JEE Physics Atoms MCQs Set 17

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Multiple Choice Questions

Question 1: An excited He\(^+\) ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to the ground state. The quantum number n corresponding to its initial excited state is [photon energy \( E=\dfrac{1240\text{ eV}}{\lambda\text{ (in nm)}} \)]
(a) n = 4
(b) n = 5
(c) n = 7
(d) n = 6
Show Answer & Explanation

Answer: (b) n = 5

Explanation:
1. 30.4 nm gives 40.8 eV, the 2 to 1 transition of He\(^+\) (\( 54.4(1-\tfrac14)=40.8 \)). 108.5 nm gives 11.43 eV.
2. \( 54.4\left(\dfrac14-\dfrac1{n^2}\right)=11.43\Rightarrow\dfrac1{n^2}=0.04\Rightarrow n=5 \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 2: In Li\(^{++}\), the electron in the first Bohr orbit is excited to a level by a radiation of wavelength \( \lambda \). When the ion gets de-excited to the ground state in all possible ways (including intermediate emissions), a total of six spectral lines are observed. The value of \( \lambda \) is [take \( h=6.63\times10^{-34} \) J s, \( c=3\times10^8 \) m/s]
(a) 9.4 nm
(b) 12.3 nm
(c) 10.8 nm
(d) 11.4 nm
Show Answer & Explanation

Answer: (c) 10.8 nm

Explanation:
1. Six lines means \( \dfrac{n(n-1)}2=6\Rightarrow n=4 \).
2. \( E=13.6\times9\left(1-\dfrac1{16}\right)=114.75 \) eV, so \( \lambda=\dfrac{1240}{114.75}=10.8 \) nm.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 3: Taking the wavelength of the first Balmer line in the hydrogen spectrum (n = 3 to n = 2) as 660 nm, the wavelength of the 2nd Balmer line (n = 4 to n = 2) will be
(a) 488.9 nm
(b) 889.2 nm
(c) 388.9 nm
(d) 642.7 nm
Show Answer & Explanation

Answer: (a) 488.9 nm

Explanation:
1. \( \dfrac{1}{\lambda_1}=R\dfrac{5}{36} \), \( \dfrac1{\lambda_2}=R\dfrac3{16} \).
2. \( \lambda_2=660\times\dfrac{5/36}{3/16}=660\times\dfrac{20}{27}=488.9 \) nm.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 4: Radiation coming from transitions n = 2 to n = 1 of hydrogen atoms falls on He\(^+\) ions in n = 1 and n = 2 states. The possible transition of helium ions as they absorb energy from the radiation is
(a) \( n=2\rightarrow n=3 \)
(b) \( n=2\rightarrow n=4 \)
(c) \( n=1\rightarrow n=4 \)
(d) \( n=2\rightarrow n=5 \)
Show Answer & Explanation

Answer: (b) \( n=2\rightarrow n=4 \)

Explanation:
1. The photon energy is \( 13.6\left(1-\tfrac14\right)=10.2 \) eV.
2. For He\(^+\): \( 54.4\left(\tfrac14-\tfrac1{16}\right)=10.2 \) eV, so n = 2 to n = 4 absorbs it exactly. Other options need 7.55, 51 or 11.4 eV.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 5: In a hydrogen-like atom, when an electron jumps from the M-shell to the L-shell, the wavelength of emitted radiation is \( \lambda \). If an electron jumps from the N-shell to the L-shell, the wavelength of emitted radiation will be
(a) \( \dfrac{27}{20}\lambda \)
(b) \( \dfrac{16}{25}\lambda \)
(c) \( \dfrac{25}{16}\lambda \)
(d) \( \dfrac{20}{27}\lambda \)
Show Answer & Explanation

Answer: (d) \( \dfrac{20}{27}\lambda \)

Explanation:
1. M to L is 3 to 2: \( \dfrac1\lambda=RZ^2\dfrac5{36} \). N to L is 4 to 2: \( \dfrac1{\lambda'}=RZ^2\dfrac3{16} \).
2. \( \dfrac{\lambda'}{\lambda}=\dfrac{5/36}{3/16}=\dfrac{20}{27} \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 6: A hydrogen atom, initially in the ground state, is excited by absorbing a photon of wavelength 980 \(Å\). The radius of the atom in the excited state, in terms of the Bohr radius \( a_0 \), will be (take \( hc=12500 \) eV-\(Å\))
(a) \( 16a_0 \)
(b) \( 4a_0 \)
(c) \( 9a_0 \)
(d) \( 25a_0 \)
Show Answer & Explanation

