Download JEE MCQs for JEE Chemistry: The Solid State
Access targeted multiple-choice questions for The Solid State designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Chapter-wise Objective Questions: The Solid State
Access the complete set of multiple-choice questions for The Solid State below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) 2
(b) 4
(c) 6
(d) 8
Show Answer & Explanation
Answer: (c) 6
Explanation:
1. This range corresponds to octahedral voids with coordination number 6.
2. Answer: (c)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 0.4
(b) 0.98
(c) 1.0
(d) 0.52
Show Answer & Explanation
Answer: (d) 0.52
Explanation:
1. r(Na+) = 95 pm and r(Cl−) = 181 pm, so the ratio is about 0.52.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) It has an fcc arrangement of Na+
(b) Na+ and Cl− ions have a coordination number of 6 : 6
(c) A unit cell of NaCl consists of four NaCl units
(d) All halides of alkali metals have rock salt type structure
Show Answer & Explanation
Answer: (d) All halides of alkali metals have rock salt type structure
Explanation:
1. CsCl, CsBr and CsI adopt the CsCl type structure, so (d) is incorrect.
2. (a), (b) and (c) are true.
3. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Cubic
(b) Tetragonal
(c) Octahedral
(d) Trigonal bipyramidal
Show Answer & Explanation
Answer: (c) Octahedral
Explanation:
1. Na+ ions fill all octahedral voids, giving 6 : 6 coordination.
2. Answer: (c)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Corners of the cube
(b) Centres of faces of the cube
(c) Corners as well as centres of the faces of the cube
(d) Edge centres of the cube
Show Answer & Explanation
Answer: (c) Corners as well as centres of the faces of the cube
Explanation:
1. Cl− forms an fcc lattice: corners and face centres.
2. Answer: (c)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Occupied by Na+ ions
(b) Occupied by Cl− ions
(c) Occupied by either Na+ or Cl− ions
(d) Vacant
Show Answer & Explanation
Answer: (d) Vacant
Explanation:
1. Na+ fills only the octahedral voids; all tetrahedral voids remain vacant.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 2
(b) 6
(c) 4
(d) 8
Show Answer & Explanation
Answer: (b) 6
Explanation:
1. Rock salt structure gives 6 : 6 coordination.
2. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) One CsCl unit
(b) Two CsCl units
(c) Four CsCl units
(d) Eight CsCl units
Show Answer & Explanation
Answer: (a) One CsCl unit
Explanation:
1. Cs+ at the body centre (1) and Cl− at corners (8 × 1/8 = 1): one formula unit.
2. Answer: (a)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 4
(b) 6
(c) 10
(d) 8
Show Answer & Explanation
Answer: (d) 8
Explanation:
1. CsCl type structure has 8 : 8 coordination.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 4 : 4
(b) 6 : 6
(c) 8 : 8
(d) 4 : 8
Show Answer & Explanation
Answer: (a) 4 : 4
Explanation:
1. Zn2+ occupies half the tetrahedral voids of an fcc S2− lattice; each ion has 4 neighbours: 4 : 4.
2. Answer: (a)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 2
(b) 4
(c) 6
(d) 8
Show Answer & Explanation
Answer: (b) 4
Explanation:
1. Ca2+ forms fcc (4 per cell) and F− fills 8 tetrahedral voids: 4 CaF2 units.
2. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) ZnS
(b) CuCl
(c) AgI
(d) All of these
Show Answer & Explanation
Answer: (d) All of these
Explanation:
1. ZnS, CuCl and AgI all adopt the zinc blende structure with 4 : 4 coordination.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 4
(b) 6
(c) 8
(d) 12
Show Answer & Explanation
Answer: (b) 6
Explanation:
1. r+/r− = 95/181 = 0.525, in the range 0.414 to 0.732.
2. Coordination number 6.
3. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) CsCl type
(b) NaCl type
(c) ZnS type
(d) CaF2 type
Show Answer & Explanation
Answer: (b) NaCl type
Explanation:
1. Radius ratio = 1.46/2.16 = 0.676, between 0.414 and 0.732.
2. Octahedral coordination: NaCl type.
3. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 100 pm
(b) 125 pm
(c) 250 pm
(d) 325 pm
Show Answer & Explanation
Answer: (b) 125 pm
Explanation:
1. Along the edge: a = 2(r+ + r−).
2. 400 = 2(75 + r−), so r− = 125 pm.
3. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 200 pm
(b) √3/√2 pm
(c) 142.2 pm
(d) √2 pm
Show Answer & Explanation
Answer: (a) 200 pm
Explanation:
1. In the CsCl-type (bcc) arrangement the closest distance is half the body diagonal: √3 a/2.
2. a = 2 × 173/√3 = 200 pm.
3. Answer: (a)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 2a pm
(b) a/2 pm
(c) 4a pm
(d) a/4 pm
Show Answer & Explanation
Answer: (a) 2a pm
Explanation:
1. Na+-Cl− contact is along the edge: edge = 2(r+ + r−) = 2a.
2. Answer: (a)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 2a cm
(b) a/2 cm
(c) 3a cm
(d) a/4 cm
Show Answer & Explanation
Answer: (b) a/2 cm
Explanation:
1. Edge = 2(r+ + r−), so the interionic distance is a/2.
2. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 4.06 × 10−8 cm
(b) 1.32 × 10−14 cm
(c) 7.8 × 10−23 cm
(d) 9.6 × 10−24 cm
Show Answer & Explanation
Answer: (a) 4.06 × 10−8 cm
Explanation:
1. a3 = 4 × 58.5/(5.85 × 6.022 × 1023) = 6.64 × 10−23 cm3.
2. a = 4.05 × 10−8 cm ≈ 4.06 × 10−8 cm.
3. Answer: (a)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 7.60 g cm−3
(b) 1.80 g cm−3
(c) 9.60 g cm−3
(d) 6.38 g cm−3
Show Answer & Explanation
Answer: (b) 1.80 g cm−3
Explanation:
1. a = 6 × 10−8 cm, a3 = 2.16 × 10−22 cm3.
2. ρ = 4 × 58.5/(6.022 × 1023 × 2.16 × 10−22) = 1.80 g cm−3.
3. Answer: (b)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Frenkel defect
(b) Schottky defect
(c) Metal excess defect
(d) No defect
Show Answer & Explanation
Answer: (d) No defect
Explanation:
1. Point defects arise from thermal energy; at 0 K a perfect crystal is expected.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) There is no effect on the density
(b) The density of the crystal increases
(c) The density of the crystal decreases
(d) Any of the above three can happen
Show Answer & Explanation
Answer: (c) The density of the crystal decreases
Explanation:
1. Pairs of cations and anions leave the lattice, so mass falls at constant volume and density decreases.
2. Answer: (c)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) AgBr
(b) AgI
(c) ZnS
(d) All of these
Show Answer & Explanation
Answer: (d) All of these
Explanation:
1. Frenkel defect needs a small cation and large difference in ion sizes; AgBr, AgI and ZnS all show it.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Lattice sites containing electrons
(b) Interstitial sites containing electrons
(c) Lattice sites that are vacant
(d) Interstitial sites containing cations
Show Answer & Explanation
Answer: (a) Lattice sites containing electrons
Explanation:
1. An F-centre is an anion vacancy (a lattice site) occupied by an electron.
2. Answer: (a)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Electrons are held in the lattice site of crystals
(b) F-centre imparts colour to the crystal
(c) Conductivity of the crystal increases due to F-centre
(d) All the three above
Show Answer & Explanation
Answer: (d) All the three above
Explanation:
1. All three are true: trapped electrons occupy anion sites, absorb visible light (colour) and add some electrical conductivity.
2. Answer: (d)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) 6
(b) 8
(c) 12
(d) 18
Show Answer & Explanation
Answer: (c) 12
Explanation:
1. hcp has coordination number 12.
2. Answer: (c)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
(a) Cu4Ag2Au
(b) Cu4Ag4Au
(c) Cu4Ag3Au
(d) CuAgAu
Show Answer & Explanation
Answer: (c) Cu4Ag3Au
Explanation:
1. Cu in fcc: 4 per cell.
2. Ag at 12 edge centres: 12 × 1/4 = 3.
3. Au at body centre: 1.
4. Formula Cu4Ag3Au.
5. Answer: (c)
Teacher's Note:
1. Use the standard relations of the crystal lattice.
2. Check the answer against the known values for each lattice.
Free study material for Chemistry
Practice MCQs for JEE Chemistry The Solid State
JEE Chemistry The Solid State Objective Test Questions
Test your conceptual understanding of The Solid State with these targeted multiple-choice questions. Designed in alignment with the latest JEE curriculum for JEE Chemistry, these problem sets build accuracy and prepare students for objective exams.
NCERT-Aligned Objective Questions and Solutions
Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
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FAQs
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