Multiple Choice Questions (MCQs) for JEE Physics: Electromagnetic Waves
Explore reliable objective questions for Electromagnetic Waves tailored for JEE learners. Utilizing these Physics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Practice Electromagnetic Waves MCQs for JEE Physics
Access the complete set of multiple-choice questions for Electromagnetic Waves below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) polarization
(b) interference
(c) reflection
(d) diffraction
Show Answer & Explanation
Answer: (a) polarization
Explanation:
1. Only transverse waves can be polarized.
2. Interference, reflection and diffraction are shown by all waves, longitudinal as well as transverse.
Teacher's Note:
1. P
2. o
3. l
4. a
5. r
6. i
7. z
8. a
9. t
10. i
11. o
12. n
13.
14. i
15. s
16.
17. t
18. h
19. e
20.
21. s
22. t
23. a
24. n
25. d
26. a
27. r
28. d
29.
30. p
31. r
32. o
33. o
34. f
35.
36. o
37. f
38.
39. t
40. r
41. a
42. n
43. s
44. v
45. e
46. r
47. s
48. e
49.
50. n
51. a
52. t
53. u
54. r
55. e
56. .
57.
58. R
59. e
60. m
61. e
62. m
63. b
64. e
65. r
66.
67. t
68. h
69. a
70. t
71.
72. s
73. o
74. u
75. n
76. d
77.
78. s
79. h
80. o
81. w
82. s
83.
84. n
85. o
86.
87. p
88. o
89. l
90. a
91. r
92. i
93. z
94. a
95. t
96. i
97. o
98. n
99. .
(a) increase
(b) decrease
(c) remain unchanged
(d) become infinite
Show Answer & Explanation
Answer: (b) decrease
Explanation:
1. Current through a capacitor is \( I = \dfrac{E}{X_C} = \omega C E = 2\pi\nu C E \), so \( I \propto \nu \).
2. Displacement current equals conduction current in the circuit, so it decreases when the frequency decreases.
Teacher's Note:
1. T
2. h
3. e
4.
5. r
6. e
7. a
8. c
9. t
10. a
11. n
12. c
13. e
14.
15. o
16. f
17.
18. a
19.
20. c
21. a
22. p
23. a
24. c
25. i
26. t
27. o
28. r
29.
30. i
31. s
32.
33. i
34. n
35. v
36. e
37. r
38. s
39. e
40. l
41. y
42.
43. p
44. r
45. o
46. p
47. o
48. r
49. t
50. i
51. o
52. n
53. a
54. l
55.
56. t
57. o
58.
59. f
60. r
61. e
62. q
63. u
64. e
65. n
66. c
67. y
68. .
69.
70. L
71. o
72. w
73. e
74. r
75.
76. f
77. r
78. e
79. q
80. u
81. e
82. n
83. c
84. y
85.
86. m
87. e
88. a
89. n
90. s
91.
92. h
93. i
94. g
95. h
96. e
97. r
98.
99. r
100. e
101. a
102. c
103. t
104. a
105. n
106. c
107. e
108.
109. a
110. n
111. d
112.
113. s
114. m
115. a
116. l
117. l
118. e
119. r
120.
121. c
122. u
123. r
124. r
125. e
126. n
127. t
128. .
(a) Hertz
(b) Maxwell
(c) Faraday
(d) Marconi
Show Answer & Explanation
Answer: (b) Maxwell
Explanation:
1. James Clerk Maxwell introduced the displacement current to make Ampere's circuital law consistent for a charging capacitor.
Teacher's Note:
1. M
2. a
3. x
4. w
5. e
6. l
7. l
8. '
9. s
10.
11. d
12. i
13. s
14. p
15. l
16. a
17. c
18. e
19. m
20. e
21. n
22. t
23.
24. c
25. u
26. r
27. r
28. e
29. n
30. t
31.
32. l
33. e
34. d
35.
36. t
37. o
38.
39. t
40. h
41. e
42.
43. p
44. r
45. e
46. d
47. i
48. c
49. t
50. i
51. o
52. n
53.
