Practice MCQs for JEE Physics Nuclei
Access targeted multiple-choice questions for Nuclei designed to align with the latest JEE academic syllabus for JEE Physics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Access Nuclei Questions and Solutions
Access the complete set of multiple-choice questions for Nuclei below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) The energy released per unit mass is more in fusion than in fission, and that per atom is more in fission
(b) The energy released per unit mass is more in fission than in fusion
(c) The energy released per atom is more in fusion than in fission
(d) Both release the same energy per atom as well as per unit mass
Show Answer & Explanation
Answer: (a) The energy released per unit mass is more in fusion than in fission, and that per atom is more in fission
Explanation:
1. Fission of one uranium atom gives about 200 MeV, fusion of two deuterons about 24 MeV, so per atom fission gives more.
2. Per unit mass fusion gives more (for example about 3.5 MeV per nucleon in D-T fusion against about 0.85 MeV per nucleon in fission).
Teacher's Note:
1. H
2. e
3. a
4. v
5. y
6.
7. n
8. u
9. c
10. l
11. e
12. i
13.
14. h
15. a
16. v
17. e
18.
19. m
20. a
21. n
22. y
23.
24. n
25. u
26. c
27. l
28. e
29. o
30. n
31. s
32.
33. p
34. e
35. r
36.
37. e
38. v
39. e
40. n
41. t
42. ,
43.
44. l
45. i
46. g
47. h
48. t
49.
50. n
51. u
52. c
53. l
54. e
55. i
56.
57. h
58. a
59. v
60. e
61.
62. f
63. e
64. w
65. ,
66.
67. w
68. h
69. i
70. c
71. h
72.
73. r
74. e
75. v
76. e
77. r
78. s
79. e
80. s
81.
82. t
83. h
84. e
85.
86. c
87. o
88. m
89. p
90. a
91. r
92. i
93. s
94. o
95. n
96.
97. b
98. e
99. t
100. w
101. e
102. e
103. n
104.
105. p
106. e
107. r
108. -
109. a
110. t
111. o
112. m
113.
114. a
115. n
116. d
117.
118. p
119. e
120. r
121. -
122. m
123. a
124. s
125. s
126.
127. e
128. n
129. e
130. r
131. g
132. y
133. .
(a) \( 4\times10^{18}\ \mathrm{s^{-1}} \)
(b) \( \frac{125}{16}\times10^{18}\ \mathrm{s^{-1}} \)
(c) \( 8\times10^{23}\ \mathrm{s^{-1}} \)
(d) \( 8\times10^{19}\ \mathrm{s^{-1}} \)
Show Answer & Explanation
Answer: (b) \( \frac{125}{16}\times10^{18}\ \mathrm{s^{-1}} \)
Explanation:
1. Fissions per second \( =\frac{10^8}{200\times1.6\times10^{-13}}=3.125\times10^{18} \).
2. Neutrons per second \( =2.5\times3.125\times10^{18}=7.8\times10^{18}=\frac{125}{16}\times10^{18} \).
Teacher's Note:
1. D
2. i
3. v
4. i
5. d
6. e
7.
8. t
9. h
10. e
11.
12. p
13. o
14. w
15. e
16. r
17.
18. b
19. y
20.
21. t
22. h
23. e
24.
25. e
26. n
27. e
28. r
29. g
30. y
31.
32. p
33. e
34. r
35.
36. f
37. i
38. s
39. s
40. i
41. o
42. n
43.
44. t
45. o
46.
47. g
48. e
49. t
50.
51. t
52. h
53. e
54.
55. f
56. i
57. s
58. s
59. i
60. o
61. n
62.
63. r
64. a
65. t
66. e
67. ,
68.
69. t
70. h
71. e
72. n
73.
74. m
75. u
76. l
77. t
78. i
79. p
80. l
81. y
82.
83. b
84. y
85.
86. t
87. h
88. e
89.
90. n
91. e
92. u
93. t
94. r
95. o
96. n
97. s
98.
99. p
100. e
101. r
102.
103. f
104. i
105. s
106. s
107. i
108. o
109. n
110. .
