Multiple Choice Questions (MCQs) for JEE Physics: Mechanical Properties Of Solids
Review structured MCQ sets for JEE Physics Mechanical Properties Of Solids. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Practice Mechanical Properties Of Solids MCQs for JEE Physics
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Multiple Choice Questions
(a) 2 : 3
(b) 1 : 1
(c) 3 : 2
(d) 4 : 9
Show Answer & Explanation
Answer: (c) 3 : 2
Explanation:
1. Thermal stress \( =Y\alpha\Delta T \), so equal stress needs \( Y_1\alpha_1=Y_2\alpha_2 \).
2. \( \frac{Y_1}{Y_2}=\frac{\alpha_2}{\alpha_1}=\frac32 \).
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88. .
(a) \( r_1^2/r_2^2 \)
(b) \( r_2^3/r_1^3 \)
(c) \( r_2^4/r_1^4 \)
(d) \( r_1^4/r_2^4 \)
Show Answer & Explanation
Answer: (c) \( r_2^4/r_1^4 \)
Explanation:
1. Angle of twist \( \theta=\frac{2\tau l}{\pi\eta r^4}\propto\frac1{r^4} \).
2. \( \frac{\theta_A}{\theta_B}=\frac{r_2^4}{r_1^4} \).
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80. .
(a) increases
(b) decreases
(c) remains constant
(d) becomes zero
Show Answer & Explanation
Answer: (b) decreases
Explanation:
1. Hooke's law holds only up to the proportional limit.
2. Beyond it, the stress–strain curve bends and stress grows more slowly than strain, so the ratio decreases.
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55. .
(a) \( \frac{W_1}{s} \)
(b) \( \frac{W_1+W/4}{s} \)
(c) \( \frac{W_1+3W/4}{s} \)
(d) \( \frac{W_1+W}{s} \)
Show Answer & Explanation
Answer: (c) \( \frac{W_1+3W/4}{s} \)
Explanation:
1. The part of the wire below that point has length 3L/4 and weight 3W/4.
2. Tension there = W₁ + 3W/4, so the stress is (W₁ + 3W/4)/s.
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72. .
(a) \( \frac{YAx^2}{2L} \)
(b) \( \frac{YAx^2}{L} \)
(c) \( \frac{YAx}{2L} \)
(d) \( YAx^2L \)
Show Answer & Explanation
Answer: (a) \( \frac{YAx^2}{2L} \)
Explanation:
1. Force \( F=\frac{YA}{L}x \) increases linearly with extension.
2. Work \( =\int_0^xFdx=\frac{YAx^2}{2L} \).
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58. .
(a) 1.55 × 10⁵ Pa
(b) 0.015 × 10⁵ Pa
(c) 1.015 × 10⁵ Pa
(d) 1.55 × 10⁶ Pa
Show Answer & Explanation
Answer: (a) 1.55 × 10⁵ Pa
Explanation:
1. \( K=\frac{\Delta P}{\Delta V/V}=\frac{0.155\times10^5}{0.10} \).
2. K = 1.55 × 10⁵ Pa.
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81. .
(a) \( \frac{s^2}{2Y} \)
(b) \( 2s^2Y \)
(c) \( \frac{2Y}{s^2} \)
(d) \( \frac12Ys^2 \)
Show Answer & Explanation
Answer: (a) \( \frac{s^2}{2Y} \)
Explanation:
1. Energy density \( =\frac12\times\text{stress}\times\text{strain}=\frac12s\cdot\frac sY \).
2. \( =\frac{s^2}{2Y} \).
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22. .
(a) 3.28 cm²
(b) 2.38 cm²
(c) 0.328 cm²
(d) 8.23 cm²
Show Answer & Explanation
Answer: (a) 3.28 cm²
Explanation:
1. Maximum tension \( T=m(g+a)=2000\times11.5=23000 \) N.
2. \( A=\frac{T}{\text{stress}}=\frac{23000}{7\times10^7}=3.29\times10^{-4} \) m² ≈ 3.28 cm².
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58. .
(a) 10³ N
(b) 10⁴ N
(c) 10⁵ N
(d) 10⁹ N
Show Answer & Explanation
Answer: (b) 10⁴ N
Explanation:
1. \( F=YA\alpha\Delta T \).
2. \( =10^{11}\times10^{-4}\times10^{-5}\times100=10^4 \) N.
