Multiple Choice Questions (MCQs) for JEE Physics: Electromagnetic Induction
Review structured MCQ sets for JEE Physics Electromagnetic Induction. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
Practice Electromagnetic Induction MCQs for JEE Physics
Access the complete set of multiple-choice questions for Electromagnetic Induction below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) N⁰
(b) N
(c) N²
(d) N⁻²
Show Answer & Explanation
Answer: (c) N²
Explanation:
1. L = μ₀ N² A/l, so L is proportional to N².
Teacher's Note:
1. Recall the basic law.
Assertion (A): In mutual induction, the self induction of each of the coils persists.
Reason (R): Self induction arises due to the change in current in the coil itself. In mutual induction the current changes in both coils.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. Each coil has a changing current, so each has self induction as well as mutual induction.
2. The reason correctly explains this.
Teacher's Note:
1. Both effects occur together.
Assertion (A): An induced current has a direction such that the magnetic field due to the current opposes the change in the magnetic flux that induces the current.
Reason (R): The above statement is in accordance with the conservation of energy.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. This is Lenz's law, and it follows from conservation of energy: if the induced current aided the change it would create energy from nothing.
Teacher's Note:
1. Lenz's law is energy conservation.
(a) change of flux
(b) time
(c) resistance of the coil
(d) none of these
Show Answer & Explanation
Answer: (b) time
Explanation:
1. q = Δφ/R depends on the flux change and the resistance but not on the time taken.
Teacher's Note:
1. Recall the basic law.
(a) 484 W
(b) 400 W
(c) 441 W
(d) 369 W
Show Answer & Explanation
Answer: (b) 400 W
Explanation:
1. I = 220/(10 + 100) = 2 A.
2. P = I²R = 4 × 100 = 400 W.
Teacher's Note:
1. Recall the basic law.
(a) a metal is kept in a varying magnetic field
(b) a metal is kept in a steady magnetic field
(c) a circular coil is placed in a magnetic field
(d) through a circular coil, current is passed
Show Answer & Explanation
Answer: (a) a metal is kept in a varying magnetic field
Explanation:
1. A changing flux induces circulating currents in the bulk of a metal.
Teacher's Note:
1. Recall the basic law.
(a) 0.1 henry
(b) 0.2 henry
(c) 0.4 henry
(d) 0.8 henry
Show Answer & Explanation
Answer: (b) 0.2 henry
Explanation:
1. L = e/(ΔI/Δt) = 8/(2/0.05) = 0.2 H.
Teacher's Note:
1. Recall the basic law.
Assertion (A): An emf can be induced by moving a conductor in a magnetic field.
Reason (R): An emf can be induced by changing the magnetic field.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (b) Both A and R are true, but R is not the correct explanation of A.
Explanation:
1. Both statements are true: motional emf and induced emf due to a changing field.
2. The second is not the explanation of the first, since in a moving conductor the field itself does not change.
Teacher's Note:
1. Two different ways to change flux.
(a) weber/ampere
(b) volt second/ampere
(c) joule/ampere²
(d) all of the above
Show Answer & Explanation
Answer: (d) all of the above
Explanation:
1. L = φ/I = (e t)/I = 2U/I², so Wb/A, V s/A and J/A² are all equal to henry.
Teacher's Note:
1. Recall the basic law.
(a) \( B\omega l^2 \)
(b) \( \tfrac12B\omega l^2 \)
(c) \( 2B\omega l^2 \)
(d) \( \tfrac14B\omega l^2 \)
Show Answer & Explanation
Answer: (b) \( \tfrac12B\omega l^2 \)
Explanation:
1. emf = ∫ B ω r dr from 0 to l = (1/2) B ω l².
Teacher's Note:
1. Recall the basic law.
(a) \( \frac{(B\pi r\omega)^2}{2R} \)
(b) \( \frac{(B\pi r^2\omega)^2}{2R} \)
(c) \( \frac{B\pi r^2\omega}{2R} \)
(d) \( \frac{(B\pi r^2\omega)^2}{8R} \)
Show Answer & Explanation
Answer: (d) \( \frac{(B\pi r^2\omega)^2}{8R} \)
Explanation:
1. The area is πr²/2, so e = (Bπr²ω/2) sin(ωt).
2. Mean power = e_0²/(2R) = (Bπr²ω)²/(8R).
Teacher's Note:
1. Recall the basic law.
(a) electric power meters
(b) induction furnace
(c) LED lights
(d) magnetic brakes in trains
Show Answer & Explanation
Answer: (c) LED lights
Explanation:
1. LED lights work on semiconductor electroluminescence.
2. The others use eddy currents.
Teacher's Note:
1. Recall the basic law.
(a) 45°
(b) 0°
(c) 180°
(d) 90°
Show Answer & Explanation
Answer: (d) 90°
Explanation:
1. Eddy currents flow in planes perpendicular to the magnetic field.
Teacher's Note:
1. Recall the basic law.
Assertion (A): An induced emf appears in any coil in which the current is changing.