Answer: (a) \( 16a_0 \)

Explanation:
1. Photon energy \( =\dfrac{12500}{980}=12.76 \) eV.
2. \( 13.6\left(1-\dfrac1{n^2}\right)=12.76\Rightarrow n=4 \), so \( r=n^2a_0=16a_0 \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 7: As an electron makes a transition from an excited state to the ground state of a hydrogen-like atom or ion,
(a) its kinetic energy, potential energy and total energy decrease
(b) its kinetic energy decreases, potential energy increases but total energy remains the same
(c) its kinetic energy increases but its potential energy and total energy decrease
(d) its kinetic energy and total energy decrease but its potential energy increases
Show Answer & Explanation

Answer: (c) its kinetic energy increases but its potential energy and total energy decrease

Explanation:
1. \( K=-E=\dfrac{13.6Z^2}{n^2} \): K increases as n falls. \( U=2E \): U becomes more negative.
2. Total energy \( E=-K \) is lower, so it decreases (a photon is emitted).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 8: Hydrogen (\( _1\)H\(^1\)), deuterium (\( _1\)H\(^2\)), singly ionised helium (\( _2\)He\(^4\))\(^+\) and doubly ionised lithium (\( _3\)Li\(^8\))\(^{++}\) all have one electron around the nucleus. Consider the transition from n = 2 to n = 1. If the wavelengths of the emitted radiation are \( \lambda_1,\lambda_2,\lambda_3,\lambda_4 \) respectively, then approximately
(a) \( 4\lambda_1=2\lambda_2=2\lambda_3=\lambda_4 \)
(b) \( \lambda_1=2\lambda_2=2\lambda_3=\lambda_4 \)
(c) \( \lambda_1=2\lambda_2=3\lambda_3=4\lambda_4 \)
(d) \( \lambda_1=\lambda_2=4\lambda_3=9\lambda_4 \)
Show Answer & Explanation

Answer: (d) \( \lambda_1=\lambda_2=4\lambda_3=9\lambda_4 \)

Explanation:
1. \( \dfrac1\lambda=RZ^2\left(1-\tfrac14\right)\propto Z^2 \) (nuclear mass effects are tiny).
2. Z = 1, 1, 2, 3 gives \( \lambda_1=\lambda_2=4\lambda_3=9\lambda_4 \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 9: The wavelength of the first spectral line in the Balmer series of the hydrogen atom is 6561 \(Å\). The wavelength of the second spectral line in the Balmer series of singly ionised helium is
(a) \( 1640\ Å \)
(b) \( 1215\ Å \)
(c) \( 2430\ Å \)
(d) \( 4687\ Å \)
Show Answer & Explanation

Answer: (b) \( 1215\ Å \)

Explanation:
1. H first Balmer line: \( \dfrac1{6561}=R\left(\dfrac14-\dfrac19\right)=\dfrac{5R}{36} \). He\(^+\) second Balmer line (4 to 2): \( \dfrac1{\lambda}=4R\left(\dfrac14-\dfrac1{16}\right)=\dfrac{3R}4 \).
2. \( \lambda=6561\times\dfrac{5/36}{3/4}=6561\times\dfrac5{27}=1215\ Å \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 10: The largest wavelength in the ultraviolet region of the hydrogen spectrum is 122 nm. The smallest wavelength in the infrared region of the hydrogen spectrum (to the nearest integer) is
(a) 802 nm
(b) 1882 nm
(c) 823 nm
(d) 1648 nm
Show Answer & Explanation

Answer: (c) 823 nm

Explanation:
1. Largest UV wavelength: Lyman, n = 2 to 1: \( \dfrac1{122}=\dfrac{3R}{4} \Rightarrow \dfrac1R=91.5 \) nm.
2. The infrared starts with the Paschen series; its smallest wavelength is the series limit \( \lambda=\dfrac{9}{R}=9\times91.5=823 \) nm.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 11: The electric potential between a proton and an electron is given by \( V=V_0\ln\dfrac r{r_0} \), where \( r_0 \) is a constant. Assuming Bohr's model to be applicable, the variation of \( r_n \) with the principal quantum number n is
(a) \( r_n\propto n \)
(b) \( r_n\propto\dfrac1n \)
(c) \( r_n\propto n^2 \)
(d) \( r_n\propto\dfrac1{n^2} \)
Show Answer & Explanation

