JEE Mathematics Limits Continuity and Differentiability MCQs Set 09

Mathematics Objective Questions and Answers: Limits Continuity and Differentiability

Explore reliable objective questions for Limits Continuity and Differentiability tailored for JEE learners. Utilizing these Mathematics multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Download Limits Continuity and Differentiability MCQs with Answers

View or download the dedicated Limits Continuity and Differentiability MCQ resource below. Practicing these 50 objective questions regularly builds familiarity with standard exam patterns and helps secure higher marks in final Mathematics evaluations.

Multiple Choice Questions

Question 1: \(\lim_{x\to\infty}\left(\dfrac{x^2+5x+3}{x^2+x+2}\right)^x\) equals
(a) \(e^2\)
(b) \(e^3\)
(c) \(e^4\)
(d) \(1\)
Show Answer & Explanation

Answer: (c) \(e^4\)

Explanation:
1. This is of the form \(1^\infty\): exponent \(\lim x\cdot\dfrac{4x+1}{x^2+x+2}=4\).
2. Limit \(=e^4\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 2: If \(3-\dfrac{x^2}{12}\le f(x)\le3+\dfrac{x^3}9\) for all \(x\ne0\), then \(\lim_{x\to0}f(x)\) is
(a) \(\dfrac13\)
(b) \(-3\)
(c) \(-\dfrac13\)
(d) \(3\)
Show Answer & Explanation

Answer: (d) \(3\)

Explanation:
1. Both bounds tend to 3 as \(x\to0\).
2. By the sandwich theorem the limit is 3.

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 3: The integer \(n\) for which \(\lim_{x\to0}\dfrac{(\cos x-1)(\cos x-e^x)}{x^n}\) is a finite non-zero number is
(a) \(1\)
(b) \(2\)
(c) \(3\)
(d) \(4\)
Show Answer & Explanation

Answer: (c) \(3\)

Explanation:
1. \(\cos x-1\sim-\dfrac{x^2}2\) and \(\cos x-e^x\sim-x\).
2. The numerator behaves like \(\dfrac{x^3}2\), so \(n=3\) (limit \(\dfrac12\)).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 4: For \(x>0\), \(\lim_{x\to0}\left((\sin x)^{1/x}+\left(\dfrac1x\right)^{\sin x}\right)\) equals
(a) \(0\)
(b) \(1\)
(c) \(-1\)
(d) \(2\)
Show Answer & Explanation

Answer: (b) \(1\)

Explanation:
1. \((\sin x)^{1/x}\approx x^{1/x}\to0\).
2. \(\left(\dfrac1x\right)^{\sin x}=e^{-\sin x\ln x}\to e^0=1\).
3. Sum \(=1\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 5: \(\lim_{x\to a}\left(2-\dfrac ax\right)^{\tan\frac{\pi x}{2a}}\) is equal to
(a) \(e^{-a/\pi}\)
(b) \(e^{2a/\pi}\)
(c) \(1\)
(d) \(e^{-2/\pi}\)
Show Answer & Explanation

Answer: (d) \(e^{-2/\pi}\)

Explanation:
1. Form \(1^\infty\): exponent \(\lim\tan\dfrac{\pi x}{2a}\left(1-\dfrac ax\right)\). Put \(x=a+h\).
2. \(\tan\left(\dfrac\pi2+\dfrac{\pi h}{2a}\right)=-\cot\dfrac{\pi h}{2a}\approx-\dfrac{2a}{\pi h}\) and \(1-\dfrac ax\approx\dfrac ha\).
3. Exponent \(=-\dfrac2\pi\); limit \(e^{-2/\pi}\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 6: \(\lim_{x\to\pi/2}\left[1^{1/\cos^2x}+2^{1/\cos^2x}+\dots+n^{1/\cos^2x}\right]^{\cos^2x}\) is
(a) \(0\)
(b) \(n\)
(c) \(\infty\)
(d) \(\dfrac{n(n+1)}2\)
Show Answer & Explanation

Answer: (b) \(n\)

Explanation:
1. As \(t=\dfrac1{\cos^2x}\to\infty\), the sum is dominated by \(n^t\).
2. \((n^t)^{1/t}\cdot\left(1+\dots\right)^{1/t}\to n\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 7: For \(k\in N\), \(\lim_{n\to\infty}\left\{\log_{n-1}n\cdot\log_n(n+1)\cdot\log_{n+1}(n+2)\cdots\log_{n^k-1}(n^k)\right\}\) is equal to
(a) \(n\)
(b) \(\infty\)
(c) \(k\)
(d) \(1\)
Show Answer & Explanation

Answer: (c) \(k\)