(a) x + vt
(b) x - vt
(c) x
(d) It depends on the direction of the train
Show Answer & Explanation
Answer: (c) x
Explanation:
1. A train moving at uniform speed is an inertial frame, and the physics of the decay is the same in every inertial frame.
2. The relative velocity of the two fragments, as measured by the passenger, is unchanged, so the separation at time t is again x.
Teacher's Note:
1. R
2. e
3. l
4. a
5. t
6. i
7. v
8. e
9.
10. m
11. o
12. t
13. i
14. o
15. n
16.
17. b
18. e
19. t
20. w
21. e
22. e
23. n
24.
25. t
26. w
27. o
28.
29. o
30. b
31. j
32. e
33. c
34. t
35. s
36.
37. d
38. o
39. e
40. s
41.
42. n
43. o
44. t
45.
46. d
47. e
48. p
49. e
50. n
51. d
52.
53. o
54. n
55.
56. t
57. h
58. e
59.
60. u
61. n
62. i
63. f
64. o
65. r
66. m
67.
68. v
69. e
70. l
71. o
72. c
73. i
74. t
75. y
76.
77. o
78. f
79.
80. t
81. h
82. e
83.
84. o
85. b
86. s
87. e
88. r
89. v
90. e
91. r
92. .
(a) a parabola
(b) an ellipse
(c) a hyperbola
(d) a straight line
Show Answer & Explanation
Answer: (d) a straight line
Explanation:
1. From \( R=R_0A^{1/3} \) we get \( \ln\frac{R}{R_0}=\tfrac13\ln A \).
2. This has the form y = mx with slope 1/3, a straight line through the origin.
Teacher's Note:
1. T
2. a
3. k
4. i
5. n
6. g
7.
8. l
9. o
10. g
11. a
12. r
13. i
14. t
15. h
16. m
17. s
18.
19. t
20. u
21. r
22. n
23. s
24.
25. a
26.
27. p
28. o
29. w
30. e
31. r
32.
33. l
34. a
35. w
36.
37. i
38. n
39. t
40. o
41.
42. a
43.
44. l
45. i
46. n
47. e
48. a
49. r
50.
51. r
52. e
53. l
54. a
55. t
56. i
57. o
58. n
59. .
60.
61. T
62. h
63. e
64.
65. s
66. l
67. o
68. p
69. e
70.
71. o
72. f
73.
74. t
75. h
76. e
77.
78. l
79. i
80. n
81. e
82.
83. i
84. s
85.
86. t
87. h
88. e
89.
90. e
91. x
92. p
93. o
94. n
95. e
96. n
97. t
98. ,
99.
100. 1
101. /
102. 3
103. .
(a) 5.83 MeV
(b) 40.8 MeV
(c) 4.08 MeV
(d) 7.0 MeV
Show Answer & Explanation
Answer: (a) 5.83 MeV
Explanation:
1. Mass defect \( \Delta m=3(1.007826)+4(1.00867)-7.014353=0.043805 \) u.
2. Binding energy \( =0.043805\times931=40.8 \) MeV.
3. Per nucleon \( 40.8/7=5.83 \) MeV.
Teacher's Note:
1. U
2. s
3. i
4. n
5. g
6.
7. a
8. t
9. o
10. m
11. i
12. c
13.
14. m
15. a
16. s
17. s
18. e
19. s
20.
21. f
22. o
23. r
24.
25. h
26. y
27. d
28. r
29. o
30. g
31. e
32. n
33.
34. a
35. u
36. t
37. o
38. m
39. a
40. t
41. i
42. c
43. a
44. l
45. l
46. y
47.
48. a
49. c
50. c
51. o
52. u
53. n
54. t
55. s
56.
57. f
58. o
59. r
60.
61. t
62. h
63. e
64.
65. e
66. l
67. e
68. c
69. t
70. r
71. o
72. n
73. s
74.
75. o
76. f
77.
78. t
79. h
80. e
81.
82. l
83. i
84. t
85. h
86. i
87. u
88. m
89.
90. a
91. t
92. o
93. m
94. .