Answer: (a) \( r_n\propto n \)

Explanation:
1. Force on the electron: \( F=e\dfrac{dV}{dr}=\dfrac{eV_0}r \). So \( \dfrac{mv^2}r=\dfrac{eV_0}r\Rightarrow v^2=\dfrac{eV_0}m \), a constant.
2. Quantisation \( mvr=\dfrac{nh}{2\pi} \) with constant v gives \( r_n\propto n \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 12: A hydrogen atom and a Li\(^{2+}\) ion are both in the second excited state. If \( l_H \) and \( l_{Li} \) are their respective electronic angular momenta, and \( E_H \) and \( E_{Li} \) their respective energies, then
(a) \( l_H\gt l_{Li}\text{ and }|E_H|\gt |E_{Li}| \)
(b) \( l_H=l_{Li}\text{ and }|E_H|\lt |E_{Li}| \)
(c) \( l_H=l_{Li}\text{ and }|E_H|\gt |E_{Li}| \)
(d) \( l_H\lt l_{Li}\text{ and }|E_H|\lt |E_{Li}| \)
Show Answer & Explanation

Answer: (b) \( l_H=l_{Li}\text{ and }|E_H|\lt |E_{Li}| \)

Explanation:
1. Second excited state: n = 3 for both, and \( L=\dfrac{nh}{2\pi} \) is the same.
2. \( |E|=\dfrac{13.6Z^2}{n^2} \): H: 1.51 eV; Li\(^{2+}\): 13.6 eV. So \( |E_H|\lt |E_{Li}| \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 13: Imagine an atom made up of a proton and a hypothetical particle of double the mass of the electron but having the same charge as the electron. Apply the Bohr atom model and consider all possible transitions of this hypothetical particle to the first excited level. The longest wavelength photon that will be emitted has wavelength \( \lambda \), given in terms of the Rydberg constant R for the hydrogen atom, equal to
(a) \( \dfrac9{5R} \)
(b) \( \dfrac{36}{5R} \)
(c) \( \dfrac4R \)
(d) \( \dfrac{18}{5R} \)
Show Answer & Explanation

Answer: (d) \( \dfrac{18}{5R} \)

Explanation:
1. Energy levels scale with the orbiting mass, so the effective Rydberg constant is 2R. The first excited level is n = 2.
2. Longest wavelength: 3 to 2: \( \dfrac1\lambda=2R\left(\dfrac14-\dfrac19\right)=\dfrac{5R}{18}\Rightarrow\lambda=\dfrac{18}{5R} \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 14: In the hydrogen spectrum, the wavelength of the H\(_\alpha\) line is 656 nm, whereas in the spectrum of a distant galaxy the H\(_\alpha\) line wavelength is 706 nm. The estimated speed of the galaxy with respect to Earth is
(a) \( 2\times10^7\ \text{m/s} \)
(b) \( 2\times10^8\ \text{m/s} \)
(c) \( 2\times10^6\ \text{m/s} \)
(d) \( 2\times10^5\ \text{m/s} \)
Show Answer & Explanation

Answer: (a) \( 2\times10^7\ \text{m/s} \)

Explanation:
1. Doppler shift for a receding source: \( \dfrac{\Delta\lambda}\lambda=\dfrac vc \).
2. \( v=3\times10^8\times\dfrac{706-656}{656}=2.3\times10^7\approx2\times10^7 \) m/s.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 15: Consider the spectral line resulting from the transition n = 2 to n = 1 in the atoms and ions given below. The shortest wavelength is produced by
(a) hydrogen atom
(b) deuterium atom
(c) doubly ionised lithium
(d) singly ionised helium
Show Answer & Explanation

Answer: (c) doubly ionised lithium

Explanation:
1. \( \dfrac1\lambda=RZ^2\left(1-\tfrac14\right)\propto Z^2 \) (nuclear mass has a negligible effect).
2. The largest Z, 3 for Li\(^{++}\), gives the shortest wavelength.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 16: A diatomic molecule has moment of inertia I. By Bohr's quantisation condition its rotational energy in the nth level (n = 0 is not allowed) is
(a) \( \dfrac1{n^2}\left(\dfrac{h^2}{8\pi^2I}\right) \)
(b) \( \dfrac1n\left(\dfrac{h^2}{8\pi^2I}\right) \)
(c) \( n\left(\dfrac{h^2}{8\pi^2I}\right) \)
(d) \( n^2\left(\dfrac{h^2}{8\pi^2I}\right) \)
Show Answer & Explanation