54. o
55. f
56.
57. e
58. l
59. e
60. c
61. t
62. r
63. o
64. m
65. a
66. g
67. n
68. e
69. t
70. i
71. c
72.
73. w
74. a
75. v
76. e
77. s
78. .
79.
80. H
81. e
82. r
83. t
84. z
85.
86. l
87. a
88. t
89. e
90. r
91.
92. p
93. r
94. o
95. d
96. u
97. c
98. e
99. d
100.
101. t
102. h
103. e
104. m
105.
106. i
107. n
108.
109. t
110. h
111. e
112.
113. l
114. a
115. b
116. o
117. r
118. a
119. t
120. o
121. r
122. y
123. .
(a) \( \sqrt{\mu\varepsilon} \)
(b) \( \dfrac{1}{\sqrt{\mu\varepsilon}} \)
(c) \( \dfrac{1}{\mu\varepsilon} \)
(d) \( \sqrt{\dfrac{\mu}{\varepsilon}} \)
Show Answer & Explanation
Answer: (b) \( \dfrac{1}{\sqrt{\mu\varepsilon}} \)
Explanation:
1. In vacuum \( c = \dfrac{1}{\sqrt{\mu_0\varepsilon_0}} \).
2. In a medium the same relation holds with \( \mu \) and \( \varepsilon \): \( v = \dfrac{1}{\sqrt{\mu\varepsilon}} \).
Teacher's Note:
1. S
2. i
3. n
4. c
5. e
6.
7. \
8. (
9.
10. \
11. m
12. u
13.
14. \
15. )
16.
17. a
18. n
19. d
20.
21. \
22. (
23.
24. \
25. v
26. a
27. r
28. e
29. p
30. s
31. i
32. l
33. o
34. n
35.
36. \
37. )
38.
39. o
40. f
41.
42. a
43.
44. m
45. e
46. d
47. i
48. u
49. m
50.
51. a
52. r
53. e
54.
55. l
56. a
57. r
58. g
59. e
60. r
61.
62. t
63. h
64. a
65. n
66.
67. t
68. h
69. o
70. s
71. e
72.
73. o
74. f
75.
76. v
77. a
78. c
79. u
80. u
81. m
82. ,
83.
84. t
85. h
86. e
87.
88. s
89. p
90. e
91. e
92. d
93.
94. i
95. n
96.
97. a
98.
99. m
100. e
101. d
102. i
103. u
104. m
105.
106. i
107. s
108.
109. l
110. e
111. s
112. s
113.
114. t
115. h
116. a
117. n
118.
119. c
120. .
(a) ultraviolet rays
(b) infrared rays
(c) X-rays
(d) radio waves
Show Answer & Explanation
Answer: (b) infrared rays
Explanation:
1. The Earth re-radiates absorbed sunlight as infrared radiation.
2. Greenhouse gases such as carbon dioxide and water vapour trap this infrared radiation and warm the surroundings.
Teacher's Note:
1. I
2. n
3. f
4. r
5. a
6. r
7. e
8. d
9.
10. r
11. a
12. d
13. i
14. a
15. t
16. i
17. o
18. n
19.
20. i
21. s
22.
23. o
24. f
25. t
26. e
27. n
28.
29. c
30. a
31. l
32. l
33. e
34. d
35.
36. h
37. e
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39. t
40.
41. r
42. a
43. d
44. i
45. a
46. t
47. i
48. o
49. n
50. .
51.
52. I
53. t
54.
55. i
56. s
57.
58. t
59. r
60. a
61. p
62. p
63. e
64. d
65.
66. b
67. y
68.
69. g
70. r
71. e
72. e
73. n
74. h
75. o
76. u
77. s
78. e
79.
80. g
81. a
82. s
83. e
84. s
85. .
(a) ultraviolet rays
(b) infrared rays
(c) gamma rays
(d) radio waves
Show Answer & Explanation
Answer: (b) infrared rays
Explanation:
1. Infrared radiation passes through haze and fog much better than visible light.
2. So infrared-sensitive films can photograph objects that are not clearly visible, for example in fog or darkness.
Teacher's Note:
1. I
2. n
3. f
4. r
5. a
6. r
7. e
8. d
9.
