( T \), so \( \sqrt{m/k} \) needs \( k \) of dimension \( MT^{-2} \).
2. \( \eta L \) has dimension \( ML^{-1}T^{-2}\cdot L = MT^{-2} \), so \( T = 2\pi\sqrt{m/(\eta L)} \).
3. Physical check: shear force \( = \eta L^2 (x/L) = \eta L x \), so the spring constant is \( \eta L \).

Teacher's Note:
1. W
2. h
3. e
4. n
5.
6. y
7. o
8. u
9.
10. c
11. a
12. n
13. n
14. o
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16.
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18. e
19. c
20. a
21. l
22. l
23.
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25.
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27. o
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29. m
30. u
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32. a
33. ,
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36. u
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56. p
57. r
58. i
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60. g
61.
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63. o
64. n
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66. t
67. a
68. n
69. t
70.
71. a
72. n
73. d
74.
75. t
76. h
77. e
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79. d
80. i
81. m
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83. n
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90. w
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101. m
102.
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105. .
106.
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108.
109. s
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120. m
121. a
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124. o
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128. i
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130. e
131. s
132.
133. a
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136. e
137. s
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139. o
140. r
141. i
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144.
145. f
146. o
147. r
148. c
149. e
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152. r
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154. p
155. o
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158. i
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160. n
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165. o
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168. h
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172. i
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175. l
176. a
177. c
178. e
179. m
180. e
181. n
182. t
183. .

Question 10: The time period of a soap bubble is \( T \propto P^a d^b S^c \), where P is pressure, d is density and S is surface tension. The values of a, b and c, respectively, are
(a) \( -1,\ -2,\ 3 \)
(b) \( -\tfrac32,\ \tfrac12,\ 1 \)
(c) \( 1,\ 2,\ -\tfrac32 \)
(d) \( 1,\ 2,\ \tfrac13 \)
Show Answer & Explanation

Answer: (b) \( -\tfrac32,\ \tfrac12,\ 1 \)

Explanation:
1. \( [P]=ML^{-1}T^{-2},\ [d]=ML^{-3},\ [S]=MT^{-2} \) and \( [T]=T \).
2. Mass: \( a+b+c=0 \); length: \( -a-3b=0 \); time: \( -2a-2c=1 \).
3. From the length equation \( a=-3b \); mass gives \( c=2b \); time gives \( 6b-4b=1 \), so \( b=\tfrac12,\ a=-\tfrac32,\ c=1 \).

Teacher's Note:
1. W
2. r
3. i
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5. e
6.
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9. e
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16. i
17. o
18. n
19.
20. f
21. o
22. r
23.
24. e
25. a
26. c
27. h
28.
29. o
30. f
31.
32. M
33. ,
34.
35. L
36.
37. a
38. n
39. d
40.
41. T
42.
43. a
44. n
45. d
46.
47. s
48. o
49. l
50. v
51. e
52.
53. t
54. h
55. e
56. m
57.
58. t
59. o
60. g
61. e
62. t
63. h
64. e
65. r
66. .
67.
68. A
69. l
70. w
71. a
72. y
73. s
74.
75. s
76. u
77. b
78. s
79. t
80. i
81. t
82. u
83. t
84. e
85.
86. t
87. h
88. e
89.
90. a
91. n
92. s
93. w
94. e
95. r
96.
97. b
98. a
99. c
100. k
101.
102. i
103. n
104. t
105. o
106.
107. a
108. l
109. l
110.
111. t
112. h
113. r
114. e
115. e
116.
117. e
118. q
119. u
120. a
121. t
122. i
123. o
124. n
125. s
126. .

Question 11: The dimensional formula for specific resistance (resistivity) in terms of M, L, T and Q is
(a) \( [ML^{3}T^{-1}Q^{-2}] \)
(b) \( [ML^{2}T^{-2}Q^{2}] \)
(c) \( [MLT^{-2}Q^{-1}] \)
(d) \( [ML^{2}T^{-2}Q^{-2}] \)
Show Answer & Explanation

Answer: (a) \( [ML^{3}T^{-1}Q^{-2}] \)

Explanation:
1. Resistance \( R = V/I \), where \( V = ML^2T^{-2}Q^{-1} \) and \( I = QT^{-1} \), so \( [R] = ML^2T^{-1}Q^{-2} \).
2. Resistivity \( \rho = RA/l \) so \( [\rho]=[R]\cdot L = ML^3T^{-1}Q^{-2} \).