(a) \( {}^A_ZX+\gamma\to{}^A_{Z-1}X+a+b \)
(b) \( {}^A_Z X\to{}^A_ZX+f \) (a photon f is emitted)
(c) \( {}^A_ZX+{}^1_0n\to{}^{A-3}_{Z-2}X+c \)
(d) \( {}^A_ZX+e^-\to{}^A_{Z-1}X+g \)
Show Answer & Explanation
Answer: (b) \( {}^A_Z X\to{}^A_ZX+f \) (a photon f is emitted)
Explanation:
1. In gamma decay the nucleus drops from an excited level to a lower level: A and Z are unchanged and only a photon is emitted.
2. The other options change Z or A.
Teacher's Note:
1. O
2. n
3. l
4. y
5.
6. t
7. h
8. e
9.
10. o
11. p
12. t
13. i
14. o
15. n
16.
17. i
18. n
19.
20. w
21. h
22. i
23. c
24. h
25.
26. b
27. o
28. t
29. h
30.
31. A
32.
33. a
34. n
35. d
36.
37. Z
38.
39. a
40. r
41. e
42.
43. t
44. h
45. e
46.
47. s
48. a
49. m
50. e
51.
52. o
53. n
54.
55. t
56. h
57. e
58.
59. t
60. w
61. o
62.
63. s
64. i
65. d
66. e
67. s
68. ,
69.
70. w
71. i
72. t
73. h
74.
75. a
76.
77. p
78. h
79. o
80. t
81. o
82. n
83.
84. e
85. m
86. i
87. t
88. t
89. e
90. d
91. ,
92.
93. i
94. s
95.
96. g
97. a
98. m
99. m
100. a
101.
102. d
103. e
104. c
105. a
106. y
107. .
(a) The rate of decay of A will first increase and then decrease
(b) If \( \lambda_2>\lambda_1 \), the activity of B will always be higher than that of A
(c) The number of nuclei of B first increases and then decreases
(d) If \( \lambda_1\gg\lambda_2 \), the number of nuclei of C is always less than that of B
Show Answer & Explanation
Answer: (c) The number of nuclei of B first increases and then decreases
Explanation:
1. B is produced from A and itself decays: \( dN_2/dt=\lambda_1N_1-\lambda_2N_2 \) is positive at first and later negative, so N2 rises and then falls.
2. The decay rate of A, \( \lambda_1N_1 \), only decreases.
3. The other two statements are not true in general.
Teacher's Note:
1. A
2. n
3.
4. i
5. n
6. t
7. e
8. r
9. m
10. e
11. d
12. i
13. a
14. t
15. e
16.
17. s
18. p
19. e
20. c
21. i
22. e
23. s
24.
25. i
26. n
27.
28. a
29.
30. d
31. e
32. c
33. a
34. y
35.
36. c
37. h
38. a
39. i
40. n
41.
42. a
43. l
44. w
45. a
46. y
47. s
48.
49. r
50. i
51. s
52. e
53. s
54.
55. t
56. o
57.
58. a
59.
60. m
61. a
62. x
63. i
64. m
65. u
66. m
67.
68. a
69. n
70. d
71.
72. t
73. h
74. e
75. n
76.
77. f
78. a
79. l
80. l
81. s
82. .
(a) \( \frac{n}{N} \) s
(b) \( 1.44\frac{n}{N} \) s
(c) \( 0.69\frac{n}{N} \) s
(d) \( 0.69\frac{N}{n} \) s
Show Answer & Explanation
Answer: (d) \( 0.69\frac{N}{n} \) s
Explanation:
1. Activity \( n=\lambda N\Rightarrow\lambda=n/N \).
2. Half-life \( T=\frac{0.693}{\lambda}=0.693\frac{N}{n} \) s.
Teacher's Note:
1. A
2. c
3. t
4. i
5. v
6. i
7. t
8. y
9.
10. d
11. i
12. v
13. i
14. d
15. e
16. d
17.
18. b
19. y
20.
21. t
22. h
23. e
24.
25. n
26. u
27. m
28. b
29. e
30. r
31.
32. o
33. f
34.
35. a
36. t
37. o
38. m
39. s
40.
41. g
42. i
43. v
44. e
45. s
46.
47. t
48. h
49. e
50.
51. d
52. e
53. c
54. a
55. y
56.
57. c
58. o
59. n
60. s
61. t
62. a
63. n
64. t
65. .
