Practice MCQs for JEE Mathematics Definite Integration
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Multiple Choice Questions
(a) \( \frac1{n+1}-\frac1{n+2} \)
(b) \( \frac1{n+2} \)
(c) \( \frac1{n+1} \)
(d) \( \frac1{n+1}+\frac1{n+2} \)
Show Answer & Explanation
Answer: (a) \( \frac1{n+1}-\frac1{n+2} \)
Explanation:
1. Write x = 1 - (1 - x): x(1 - x)^n = (1 - x)^n - (1 - x)^(n+1).
2. ∫0^1 = 1/(n + 1) - 1/(n + 2).
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( -1 \)
(b) \( 0 \)
(c) \( 1 \)
(d) \( \frac12 \)
Show Answer & Explanation
Answer: (c) \( 1 \)
Explanation:
1. f(x) = -1 for x < 0 and 1 for x ≥ 0.
2. ∫_(-4)^0 (-1) dx = -4 and ∫0^5 1 dx = 5.
3. Total = 1.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac1{n-2} \)
(b) \( \frac1{n+1} \)
(c) \( \frac1{n-1} \)
(d) \( \frac1n \)
Show Answer & Explanation
Answer: (c) \( \frac1{n-1} \)
Explanation:
1. On [0, π/4], [x] = 0, so the integrand is tan^n x + tan^(n-2) x = tan^(n-2) x sec²x.
2. ∫0^(π/4) tan^(n-2) x sec²x dx = 1/(n - 1).
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 2\pi \)
(b) \( 3\pi \)
(c) \( \pi \)
(d) \( 4\pi \)
Show Answer & Explanation
Answer: (c) \( \pi \)
Explanation:
1. For y > 0, tan⁻¹y + tan⁻¹(1/y) = π/2; for y < 0 it is -π/2.
2. The argument x/(x² + 1) has the sign of x.
3. ∫_(-1)^0 (-π/2) dx + ∫0^3 (π/2) dx = -π/2 + 3π/2 = π.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 1 \)
(b) \( \frac12 \)
(c) \( -1 \)
(d) \( 2 \)
Show Answer & Explanation
Answer: (b) \( \frac12 \)
Explanation:
1. The numerator is 1 - cos x.
2. (1 - cos x)/sin²x = 1/(1 + cos x) → 1/2.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac{\sqrt{5} \pi}{5} \)
(b) \( \frac{\sqrt{5} \pi}{15} \)
(c) \( \frac{\sqrt{5} \pi}{10} \)
(d) \( \frac{\pi}{2} \)
Show Answer & Explanation
Answer: (c) \( \frac{\sqrt{5} \pi}{10} \)
Explanation:
1. Divide by cos²x: ∫ sec²x dx/(1 + 5tan²x).
2. Put tan x = t: ∫0^∞ dt/(1 + 5t²) = (1/√5)(π/2) = π/(2√5).
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac{2}{29} \)
(b) \( - \frac{2}{29} \)
(c) \( \frac{7}{25} \)
(d) \( \frac{5}{29} \)
Show Answer & Explanation
Answer: (d) \( \frac{5}{29} \)
Explanation:
1. Use ∫0^∞ e^(-ax) sin bx dx = b/(a² + b²).
2. With a = 2, b = 5: 5/29.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( -30 \)
(b) \( -20 \)
(c) \( -40 \)
(d) \( -60 \)
Show Answer & Explanation
Answer: (c) \( -40 \)
Explanation:
1. Replace x by -x: I = ∫|sin x|[-sin x] dx.
2. Adding, 2I = ∫|sin x|([sin x] + [-sin x]) dx = -∫_(-20π)^(20π) |sin x| dx (as [t] + [-t] = -1 for non-integers).
3. ∫_(-20π)^(20π) |sin x| dx = 40 × 2 = 80, so I = -40.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac{\pi}{6} \)
(b) \( \frac{\pi}{4} \)
(c) \( \frac{\pi}{2} \)
(d) \( \frac{\pi}{3} \)
Show Answer & Explanation
Answer: (b) \( \frac{\pi}{4} \)
Explanation:
1. Put tan(x/2) = t: 3 + 2 sin x + cos x = (2t² + 4t + 4)/(1 + t²).
2. The integral is ∫0^∞ dt/(t² + 2t + 2) = [tan⁻¹(t + 1)] from 0 to ∞ = π/2 - π/4 = π/4.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 6 \)
(b) \( 9 \)
(c) \( 8 \)
(d) \( 7 \)
Show Answer & Explanation
Answer: (b) \( 9 \)
Explanation:
1. On [0.5, 4.5], [x] = 0, 1, 2, 3, 4 on intervals of lengths 0.5, 1, 1, 1, 0.5, so ∫ = 0 + 1 + 2 + 3 + 2 = 8.
2. ∫_(-1)^1 |x| dx = 1.
3. Total = 9.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 0 \)
(b) \( \infty \)
(c) \( 1 \)
(d) \( \frac12 \)
Show Answer & Explanation
Answer: (c) \( 1 \)
Explanation:
1. I_n + I_(n+2) = ∫0^(π/4) tan^n x sec²x dx = 1/(n + 1).
2. n/(n + 1) → 1.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 0 \)
(b) \( 2 \)
(c) \( 4 \)
(d) \( -1 \)
Show Answer & Explanation
Answer: (c) \( 4 \)
Explanation:
1. x² + 2x - 3 = (x + 3)(x - 1) is negative on (0, 1) and positive on (1, 2).
2. ∫0^1 -(x² + 2x - 3) dx = 5/3 and ∫1^2 (x² + 2x - 3) dx = 7/3.
3. Total = 4.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 2\int_0^1\frac{\sin x-x^2}{3-|x|}dx \)
(b) \( 0 \)
(c) \( \int_0^1\frac{-2x^2}{3-|x|}dx \)
(d) \( \int_0^1\frac{\sin x}{3-|x|}dx \)
Show Answer & Explanation
Answer: (c) \( \int_0^1\frac{-2x^2}{3-|x|}dx \)
Explanation:
1. sin x/(3 - |x|) is odd, so its integral over [-1, 1] is 0.
2. -x²/(3 - |x|) is even, so ∫_(-1)^1 = 2∫0^1 -x²/(3 - |x|) dx = ∫0^1 -2x²/(3 - |x|) dx.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac\pi3 \)
(b) \( \frac\pi4 \)
(c) \( \frac\pi2 \)
(d) \( \frac\pi6 \)
Show Answer & Explanation
Answer: (c) \( \frac\pi2 \)
Explanation:
1. The r-th term is 1/√(2rn - r²) = (1/n)·1/√(2(r/n) - (r/n)²), for r = 1 to n.
2. The limit is ∫0^1 dx/√(2x - x²) = ∫0^1 dx/√(1 - (x - 1)²) = [sin⁻¹(x - 1)] = 0 + π/2 = π/2.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( I>\frac{\sqrt7}2 \)
(b) \( I>1 \)
(c) \( I<1 \)
(d) \( I>\frac{\sqrt5}2 \)
Show Answer & Explanation
Answer: (b) \( I>1 \)
Explanation:
1. For 0 < x < 1, 1 < √(1 + x³) < √2.
2. So ∫0^1 1 dx < I, i.e. I > 1.
3. (The true value is about 1.11, which is less than √5/2, about 1.118.)
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 0 \)
(b) \( 6 \)
(c) \( 3 \)
(d) \( 4 \)
Show Answer & Explanation
Answer: (b) \( 6 \)
Explanation:
1. Write the integrand as (1/x² - 1)^(1/3)/x³.
2. Put 1/x² - 1 = t, so -2dx/x³ = dt; the limits become 8 to 0.
3. ∫ = (1/2)∫0^8 t^(1/3) dt = (1/2)(3/4)(16) = 6.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 10 \)
(b) \( 20 \)
(c) \( 8 \)
(d) \( 18 \)
Show Answer & Explanation
Answer: (d) \( 18 \)
Explanation:
1. |sin x| has period π and ∫0^π |sin x| dx = 2.