Teacher's Note:
1. R
2. e
3. s
4. i
5. s
6. t
7. i
8. v
9. i
10. t
11. y
12.
13. i
14. s
15.
16. r
17. e
18. s
19. i
20. s
21. t
22. a
23. n
24. c
25. e
26.
27. m
28. u
29. l
30. t
31. i
32. p
33. l
34. i
35. e
36. d
37.
38. b
39. y
40.
41. a
42.
43. l
44. e
45. n
46. g
47. t
48. h
49. ,
50.
51. s
52. i
53. n
54. c
55. e
56.
57. \
58. (
59.
60. R
61. =
62. \
63. r
64. h
65. o
66.
67. l
68. /
69. A
70.
71. \
72. )
73. .
74.
75. C
76. a
77. r
78. r
79. y
80.
81. c
82. h
83. a
84. r
85. g
86. e
87.
88. Q
89.
90. a
91. s
92.
93. i
94. t
95. s
96.
97. o
98. w
99. n
100.
101. d
102. i
103. m
104. e
105. n
106. s
107. i
108. o
109. n
110.
111. w
112. h
113. e
114. n
115.
116. c
117. u
118. r
119. r
120. e
121. n
122. t
123.
124. i
125. s
126.
127. e
128. x
129. p
130. r
131. e
132. s
133. s
134. e
135. d
136.
137. t
138. h
139. r
140. o
141. u
142. g
143. h
144.
145. i
146. t
147. .

Question 12: Which of the following pairs have the same dimensions?
(a) Force and strain
(b) Angular velocity and frequency
(c) Force and stress
(d) Energy and strain
Show Answer & Explanation

Answer: (b) Angular velocity and frequency

Explanation:
1. Angular velocity \( \omega \) is angle per time, \( T^{-1} \); frequency is \( T^{-1} \).
2. Force is \( MLT^{-2} \), stress \( ML^{-1}T^{-2} \), strain and angle are dimensionless, energy \( ML^2T^{-2} \).

Teacher's Note:
1. R
2. a
3. d
4. i
5. a
6. n
7.
8. i
9. s
10.
11. a
12.
13. r
14. a
15. t
16. i
17. o
18.
19. o
20. f
21.
22. l
23. e
24. n
25. g
26. t
27. h
28. s
29. ,
30.
31. s
32. o
33.
34. i
35. t
36.
37. a
38. d
39. d
40. s
41.
42. n
43. o
44.
45. d
46. i
47. m
48. e
49. n
50. s
51. i
52. o
53. n
54. .
55.
56. T
57. h
58. a
59. t
60.
61. i
62. s
63.
64. w
65. h
66. y
67.
68. a
69. n
70. g
71. u
72. l
73. a
74. r
75.
76. v
77. e
78. l
79. o
80. c
81. i
82. t
83. y
84.
85. a
86. n
87. d
88.
89. f
90. r
91. e
92. q
93. u
94. e
95. n
96. c
97. y
98.
99. m
100. a
101. t
102. c
103. h
104.
105. d
106. i
107. m
108. e
109. n
110. s
111. i
112. o
113. n
114. a
115. l
116. l
117. y
118. .

Question 13: The velocity v of water waves depends on the wavelength \( \lambda \), the density \( \rho \) of water and the acceleration due to gravity g. The method of dimensions gives
(a) \( v^2\propto g^{-1}\lambda^{-1}\rho \)
(b) \( v^2\propto g\lambda\rho \)
(c) \( v^2\propto g\lambda \)
(d) \( v^2\propto g^{-1}\lambda^{-3}\rho \)
Show Answer & Explanation

Answer: (c) \( v^2\propto g\lambda \)

Explanation:
1. Let \( v = k\lambda^a\rho^b g^c \).
2. Mass: \( b=0 \). Time: \( -2c=-1 \), so \( c=\tfrac12 \). Length: \( a-3b+c=1 \), so \( a=\tfrac12 \).
3. Therefore \( v \propto \sqrt{g\lambda} \), i.e. \( v^2\propto g\lambda \), independent of density.