(a) \( m\propto V \) (density is constant)
(b) \( m\propto 1/V \)
(c) \( m\propto\sqrt V \)
(d) \( m\propto V^2 \)
Show Answer & Explanation
Answer: (a) \( m\propto V \) (density is constant)
Explanation:
1. Nuclear matter has nearly the same density in all nuclei, \( \rho\approx 2.3\times10^{17}\ \mathrm{kg\,m^{-3}} \).
2. So \( m=\rho V \) and m is directly proportional to V.
Teacher's Note:
1. T
2. h
3. e
4.
5. n
6. u
7. c
8. l
9. e
10. a
11. r
12.
13. d
14. e
15. n
16. s
17. i
18. t
19. y
20.
21. i
22. s
23.
24. i
25. n
26. d
27. e
28. p
29. e
30. n
31. d
32. e
33. n
34. t
35.
36. o
37. f
38.
39. m
40. a
41. s
42. s
43.
44. n
45. u
46. m
47. b
48. e
49. r
50. .
51.
52. M
53. a
54. s
55. s
56.
57. i
58. s
59.
60. t
61. h
62. e
63. n
64.
65. s
66. i
67. m
68. p
69. l
70. y
71.
72. p
73. r
74. o
75. p
76. o
77. r
78. t
79. i
80. o
81. n
82. a
83. l
84.
85. t
86. o
87.
88. v
89. o
90. l
91. u
92. m
93. e
94. .
(a) \( 3.5\times10^{-8} \) J
(b) \( 7.4\times10^{-13} \) J
(c) \( 4.6\times10^{-12} \) J
(d) \( 6.0\times10^{-10} \) J
Show Answer & Explanation
Answer: (b) \( 7.4\times10^{-13} \) J
Explanation:
1. Mass defect \( =236.045562-232.038054-4.002603=0.004905 \) u.
2. Energy \( =0.004905\times1.5\times10^{-10}=7.4\times10^{-13} \) J.
Teacher's Note:
1. E
2. n
3. e
4. r
5. g
6. y
7.
8. r
9. e
10. l
11. e
12. a
13. s
14. e
15. d
16.
17. e
18. q
19. u
20. a
21. l
22. s
23.
24. t
25. h
26. e
27.
28. m
29. a
30. s
31. s
32.
33. d
34. e
35. f
36. e
37. c
38. t
39.
40. t
41. i
42. m
43. e
44. s
45.
46. t
47. h
48. e
49.
50. e
51. n
52. e
53. r
54. g
55. y
56.
57. e
58. q
59. u
60. i
61. v
62. a
63. l
64. e
65. n
66. t
67.
68. o
69. f
70.
71. o
72. n
73. e
74.
75. a
76. t
77. o
78. m
79. i
80. c
81.
82. m
83. a
84. s
85. s
86.
87. u
88. n
89. i
90. t
91. .
(a) \( T\ln\left(\frac{A_P}{A_Q}\right) \)
(b) \( \frac1T\ln\left(\frac{A_P}{A_Q}\right) \)
(c) \( T\ln\left(\frac{A_Q}{A_P}\right) \)
(d) \( T\left(\frac{A_P}{A_Q}\right) \)
Show Answer & Explanation
Answer: (c) \( T\ln\left(\frac{A_Q}{A_P}\right) \)
Explanation:
1. \( A_P=A_0e^{-t_P/T} \) and \( A_Q=A_0e^{-t_Q/T} \).
2. \( \frac{A_Q}{A_P}=e^{(t_P-t_Q)/T}\Rightarrow t_P-t_Q=T\ln\frac{A_Q}{A_P} \).
Teacher's Note:
1. T
2. a
3. k
4. e
5.
6. t
7. h
8. e
9.
10. r
11. a
12. t
13. i
14. o
15.
16. o
17. f
18.
19. t
20. h
21. e
22.
23. t
24. w
25. o
26.
27. e
28. x
29. p
30. o
31. n
32. e
33. n
34. t
35. i
36. a
37. l
38. s
39.
40. a
41. n
42. d
43.
44. s
45. o
46. l
47. v
48. e
49.
50. f
51. o
52. r
53.
54. t
55. h
56. e
57.