10. p
11. h
12. o
13. t
14. o
15. g
16. r
17. a
18. p
19. h
20. y
21.
22. i
23. s
24.
25. u
26. s
27. e
28. d
29.
30. i
31. n
32.
33. r
34. e
35. m
36. o
37. t
38. e
39.
40. s
41. e
42. n
43. s
44. i
45. n
46. g
47.
48. a
49. n
50. d
51.
52. i
53. n
54.
55. n
56. i
57. g
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59. t
60.
61. p
62. h
63. o
64. t
65. o
66. g
67. r
68. a
69. p
70. h
71. y
72. .
(a) Displacement current comes into play in a region where the electric field changes with time
(b) Beta rays are electromagnetic waves
(c) Energy stored in electromagnetic oscillations is in the form of electric energy only
(d) Doubling the amplitude of an electromagnetic wave in vacuum changes its speed
Show Answer & Explanation
Answer: (a) Displacement current comes into play in a region where the electric field changes with time
Explanation:
1. Displacement current is \( I_D = \varepsilon_0 \dfrac{d\phi_E}{dt} \), so it exists only when the electric flux changes.
2. Beta rays are fast electrons, not electromagnetic waves.
3. The energy is shared between electric and magnetic fields.
4. The speed \( c = 1/\sqrt{\mu_0\varepsilon_0} \) does not depend on amplitude.
Teacher's Note:
1. C
2. h
3. e
4. c
5. k
6.
7. e
8. a
9. c
10. h
11.
12. s
13. t
14. a
15. t
16. e
17. m
18. e
19. n
20. t
21.
22. a
23. g
24. a
25. i
26. n
27. s
28. t
29.
30. i
31. t
32. s
33.
34. d
35. e
36. f
37. i
38. n
39. i
40. t
41. i
42. o
43. n
44. .
45.
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47. e
48. t
49. a
50.
51. r
52. a
53. y
54. s
55.
56. a
57. r
58. e
59.
60. p
61. a
62. r
63. t
64. i
65. c
66. l
67. e
68. s
69. ,
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72. o
73.
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75. h
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80. r
81. e
82.
83. n
84. o
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100. l
101. e
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104. r
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108. g
109. n
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112. i
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116. p
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120. r
121. u
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123. .
(a) The frequency of microwaves is greater than that of ultraviolet rays
(b) Gamma rays have the shortest wavelength in the electromagnetic spectrum
(c) Radiation pressure on a fully absorbing surface is \( 2I/c \)
(d) The speed of an electromagnetic wave in vacuum depends on its amplitude
Show Answer & Explanation
Answer: (b) Gamma rays have the shortest wavelength in the electromagnetic spectrum
Explanation:
1. Wavelength order: radio, microwave, infrared, visible, ultraviolet, X-rays, gamma rays, so gamma rays have the shortest wavelength.
2. Microwaves have lower frequency than ultraviolet rays.
3. Radiation pressure is \( I/c \) for total absorption.
4. Speed in vacuum is the constant c.
Teacher's Note:
1. L
2. e
3. a
4. r
5. n
6.
7. t
8. h
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10.
11. s
12. p
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70. I
71. V
72. U
73. X
74. G
75.
76. h
77. e
78. l
79. p
80. s
81. .
(a) \( I/c \)
(b) \( 2I/c \)
(c) \( Ic \)
(d) \( I/c^2 \)
Show Answer & Explanation
Answer: (a) \( I/c \)
Explanation:
1. Momentum delivered per unit time per unit area equals \( I/c \) when the wave is fully absorbed.
2. If it is totally reflected the momentum change doubles, giving \( 2I/c \).
Teacher's Note:
1. R
2. a
3. d
4. i
5. a
6. t
7. i
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10.
11. p
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60. o
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65. u
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67. .
