JEE Mathematics Miscellaneous Problems MCQs Set 04

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Chapter-wise Objective Questions: Miscellaneous Problems

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Multiple Choice Questions

Question 1:
Assertion (A): The curve C is the locus of a point whose sum of distances from the points S(√3, 0) and S′(−√3, 0) is 4. The curve C cuts off an intercept of length 2√3 from the line 2y − 1 = 0.
Reason (R): The equation of the curve C is \( \frac{x^2}4+2y^2=\frac54 \).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. Sum of focal distances 2a = 4 so a = 2, and ae = √3 gives b² = 4 − 3 = 1. The curve is \( \frac{x^2}4+y^2=1 \).
2. On y = 1/2: x²/4 = 3/4, so x = ±√3 and the intercept is 2√3, so the Assertion is true.
3. The curve is x²/4 + y² = 1, not x²/4 + 2y² = 5/4, so the Reason is false.

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Question 2:
Assertion (A): \( \int_0^{\pi/2}\frac{dx}{1+\tan^3x}=\frac\pi4 \).
Reason (R): \( \int_0^af(x)\,dx=\int_0^af(x+a)\,dx \), where f(x) is an integrable function.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. Let \( I=\int_0^{\pi/2}\frac{dx}{1+\tan^3x} \). Replacing x by π/2 − x gives \( I=\int_0^{\pi/2}\frac{\tan^3x}{1+\tan^3x}dx \).
2. Adding: 2I = π/2, so I = π/4: the Assertion is true.
3. The correct property is \( \int_0^af(x)dx=\int_0^af(a-x)dx \); the shift f(x + a) changes the limits, so the Reason is false.

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Question 3:
Assertion (A): Let \( F(x)=\int_0^{x^2}\cos\sqrt t\,dt \). Then F′(x) = cos x.
Reason (R): If \( f(x)=\int_a^x\phi(t)\,dt \) then f′(x) = φ(x).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. By the chain rule, \( F'(x)=\cos\sqrt{x^2}\cdot2x=2x\cos x \) (for x ≥ 0), not cos x, so the Assertion is false.
2. The Reason is the fundamental theorem of calculus and is true.

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Question 4:
Assertion (A): \( 1\cdot3\cdot5\cdots(2n-1)\gt n^n \), n ∈ N.
Reason (R): The sum of the first n odd natural numbers is equal to n².
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. For n = 1 the left side is 1 = 1¹, and for n = 2 it is 3 < 4. By AM-GM, \( 1\cdot3\cdots(2n-1)\le\left(\frac{1+3+\cdots+(2n-1)}n\right)^n=n^n \), so the product is never greater than nⁿ: the Assertion is false.
2. The sum of the first n odd numbers is n², so the Reason is true.

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Question 5:
Assertion (A): ABCD is a quadrilateral in which a circle is inscribed. The lengths of the sides of the quadrilateral can be in AP.
Reason (R): The lengths of tangents from an external point to a circle are equal.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Equal tangent lengths give AB + CD = BC + DA, the condition for a quadrilateral to have an incircle.
2. For sides a, a + d, a + 2d, a + 3d (in order) we get a + (a + 3d) = (a + d) + (a + 2d), so the condition holds. The Assertion is true.
3. The Reason is true and is exactly why AB + CD = BC + DA, so it explains the Assertion.

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Question 6:
Assertion (A): a, b, c are three unequal positive numbers. The product of their sum and the sum of their reciprocals exceeds 9.
Reason (R): The AM of n positive numbers exceeds their HM.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. By AM > HM for unequal positive numbers: \( \frac{a+b+c}3\gt \frac3{\frac1a+\frac1b+\frac1c} \).
2. Rearranging: \( (a+b+c)\left(\frac1a+\frac1b+\frac1c\right)\gt 9 \). Both statements are true and the Reason explains the Assertion.

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Question 7:
Assertion (A): z is a unimodular complex number. Then \( \arg(z^2+\bar z)=\arg z \).
Reason (R): \( \bar z=\cos(\arg z)-i\sin(\arg z) \).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. Let z = e^{iθ}. Then \( z^2+\bar z=e^{2i\theta}+e^{-i\theta}=2\cos\frac{3\theta}2\,e^{i\theta/2} \).
2. Its argument is θ/2 (or θ/2 + π), not θ, so the Assertion is false.
3. For |z| = 1, \( \bar z=\cos\theta-i\sin\theta \), so the Reason is true.