58. d
59. i
60. f
61. f
62. e
63. r
64. e
65. n
66. c
67. e
68.
69. i
70. n
71.
72. t
73. i
74. m
75. e
76. s
77. .
(a) 4
(b) 2
(c) 5
(d) 3
Show Answer & Explanation
Answer: (d) 3
Explanation:
1. Equal initial masses, so \( \frac{m_A}{m_B}=2^{-t/12+t/18} \).
2. \( \frac{0.53}{2.20}=2^{-t/36}\Rightarrow t=36\log_2\frac{2.20}{0.53}=36\times2.05=73.9\approx74 \) years.
3. So M = 7, n = 4 and M - n = 3.
Teacher's Note:
1. E
2. q
3. u
4. a
5. l
6.
7. i
8. n
9. i
10. t
11. i
12. a
13. l
14.
15. m
16. a
17. s
18. s
19. e
20. s
21.
22. m
23. e
24. a
25. n
26.
27. t
28. h
29. e
30.
31. r
32. a
33. t
34. i
35. o
36.
37. o
38. f
39.
40. f
41. i
42. n
43. a
44. l
45.
46. m
47. a
48. s
49. s
50. e
51. s
52.
53. d
54. e
55. p
56. e
57. n
58. d
59. s
60.
61. o
62. n
63. l
64. y
65.
66. o
67. n
68.
69. t
70. h
71. e
72.
73. d
74. i
75. f
76. f
77. e
78. r
79. e
80. n
81. c
82. e
83.
84. o
85. f
86.
87. t
88. h
89. e
90.
91. t
92. w
93. o
94.
95. d
96. e
97. c
98. a
99. y
100.
101. f
102. a
103. c
104. t
105. o
106. r
107. s
108. .
(a) 7
(b) 8
(c) 6
(d) 9
Show Answer & Explanation
Answer: (a) 7
Explanation:
1. Fraction reaching the receptor \( =\frac{10^{-4}}{4\pi(1)^2} \).
2. Counts \( =\lambda N_0\frac{10^{-4}}{4\pi}=5\times10^4\Rightarrow\lambda=\frac{4\pi\times5\times10^4}{3\times10^{16}\times10^{-4}}=2.1\times10^{-7}\ \mathrm{s^{-1}} \).
3. \( 3n\times10^{-(n+1)} \) equals \( 2.1\times10^{-7} \) for n = 7 (\( 21\times10^{-8} \)).
Teacher's Note:
1. T
2. h
3. e
4.
5. d
6. e
7. t
8. e
9. c
10. t
11. o
12. r
13.
14. s
15. u
16. b
17. t
18. e
19. n
20. d
21. s
22.
23. a
24.
25. f
26. r
27. a
28. c
29. t
30. i
31. o
32. n
33.
34. (
35. a
36. r
37. e
38. a
39.
40. d
41. i
42. v
43. i
44. d
45. e
46. d
47.
48. b
49. y
50.
51. 4
52.
53. p
54. i
55.
56. r
57.
58. s
59. q
60. u
61. a
62. r
63. e
64. d
65. )
66.
67. o
68. f
69.
70. t
71. h
72. e
73.
74. e
75. m
76. i
77. s
78. s
79. i
80. o
81. n
82. ,
83.
84. s
85. o
86.
87. t
88. h
89. e
90.
91. a
92. c
93. t
94. i
95. v
96. i
97. t
98. y
99.
100. i
101. s
102.
103. s
104. c
105. a
106. l
107. e
108. d
109.
110. b
111. y
112.
113. t
114. h
115. a
116. t
117.
118. f
119. r
120. a
121. c
122. t
123. i
124. o
125. n
126. .
(a) \( \frac{\tau}{C} \)
(b) \( \frac{2\tau}{C} \)
(c) \( \frac{\tau}{2C} \)
(d) \( \frac{3\tau}{2C} \)
Show Answer & Explanation
Answer: (b) \( \frac{2\tau}{C} \)
Explanation:
1. Energy stored \( U=U_0e^{-2t/RC} \) (charge falls as \( e^{-t/RC} \)); activity \( A=A_0e^{-t/\tau} \).
2. For U/A to be constant: \( \frac{2}{RC}=\frac1\tau\Rightarrow R=\frac{2\tau}{C} \).
Teacher's Note:
1. E
2. n
3. e
4. r
5. g
6. y
7.