(a) microwaves
(b) ultraviolet rays
(c) gamma rays
(d) radio waves
Show Answer & Explanation
Answer: (b) ultraviolet rays
Explanation:
1. Ultraviolet radiation kills bacteria and is used to sterilize food and water.
Teacher's Note:
1. U
2. V
3.
4. r
5. a
6. y
7. s
8.
9. a
10. r
11. e
12.
13. g
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69. .
(a) \( 2\ \text{m}^{-1} \)
(b) \( 0.5\ \text{m}^{-1} \)
(c) \( 6\ \text{m}^{-1} \)
(d) \( 3\ \text{m}^{-1} \)
Show Answer & Explanation
Answer: (a) \( 2\ \text{m}^{-1} \)
Explanation:
1. Comparing with \( \cos(kz - \omega t) \), \( \omega = 6\times10^{8} \) rad/s.
2. \( k = \dfrac{\omega}{c} = \dfrac{6\times10^{8}}{3\times10^{8}} = 2\ \text{m}^{-1} \).
Teacher's Note:
1. U
2. s
3. e
4.
5. \
6. (
7.
8. k
9.
10. =
11.
12. \
13. o
14. m
15. e
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17. a
18. /
19. c
20.
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22. )
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36.
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46. e
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49.
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51. (
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53. \
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57. g
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61. )
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89. .
(a) a neutron moving in a straight line with constant speed
(b) a proton moving in a straight line with constant speed
(c) an electron oscillating about a mean position
(d) a stationary charged particle
Show Answer & Explanation
Answer: (c) an electron oscillating about a mean position
Explanation:
1. Electromagnetic waves are produced only by accelerated charges.
2. An oscillating electron is continuously accelerated, so it radiates; the other three have zero acceleration or no charge.
Teacher's Note:
1. R
2. e
3. m
4. e
5. m
6. b
7. e
8. r
9.
10. t
11. h
12. a
13. t
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16. n
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81. .
(a) \( \dfrac{c\mu_0B_0^2}{2} \)
(b) \( \dfrac{c\varepsilon_0B_0^2}{2} \)
(c) \( \dfrac{cB_0^2}{2\mu_0} \)
(d) \( \dfrac{E_0^2}{2c\varepsilon_0} \)
Show Answer & Explanation
Answer: (c) \( \dfrac{cB_0^2}{2\mu_0} \)
Explanation:
1. \( I = \dfrac{1}{2}\varepsilon_0E_0^2c \) and \( E_0 = cB_0 \).
2. So \( I = \dfrac{1}{2}\varepsilon_0c^3B_0^2 \). Using \( \varepsilon_0c^2 = 1/\mu_0 \), \( I = \dfrac{cB_0^2}{2\mu_0} \).
Teacher's Note:
1. I
2. n
3. t
4. e
5. n
6. s
7. i
8. t
9. y
10.
11. e
12. q
13. u
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27. g
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30. e
31. n
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63. e
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71.
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73. n
74. d
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77.
78. w
79. i
80. t
81. h
82.
83. \
84. (
85.
86. E
87. _
88. 0
89.
90. =
91.
92. c
93. B
94. _
95. 0
96.
97. \
98. )
99. .
(a) E = constant, B = constant
(b) \( E \propto \dfrac{1}{r},\ B \propto \dfrac{1}{r} \)
(c) \( E \propto \dfrac{1}{r^2},\ B \propto \dfrac{1}{r^2} \)
(d) \( E \propto \dfrac{1}{r^3},\ B \propto \dfrac{1}{r^3} \)
Show Answer & Explanation
Answer: (b) \( E \propto \dfrac{1}{r},\ B \propto \dfrac{1}{r} \)
Explanation:
1. Intensity falls as \( 1/r^2 \) because the energy spreads over a sphere of area \( 4\pi r^2 \).
2. Intensity is proportional to \( E_0^2 \) (and \( B_0^2 \)), so the amplitudes fall as \( 1/r \).
Teacher's Note:
1. I
2. n
3. t
4. e
5. n
6. s
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(a) Maxwell
(b) Hertz
(c) Bose
(d) Marconi
Show Answer & Explanation
Answer: (a) Maxwell
Explanation:
1. Maxwell predicted electromagnetic waves from his equations; Hertz detected them experimentally.
Teacher's Note:
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65. .
