JEE Physics Oscillations MCQs Set 24

Practice MCQs for JEE Physics Oscillations

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Multiple Choice Questions

Question 1: What is the amplitude of simple harmonic motion at resonance in the ideal case of zero damping?
(a) zero
(b) −1
(c) 1
(d) infinite
Show Answer & Explanation

Answer: (d) infinite

Explanation:
1. With no damping, energy keeps being supplied at the natural frequency.
2. The amplitude grows without limit in the ideal case.

Teacher's Note:
1. No damping gives infinite amplitude.

Question 2:
Assertion (A): The amplitude of a forced vibration can never reach infinity.
Reason (R): The driving frequency cannot be increased beyond a certain limit.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. Real systems have damping, which limits the amplitude, so the assertion is true.
2. The driving frequency can be set to any value, so the reason is false.

Teacher's Note:
1. Damping limits the amplitude.

Question 3: A simple pendulum oscillates in air with time period T and amplitude A. As time passes
(a) T and A both decrease
(b) T increases and A is constant
(c) T remains the same and A decreases
(d) T decreases and A is constant
Show Answer & Explanation

Answer: (c) T remains the same and A decreases

Explanation:
1. Air resistance removes energy, so the amplitude decays.
2. The period of small oscillations does not depend on amplitude and stays the same.

Teacher's Note:
1. Damping reduces A, not T.

Question 4: Select the false statement(s). I. The displacement amplitude of an oscillator is independent of the angular frequency of the driving force. II. The amplitude tends to infinity when the driving frequency equals the natural frequency. III. The maximum possible amplitude for a given driving frequency is governed by the driving frequency and the damping.
(a) I only
(b) II only
(c) I and II
(d) I, II and III
Show Answer & Explanation

Answer: (c) I and II

Explanation:
1. The amplitude depends on the driving frequency, so I is false.
2. With damping the amplitude at resonance stays finite, so II is false.
3. III is true.

Teacher's Note:
1. Damping limits the amplitude.

Question 5: Two particles execute simple harmonic motion of the same amplitude A and frequency ω along the x-axis. Their mean positions are separated by a distance X₀ (X₀ > A). If the maximum separation between them is (X₀ + A), the phase difference between them is
(a) \( \frac\pi3 \)
(b) \( \frac\pi4 \)
(c) \( \frac\pi6 \)
(d) \( \frac\pi2 \)
Show Answer & Explanation

Answer: (a) \( \frac\pi3 \)

Explanation:
1. The separation oscillates about X₀ with amplitude 2A sin(φ/2).
2. Setting 2A sin(φ/2) = A gives φ/2 = π/6, so φ = π/3.

Teacher's Note:
1. Superpose the two SHMs.

Question 6: The total mechanical energy of a harmonic oscillator is given as
(a) \( \frac14m\omega^2A^2 \)
(b) \( \frac14m^2\omega A^2 \)
(c) \( \frac12m\omega^2A^2 \)
(d) \( \frac12m^2\omega^2A^2 \)
Show Answer & Explanation

Answer: (c) \( \frac12m\omega^2A^2 \)

Explanation:
1. E = ½kA² and k = mω².
2. So E = ½mω²A².

Teacher's Note:
1. E = ½mω²A².

Question 7: Resonance is an example of
(a) tuning fork
(b) forced vibration
(c) free vibration
(d) damped vibration
Show Answer & Explanation

Answer: (b) forced vibration

Explanation:
1. Resonance occurs when a system is driven at its natural frequency, so it is a case of forced vibration.

Teacher's Note:
1. Resonance is forced vibration.

Question 8: Two pendulums of lengths 1.44 m and 1 m start to swing together. The number of vibrations of the longer pendulum after which they will again swing together is
(a) 4
(b) 3
(c) 5
(d) 2
Show Answer & Explanation

Answer: (c) 5

Explanation:
1. T ∝ √l, so T₁ : T₂ = 1.2 : 1 = 6 : 5.
2. When the longer pendulum has made 5 vibrations, the shorter has made 6, so they are together again.

Teacher's Note:
1. Find the least common time.