Reason (R): Self induction obeys Faraday's law of induction.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. A changing current changes the flux through the coil itself, and by Faraday's law this induces an emf.
2. The reason therefore explains the assertion.
Teacher's Note:
1. Self induction follows from Faraday's law.
(a) 3A0B0/t
(b) 4A0B0/t
(c) 3B0/(A0 t)
(d) 4A0/(B0 t)
Show Answer & Explanation
Answer: (a) 3A0B0/t
Explanation:
1. emf = ΔΦ/t = A0(4B0 - B0)/t = 3A0B0/t.
Teacher's Note:
1. Recall the basic law.
(a) mutual induction
(b) self induction
(c) eddy currents
(d) hysteresis
Show Answer & Explanation
Answer: (b) self induction
Explanation:
1. This is self induction.
Teacher's Note:
1. Recall the basic law.
(a) zero
(b) 0.5 V
(c) 1 V
(d) 2 V
Show Answer & Explanation
Answer: (a) zero
Explanation:
1. Both move at 2 m/s, so there is no relative motion.
2. The flux through the coil does not change and the emf is zero.
Teacher's Note:
1. Recall the basic law.
(a) electromagnetic induction
(b) mutual induction
(c) self induction
(d) induction furnace
Show Answer & Explanation
Answer: (b) mutual induction
Explanation:
1. An induction coil produces a high voltage in the secondary due to the changing current in the primary: mutual induction.
Teacher's Note:
1. Recall the basic law.
(a) 2π
(b) 5π
(c) π
(d) 4π
Show Answer & Explanation
Answer: (b) 5π
Explanation:
1. e_max = M I0 ω = 0.005 × 10 × 100π = 5π V.
Teacher's Note:
1. Recall the basic law.
Assertion (A): A metallic conductor moves parallel to the magnetic field. The induced emf across its ends is zero.
Reason (R): The induced emf across the ends of a conductor is given by e = B v l sin θ.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (a) Both A and R are true, and R is the correct explanation of A.
Explanation:
1. When v is parallel to B, θ = 0 and e = B v l sin θ = 0.
2. So the reason explains the assertion.
Teacher's Note:
1. sin θ = 0.
(a) the medium between the coils
(b) the separation between the two coils
(c) the orientation of the two coils
(d) all of the above
Show Answer & Explanation
Answer: (d) all of the above
Explanation:
1. M depends on the geometry (separation, orientation), the number of turns and the medium.
Teacher's Note:
1. Recall the basic law.
(a) the induced emf is produced only when the magnetic flux decreases
(b) the induced emf opposes the change in the magnetic flux
(c) the induced emf is opposite to the direction of the flux
(d) none of the above
Show Answer & Explanation
Answer: (b) the induced emf opposes the change in the magnetic flux
Explanation:
1. The negative sign expresses Lenz's law: the induced emf opposes the change in flux that produces it.
Teacher's Note:
1. Recall the basic law.
(a) \( 2.4\times10^{-4}\ \text{V} \)
(b) \( 2.4\times10^{-2}\ \text{V} \)
(c) \( 4.8\times10^{-4}\ \text{V} \)
(d) \( 4.8\times10^{-2}\ \text{V} \)
Show Answer & Explanation
Answer: (d) \( 4.8\times10^{-2}\ \text{V} \)
Explanation:
1. M = μ₀ N1 N2 A/l = 4π × 10⁻⁷ × 2000 × 300 × 1.2 × 10⁻³/0.3 = 3.02 × 10⁻³ H.
2. e = M ΔI/Δt = 3.02 × 10⁻³ × 4/0.25 = 4.8 × 10⁻² V.
Teacher's Note:
1. Recall the basic law.
(a) 0.2 A
(b) 0.6 A
(c) 1.2 A
(d) 0.8 A
Show Answer & Explanation
Answer: (a) 0.2 A
Explanation:
1. e = dφ/dt = 12t - 5 = -2 V at t = 0.25 s.
2. |I| = 2/10 = 0.2 A.
Teacher's Note:
1. Recall the basic law.
(a) 8.4 V
(b) 84 V
(c) 42 V
(d) 4.2 V
Show Answer & Explanation
Answer: (a) 8.4 V
Explanation:
1. Flux changes from +BA to -BA, so |ΔΦ| = 2BA per turn.
2. e = N 2BA/t = 200 × 2 × 0.3 × 70 × 10⁻⁴/0.1 = 8.4 V.
Teacher's Note:
1. Recall the basic law.
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JEE Physics Electromagnetic Induction Objective Test Questions
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FAQs
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