8. g
9. o
10. e
11. s
12.
13. a
14. s
15.
16. t
17. h
18. e
19.
20. s
21. q
22. u
23. a
24. r
25. e
26.
27. o
28. f
29.
30. c
31. h
32. a
33. r
34. g
35. e
36. ,
37.
38. s
39. o
40.
41. i
42. t
43.
44. d
45. e
46. c
47. a
48. y
49. s
50.
51. t
52. w
53. i
54. c
55. e
56.
57. a
58. s
59.
60. f
61. a
62. s
63. t
64.
65. a
66. s
67.
68. t
69. h
70. e
71.
72. c
73. h
74. a
75. r
76. g
77. e
78.
79. d
80. o
81. e
82. s
83. .
(a) \( 2.5\times10^{16} \)
(b) \( 1.1\times10^{18} \)
(c) \( 1.1\times10^{15} \)
(d) \( 2.5\times10^{13} \)
Show Answer & Explanation
Answer: (c) \( 1.1\times10^{15} \)
Explanation:
1. Number of atoms \( N_0=\frac{10^{-6}}{24}\times6\times10^{23}=2.5\times10^{16} \).
2. Decayed in 1 h \( =N_0(1-0.955)=1.1\times10^{15} \).
Teacher's Note:
1. E
2. a
3. c
4. h
5.
6. d
7. e
8. c
9. a
10. y
11.
12. o
13. f
14.
15. s
16. o
17. d
18. i
19. u
20. m
21. -
22. 2
23. 4
24.
25. e
26. m
27. i
28. t
29. s
30.
31. o
32. n
33. e
34.
35. b
36. e
37. t
38. a
39.
40. p
41. a
42. r
43. t
44. i
45. c
46. l
47. e
48. ,
49.
50. s
51. o
52.
53. t
54. h
55. e
56.
57. n
58. u
59. m
60. b
61. e
62. r
63.
64. d
65. e
66. c
67. a
68. y
69. e
70. d
71.
72. e
73. q
74. u
75. a
76. l
77. s
78.
79. t
80. h
81. e
82.
83. n
84. u
85. m
86. b
87. e
88. r
89.
90. e
91. m
92. i
93. t
94. t
95. e
96. d
97. .
(a) B and D only
(b) A and D only
(c) B and C only
(d) A and C only
Show Answer & Explanation
Answer: (d) A and C only
Explanation:
1. After the alpha: mass number A - 4, charge Z - 2. After the beta-minus: mass number A - 4, charge Z - 1.
2. Neutrons \( =(A-4)-(Z-1)=A-Z-3 \).
3. So (A) and (C) are true, (B) and (D) are false.
Teacher's Note:
1. B
2. e
3. t
4. a
5. -
6. m
7. i
8. n
9. u
10. s
11.
12. r
13. a
14. i
15. s
16. e
17. s
18.
19. Z
20.
21. b
22. y
23.
24. o
25. n
26. e
27.
28. w
29. i
30. t
31. h
32. o
33. u
34. t
35.
36. c
37. h
38. a
39. n
40. g
41. i
42. n
43. g
44.
45. A
46. .
(a) 19%
(b) 38%
(c) 9%
(d) 62%
Show Answer & Explanation
Answer: (a) 19%
Explanation:
1. Fraction left after t is 0.9, so after 2t it is \( 0.9^2=0.81 \).
2. Disintegrated \( =1-0.81=0.19 \), i.e. 19 percent.
Teacher's Note:
1. F
2. r
3. a
4. c
5. t
6. i
7. o
8. n
9. s
10.
11. l
12. e
13. f
14. t
15.
16. m
17. u
18. l
19. t
20. i
21. p
22. l
23. y
24.
25. f
26. o
27. r
28.
29. s
30. u
31. c
32. c
33. e
34. s
35. s
36. i
37. v
38. e
39.
40. e
41. q
42. u
43. a
44. l
45.
46. i
47. n
48. t
49. e
50. r
51. v
52. a
53. l
54. s
55. .