Question 9: The maximum velocity of a particle executing simple harmonic motion with an amplitude of 7 mm is 4.4 m/s. The period of oscillation is
(a) 0.01 s
(b) 10 s
(c) 0.1 s
(d) 100 s
Show Answer & Explanation

Answer: (a) 0.01 s

Explanation:
1. v_max = Aω gives ω = 4.4/0.007 ≈ 628.6 rad/s.
2. T = 2π/ω ≈ 0.01 s.

Teacher's Note:
1. v_max = Aω.

Question 10: Motion of an oscillating liquid column in a U-tube is
(a) periodic but not simple harmonic
(b) non-periodic
(c) simple harmonic and the time period is independent of the density of the liquid
(d) simple harmonic and the time period is directly proportional to the density of the liquid
Show Answer & Explanation

Answer: (c) simple harmonic and the time period is independent of the density of the liquid

Explanation:
1. The restoring force is proportional to the density and so is the inertia.
2. T = 2π√(h/g) (h is the column length) does not depend on the density.

Teacher's Note:
1. Density cancels out.

Question 11: In the case of a forced vibration, the resonance wave becomes very sharp when the
(a) quality factor is small
(b) damping force is small
(c) restoring force is small
(d) applied periodic force is small
Show Answer & Explanation

Answer: (b) damping force is small

Explanation:
1. Smaller damping gives a taller and narrower resonance peak.

Teacher's Note:
1. Low damping, sharp resonance.

Question 12: A particle moves on the X-axis according to the equation x = A + B sin ωt. The motion is simple harmonic with amplitude
(a) A
(b) B
(c) A + B
(d) \( \sqrt{A^2+B^2} \)
Show Answer & Explanation

Answer: (b) B

Explanation:
1. The particle oscillates about the mean position x = A.
2. The displacement from the mean position is B sin ωt, so the amplitude is B.

Teacher's Note:
1. Shift of the origin does not change amplitude.

Question 13: A periodic to-and-fro motion is called
(a) periodic motion
(b) orbital motion
(c) oscillatory motion
(d) rectilinear motion
Show Answer & Explanation

Answer: (c) oscillatory motion

Explanation:
1. A motion that repeats itself in a to-and-fro manner about a mean position is called an oscillatory motion.

Teacher's Note:
1. To-and-fro means oscillatory.

Question 14: The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
(a) \( \pi \)
(b) \( 0.707\pi \)
(c) zero
(d) \( 0.5\pi \)
Show Answer & Explanation

Answer: (d) \( 0.5\pi \)

Explanation:
1. If x = A sin ωt, then v = Aω cos ωt and a = −Aω² sin ωt.
2. Velocity leads the acceleration by π/2.

Teacher's Note:
1. v and a differ by π/2.

Question 15: A body oscillates with SHM according to x = 5 cos(2πt − π/4) (in SI units). Its instantaneous displacement at t = 1 s is
(a) \( \frac{\sqrt2}{5}\ \text{m} \)
(b) \( \frac1{\sqrt3}\ \text{m} \)
(c) \( \frac{5}{\sqrt2}\ \text{m} \)
(d) \( \frac12\ \text{m} \)
Show Answer & Explanation

Answer: (c) \( \frac{5}{\sqrt2}\ \text{m} \)

Explanation:
1. At t = 1, x = 5 cos(2π − π/4) = 5 cos(π/4).
2. = 5/√2 m.

Teacher's Note:
1. Substitute t = 1.

Question 16: If a is the amplitude of SHM, the kinetic energy equals the potential energy at a distance ____ from the mean position.
(a) \( \frac{a}{\sqrt2} \)
(b) \( \frac a2 \)
(c) \( \frac a4 \)
(d) \( a \)
Show Answer & Explanation

Answer: (a) \( \frac{a}{\sqrt2} \)

Explanation:
1. ½k(a² − x²) = ½kx² gives x² = a²/2.
2. So x = a/√2.

Teacher's Note:
1. KE = PE at a/√2.