2. The interval [π, 10π] has 9 periods, giving 9 × 2 = 18.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( - \frac{\log{\left(3 \right)}}{4} \)
(b) \( - \frac{\log{\left(4 \right)}}{3} \)
(c) \( \frac{\log{\left(3 \right)}}{2} \)
(d) \( \frac{\log{\left(3 \right)}}{4} \)
Show Answer & Explanation
Answer: (d) \( \frac{\log{\left(3 \right)}}{4} \)
Explanation:
1. Put sin x - cos x = u: du = (cos x + sin x) dx and 3 + sin 2x = 4 - u².
2. ∫_(-1)^0 du/(4 - u²) = (1/4) log((2 + u)/(2 - u)) from -1 to 0 = (1/4) log 3.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac{\sqrt{3} \pi}{12} \)
(b) \( - \frac{\sqrt{3} \pi}{12} + \frac{1}{2} \)
(c) \( - \frac{\sqrt{3} \pi}{12} \)
(d) \( \frac{\sqrt{3} \pi}{12} + \frac{1}{2} \)
Show Answer & Explanation
Answer: (b) \( - \frac{\sqrt{3} \pi}{12} + \frac{1}{2} \)
Explanation:
1. By parts with u = sin⁻¹x and dv = x dx/√(1 - x²), v = -√(1 - x²).
2. I = [-√(1 - x²) sin⁻¹x] + ∫0^(1/2) dx = -(√3/2)(π/6) + 1/2.
3. = 1/2 - π√3/12.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( \frac{\pi \log{\left(2 \right)}}{2} \)
(b) \( - \pi \log{\left(2 \right)} \)
(c) \( - \frac{\pi \log{\left(2 \right)}}{2} \)
(d) \( \pi \log{\left(2 \right)} \)
Show Answer & Explanation
Answer: (d) \( \pi \log{\left(2 \right)} \)
Explanation:
1. Put x = tan θ: the integral is ∫0^(π/2) log sec²θ dθ = -2∫0^(π/2) log cos θ dθ.
2. = -2(-(π/2) log 2) = π log 2.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( ae^{-b} \)
(b) \( -ae^{-b} \)
(c) \( -be^{-a} \)
(d) \( ae^{b} \)
Show Answer & Explanation
Answer: (b) \( -ae^{-b} \)
Explanation:
1. Put t = b - y, so dt = -dy; the limits become 1 to 0.
2. The integral becomes ∫1^0 e^(-b+y)/(-y - 1)(-dy) = -e^(-b)∫0^1 e^y/(y + 1) dy.
3. = -a e^(-b).
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 2 \)
(b) \( -1 \)
(c) \( \frac{1}{2} \)
(d) \( 1 \)
Show Answer & Explanation
Answer: (a) \( 2 \)
Explanation:
1. sin|x| is even.
2. ∫_(-π/2)^(π/2) = 2∫0^(π/2) sin x dx = 2.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 2 \)
(b) \( 0 \)
(c) \( 3 \)
(d) \( 1 \)
Show Answer & Explanation
Answer: (b) \( 0 \)
Explanation:
1. Both numerator and denominator tend to 0.
2. By L'Hospital's rule the ratio tends to 2e^(x²)(∫0^x e^(t²) dt)/e^(2x²).
3. As x → 0, ∫0^x e^(t²) dt → 0, so the limit is 0.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
(a) \( 75 \pi \)
(b) \( 50 \pi \)
(c) \( 25 \pi \)
(d) \( 150 \pi \)
Show Answer & Explanation
Answer: (a) \( 75 \pi \)
Explanation:
1. Replace x by π/2 - x and add: 2I = 300∫0^(π/2) dx = 150π.
2. I = 75π.
Teacher's Note:
1. Look for a standard property of definite integrals such as symmetry, the king property or periodicity.
2. Split the interval where the integrand changes its form.
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