JEE Chemistry The D and F Block Elements MCQs Set 09

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Chapter-wise Objective Questions: The D and F Block Elements

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Multiple Choice Questions

Question 1: KMnO4 is a strong oxidising agent in acid medium. To provide acid medium, H2SO4 is used instead of HCl because
(a) H2SO4 is a stronger acid than HCl
(b) HCl is oxidised by KMnO4 to Cl2
(c) H2SO4 is a dibasic acid
(d) The rate is faster in the presence of H2SO4
Show Answer & Explanation

Answer: (b) HCl is oxidised by KMnO4 to Cl2

Explanation:
1. Permanganate would oxidise HCl to chlorine and give wrong titre values.

Teacher's Note:
1. Use dilute sulphuric acid.

Question 2: When hydrogen peroxide is added to acidified potassium dichromate, a blue colour is produced due to the formation of
(a) CrO3
(b) Cr2O3
(c) CrO5
(d) CrO4 2-
Show Answer & Explanation

Answer: (c) CrO5

Explanation:
1. The blue peroxide CrO5 is formed.

Teacher's Note:
1. Test for H2O2.

Question 3: Identify the incorrect statement.
(a) 4f and 5f orbitals are equally shielded
(b) d-Block elements show irregular and erratic chemical properties among themselves
(c) La and Lu have partially filled d orbitals and no other partially filled orbitals
(d) The chemistry of various lanthanides is very similar
Show Answer & Explanation

Answer: (a) 4f and 5f orbitals are equally shielded

Explanation:
1. The 5f orbitals are less effectively shielded than the 4f orbitals.

Teacher's Note:
1. Hence actinoids show more variability.

Question 4: The actinoids exhibit more oxidation states than the lanthanoids because
(a) There is less energy difference between 6d and 5f orbitals
(b) The 5f orbitals are more buried than the 4f orbitals
(c) There is similarity in the angular part of the wave function
(d) The actinoids are more reactive
Show Answer & Explanation

Answer: (a) There is less energy difference between 6d and 5f orbitals

Explanation:
1. The 5f, 6d and 7s levels are close in energy.

Teacher's Note:
1. Smaller energy gap.

Question 5: In the reaction Cr2O7 2- gives CrO4 2- the change in oxidation number of Cr is
(a) +3
(b) -2
(c) +2
(d) 0
Show Answer & Explanation

Answer: (d) 0

Explanation:
1. Chromium is +6 in both ions, so it is not a redox reaction.

Teacher's Note:
1. Acid-base interconversion.

Question 6: Similar sizes of the second and third transition series can be explained on the basis of
(a) Inert pair effect
(b) Screening effect
(c) Lanthanide contraction
(d) Increasing effective nuclear charge
Show Answer & Explanation

Answer: (c) Lanthanide contraction

Explanation:
1. The 4f subshell is filled between the two series and shields poorly.

Teacher's Note:
1. Lanthanide contraction.

Question 7: Iron exhibits +2 and +3 oxidation states. Which statement about iron is incorrect?
(a) Ferrous compounds are more easily hydrolysed than the corresponding ferric compounds
(b) Ferrous oxide is more basic than ferric oxide
(c) Ferrous compounds are relatively more ionic than the corresponding ferric compounds
(d) Ferrous compounds are less volatile than the corresponding ferric compounds
Show Answer & Explanation

Answer: (a) Ferrous compounds are more easily hydrolysed than the corresponding ferric compounds

Explanation:
1. The more highly charged Fe3+ is hydrolysed more easily.

Teacher's Note:
1. Higher charge, more hydrolysis.

Question 8: Four successive members of the first row transition elements are Cr (24), Mn (25), Fe (26) and Co (27). Which is expected to have the highest positive E0 (M3+/M2+)?
(a) Cr
(b) Mn
(c) Fe
(d) Co
Show Answer & Explanation

Answer: (d) Co

Explanation:
1. Co3+/Co2+ has the highest value because Co3+ is a strong oxidant.

Teacher's Note:
1. Mn3+/Mn2+ is also high but lower.

Question 9: Which metal cation is reduced from its higher oxidation state (+2) to (+1) by both KI solution and excess KCN solution?
(a) Zn2+
(b) Hg2+
(c) Cu2+
(d) None
Show Answer & Explanation

Answer: (c) Cu2+

Explanation:
1. Cu2+ is reduced to Cu(I) by iodide and by cyanide.

Teacher's Note:
1. Cu(II) is a good oxidant toward I- and CN-.

Question 10: A test tube containing a nitrate and another containing a bromide and MnO2 are treated with conc. H2SO4. The reddish brown fumes evolved are passed through water. The water will be coloured by
(a) The nitrate
(b) The bromide
(c) Both
(d) None of the two
Show Answer & Explanation

Answer: (b) The bromide

Explanation:
1. The bromide gives red-brown bromine which colours water; with MnO2 the nitrate gives colourless HNO3.

Teacher's Note:
1. Bromine water is orange.

Question 11: Cr2+ is reducing in nature because
(a) Its configuration changes from d4 to d3 to achieve half-filled t2g
(b) Cr2+ gains an electron to achieve d5 configuration
(c) Cr2+ gives an electron to achieve d5 configuration
(d) Its configuration changes from d4 to d3 to achieve half-filled d-subshell
Show Answer & Explanation

Answer: (a) Its configuration changes from d4 to d3 to achieve half-filled t2g

Explanation:
1. Cr2+ (d4) is oxidised to Cr3+ (d3) with the stable half-filled t2g set.