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(a) 1.32 × 10⁷ N/m²
(b) 1.10 × 10¹⁵ N/m²
(c) 1.32 × 10⁸ N/m²
(d) 1.10 × 10⁶ N/m²
Show Answer & Explanation
Answer: (a) 1.32 × 10⁷ N/m²
Explanation:
1. Stress \( =Y\alpha\Delta T \).
2. \( =1.2\times10^{11}\times1.1\times10^{-5}\times10=1.32\times10^7 \) N/m².
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67. .
(a) 6250 J
(b) 0.177 J
(c) 0.075 J
(d) 0.150 J
Show Answer & Explanation
Answer: (c) 0.075 J
Explanation:
1. Energy \( =\frac12Y(\text{strain})^2\times\text{volume} \), strain \( =\frac{10^{-3}}4=2.5\times10^{-4} \).
2. \( =\frac12\times2\times10^{11}\times6.25\times10^{-8}\times(3\times10^{-6}\times4)=0.075 \) J.
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52. .
(a) \( -1\ \text{to}\ \frac12 \)
(b) \( -\frac34\ \text{to}\ -\frac12 \)
(c) \( -\frac12\ \text{to}\ 1 \)
(d) 1 to 2
Show Answer & Explanation
Answer: (a) \( -1\ \text{to}\ \frac12 \)
Explanation:
1. Positive Young's and bulk moduli require −1 < σ < ½ theoretically.
2. Most real materials have values between 0 and 0.5.
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(a) 34 m
(b) 30 m
(c) 300 m
(d) 3 m
Show Answer & Explanation
Answer: (a) 34 m
Explanation:
1. Stress at the top \( =\rho Lg \).
2. \( L=\frac{10^6}{3\times10^3\times9.8}=34 \) m.
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52. .
(a) \( \frac{mg}{AK} \)
(b) \( \frac{mg}{3AK} \)
(c) \( \frac{mg}{A} \)
(d) \( \frac{3mg}{AK} \)
Show Answer & Explanation
Answer: (b) \( \frac{mg}{3AK} \)
Explanation:
1. Excess pressure \( =\frac{mg}{A} \), so \( \frac{\Delta V}V=\frac{mg}{AK} \).
2. \( V\propto R^3\Rightarrow\frac{\delta R}R=\frac13\frac{\Delta V}V=\frac{mg}{3AK} \).
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61. .
(a) A
(b) A and B
(c) B and C
(d) D
Show Answer & Explanation
Answer: (b) A and B
Explanation:
1. Stress = force/area: A gives 4F/A, B gives 4F/A, C gives 2F/A, D gives 1.67F/A.
2. The greatest stress is shared by A and B.
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45. .
(a) \( \theta/4 \)
(b) \( \theta/2 \)
(c) \( 5\theta/6 \)
(d) \( 8\theta/9 \)
Show Answer & Explanation
Answer: (d) \( 8\theta/9 \)
Explanation:
1. Same torque in both rods and twist \( \phi\propto\frac{L}{r^4} \). Large rod: \( \frac{l}{r^4} \); small rod: \( \frac{l/2}{(r/2)^4}=\frac{8l}{r^4} \).
2. The small rod twists 8 times as much as the large one: \( \phi_s=\frac89\theta \), which is the angle at the joint.
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64. .
(a) \( \frac13 \)
(b) \( \frac14 \)
(c) \( \frac43 \)
(d) \( \frac12 \)
Show Answer & Explanation
Answer: (d) \( \frac12 \)
Explanation:
1. Equal stress: \( \frac{T_1}{A_1}=\frac{T_2}{A_2} \).
2. \( \frac{T_1}{T_2}=\frac{A_1}{A_2}=\frac{0.1}{0.2}=\frac12 \).
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62. .
(a) l
(b) 2l
(c) \( \frac l2 \)
(d) \( \frac l4 \)
Show Answer & Explanation
Answer: (a) l
Explanation:
1. \( \Delta L=\frac{FL}{\pi r^2Y} \).
2. New: \( \frac{(2F)(2L)}{\pi(2r)^2Y}=\frac{4FL}{4\pi r^2Y}=l \).
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66. .
(a) a − b
(b) 5b − 4a
(c) \( 2b-\frac14a \)
(d) 4a − 3b
Show Answer & Explanation
Answer: (b) 5b − 4a
Explanation:
1. Extension is proportional to the extra tension: each extra newton adds \( (b-a) \) m.
2. Length at 9 N = a + 5(b − a) = 5b − 4a.
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(a) 1 and 2
(b) 2 and 3
(c) 3 and 4
(d) 1 and 4
Show Answer & Explanation
Answer: (b) 2 and 3
Explanation:
1. Strain \( =\alpha\Delta T \) and stress \( =Y\alpha\Delta T \) are the same for all rods (1 and 4 false).
2. Force \( =\text{stress}\times\pi r^2 \) and stored energy \( =\frac12\text{stress}\times\text{strain}\times\text{volume} \) are proportional to \( r^2 \), that is 1 : 2 : 3 : 4 (2 and 3 true).