Teacher's Note:
1. W
2. h
3. e
4. n
5. e
6. v
7. e
8. r
9.
10. t
11. h
12. e
13.
14. m
15. a
16. s
17. s
18.
19. d
20. i
21. m
22. e
23. n
24. s
25. i
26. o
27. n
28.
29. a
30. p
31. p
32. e
33. a
34. r
35. s
36.
37. o
38. n
39. l
40. y
41.
42. i
43. n
44.
45. o
46. n
47. e
48.
49. v
50. a
51. r
52. i
53. a
54. b
55. l
56. e
57. ,
58.
59. i
60. t
61. s
62.
63. p
64. o
65. w
66. e
67. r
68.
69. m
70. u
71. s
72. t
73.
74. b
75. e
76.
77. z
78. e
79. r
80. o
81. .
82.
83. T
84. h
85. a
86. t
87.
88. t
89. e
90. l
91. l
92. s
93.
94. y
95. o
96. u
97.
98. t
99. h
100. e
101.
102. a
103. n
104. s
105. w
106. e
107. r
108.
109. d
110. o
111. e
112. s
113.
114. n
115. o
116. t
117.
118. d
119. e
120. p
121. e
122. n
123. d
124.
125. o
126. n
127.
128. d
129. e
130. n
131. s
132. i
133. t
134. y
135. .

Question 14: L, C and R represent inductance, capacitance and resistance respectively. Which combination has the dimensions of an angle (is dimensionless)?
(a) \( \dfrac{1}{RC} \)
(b) \( \dfrac{R}{L} \)
(c) \( \dfrac{C}{L} \)
(d) \( \dfrac{R^2C}{L} \)
Show Answer & Explanation

Answer: (d) \( \dfrac{R^2C}{L} \)

Explanation:
1. The time constants are \( RC \) and \( L/R \), both with dimension \( T \).
2. \( R^2C/L = (RC)/(L/R) = T/T \), which is dimensionless.
3. \( 1/RC \) and \( R/L \) have dimension \( T^{-1} \).

Teacher's Note:
1. I
2. d
3. e
4. n
5. t
6. i
7. f
8. y
9.
10. t
11. h
12. e
13.
14. t
15. w
16. o
17.
18. t
19. i
20. m
21. e
22.
23. c
24. o
25. n
26. s
27. t
28. a
29. n
30. t
31. s
32.
33. o
34. f
35.
36. R
37. C
38.
39. a
40. n
41. d
42.
43. L
44. R
45.
46. c
47. i
48. r
49. c
50. u
51. i
52. t
53. s
54.
55. f
56. i
57. r
58. s
59. t
60. ;
61.
62. t
63. h
64. e
65. n
66.
67. r
68. a
69. t
70. i
71. o
72. s
73.
74. b
75. u
76. i
77. l
78. t
79.
80. f
81. r
82. o
83. m
84.
85. t
86. h
87. e
88. m
89.
90. a
91. r
92. e
93.
94. d
95. i
96. m
97. e
98. n
99. s
100. i
101. o
102. n
103. l
104. e
105. s
106. s
107. .
108.
109. T
110. h
111. i
112. s
113.
114. a
115. l
116. s
117. o
118.
119. t
120. e
121. l
122. l
123. s
124.
125. y
126. o
127. u
128.
129. t
130. h
131. e
132.
133. u
134. n
135. i
136. t
137.
138. o
139. f
140.
141. e
142. a
143. c
144. h
145.
146. t
147. i
148. m
149. e
150.
151. c
152. o
153. n
154. s
155. t
156. a
157. n
158. t
159.
160. i
161. s
162.
163. t
164. h
165. e
166.
167. s
168. e
169. c
170. o
171. n
172. d
173. .

Question 15: The vernier scale of a circular scale is divided into 30 divisions which coincide with 29 main scale divisions. If each main scale division is \( (1/2)^\circ \), the least count of the instrument is
(a) 1 minute of arc
(b) 0.1 minute of arc
(c) 10 minutes of arc
(d) 30 minutes of arc
Show Answer & Explanation

Answer: (a) 1 minute of arc

Explanation:
1. Least count = 1 MSD - 1 VSD = 1 MSD divided by N for N vernier divisions.
2. \( \text{LC} = \dfrac{(1/2)^\circ}{30} = \dfrac{30'}{30} = 1' \).