Teacher's Note:
1. Cr(III) is stable.

Question 12: The highest stable Mn fluoride is MnF4 whereas the highest Mn oxide is Mn2O7 due to
(a) O atom is smaller than F
(b) Oxygen has the ability to form multiple bonds
(c) Mn7+ does not exist
(d) F cannot stabilise higher oxidation states
Show Answer & Explanation

Answer: (b) Oxygen has the ability to form multiple bonds

Explanation:
1. Oxygen can form pi bonds with the metal and stabilise Mn(VII).

Teacher's Note:
1. Multiple bonding.

Question 13: Which order of oxidising power is correct?
(a) CrO4- < MoO4- < WO4-
(b) VO2+ < Cr2O7 2- < MnO4-
(c) CrO3 < MnO2 < Fe2O3
(d) Pb4+ < Sn4+ < C4+
Show Answer & Explanation

Answer: (b) VO2+ < Cr2O7 2- < MnO4-

Explanation:
1. Oxidising power increases from V(V) to Cr(VI) to Mn(VII).

Teacher's Note:
1. Higher oxidation state, stronger oxidant.

Question 14: The Cu+ ion is not stable in aqueous solution due to
(a) d10 configuration
(b) Disproportionation
(c) Less charge
(d) Pseudo inert gas configuration
Show Answer & Explanation

Answer: (b) Disproportionation

Explanation:
1. 2Cu+ gives Cu2+ + Cu in water, because of the large hydration enthalpy of Cu2+.

Teacher's Note:
1. Cu+ disproportionates.

Question 15:
Assertion (A): La(OH)3 is more basic than Lu(OH)3
Reason (R): Lanthanum is a d-block element
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. The basicity falls from La to Lu because of the decreasing ionic size.
2. The reason is true by itself but does not explain it.

Teacher's Note:
1. Basicity falls across the series.

Question 16:
Assertion (A): Actinides show a much higher range of oxidation states
Reason (R): The energy difference between the 5f and 6d orbitals is large
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. The assertion is true.
2. The energy gap is small, so the reason is false.

Teacher's Note:
1. Close 5f and 6d.

Question 17:
Assertion (A): All the lanthanide elements exhibit a common oxidation state of +3 in their compounds
Reason (R): The atoms of the lanthanide elements contain three electrons in their outermost shell
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. The assertion is true.
2. They have two electrons in 6s and sometimes one in 5d, and the outer shell does not have three electrons.

Teacher's Note:
1. Reason is wrong.

Question 18:
Assertion (A): K2Cr2O7 is used as a primary standard in volumetric analysis
Reason (R): It has a good solubility in water
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. The assertion is true because it is not hygroscopic and is easily purified.
2. The reason is false; its solubility is moderate and is not the reason.

Teacher's Note:
1. Primary standard properties.

Question 19:
Assertion (A): A change in colour of acidified potassium dichromate solution by breath is used to test drunk drivers
Reason (R): The change in colour is due to the complexation of alcohol with potassium dichromate
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (c) A is true, but R is false.

Explanation:
1. The assertion is true.
2. The colour changes because alcohol is oxidised and Cr(VI) is reduced to Cr(III), not because of complexation.

Teacher's Note:
1. Orange to green.

Question 20:
Assertion (A): MnO2 is antiferromagnetic in nature
Reason (R): In MnO2 an equal number of domains are aligned with parallel and antiparallel spin
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. Equal opposed domains give an antiferromagnetic material.

Teacher's Note:
1. Spins cancel.

Question 21:
Assertion (A): La2O3 is basic in nature
Reason (R): La in aqueous solution gives La(OH)3
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (a) Both A and R are true, and R is the correct explanation of A.

Explanation:
1. The oxide gives the strongly basic hydroxide with water.

Teacher's Note:
1. La(OH)3 is a base.

Question 22:
Assertion (A): FeCl3 does not affect the iodometric titration of CuSO4 solution
Reason (R): FeI3 is formed
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (d) A is false, but R is true.

Explanation:
1. Fe3+ oxidises iodide to iodine, so it interferes.
2. FeI3 is not formed, since Fe3+ oxidises I-.

Teacher's Note:
1. Both false.

Question 23:
Assertion (A): Actinides can possess the +4 oxidation state more easily than lanthanides
Reason (R): 4f, 5d and 6s have almost the same energy levels
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. The 5f, 6d and 7s levels are the ones of comparable energy for the actinides, and this reason does not explain the assertion.

Teacher's Note:
1. Wrong sublevels quoted.

Question 24:
Assertion (A): UF6 is more covalent than UF4
Reason (R): Fluorine is smaller in size
(a) Both A and R are true, and R is the correct explanation of A.
(b) Both A and R are true, but R is not the correct explanation of A.
(c) A is true, but R is false.
(d) A is false, but R is true.
Show Answer & Explanation

Answer: (b) Both A and R are true, but R is not the correct explanation of A.

Explanation:
1. Higher oxidation state increases covalent character and polarisation.
2. The small fluorine size is true but is not the reason.

Teacher's Note:
1. Higher charge, more covalent.

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