Teacher's Note:
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(a) 1 and 2
(b) 3 and 4
(c) 1 and 4
(d) 2 and 3
Show Answer & Explanation
Answer: (a) 1 and 2
Explanation:
1. Top part is stretched/compressed by \( x \): its reaction \( R_1 \) and the bottom reaction \( R_2 \) satisfy \( R_1+R_2=W \) and equal deformation: \( \frac{R_1(2l)}{AY}=\frac{R_2(3l)}{AY} \).
2. \( R_1:R_2=3:2 \), so \( R_1=3000 \) N and \( R_2=2000 \) N.
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(a) 1, 2 and 3
(b) 1, 3 and 4
(c) 2 and 4
(d) 1 and 2
Show Answer & Explanation
Answer: (b) 1, 3 and 4
Explanation:
1. The mass falls through l, losing \( Mgl \) of PE (1 true).
2. The wire stores \( \frac12Mgl \) (3 true, 2 false); the remaining \( \frac12Mgl \) is dissipated as heat when the mass oscillates and settles (4 true).
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(a) 1, 2 and 3
(b) 1, 2 and 4
(c) 2 and 3
(d) 3 and 4
Show Answer & Explanation
Answer: (b) 1, 2 and 4
Explanation:
1. Strain = Δl/l = 1 (1 true), so stress = Y × 1 = Y (2 true).
2. Energy density \( =\frac12Y\times1^2 \), so Y = 2u (4 true). The radius falls by a factor √2 (volume conserved), not 2 (3 false).
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41. .
(a) 0.05 cm
(b) 0.5 cm
(c) 5 cm
(d) 50 cm
Show Answer & Explanation
Answer: (c) 5 cm
Explanation:
1. Force constant \( k=\frac{YA}{L}=\frac{2\times10^5\times10^{-3}}{1}=200 \) N/m.
2. Extension \( =\frac{mg}{k}=\frac{10}{200}=0.05 \) m = 5 cm.
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61. .
(a) \( \pi\eta lv_0 \)
(b) \( 2\pi\eta lv_0 \)
(c) \( 4\pi\eta lv_0 \)
(d) \( 6\pi\eta lv_0 \)
Show Answer & Explanation
Answer: (c) \( 4\pi\eta lv_0 \)
Explanation:
1. At the wall \( \left|\frac{dv}{dr}\right|=\frac{2v_0}{R} \).
2. Force \( =\eta(2\pi Rl)\frac{2v_0}R=4\pi\eta lv_0 \).
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(a) \( \rho\pi R^2lv_0 \)
(b) \( \rho\pi R^2lv_0/2 \)
(c) \( 2\rho\pi R^2lv_0 \)
(d) \( \rho\pi R^2lv_0/4 \)
Show Answer & Explanation
Answer: (b) \( \rho\pi R^2lv_0/2 \)
Explanation:
1. Momentum \( =\int\rho v\,dV=\rho v_0\int_0^R\left(1-\frac{r^2}{R^2}\right)2\pi rl\,dr \).
2. \( =\rho v_0\,2\pi l\left(\frac{R^2}2-\frac{R^2}4\right)=\frac{\rho\pi R^2lv_0}{2} \).
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Assertion (A): Steel is more elastic than rubber.
Reason (R): Under a given deforming force, steel is deformed less than rubber.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. Elasticity is the ability to resist deformation and regain shape; steel has the much larger Young's modulus: assertion true.
2. Statement 2 is a true observation, but 'deformed less' only restates the larger modulus rather than explaining why elasticity is greater.
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Assertion (A): Bridges are declared unsafe after a long use.
Reason (R): The elastic strength of bridges decreases with time.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Repeated loading causes elastic fatigue, so the elastic strength falls with time.
2. Hence old bridges are declared unsafe.
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Assertion (A): Wet clay does not regain its shape.
Reason (R): Young's modulus for a perfectly plastic body is zero.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Clay is nearly perfectly plastic and does not recover after deformation.
2. A perfectly plastic body has no restoring force, so its Young's modulus is zero.
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