Teacher's Note:
1. W
2. i
3. t
4. h
5.
6. n
7.
8. v
9. e
10. r
11. n
12. i
13. e
14. r
15.
16. d
17. i
18. v
19. i
20. s
21. i
22. o
23. n
24. s
25.
26. e
27. q
28. u
29. a
30. l
31.
32. t
33. o
34.
35. (
36. n
37. -
38. 1
39. )
40.
41. m
42. a
43. i
44. n
45.
46. d
47. i
48. v
49. i
50. s
51. i
52. o
53. n
54. s
55. ,
56.
57. l
58. e
59. a
60. s
61. t
62.
63. c
64. o
65. u
66. n
67. t
68.
69. i
70. s
71.
72. a
73. l
74. w
75. a
76. y
77. s
78.
79. o
80. n
81. e
82.
83. m
84. a
85. i
86. n
87.
88. d
89. i
90. v
91. i
92. s
93. i
94. o
95. n
96.
97. d
98. i
99. v
100. i
101. d
102. e
103. d
104.
105. b
106. y
107.
108. n
109. .
110.
111. C
112. o
113. n
114. v
115. e
116. r
117. t
118.
119. d
120. e
121. g
122. r
123. e
124. e
125. s
126.
127. t
128. o
129.
130. m
131. i
132. n
133. u
134. t
135. e
136. s
137.
138. a
139. t
140.
141. t
142. h
143. e
144.
145. e
146. n
147. d
148. .

Question 16: Dimensional analysis of the equation \( (\text{velocity})^x = (\text{pressure difference})^{3/2}\times(\text{density})^{-3/2} \) gives x equal to
(a) 3
(b) 1
(c) 2
(d) 4
Show Answer & Explanation

Answer: (a) 3

Explanation:
1. \( \Delta P/\rho = ML^{-1}T^{-2}/ML^{-3} = L^2T^{-2} \).
2. So the right side is \( (L^2T^{-2})^{3/2} = L^3T^{-3} = (LT^{-1})^3 \).
3. Hence \( x=3 \).

Teacher's Note:
1. C
2. o
3. m
4. b
5. i
6. n
7. e
8.
9. t
10. h
11. e
12.
13. t
14. w
15. o
16.
17. q
18. u
19. a
20. n
21. t
22. i
23. t
24. i
25. e
26. s
27.
28. w
29. i
30. t
31. h
32.
33. t
34. h
35. e
36.
37. s
38. a
39. m
40. e
41.
42. e
43. x
44. p
45. o
46. n
47. e
48. n
49. t
50.
51. i
52. n
53. t
54. o
55.
56. o
57. n
58. e
59.
60. r
61. a
62. t
63. i
64. o
65. .
66.
67. P
68. r
69. e
70. s
71. s
72. u
73. r
74. e
75.
76. d
77. i
78. v
79. i
80. d
81. e
82. d
83.
84. b
85. y
86.
87. d
88. e
89. n
90. s
91. i
92. t
93. y
94.
95. h
96. a
97. s
98.
99. t
100. h
101. e
102.
103. d
104. i
105. m
106. e
107. n
108. s
109. i
110. o
111. n
112.
113. o
114. f
115.
116. v
117. e
118. l
119. o
120. c
121. i
122. t
123. y
124.
125. s
126. q
127. u
128. a
129. r
130. e
131. d
132. .

Question 17: The force on a particle depends on its position as \( F = ax + bx^2 \). The dimensions of a and b are respectively
(a) \( [MT^{-2}]\ \text{and}\ [ML^{-1}T^{-2}] \)
(b) \( [MLT^{-2}]\ \text{and}\ [MT^{-2}] \)
(c) \( [ML^{-1}T^{-2}]\ \text{and}\ [MT^{-2}] \)
(d) \( [ML^{2}T^{-2}]\ \text{and}\ [ML^{-1}T^{-2}] \)
Show Answer & Explanation

Answer: (a) \( [MT^{-2}]\ \text{and}\ [ML^{-1}T^{-2}] \)

Explanation:
1. Every term must have the dimensions of force, \( MLT^{-2} \).
2. \( [a] = MLT^{-2}/L = MT^{-2} \).
3. \( [b] = MLT^{-2}/L^2 = ML^{-1}T^{-2} \).