Answer: (d) \( n^2\left(\dfrac{h^2}{8\pi^2I}\right) \)

Explanation:
1. Quantised angular momentum: \( L=I\omega=\dfrac{nh}{2\pi} \).
2. \( E=\dfrac{L^2}{2I}=\dfrac{n^2h^2}{8\pi^2I} \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 17: In a CO molecule the moment of inertia about the centre of mass is \( 1.87\times10^{-46} \) kg m\(^2\). The masses of C and O are 12 amu and 16 amu, where 1 amu \( =\dfrac53\times10^{-27} \) kg. The distance between C and O is close to
(a) \( 2.4\times10^{-10}\ \text m \)
(b) \( 1.3\times10^{-10}\ \text m \)
(c) \( 1.9\times10^{-10}\ \text m \)
(d) \( 4.4\times10^{-10}\ \text m \)
Show Answer & Explanation

Answer: (b) \( 1.3\times10^{-10}\ \text m \)

Explanation:
1. Moment of inertia \( I=\mu d^2 \) with reduced mass \( \mu=\dfrac{12\times16}{28}=6.86 \) amu \( =1.143\times10^{-26} \) kg.
2. \( d=\sqrt{\dfrac{1.87\times10^{-46}}{1.143\times10^{-26}}}=1.28\times10^{-10}\approx1.3\times10^{-10} \) m.

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 18: A particle is restricted to move along the x-axis between x = 0 and x = a (a of nanometre dimension). Standing waves with nodes at both ends form, and the energy is \( \dfrac{p^2}{2m} \) with de Broglie momentum p. The allowed energy of the particle for a particular value of n is proportional to
(a) \( a^{-3/2} \)
(b) \( a^{-1} \)
(c) \( a^{-2} \)
(d) \( a^2 \)
Show Answer & Explanation

Answer: (c) \( a^{-2} \)

Explanation:
1. Standing wave condition: \( a=\dfrac{n\lambda}2\Rightarrow\lambda=\dfrac{2a}n \), so \( p=\dfrac h\lambda=\dfrac{nh}{2a} \).
2. \( E=\dfrac{p^2}{2m}=\dfrac{n^2h^2}{8ma^2}\propto a^{-2} \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 19: A particle of mass m moves in a line between x = 0 and x = a, with standing de Broglie waves (n = 1, 2, 3, ...). The speed of the particle can take discrete values proportional to
(a) \( n \)
(b) \( n^{-3/2} \)
(c) \( n^{-1} \)
(d) \( n^{1/2} \)
Show Answer & Explanation

Answer: (a) \( n \)

Explanation:
1. \( p=\dfrac{nh}{2a} \).
2. \( v=\dfrac pm=\dfrac{nh}{2ma}\propto n \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 20: In a mixture of H and He\(^+\) gas, H atoms and He\(^+\) ions are excited to their respective first excited states. Subsequently, H atoms transfer their total excitation energy to He\(^+\) ions (by collisions). The Bohr model is exactly valid. The quantum number n of the state finally populated in He\(^+\) ions is
(a) 2
(b) 4
(c) 3
(d) 5
Show Answer & Explanation

Answer: (b) 4

Explanation:
1. The excitation energy of H in n = 2 is \( 13.6\times\tfrac34=10.2 \) eV. He\(^+\) in n = 2 has energy \( -13.6 \) eV.
2. Final energy \( -13.6+10.2=-3.4 \) eV \( =-\dfrac{54.4}{n^2}\Rightarrow n=4 \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

Question 21: The ratio of the kinetic energy of the n = 2 electron for the H atom to that of the He\(^+\) ion is
(a) 1/2
(b) 1
(c) 2
(d) 1/4
Show Answer & Explanation

Answer: (d) 1/4

Explanation:
1. \( K=\dfrac{13.6Z^2}{n^2} \).
2. \( \dfrac{K_H}{K_{He^+}}=\dfrac{1}{4} \).

Teacher's Note:
1. Write the energy or radius formula for a hydrogen-like atom, with the correct Z, before comparing levels.
2. Check the sign and the order of magnitude: energies of bound levels are negative and shrink as n increases.

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