Multiple Choice Questions (MCQs) for JEE Physics: Alternating Current
Review structured MCQ sets for JEE Physics Alternating Current. Built according to official JEE guidelines, these downloadable questions support daily revision and core concept reinforcement.
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Multiple Choice Questions
(a) 60%
(b) 35%
(c) 50%
(d) 90%
Show Answer & Explanation
Answer: (d) 90%
Explanation:
1. Input power = 220 × 0.5 = 110 W.
2. Efficiency = 100/110, about 90%.
Teacher's Note:
1. Recall the basic relation.
(a) large
(b) moderate
(c) small
(d) cannot say
Show Answer & Explanation
Answer: (c) small
Explanation:
1. P = V I cos φ, so a small power factor gives the minimum power dissipation.
Teacher's Note:
1. Recall the basic relation.
(a) 1.3 A
(b) 0.5 A
(c) 0.6 A
(d) 0.36 A
Show Answer & Explanation
Answer: (b) 0.5 A
Explanation:
1. The currents in L and C are 180° out of phase.
2. I = 0.9 - 0.4 = 0.5 A.
Teacher's Note:
1. Recall the basic relation.
(a) \( 1.1\times10^3\ \text{rad s}^{-1} \)
(b) \( 2.1\times10^3\ \text{rad s}^{-1} \)
(c) \( 3.1\times10^3\ \text{rad s}^{-1} \)
(d) \( 4.1\times10^3\ \text{rad s}^{-1} \)
Show Answer & Explanation
Answer: (a) \( 1.1\times10^3\ \text{rad s}^{-1} \)
Explanation:
1. ω = 1/√(LC) = 1/√(27 × 10⁻³ × 30 × 10⁻⁶) = 1/√(8.1 × 10⁻⁷) = 1.1 × 10³ rad/s.
Teacher's Note:
1. Recall the basic relation.
(a) resonant frequency
(b) impedance
(c) amplitude of the current
(d) reactance
Show Answer & Explanation
Answer: (c) amplitude of the current
Explanation:
1. At resonance the impedance is minimum, so the current amplitude is maximum.
Teacher's Note:
1. Recall the basic relation.
(a) pure capacitive circuit
(b) pure inductive circuit
(c) pure resistive circuit
(d) none of these
Show Answer & Explanation
Answer: (c) pure resistive circuit
Explanation:
1. Power factor is 1 for a pure resistor, so the average power is maximum.
Teacher's Note:
1. Recall the basic relation.
(a) I_p² R cos θ
(b) \( \tfrac12I_p^2R \)
(c) \( \tfrac4\pi I_p^2R \)
(d) \( \tfrac1{\pi^2}I_p^2R \)
Show Answer & Explanation
Answer: (b) \( \tfrac12I_p^2R \)
Explanation:
1. I_rms² R = (I_p²/2) R.
Teacher's Note:
1. Recall the basic relation.
(a) \( R/\omega L \)
(b) \( (\omega L/R)^2 \)
(c) \( (R/\omega L)^{1/2} \)
(d) \( \omega L/R \)
Show Answer & Explanation
Answer: (d) \( \omega L/R \)
Explanation:
1. Q = ωL/R.
Teacher's Note:
1. Recall the basic relation.
Assertion (A): In the purely resistive element of a series LCR a.c. circuit, the maximum value of the rms current increases with an increase in the angular frequency of the applied emf.
Reason (R): I_max = ε_max/Z, where Z = √[R² + (ωL - 1/ωC)²].
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (d) A is false, but R is true.
Explanation:
1. The current increases with frequency only until resonance and then decreases, so the assertion is false.
2. The expression for I_max is correct.
Teacher's Note:
1. Current peaks at resonance.
(a) \( \frac\pi4\sqrt{LC} \)
(b) \( 2\pi\sqrt{LC} \)
(c) \( \sqrt{LC} \)
(d) \( \pi\sqrt{LC} \)
Show Answer & Explanation
Answer: (a) \( \frac\pi4\sqrt{LC} \)
Explanation:
1. q = Q0 cos(ωt) with ω = 1/√(LC).
2. Equal energies need q² = Q0²/2, i.e. ωt = π/4, so t = (π/4)√(LC).
Teacher's Note:
1. Recall the basic relation.
(a) 4 A
(b) 2 A
(c) 6 A
(d) 10 A
Show Answer & Explanation
Answer: (b) 2 A
Explanation:
1. For an ideal transformer I_s = I_p N_p/N_s = 4 × 140/280 = 2 A.
Teacher's Note:
1. Recall the basic relation.
(a) X_L is independent of frequency
(b) X_L is directly proportional to frequency (a straight line through the origin)
(c) X_L is infinite at one particular frequency and zero elsewhere
(d) X_L decreases linearly with frequency
Show Answer & Explanation
Answer: (b) X_L is directly proportional to frequency (a straight line through the origin)
Explanation:
1. X_L = 2πfL.
Teacher's Note:
1. Recall the basic relation.
(a) I and II
(b) II and III
(c) I and III only
(d) I, II and III
Show Answer & Explanation
Answer: (d) I, II and III
Explanation:
1. All three statements are true statements about sharpness of resonance and quality factor.
Teacher's Note:
1. Recall the basic relation.
Assertion (A): Power is produced when a transformer steps up the voltage.