(a) 10 g
(b) 2.5 g
(c) 7.5 g
(d) 5 g
Show Answer & Explanation
Answer: (b) 2.5 g
Explanation:
1. 540 days = 2 half-lives, so the cobalt left is \( 10\times\tfrac14=2.5 \) g.
2. The cobalt-57 is what remains; the beta particles and the daughter nuclei are not counted as cobalt.
Teacher's Note:
1. N
2. u
3. m
4. b
5. e
6. r
7.
8. o
9. f
10.
11. h
12. a
13. l
14. f
15. -
16. l
17. i
18. v
19. e
20. s
21.
22. =
23.
24. e
25. l
26. a
27. p
28. s
29. e
30. d
31.
32. t
33. i
34. m
35. e
36.
37. d
38. i
39. v
40. i
41. d
42. e
43. d
44.
45. b
46. y
47.
48. h
49. a
50. l
51. f
52. -
53. l
54. i
55. f
56. e
57. ;
58.
59. t
60. h
61. e
62.
63. a
64. m
65. o
66. u
67. n
68. t
69.
70. h
71. a
72. l
73. v
74. e
75. s
76.
77. e
78. a
79. c
80. h
81.
82. t
83. i
84. m
85. e
86. .
(a) both the isobars are stable
(b) Zn-64 is radioactive, decaying to Cu-64 through beta decay
(c) Cu-64 is radioactive, decaying to Zn-64 through beta decay
(d) Cu-64 is radioactive, decaying to Zn-64 through gamma decay
Show Answer & Explanation
Answer: (c) Cu-64 is radioactive, decaying to Zn-64 through beta decay
Explanation:
1. Cu-64 is heavier than Zn-64 by 0.0006 u, so it can decay to Zn-64.
2. Z increases from 29 to 30 at constant A: that is beta-minus decay.
Teacher's Note:
1. A
2.
3. n
4. u
5. c
6. l
7. e
8. u
9. s
10.
11. c
12. a
13. n
14.
15. d
16. e
17. c
18. a
19. y
20.
21. i
22. n
23. t
24. o
25.
26. a
27. n
28.
29. i
30. s
31. o
32. b
33. a
34. r
35.
36. o
37. n
38. l
39. y
40.
41. i
42. f
43.
44. t
45. h
46. e
47.
48. d
49. a
50. u
51. g
52. h
53. t
54. e
55. r
56.
57. h
58. a
59. s
60.
61. t
62. h
63. e
64.
65. l
66. o
67. w
68. e
69. r
70.
71. m
72. a
73. s
74. s
75. .
(a) \( 1.5\times10^{-4} \) g
(b) \( 2.9\times10^{-7} \) g
(c) \( 5.8\times10^{-4} \) g
(d) \( 2.9\times10^{-4} \) g
Show Answer & Explanation
Answer: (d) \( 2.9\times10^{-4} \) g
Explanation:
1. Q \( =(2\times2.014102-4.002603)\times931=23.8 \) MeV per fusion.
2. Required thermal power \( =50/0.3=167 \) MW, so fusions per second \( =\frac{1.67\times10^8}{23.8\times1.6\times10^{-13}}=4.4\times10^{19} \).
3. Each fusion uses 2 deuterons: mass \( =\frac{8.7\times10^{19}\times2.014}{6.02\times10^{23}}=2.9\times10^{-4} \) g/s.
Teacher's Note:
1. E
2. f
3. f
4. i
5. c
6. i
7. e
8. n
9. c
10. y
11.
12. r
13. a
14. i
15. s
16. e
17. s
18.
19. t
20. h
21. e
22.
23. r
24. e
25. q
26. u
27. i
28. r
29. e
30. d
31.
32. e
33. n
34. e
35. r
36. g
37. y
38.
39. i
40. n
41. p
42. u
43. t
44. :
45.
46. o
47. u
48. t
49. p
50. u
51. t
52.
53. d
54. i
55. v
56. i
57. d
58. e
59. d
60.
61. b
62. y
63.
64. e
65. f
66. f
67. i
68. c
69. i
70. e
71. n
72. c
73. y
74. .