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Question 8:
Assertion (A): Let \( (1+x)^{36}=a_0+a_1x+a_2x^2+\cdots+a_{36}x^{36} \). Then \( a_0+a_3+a_6+\cdots+a_{36}=\frac23(2^{35}+1) \).
Reason (R): \( a_0+a_1+\cdots+a_{36}=2^{36} \) and \( a_0+a_2+a_4+\cdots+a_{36}=2^{35} \).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. With ω a cube root of unity: \( a_0+a_3+\cdots=\frac13[2^{36}+(1+\omega)^{36}+(1+\omega^2)^{36}]=\frac13(2^{36}+1+1)=\frac23(2^{35}+1) \), so the Assertion is true.
2. The two sums in the Reason are standard (x = 1 and x = ±1) and true, but they do not give the sum of every third coefficient, so the Reason does not explain the Assertion.

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Question 9:
Assertion (A): Let a, b, c be real such that \( ax^2+bx+c=0 \) and \( x^2+x+1=0 \) have a common root. Then a = b = c.
Reason (R): Two quadratic equations with real coefficients cannot have only one imaginary root in common.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Roots of x² + x + 1 = 0 are non-real. Complex roots of a real-coefficient equation come in conjugate pairs, so a common root forces both roots to be common.
2. Hence the two equations are proportional: a = b = c, so the Assertion is true.
3. The Reason states exactly why both roots must be common, so it explains the Assertion.

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Question 10:
Assertion (A): In triangle ABC, a : b : c = cos A : cos B : cos C. Then triangle ABC is equilateral.
Reason (R): \( \cos A=\frac{b^2+c^2-a^2}{2bc} \), \( \cos B=\frac{c^2+a^2-b^2}{2ca} \), \( \cos C=\frac{a^2+b^2-c^2}{2ab} \).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. By the sine rule a : b : c = sin A : sin B : sin C, so sin A : sin B : sin C = cos A : cos B : cos C, which gives tan A = tan B = tan C.
2. So A = B = C = 60° and the triangle is equilateral: the Assertion is true.
3. The Reason (the cosine rule) is true and is the tool that links the sides to the cosines used in the argument, so it explains the Assertion.

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Question 11:
Assertion (A): \( I_4=\int_0^{\pi/4}\tan^4x\,dx=\frac{3\pi-8}{12} \).
Reason (R): Let \( I_n=\int_0^{\pi/4}\tan^nx\,dx \). Then \( I_n+I_{n-2}=\frac1{n-1} \).
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Reduction: \( I_n+I_{n-2}=\int_0^{\pi/4}\tan^{n-2}x\sec^2x\,dx=\frac1{n-1} \), so the Reason is true.
2. I₂ = 1 − π/4, hence \( I_4=\frac13-I_2=\frac\pi4-\frac23=\frac{3\pi-8}{12} \), so the Assertion is true, and it follows from the Reason.

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Question 12:
Assertion (A): The cubic equation \( 4x^3-15x^2+14x-5=0 \) has a root in the interval (2, 3).
Reason (R): If f(x) = 0 is a polynomial equation which has two real roots α, β (α < β), then f′(x) = 0 will have a root γ such that α < γ < β.
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. f(2) = 32 − 60 + 28 − 5 = −5 and f(3) = 108 − 135 + 42 − 5 = 10 have opposite signs, so a root lies in (2, 3) by the intermediate value theorem: the Assertion is true.
2. The Reason is Rolle's theorem, which is true, but it is not what proves the Assertion.

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Miscellaneous Problems Objective Questions & Solutions for JEE Mathematics

JEE Mathematics Miscellaneous Problems Objective Test Questions

Review structured objective questions for JEE Mathematics Miscellaneous Problems. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.

NCERT-Aligned Objective Questions and Solutions

Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.

Next Steps in Your Exam Preparation

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FAQs

Where can I access latest JEE Mathematics Miscellaneous Problems MCQs Set 04?

You can get most exhaustive JEE Mathematics Miscellaneous Problems MCQs Set 04 for free on StudiesToday.com. These MCQs for JEE Mathematics are updated for the 2026-27 academic session as per JEE examination standards.

Are Assertion-Reasoning and Case-Study MCQs included in the Mathematics JEE material?

Yes, our JEE Mathematics Miscellaneous Problems MCQs Set 04 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.

How do practicing Mathematics MCQs help in scoring full marks in JEE exams?

By solving our JEE Mathematics Miscellaneous Problems MCQs Set 04, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Mathematics.

Do you provide answers and explanations for JEE Mathematics Miscellaneous Problems MCQs Set 04?

Yes, Mathematics MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.

Can I practice these Mathematics JEE MCQs online?

Yes, you can also access online interactive tests for JEE Mathematics Miscellaneous Problems MCQs Set 04 on StudiesToday.com as they provide instant answers and score to help you track your progress in Mathematics.