Explanation:
1. Using \(\log_ab=\dfrac{\ln b}{\ln a}\) the product telescopes to \(\dfrac{\ln n^k}{\ln(n-1)}\).
2. \(=k\dfrac{\ln n}{\ln(n-1)}\to k\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 8: \(\lim_{x\to0}\left\{\sin^2\left(\dfrac\pi{2-ax}\right)\right\}^{\sec^2\left(\frac\pi{2-bx}\right)}\) (with \(b\ne0\)) is equal to
(a) \(e^{-a^2/b^2}\)
(b) \(e^{-a/b}\)
(c) \(a^{2a/b}\)
(d) \(e^{4a/b}\)
Show Answer & Explanation

Answer: (a) \(e^{-a^2/b^2}\)

Explanation:
1. Form \(1^\infty\): exponent \(\lim\sec^2\left(\dfrac\pi{2-bx}\right)\left(\sin^2\dfrac\pi{2-ax}-1\right)=-\lim\dfrac{\cos^2\frac\pi{2-ax}}{\cos^2\frac\pi{2-bx}}\).
2. \(\cos\dfrac\pi{2-ax}\approx-\dfrac{\pi ax}4\) and \(\cos\dfrac\pi{2-bx}\approx-\dfrac{\pi bx}4\), so the ratio of squares tends to \(\dfrac{a^2}{b^2}\).
3. Limit \(e^{-a^2/b^2}\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 9: If \(\lim_{x\to0}\dfrac{f(x)}{x^2}=a\) and \(\lim_{x\to0}\dfrac{f(1-\cos x)}{g(x)\sin^2x}=b\) (\(b\ne0\)), then \(\lim_{x\to0}\dfrac{g(1-\cos2x)}{x^4}\) is
(a) \(\dfrac{4a}b\)
(b) \(\dfrac a{4b}\)
(c) \(\dfrac{a}{2b}\)
(d) \(\dfrac ab\)
Show Answer & Explanation

Answer: (d) \(\dfrac ab\)

Explanation:
1. \(f(1-\cos x)\approx a(1-\cos x)^2\approx\dfrac{ax^4}4\), so \(g(x)\approx\dfrac{ax^4}{4bx^2}=\dfrac{ax^2}{4b}\).
2. \(g(1-\cos2x)\approx g(2x^2)\approx\dfrac{a(2x^2)^2}{4b}=\dfrac{ax^4}b\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 10: Let \(f(x)\) be a polynomial satisfying \(f(x)\cdot f\left(\dfrac1x\right)=f(x)+f\left(\dfrac1x\right)\) with \(f(4)=65\). If \(l_1,l_2,l_3\) are in G.P., then \(f'(l_1),f'(l_2),f'(l_3)\) are in
(a) \(A.P.\)
(b) \(H.P.\)
(c) \(G.P.\)
(d) \(none of these progressions\)
Show Answer & Explanation

Answer: (c) \(G.P.\)

Explanation:
1. The relation gives \(f(x)=1\pm x^n\); \(f(4)=65\) gives \(f(x)=x^3+1\).
2. \(f'(x)=3x^2\): if \(l_2^2=l_1l_3\) then \((3l_2^2)^2=3l_1^2\cdot3l_3^2\), so G.P.

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 11: \(\lim_{x\to\pi/2}(\sin x)^{\tan x}\) is
(a) 0
(b) 1
(c) e
(d) \(\dfrac1e\)
Show Answer & Explanation

Answer: (b) 1

Explanation:
1. Form \(1^\infty\): exponent \(\lim\tan x(\sin x-1)=\lim\dfrac{\sin x(\sin x-1)}{\cos x}=0\).
2. So the limit is \(e^0=1\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 12: \(\lim_{x\to\infty}\left[\sqrt{x+\sqrt{x+\sqrt x}}-\sqrt x\right]\) is equal to
(a) \(1\)
(b) \(\dfrac12\)
(c) \(0\)
(d) \(\infty\)
Show Answer & Explanation

Answer: (b) \(\dfrac12\)

Explanation:
1. Rationalise: \(\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x+\sqrt{x+\sqrt x}}+\sqrt x}\).
2. Divide by \(\sqrt x\): numerator \(\to1\), denominator \(\to2\); the limit is \(\dfrac12\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 13: Let \(\lim_{x\to0}\dfrac{f(x)}x=1\) and \(\lim_{x\to0}\dfrac{x(1+a\cos x)-b\sin x}{\{f(x)\}^3}=1\). Then \(b-3a\) is
(a) 3
(b) -6
(c) 6
(d) 9
Show Answer & Explanation