(a) 0.1 g
(b) 0.01 g
(c) 1 g
(d) 10 g
Show Answer & Explanation
Answer: (a) 0.1 g
Explanation:
1. Reactions per day \( =\frac{10^6\times86400}{20\times1.6\times10^{-13}}=2.7\times10^{22} \).
2. Each reaction uses one deuteron: mass \( =\frac{2.7\times10^{22}\times2}{6.02\times10^{23}}\approx0.09 \) g, about 0.1 g.
Teacher's Note:
1. C
2. o
3. n
4. v
5. e
6. r
7. t
8.
9. p
10. o
11. w
12. e
13. r
14.
15. t
16. o
17.
18. r
19. e
20. a
21. c
22. t
23. i
24. o
25. n
26. s
27.
28. p
29. e
30. r
31.
32. s
33. e
34. c
35. o
36. n
37. d
38. ,
39.
40. t
41. h
42. e
43. n
44.
45. t
46. o
47.
48. n
49. u
50. m
51. b
52. e
53. r
54.
55. o
56. f
57.
58. d
59. e
60. u
61. t
62. e
63. r
64. i
65. u
66. m
67.
68. a
69. t
70. o
71. m
72. s
73. ,
74.
75. t
76. h
77. e
78. n
79.
80. t
81. o
82.
83. g
84. r
85. a
86. m
87. s
88.
89. u
90. s
91. i
92. n
93. g
94.
95. A
96. v
97. o
98. g
99. a
100. d
101. r
102. o
103. '
104. s
105.
106. n
107. u
108. m
109. b
110. e
111. r
112. .
(a) 1/2
(b) 2
(c) \( \frac{\ln 2}{2} \)
(d) This is never possible
Show Answer & Explanation
Answer: (b) 2
Explanation:
1. N2 is maximum when \( dN_2/dt=0 \).
2. \( \frac{dN_2}{dt}=\lambda N_1-2\lambda N_2=0\Rightarrow N_1=2N_2 \).
3. Hence \( N_1:N_2=2 \).
Teacher's Note:
1. A
2. t
3.
4. t
5. h
6. e
7.
8. m
9. a
10. x
11. i
12. m
13. u
14. m
15.
16. o
17. f
18.
19. t
20. h
21. e
22.
23. i
24. n
25. t
26. e
27. r
28. m
29. e
30. d
31. i
32. a
33. t
34. e
35.
36. s
37. p
38. e
39. c
40. i
41. e
42. s
43.
44. i
45. t
46. s
47.
48. p
49. r
50. o
51. d
52. u
53. c
54. t
55. i
56. o
57. n
58.
59. r
60. a
61. t
62. e
63.
64. e
65. q
66. u
67. a
68. l
69. s
70.
71. i
72. t
73. s
74.
75. d
76. e
77. c
78. a
79. y
80.
81. r
82. a
83. t
84. e
85. .
(a) 30 mm
(b) 2350 mm
(c) 60 mm
(d) 2380 mm
Show Answer & Explanation
Answer: (c) 60 mm
Explanation:
1. Radius \( r=\frac{mv}{qB}\propto m \) for the same q, v, B; so r for U-235 is 2350 mm and for U-238 is 2380 mm (taking mass numbers as the mass ratio to the proton).
2. After a semicircle the ions are at distance \( 2r \) from the entry slit, so the separation is \( 2(2380-2350)=60 \) mm.
Teacher's Note:
1. T
2. h
3. e
4.
5. i
6. o
7. n
8. s
9.
10. l
11. a
12. n
13. d
14.
15. a
16. t
17.
18. o
19. n
20. e
21.
22. d
23. i
24. a
25. m
26. e
27. t
28. e
29. r
30.
31. f
32. r
33. o
34. m
35.
36. t
37. h
38. e
39.
40. s
41. l
42. i
43. t
44. ,
45.
46. s
47. o
48.
49. t
50. h
51. e
52.
53. s
54. e
55. p
56. a
57. r
58. a
59. t
60. i
61. o
62. n
63.
64. i
65. s
66.
67. t
68. w
69. i
70. c
71. e
72.
73. t
74. h
75. e
76.
77. d
78. i
79. f
80. f
81. e
82. r
83. e
84. n
85. c
86. e
87.
88. i
89. n
90.
91. r
92. a
93. d
94. i
95. i
96. .
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