JEE Mathematics Set Operations Relations and Mappings MCQs Set 08

Multiple Choice Questions (MCQs) for JEE Mathematics: Set Operations Relations and Mappings

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Multiple Choice Questions

Question 1: Let \(A=\{1,2,3,4\}\) and \(R:A\to A\) be the relation \(R=\{(1,1),(2,3),(3,4),(4,2)\}\). The correct statement is:
(a) R does not have an inverse
(b) R is not a one to one function
(c) R is an onto function
(d) R is not a function
Show Answer & Explanation

Answer: (c) R is an onto function

Explanation:
1. Each element of \(A\) appears exactly once as a first component, so \(R\) is a function.
2. The images \(1,3,4,2\) are all different, so it is one-one, and since \(A\) is finite it is also onto.
3. Hence R is a bijection with an inverse; the correct statement is that it is onto.

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Question 2: Let \(R=\{(x,y):x,y\in N\text{ and }x^2-4xy+3y^2=0\}\), where \(N\) is the set of natural numbers. Then the relation \(R\) is:
(a) reflexive but neither symmetric nor transitive
(b) symmetric and transitive
(c) reflexive and symmetric
(d) reflexive and transitive
Show Answer & Explanation

Answer: (a) reflexive but neither symmetric nor transitive

Explanation:
1. \(x^2-4xy+3y^2=(x-y)(x-3y)=0\), so \(R\) holds when \(x=y\) or \(x=3y\).
2. Reflexive: \(x=x\) always. Not symmetric: \((3,1)\in R\) but \((1,3)\notin R\).
3. Not transitive: \((9,3),(3,1)\in R\) but \((9,1)\notin R\).

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Question 3: Let \(A\) and \(B\) be two sets containing \(2\) and \(4\) elements respectively. The number of subsets of \(A\times B\) having \(3\) or more elements is:
(a) 211
(b) 256
(c) 220
(d) 219
Show Answer & Explanation

Answer: (d) 219

Explanation:
1. \(n(A\times B)=8\), so there are \(2^8=256\) subsets.
2. Subsets with fewer than 3 elements: \(1+8+28=37\).
3. Required number \(=256-37=219\).

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Question 4: If \(aN=\{ax:x\in N\}\), then \(3N\cap7N=kN\), where \(k\) equals:
(a) 10
(b) 21
(c) 42
(d) 4
Show Answer & Explanation

Answer: (b) 21

Explanation:
1. \(3N\cap 7N\) consists of the natural numbers divisible by both \(3\) and \(7\).
2. These are exactly the multiples of \(\text{lcm}(3,7)=21\), so \(3N\cap7N=21N\) and \(k=21\).

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Question 5: If two sets \(A\) and \(B\) have \(99\) elements in common, then the number of elements common to the sets \(A\times B\) and \(B\times A\) is \(k^2\). Then \(k\) is:
(a) 9
(b) 99
(c) 33
(d) 198
Show Answer & Explanation

Answer: (b) 99

Explanation:
1. \((A\times B)\cap(B\times A)=(A\cap B)\times(B\cap A)=(A\cap B)\times(A\cap B)\).
2. It has \(99\times99=99^2\) elements, so \(k=99\).

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Question 6: If \(n(A)=3\), \(n(B)=6\) and \(A\subseteq B\), then the number of elements in \(A\cup B\) is:
(a) 3
(b) 6
(c) 9
(d) 18
Show Answer & Explanation

Answer: (b) 6

Explanation:
1. Since \(A\subseteq B\), \(A\cup B=B\), which has \(6\) elements.

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Question 7: If \(n(A)=4\), \(n(B)=3\) and \(n(A\times B\times C)=24\), then \(n(C)\) is:
(a) 1
(b) 2
(c) 3
(d) 4
Show Answer & Explanation

Answer: (b) 2

Explanation:
1. \(n(A\times B\times C)=4\times3\times n(C)=24\Rightarrow n(C)=2\).

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Question 8: Given \(n(U)=20\), \(n(A)=12\), \(n(B)=9\) and \(n(A\cap B)=4\), where \(U\) is the universal set and \(A,B\subseteq U\), then \(n\big((A\cup B)^C\big)\) equals:
(a) 1
(b) 3
(c) 5
(d) 8
Show Answer & Explanation

Answer: (b) 3

Explanation:
1. \(n(A\cup B)=12+9-4=17\).
2. \(n((A\cup B)^C)=20-17=3\).

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