Answer: (c) 6

Explanation:
1. \(f(x)\sim x\), so the numerator must be \(x^3+\dots\): \(x(1+a)-bx+\left(-\dfrac a2+\dfrac b6\right)x^3\).
2. \(1+a-b=0\) and \(-\dfrac a2+\dfrac b6=1\): \(a=-\dfrac52,\ b=-\dfrac32\).
3. \(b-3a=-\dfrac32+\dfrac{15}2=6\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 14: For \(m,n\in I^+\), \(\lim_{x\to0}\dfrac{\sin x^n}{(\sin x)^m}\) is equal to
(a) \(0\text{ if }n>m\)
(b) \(1\text{ if }n<m\)
(c) \(\dfrac nm\)
(d) \(0\text{ if }n=m\)
Show Answer & Explanation

Answer: (a) \(0\text{ if }n>m\)

Explanation:
1. \(\dfrac{\sin x^n}{(\sin x)^m}\sim x^{n-m}\).
2. It tends to 0 for \(n>m\), to 1 for \(n=m\) and is unbounded for \(n<m\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 15: If \(S_n=\sum_{k=1}^na_k\) and \(\lim_{n\to\infty}a_n=a\), then \(\lim_{n\to\infty}\dfrac{S_{n+1}-S_n}{\sqrt{\sum_{k=1}^nk}}\) is equal to
(a) a
(b) \(\sqrt2a\)
(c) 0
(d) \(2a\)
Show Answer & Explanation

Answer: (c) 0

Explanation:
1. \(S_{n+1}-S_n=a_{n+1}\to a\).
2. \(\sqrt{\sum k}=\sqrt{\dfrac{n(n+1)}2}\to\infty\), so the limit is 0.

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 16: Let \(a=\min\{x^2+2x+3:x\in R\}\) and \(b=\lim_{\theta\to0}\dfrac{1-\cos\theta}{\theta^2}\). The value of \(\sum_{r=0}^na^rb^{n-r}\) is
(a) \(\dfrac{2^{n+1}-1}{3\cdot2^n}\)
(b) \(\dfrac{2^{n+1}+1}{3\cdot2^n}\)
(c) \(\dfrac{4^{n+1}+1}{3\cdot2^n}\)
(d) \(\dfrac{4^{n+1}-1}{3\cdot2^n}\)
Show Answer & Explanation

Answer: (d) \(\dfrac{4^{n+1}-1}{3\cdot2^n}\)

Explanation:
1. \(a=2\) (at \(x=-1\)) and \(b=\dfrac12\).
2. \(\sum_{r=0}^n2^r2^{-(n-r)}=2^{-n}\sum4^r=\dfrac{4^{n+1}-1}{3\cdot2^n}\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 17: Let \(f(x)=|x^2-3|x|+2|\). Consider the statements: (1) \(f'(x)=2x-3\) for \(x\in(0,1)\cup(2,\infty)\); (2) \(f'(x)=2x+3\) for \(x\in(-\infty,-2)\cup(-1,0)\); (3) \(f'(x)=-2x-3\) for \(x\in(-2,-1)\). Which of these are correct?
(a) 1, 2 and 3
(b) 1 and 2 only
(c) 2 and 3 only
(d) 1 and 3 only
Show Answer & Explanation

Answer: (a) 1, 2 and 3

Explanation:
1. For \(x>0\): \(x^2-3x+2=(x-1)(x-2)\) is positive on \((0,1)\cup(2,\infty)\) and negative on \((1,2)\), so \(f'=2x-3\) on the first set: statement 1 holds.
2. For \(x<0\): \(x^2+3x+2=(x+1)(x+2)\) is positive on \((-\infty,-2)\cup(-1,0)\) (so \(f'=2x+3\)) and negative on \((-2,-1)\) (so \(f'=-2x-3\)).
3. All three statements are correct.

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 18: Let \(f(x)=\lim_{n\to\infty}\dfrac x{x^{2n}+1}\). Then \(f(1^+)+f(1^-)+f(1)\) equals
(a) \(0\)
(b) \(\dfrac32\)
(c) \(1\)
(d) \(\dfrac12\)
Show Answer & Explanation

Answer: (b) \(\dfrac32\)

Explanation:
1. For \(|x|<1\): \(f=x\); for \(|x|>1\): \(f=0\); \(f(1)=\dfrac12\).
2. \(f(1^+)=0,\ f(1^-)=1,\ f(1)=\dfrac12\); the sum is \(\dfrac32\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 19: Let \(f(x)=\lim_{n\to\infty}\dfrac{x^{2n}-1}{x^{2n}+1}\). Then
(a) \(f(x)=1\text{ for }|x|<1\text{ and }f(x)=-1\text{ for }|x|>1\)
(b) \(f(x)\text{ is not defined for any }x\)
(c) \(f(x)=1\text{ for }|x|=1\)
(d) \(f(x)=1\text{ for }|x|>1\text{ and }f(x)=-1\text{ for }|x|<1\)
Show Answer & Explanation