Teacher's Note:
1. T
2. h
3. e
4.
5. p
6. r
7. i
8. n
9. c
10. i
11. p
12. l
13. e
14.
15. o
16. f
17.
18. h
19. o
20. m
21. o
22. g
23. e
24. n
25. e
26. i
27. t
28. y
29.
30. s
31. a
32. y
33. s
34.
35. e
36. v
37. e
38. r
39. y
40.
41. t
42. e
43. r
44. m
45.
46. a
47. d
48. d
49. e
50. d
51.
52. m
53. u
54. s
55. t
56.
57. h
58. a
59. v
60. e
61.
62. t
63. h
64. e
65.
66. s
67. a
68. m
69. e
70.
71. d
72. i
73. m
74. e
75. n
76. s
77. i
78. o
79. n
80. s
81. .
82.
83. D
84. i
85. v
86. i
87. d
88. e
89.
90. t
91. h
92. e
93.
94. d
95. i
96. m
97. e
98. n
99. s
100. i
101. o
102. n
103.
104. o
105. f
106.
107. f
108. o
109. r
110. c
111. e
112.
113. b
114. y
115.
116. t
117. h
118. e
119.
120. d
121. i
122. m
123. e
124. n
125. s
126. i
127. o
128. n
129.
130. o
131. f
132.
133. t
134. h
135. e
136.
137. v
138. a
139. r
140. i
141. a
142. b
143. l
144. e
145.
146. m
147. u
148. l
149. t
150. i
151. p
152. l
153. y
154. i
155. n
156. g
157.
158. t
159. h
160. e
161.
162. c
163. o
164. n
165. s
166. t
167. a
168. n
169. t
170. .

Question 18: The dimensional formula of capacitance C is
(a) \( [ML^{2}T^{-3}A^{-1}] \)
(b) \( [M^{-1}L^{-2}T^{2}A^{2}] \)
(c) \( [M^{-1}L^{-2}T^{4}A^{2}] \)
(d) \( [ML^{2}T^{-2}A^{-2}] \)
Show Answer & Explanation

Answer: (c) \( [M^{-1}L^{-2}T^{4}A^{2}] \)

Explanation:
1. \( C = Q/V \) with \( Q = AT \) and \( V = W/Q = ML^2T^{-3}A^{-1} \).
2. \( [C] = AT/(ML^2T^{-3}A^{-1}) = M^{-1}L^{-2}T^{4}A^{2} \).

Teacher's Note:
1. G
2. e
3. t
4.
5. t
6. h
7. e
8.
9. p
10. o
11. t
12. e
13. n
14. t
15. i
16. a
17. l
18.
19. f
20. r
21. o
22. m
23.
24. e
25. n
26. e
27. r
28. g
29. y
30.
31. p
32. e
33. r
34.
35. u
36. n
37. i
38. t
39.
40. c
41. h
42. a
43. r
44. g
45. e
46.
47. f
48. i
49. r
50. s
51. t
52. ,
53.
54. t
55. h
56. e
57. n
58.
59. d
60. i
61. v
62. i
63. d
64. e
65.
66. c
67. h
68. a
69. r
70. g
71. e
72.
73. b
74. y
75.
76. i
77. t
78. .
79.
80. C
81. h
82. e
83. c
84. k
85.
86. w
87. i
88. t
89. h
90.
91. t
92. h
93. e
94.
95. f
96. a
97. r
98. a
99. d
100. :
101.
102. C
103.
104. V
105.
106. s
107. q
108. u
109. a
110. r
111. e
112. d
113.
114. m
115. u
116. s
117. t
118.
119. g
120. i
121. v
122. e
123.
124. a
125.
126. j
127. o
128. u
129. l
130. e
131. .

Question 19: The diameter of a circle is measured with an error of 4%. The percentage error in the calculated radius is
(a) 2%
(b) 4%
(c) 8%
(d) 16%
Show Answer & Explanation

Answer: (b) 4%

Explanation:
1. \( r = d/2 \), so \( \Delta r/r = \Delta d/d \).
2. The constant factor 1/2 does not change the fractional error, so the error is 4%.

Teacher's Note:
1. A
2.
3. c
4. o
5. n
6. s
7. t
8. a
9. n
10. t
11.
12. f
13. a
14. c
15. t
16. o
17. r
18.
19. h
20. a
21. s
22.
23. n
24. o
25.
26. e
27. r
28. r
29. o
30. r
31. ,
32.
33. s
34. o
35.
36. i
37. t
38.
39. n
40. e
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Question 20: The density of a material in the CGS system is 8 g cm\(^{-3}\). In a system in which the unit of length is 5 cm and the unit of mass is 20 g, its value is
(a) 8
(b) 20
(c) 50
(d) 0.16
Show Answer & Explanation

Answer: (c) 50

Explanation:
1. Unit of density in the new system = \( 20\ \text{g}/(5\ \text{cm})^3 = 0.16\ \text{g cm}^{-3} \).
2. Numerical value \( = 8/0.16 = 50 \).

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Multiple Choice Questions (MCQs) for JEE Physics Units and Dimensions

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