(a) \( B_z = \dfrac{60}{c}\sin(kz + \omega t)\ \text{T} \)
(b) \( B_z = \dfrac{60}{c}\sin(kx + \omega t)\ \text{T} \)
(c) \( B_y = \dfrac{60}{c}\sin(ky + \omega t)\ \text{T} \)
(d) \( B_y = \dfrac{60}{c}\sin(kx + \omega t)\ \text{T} \)
Show Answer & Explanation
Answer: (d) \( B_y = \dfrac{60}{c}\sin(kx + \omega t)\ \text{T} \)
Explanation:
1. The phase \( kx + \omega t \) means the wave travels along \( -x \), with E along z.
2. B must be perpendicular to both E and the direction of travel, so it is along y.
3. Amplitude is \( B_0 = E_0/c = 60/c \), and B has the same phase as E. Hence \( B_y = \dfrac{60}{c}\sin(kx+\omega t) \).
Teacher's Note:
1. E
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128. .
(a) 36.6 m
(b) 40.5 m
(c) 42.3 m
(d) 50.9 m
Show Answer & Explanation
Answer: (a) 36.6 m
Explanation:
1. \( \lambda = \dfrac{c}{\nu} = \dfrac{3\times10^{8}}{8.2\times10^{6}} = 36.6 \) m.
Teacher's Note:
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55. .
(a) The radiation lies in the ultraviolet region and hence is not visible
(b) The radiation lies in the infrared region
(c) The radiation is emitted only during the day
(d) The radiation is emitted during summers and absorbed during winters
Show Answer & Explanation
Answer: (b) The radiation lies in the infrared region
Explanation:
1. The human body is at about 310 K.
2. By Wien's law the peak wavelength is of the order of 10 micrometres, which lies in the infrared region. The body radiates all the time.
Teacher's Note:
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(a) \( 10^{15} \) Hz
(b) \( 10^{14} \) Hz
(c) \( 10^{13} \) Hz
(d) \( 10^{12} \) Hz
Show Answer & Explanation
Answer: (b) \( 10^{14} \) Hz
Explanation:
1. To observe a particle the wavelength must be comparable to its size. Diameter \( = 6\times10^{-4} \) cm \( = 6\times10^{-6} \) m.
2. \( \nu = \dfrac{c}{\lambda} = \dfrac{3\times10^{8}}{6\times10^{-6}} = 5\times10^{13} \) Hz, which is of the order of \( 10^{14} \) Hz.
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(a) the speed of light in vacuum
(b) the reciprocal of the speed of light in vacuum
(c) the ratio of magnetic permeability to electric susceptibility of vacuum
(d) unity
Show Answer & Explanation
Answer: (b) the reciprocal of the speed of light in vacuum
Explanation:
1. \( \dfrac{E_0}{B_0} = c \), so \( \dfrac{B_0}{E_0} = \dfrac{1}{c} \).
Teacher's Note:
1. R
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61. .
(a) \( 2.7\times10^{12} \) T
(b) \( 9.0\times10^{-3} \) T
(c) \( 3.0\times10^{-4} \) T
(d) \( 3.0\times10^{-5} \) T
Show Answer & Explanation
Answer: (d) \( 3.0\times10^{-5} \) T
Explanation:
1. \( B_0 = \dfrac{E_0}{c} = \dfrac{9\times10^{3}}{3\times10^{8}} = 3\times10^{-5} \) T.
Teacher's Note:
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(a) Cosmic rays
(b) Gamma rays
(c) Beta rays
(d) X-rays
Show Answer & Explanation
Answer: (c) Beta rays
Explanation:
1. Gamma rays and X-rays are electromagnetic radiation.
2. Beta rays are streams of fast-moving electrons, which are particles, so they are not electromagnetic waves.
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