Answer: (d) \(f(x)=1\text{ for }|x|>1\text{ and }f(x)=-1\text{ for }|x|<1\)

Explanation:
1. For \(|x|>1\): \(x^{2n}\to\infty\) and \(f=1\).
2. For \(|x|<1\): \(x^{2n}\to0\) and \(f=-1\); at \(|x|=1\), \(f=0\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 20: The sum of all values of \(n\) (a whole number) for which \(f'(x+y)+1=f'(x)+f'(y)\) holds for all \(x,y\), where \(f(x)=x^n+x\), is
(a) 2
(b) 1
(c) 3
(d) 4
Show Answer & Explanation

Answer: (a) 2

Explanation:
1. \(f'(x)=nx^{n-1}+1\), so the condition is \(n(x+y)^{n-1}=nx^{n-1}+ny^{n-1}\).
2. \(n=0\) works trivially (\(0=0\)); \(n=2\) works (\(x+y=x+y\)); \(n=1\) fails (\(1=2\)).
3. Sum \(=0+2=2\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 21: For \(n\in N\), \(\lim_{x\to\infty}\dfrac{-\ln x^n+[x]}{[x]}\), where \([\cdot]\) is the greatest integer function, is
(a) 0
(b) n
(c) 1
(d) -1
Show Answer & Explanation

Answer: (c) 1

Explanation:
1. \(=1-\dfrac{n\ln x}{[x]}\).
2. \(\dfrac{\ln x}{[x]}\to0\), so the limit is 1.

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 22: If \(y=(1+x)(1+x^2)(1+x^4)\cdots(1+x^{2^n})\), then \(\dfrac{dy}{dx}\) at \(x=0\) is
(a) 1
(b) 0
(c) 2
(d) n
Show Answer & Explanation

Answer: (a) 1

Explanation:
1. \(y=\dfrac{1-x^{2^{n+1}}}{1-x}=1+x+x^2+\dots+x^{2^{n+1}-1}\).
2. \(y'(0)=1\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 23: If \(L=\lim_{x\to0}\dfrac{\sin x+ae^x+be^{-x}+c\ln(1+x)}{x^3}\) is finite, the value of \(L\) is
(a) \(\dfrac12\)
(b) \(-\dfrac13\)
(c) \(-\dfrac16\)
(d) \(3\)
Show Answer & Explanation

Answer: (b) \(-\dfrac13\)

Explanation:
1. Expand and set the coefficients of \(1,x,x^2\) to zero: \(a+b=0,\ 1+a-b+c=0,\ a+b-c=0\).
2. So \(c=0,\ a=-\dfrac12,\ b=\dfrac12\).
3. Coefficient of \(x^3\): \(-\dfrac16+\dfrac a6-\dfrac b6+\dfrac c3=-\dfrac13\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 24: If \(f(x)=\left(\dfrac{|x|}{|x|+2}\right)^{-x}\), then \(\lim_{x\to-\infty}f(x)\) equals
(a) \(e^2\)
(b) \(1\)
(c) \(e^{-2}\)
(d) \(-e^{-2}\)
Show Answer & Explanation

Answer: (c) \(e^{-2}\)

Explanation:
1. Let \(t=-x\to\infty\): \(f=\left(\dfrac t{t+2}\right)^t=\left(1+\dfrac2t\right)^{-t}\).
2. The limit is \(e^{-2}\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 25: If \(f(x)=\dfrac{(1+x)^{1/x}-e}x\), then \(\lim_{x\to0}f(x)\) equals
(a) \(e^2\)
(b) \(\dfrac e2\)
(c) \(-e^2\)
(d) \(-\dfrac e2\)
Show Answer & Explanation

Answer: (d) \(-\dfrac e2\)

Explanation:
1. \((1+x)^{1/x}=e^{\frac{\ln(1+x)}x}=e\cdot e^{-x/2+x^2/3-\dots}\approx e\left(1-\dfrac x2\right)\).
2. So \(f(x)\to-\dfrac e2\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

Question 26: If \(f(x)=\left(\dfrac{1+5x^2}{1+3x^2}\right)^{1/x^2}\), then \(\lim_{x\to0}f(x)\) equals
(a) \(e^2\)
(b) \(e^{-2}\)
(c) \(e^{8}\)
(d) \(e^{5/3}\)
Show Answer & Explanation

Answer: (a) \(e^2\)

Explanation:
1. Form \(1^\infty\): exponent \(\dfrac1{x^2}\cdot\dfrac{2x^2}{1+3x^2}\to2\).
2. The limit is \(e^2\).

Teacher's Note:
1. Identify the indeterminate form first, then use standard limits, series expansions or the exponential form for 1 to the power infinity.
2. Check left-hand and right-hand limits separately when greatest-integer, modulus or piecewise functions appear.

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