Question 17: Two particles oscillate along two close parallel straight lines side by side, with the same frequency and amplitude. They pass each other, moving in opposite directions, when their displacement is half the amplitude. The mean positions lie on a straight line perpendicular to the paths. The phase difference is
(a) 0
(b) \( 2\pi/3 \)
(c) \( \pi \)
(d) \( \pi/6 \)
Show Answer & Explanation

Answer: (b) \( 2\pi/3 \)

Explanation:
1. At displacement A/2 moving in opposite directions, the phases are π/6 and π − π/6 = 5π/6.
2. The difference is 5π/6 − π/6 = 2π/3.

Teacher's Note:
1. Opposite velocities, same displacement.

Question 18: A simple harmonic motion is represented by y(t) = 10 sin(20t + 0.5). The frequency is
(a) \( \frac{20}{2\pi}\ \text{Hz} \)
(b) \( \frac{10}{2\pi}\ \text{Hz} \)
(c) \( \frac{\pi}{20}\ \text{Hz} \)
(d) \( 2\pi\ \text{Hz} \)
Show Answer & Explanation

Answer: (a) \( \frac{20}{2\pi}\ \text{Hz} \)

Explanation:
1. Comparing with y = a sin(ωt + φ) gives ω = 20 rad/s.
2. f = ω/2π = 20/2π Hz.

Teacher's Note:
1. f = ω/2π.

Question 19: The force acting in simple harmonic motion is always
(a) directly proportional to the displacement
(b) inversely proportional to the displacement
(c) directly proportional to the square of the displacement
(d) inversely proportional to the square of the displacement
Show Answer & Explanation

Answer: (a) directly proportional to the displacement

Explanation:
1. In SHM the restoring force is F = −kx.
2. It is directly proportional to the displacement.

Teacher's Note:
1. F ∝ −x.

Question 20:
Assertion (A): In SHM, kinetic and potential energies become equal when the displacement is 1/√2 times the amplitude.
Reason (R): In SHM, kinetic energy is zero when the potential energy is maximum.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. KE = PE at x = A/√2, so the assertion is true.
2. The reason is also true but it does not give the condition for equality.

Teacher's Note:
1. KE = PE at A/√2.

Question 21: Choose the false statement(s). I. The natural frequency of a body depends on the elastic properties of the material of the body. II. The natural frequency of a body depends on the dimensions of the body.
(a) I only
(b) II only
(c) I and II
(d) none of these
Show Answer & Explanation

Answer: (d) none of these

Explanation:
1. Both the elastic properties and the dimensions of a body determine its natural frequency.
2. So neither statement is false.

Teacher's Note:
1. Both statements are true.

Question 22:
Assertion (A): Sine and cosine functions are periodic functions.
Reason (R): Sinusoidal functions repeat their values after a definite interval of time.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Sine and cosine repeat after 2π.
2. The reason states exactly this property.

Teacher's Note:
1. Periodic means repeating.

Question 23: The bob of a simple pendulum of mass m and total energy E will have maximum linear momentum equal to
(a) \( \sqrt{\frac{2E}{m}} \)
(b) \( \sqrt{2mE} \)
(c) \( 2mE \)
(d) \( mE^2 \)
Show Answer & Explanation

Answer: (b) \( \sqrt{2mE} \)

Explanation:
1. At the mean position the energy is all kinetic: E = p²/2m.
2. So p = √(2mE).

Teacher's Note:
1. E = p²/2m.

Question 24: During simple harmonic motion, the kinetic and potential energies of the particle each vary periodically. Compared with the frequency of the SHM, the frequency of variation of the kinetic and potential energies is
(a) double
(b) four times
(c) half
(d) equal
Show Answer & Explanation

Answer: (a) double

Explanation:
1. KE and PE depend on sin² or cos² of ωt, which have period T/2.
2. Their frequency is double that of the SHM.

Teacher's Note:
1. Energy repeats twice per cycle.

Question 25:
Assertion (A): If the amplitude of a simple pendulum increases, the motion of the pendulum is oscillatory but not simple harmonic.
Reason (R): For larger amplitude θ is large and then sin θ ≠ θ, so the motion is no longer SHM.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. The restoring torque is proportional to sin θ, not θ.
2. For large θ the motion is not SHM, as the reason states.

Teacher's Note:
1. SHM needs sin θ ≈ θ.

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