Practice MCQs for JEE Physics Communication System
Access targeted multiple-choice questions for Communication System designed to align with the latest JEE academic syllabus for JEE Physics. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
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Access the complete set of multiple-choice questions for Communication System below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) inversely proportional to the carrier frequency
(b) proportional to the carrier frequency
(c) inversely proportional to the modulation frequency
(d) independent of both the carrier and the modulation frequency
Show Answer & Explanation
Answer: (a) inversely proportional to the carrier frequency
Explanation:
1. An efficient antenna has a length of the order of the carrier wavelength (typically \( \lambda/4 \)).
2. \( \lambda=\dfrac cf \), so the size is inversely proportional to the carrier frequency.
Teacher's Note:
1. Write the standard relation for modulation index, bandwidth or line of sight, then substitute carefully.
2. Check the units (kHz, MHz, GHz) before comparing the options.
(a) \( \sqrt2 \)
(b) 4
(c) 2
(d) \( \dfrac1{\sqrt2} \)
Show Answer & Explanation
Answer: (b) 4
Explanation:
1. Range \( d=\sqrt{2Rh}\propto\sqrt h \).
2. Doubling d needs \( h\to4h \).
Teacher's Note:
1. Write the standard relation for modulation index, bandwidth or line of sight, then substitute carefully.
2. Check the units (kHz, MHz, GHz) before comparing the options.
(a) \( 2\times10^6 \)
(b) \( 2\times10^3 \)
(c) \( 2\times10^5 \)
(d) \( 2\times10^4 \)
Show Answer & Explanation
Answer: (c) \( 2\times10^5 \)
Explanation:
1. Available bandwidth \( =0.1\times10\times10^9=10^9 \) Hz.
2. Channels \( =\dfrac{10^9}{5\times10^3}=2\times10^5 \).
Teacher's Note:
1. Write the standard relation for modulation index, bandwidth or line of sight, then substitute carefully.
2. Check the units (kHz, MHz, GHz) before comparing the options.
(a) 32
(b) 4
(c) 64
(d) 60
Show Answer & Explanation
Answer: (d) 60
Explanation:
1. Electrons per shell: \( 2n^2 \) gives 2, 8, 18 and 32 for n = 1, 2, 3, 4.
2. Total \( =2+8+18+32=60 \).
Teacher's Note:
1. Write the standard relation for modulation index, bandwidth or line of sight, then substitute carefully.
2. Check the units (kHz, MHz, GHz) before comparing the options.
(a) atomic number; mass number
(b) mass number; atomic number
(c) neutron number; atomic number
(d) atomic number; electron number
Show Answer & Explanation
Answer: (a) atomic number; mass number
Explanation:
1. Isotopes are nuclei of the same element, so they have the same number of protons.
2. They differ in the number of neutrons, hence in mass number.
Teacher's Note:
1. Write the standard relation for modulation index, bandwidth or line of sight, then substitute carefully.
2. Check the units (kHz, MHz, GHz) before comparing the options.
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Practice MCQs for JEE Physics Communication System
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FAQs
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Yes, our JEE Physics Communication System MCQs Set 12 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Physics Communication System MCQs Set 12, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Physics.
Yes, Physics MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Physics Communication System MCQs Set 12 on StudiesToday.com as they provide instant answers and score to help you track your progress in Physics.