Multiple Choice Questions (MCQs) for JEE Chemistry: Surface Chemistry
Explore reliable objective questions for Surface Chemistry tailored for JEE learners. Utilizing these Chemistry multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.
Practice Surface Chemistry MCQs for JEE Chemistry
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Multiple Choice Questions
(a) Pt
(b) Ag
(c) Au
(d) Fe
Show Answer & Explanation
Answer: (d) Fe
Explanation:
1. Bredig's arc method works for inert metals such as Pt, Ag and Au.
2. Iron is oxidised in the arc, so its sol cannot be made this way.
3. Answer: (d)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) emulsion – curd
(b) foam – mist
(c) aerosol – smoke
(d) sol – cake
Show Answer & Explanation
Answer: (c) aerosol – smoke
Explanation:
1. Smoke is a solid dispersed in a gas, i.e. an aerosol.
2. Curd is a gel, mist an aerosol (liquid in gas), and cake is a solid foam.
3. Answer: (c)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) coagulation value
(b) gold number
(c) critical micelle concentration
(d) oxidation number
Show Answer & Explanation
Answer: (b) gold number
Explanation:
1. Gold number is the minimum mass (mg) of a protective colloid that prevents coagulation of 10 mL of gold sol on adding 1 mL of 10% NaCl.
2. A smaller gold number means greater protecting power.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) x/m ∝ p0
(b) x/m ∝ p1/n
(c) x/m ∝ p1
(d) all the above are correct for different pressure ranges
Show Answer & Explanation
Answer: (d) all the above are correct for different pressure ranges
Explanation:
1. The isotherm is x/m = kp1/n with 1/n between 0 and 1.
2. At low pressure x/m ∝ p1, at intermediate pressure p1/n, and at high pressure p0.
3. Answer: (d)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) Na2SO4
(b) CaCl2
(c) Al2(SO4)3
(d) NH4Cl
Show Answer & Explanation
Answer: (c) Al2(SO4)3
Explanation:
1. Sb2S3 sol is negatively charged, so the cation does the coagulating (Hardy–Schulze rule).
2. Al3+ has the highest charge, so Al2(SO4)3 is the most effective.
3. Answer: (c)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) 1/n
(b) log K
(c) −log K
(d) n
Show Answer & Explanation
Answer: (a) 1/n
Explanation:
1. Taking logs of x/m = kP1/n gives log(x/m) = log k + (1/n) log P.
2. The slope is 1/n and the intercept is log k.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) platinum
(b) ZSM-5
(c) iron
(d) nickel
Show Answer & Explanation
Answer: (b) ZSM-5
Explanation:
1. ZSM-5 is a shape-selective zeolite catalyst.
2. It converts alcohols into a gasoline-range hydrocarbon mixture.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) adsorption is irreversible
(b) ΔH is of the order of 40 kJ
(c) adsorption is specific
(d) adsorption increases with increase of surface area
Show Answer & Explanation
Answer: (b) ΔH is of the order of 40 kJ
Explanation:
1. Chemisorption involves bond formation, with ΔH about 80–240 kJ mol−1.
2. An enthalpy of about 40 kJ is typical of physisorption.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) positive catalysis
(b) negative catalysis
(c) autocatalysis
(d) none of these
Show Answer & Explanation
Answer: (c) autocatalysis
Explanation:
1. When a product speeds up its own formation the process is autocatalysis.
2. An example is Mn2+ catalysing the oxalic acid and KMnO4 reaction.
3. Answer: (c)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) I-A, II-B, III-C, IV-D
(b) I-A, II-C, III-B, IV-D
(c) I-B, II-A, III-D, IV-C
(d) I-B, II-A, III-C, IV-D
Show Answer & Explanation
Answer: (c) I-B, II-A, III-D, IV-C
Explanation:
1. Smoke is a solid in gas (aerosol) and gelatin is a gel.
2. Soap lather is gas in liquid (foam) and milk is liquid in liquid (emulsion).
3. Answer: (c)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) I, III, IV
(b) II, III, IV, V
(c) I, IV, V
(d) II, IV, VI
Show Answer & Explanation
Answer: (a) I, III, IV
Explanation:
1. Urea, glucose and NaCl dissolve as molecules or ions below 1 nm, forming true solutions.
2. Gelatin, butter and blood are colloidal.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) A–Q, B–P, C–R, D–S
(b) A–P, B–Q, C–R, D–S
(c) A–S, B–R, C–Q, D–P
(d) A–Q, B–S, C–P, D–R
Show Answer & Explanation
Answer: (a) A–Q, B–P, C–R, D–S
Explanation:
1. Chemisorption is specific and needs activation (rises with temperature at first); physisorption is non-specific and falls with temperature.