Reason (R): In an ideal transformer V I = constant.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation
Answer: (d) A is false, but R is true.
Explanation:
1. A transformer does not produce power; it transfers it, so the assertion is false.
2. In an ideal transformer V_p I_p = V_s I_s, so the reason is true.
Teacher's Note:
1. Power in = power out.
(a) the rate of transmission is faster at high voltages
(b) it is more economical due to less power loss
(c) power cannot be transmitted at low voltages
(d) it is a precaution against theft of transmission lines
Show Answer & Explanation
Answer: (b) it is more economical due to less power loss
Explanation:
1. For a given power the current is smaller at high voltage, so the I²R loss in the lines is less.
Teacher's Note:
1. Recall the basic relation.
(a) DC
(b) AC
(c) DC as well as AC
(d) neither AC nor DC
Show Answer & Explanation
Answer: (a) DC
Explanation:
1. X_C = 1/(ωC) tends to infinity as ω tends to zero (d.c.).
Teacher's Note:
1. Recall the basic relation.
(a) \( R/\omega L \)
(b) \( R/(R^2\omega^2L^2) \)
(c) \( \omega L/R \)
(d) \( R/(R^2+\omega^2L^2)^{1/2} \)
Show Answer & Explanation
Answer: (d) \( R/(R^2+\omega^2L^2)^{1/2} \)
Explanation:
1. cos φ = R/Z = R/√(R² + ω²L²).
Teacher's Note:
1. Recall the basic relation.
(a) e_rms I_rms
(b) e_rms I_rms cos φ
(c) 0
(d) none of these
Show Answer & Explanation
Answer: (a) e_rms I_rms
Explanation:
1. For a resistor φ = 0, so P = e_rms I_rms.
Teacher's Note:
1. Recall the basic relation.
(a) DC voltage, AC current
(b) AC voltage, DC current
(c) AC voltage, AC voltage
(d) AC voltage, AC current
Show Answer & Explanation
Answer: (d) AC voltage, AC current
Explanation:
1. A sinusoidally varying voltage is an a.c. voltage and it drives an a.c. current.
Teacher's Note:
1. Recall the basic relation.
(a) \( \tan^{-1}\left(\frac1{\omega CR}\right) \)
(b) \( \tan^{-1}(\omega CR) \)
(c) \( \tan^{-1}\left(\frac{\omega C}{R}\right) \)
(d) \( \tan^{-1}\left(\frac R{\omega C}\right) \)
Show Answer & Explanation
Answer: (a) \( \tan^{-1}\left(\frac1{\omega CR}\right) \)
Explanation:
1. tan φ = X_C/R = 1/(ωCR).
Teacher's Note:
1. Recall the basic relation.
(a) 10 mA
(b) 100 mA
(c) 200 mA
(d) 20 mA
Show Answer & Explanation
Answer: (d) 20 mA
Explanation:
1. X_C = 1/(100 × 10⁻⁶) = 10⁴ ohm.
2. I_rms = 200/10⁴ = 0.02 A = 20 mA.
Teacher's Note:
1. Recall the basic relation.
(a) 10 mH
(b) 12 mH
(c) 16 mH
(d) 20 mH
Show Answer & Explanation
Answer: (c) 16 mH
Explanation:
1. tan 45° = X_L/R, so X_L = 100 ohm.
2. L = 100/(2π × 1000) = 15.9 mH, about 16 mH.
Teacher's Note:
1. Recall the basic relation.
(a) 25 A
(b) 50 A
(c) 15 A
(d) 12.5 A
Show Answer & Explanation
Answer: (b) 50 A
Explanation:
1. I_p/I_s = N_s/N_p = 25.
2. I_p = 25 × 2 = 50 A.
Teacher's Note:
1. Recall the basic relation.
(a) the average value of current over a cycle is zero
(b) the average value of the square of the current is zero
(c) the average power dissipation is zero
(d) the phase difference between voltage and current is zero
Show Answer & Explanation
Answer: (a) the average value of current over a cycle is zero
Explanation:
1. For a sinusoidal current the positive and negative half cycles cancel, so the average over a cycle is zero.
2. The average of i² and the average power in a resistor are not zero.
Teacher's Note:
1. Recall the basic relation.
(a) 30 c/s
(b) 50 c/s
(c) 60 c/s
(d) 120 c/s
Show Answer & Explanation
Answer: (b) 50 c/s
Explanation:
1. The mains frequency in India is 50 Hz.
Teacher's Note:
1. Recall the basic relation.
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Alternating Current Objective Questions & Solutions for JEE Physics
About Alternating Current MCQs for JEE Physics
Review structured objective questions for JEE Physics Alternating Current. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.
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FAQs
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