2. Adsorption of a solute lowers surface tension; desorption raises it.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) A–R, B–P, C–S, D–Q
(b) A–P, B–Q, C–R, D–S
(c) A–S, B–R, C–Q, D–P
(d) A–Q, B–R, C–P, D–S
Show Answer & Explanation
Answer: (a) A–R, B–P, C–S, D–Q
Explanation:
1. Liquid in gas is an aerosol and gas in liquid is a foam.
2. Liquid in solid is a gel and liquid in liquid is an emulsion.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) A–R, B–P, C–Q, D–S
(b) A–P, B–Q, C–R, D–S
(c) A–S, B–Q, C–P, D–R
(d) A–S, B–P, C–Q, D–R
Show Answer & Explanation
Answer: (a) A–R, B–P, C–Q, D–S
Explanation:
1. Coagulation happens when the charge on particles is neutralised.
2. Electrophoresis arises from charge, the Tyndall effect from light scattering, and Brownian motion from molecular impacts.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) 5
(b) 10
(c) 100
(d) none of these
Show Answer & Explanation
Answer: (c) 100
Explanation:
1. KCl used = 10 × 0.5 = 5 millimoles.
2. Per litre of sol: 5 × (1000/50) = 100 millimoles/litre.
3. Answer: (c)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) ΔH < 0, ΔS > 0, ΔG > 0
(b) ΔH < 0, ΔS < 0, ΔG < 0
(c) ΔH > 0, ΔS > 0, ΔG > 0
(d) ΔH > 0, ΔS < 0, ΔG > 0
Show Answer & Explanation
Answer: (b) ΔH < 0, ΔS < 0, ΔG < 0
Explanation:
1. Adsorption is spontaneous (ΔG < 0) and exothermic (ΔH < 0).
2. The gas loses freedom on the surface, so ΔS < 0.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) metallic sulphides
(b) Pt
(c) acid dye
(d) all of these
Show Answer & Explanation
Answer: (d) all of these
Explanation:
1. Metal sulphide sols, platinum and gold sols and acid dyes carry a negative charge.
2. So all of these are negatively charged.
3. Answer: (d)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) 1 in case of physical adsorption
(b) 1 in case of chemisorption
(c) between 0 and 1 in all cases
(d) between 2 and 4 in all cases
Show Answer & Explanation
Answer: (c) between 0 and 1 in all cases
Explanation:
1. The isotherm is x/m = kP1/n with n > 1.
2. So 1/n always lies between 0 and 1.
3. Answer: (c)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) the adsorption sites are equivalent in their ability to adsorb the particles
(b) the heat of adsorption varies with adsorption
(c) the adsorbed molecules interact with each other
(d) the adsorption takes place in multilayers
Show Answer & Explanation
Answer: (a) the adsorption sites are equivalent in their ability to adsorb the particles
Explanation:
1. Langmuir assumed a homogeneous surface of equivalent sites with monolayer adsorption.
2. He assumed no interaction between adsorbed molecules and a constant heat of adsorption.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) critical temperature (Tc)
(b) temperature of the gas
(c) pressure of the gas
(d) all of these
Show Answer & Explanation
Answer: (d) all of these
Explanation:
1. Easily liquefiable gases (higher Tc) are adsorbed more.
2. Adsorption also depends on temperature and pressure.
3. Answer: (d)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) increases
(b) decreases
(c) first increases then decreases
(d) remains unchanged
Show Answer & Explanation
Answer: (b) decreases
Explanation:
1. Physisorption is exothermic and held by weak forces.
2. Raising the temperature favours desorption, so the extent decreases.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) A–P, B–Q, C–R
(b) A–Q, B–P, C–R
(c) A–R, B–P, C–Q
(d) A–R, B–Q, C–P
Show Answer & Explanation
Answer: (b) A–Q, B–P, C–R
Explanation:
1. x/m against P is a curve that levels off at high pressure (Q).
2. log(x/m) against log P is a straight line of slope 1/n (P); x/m = KC1/n is the form used for adsorption from solution (R).
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) coagulation
(b) ultrafiltration
(c) electrophoresis
(d) Tyndall effect
Show Answer & Explanation
Answer: (b) ultrafiltration
Explanation:
1. Ultrafiltration separates colloidal particles from dissolved impurities using special filters.
2. Coagulation destroys the sol, and electrophoresis and the Tyndall effect are properties, not purification methods.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) it occurs because of van der Waals forces
(b) easily liquefiable gases are adsorbed readily
(c) under high pressure it may result in multilayered adsorption on the adsorbent surface
(d) enthalpy of adsorption is positive
Show Answer & Explanation
Answer: (d) enthalpy of adsorption is positive
Explanation:
1. Adsorption is always exothermic, so the enthalpy of adsorption is negative.
2. The other three statements are correct.
3. Answer: (d)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) decreases
(b) increases
(c) remains unaffected
(d) decreases first and then increases
Show Answer & Explanation
Answer: (b) increases
Explanation:
1. Adsorption is exothermic, so low temperature favours it.
2. Higher pressure also increases the amount adsorbed.
3. Answer: (b)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
(a) 20–40
(b) 40–100
(c) 100–200
(d) 200–400
Show Answer & Explanation
Answer: (a) 20–40
Explanation:
1. Physisorption involves weak van der Waals forces.
2. Its enthalpy change is only about 20–40 kJ mol−1.
3. Answer: (a)
Teacher's Note:
1. Recall the definition or classification first and eliminate options that contradict it. Check the answer against a standard example.
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FAQs
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