Chemistry Objective Questions and Answers: S Block Elements
Access targeted multiple-choice questions for S Block Elements designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Download S Block Elements MCQs with Answers
Navigate directly to the 50 objective questions for S Block Elements using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) K2O
(b) K2O2
(c) KO2
(d) Na2O
Show Answer & Explanation
Answer: (c) KO2
Explanation:
1. KO2 contains O2-, which has one unpaired electron
2. The others have no unpaired electrons
Teacher's Note:
1. Superoxides are paramagnetic and coloured.
(a) Li3N
(b) LiNO3
(c) NaNO3
(d) none of these
Show Answer & Explanation
Answer: (a) Li3N
Explanation:
1. Li3N + 3H2O gives 3LiOH + NH3
Teacher's Note:
1. Nitrides give ammonia with water.
(a) Li+
(b) Be2+
(c) Na+
(d) K+
Show Answer & Explanation
Answer: (b) Be2+
Explanation:
1. Be2+ has a very high excitation energy
2. So it gives no colour
Teacher's Note:
1. Be and Mg do not impart colour.
(a) NaCl
(b) LiCl
(c) RbCl
(d) KCl
Show Answer & Explanation
Answer: (b) LiCl
Explanation:
1. Li+ is highly hydrated
2. LiCl crystallises as LiCl.2H2O
Teacher's Note:
1. Other alkali chlorides are anhydrous.
(a) Ba, Li
(b) Li, Be
(c) Cs, Ba
(d) Ba, Cs
Show Answer & Explanation
Answer: (a) Ba, Li
Explanation:
1. Ba is the strongest reductant in group 2
2. Li has the most negative reduction potential in group 1
Teacher's Note:
1. Hydration energy makes Li the strongest in water.
(a) the solution becomes blue
(b) the solution becomes a good conductor
(c) the solution remains colourless
(d) both (a) and (b) are correct
Show Answer & Explanation
Answer: (d) both (a) and (b) are correct
Explanation:
1. Alkaline earth metals dissolve in liquid NH3 giving blue solutions
2. The ammoniated electrons and ions make it conducting
Teacher's Note:
1. Solvated electrons cause the blue colour.
(a) K > Cs > Rb
(b) Cs > Rb > K
(c) K < Cs < Rb
(d) Rb > Cs > K
Show Answer & Explanation
Answer: (b) Cs > Rb > K
Explanation:
1. Ionisation energy decreases from K to Cs
2. So reducing power in gaseous state is Cs > Rb > K
Teacher's Note:
1. Gaseous state follows ionisation energy.
(a) Be > Mg > Ca > Sr
(b) Ca > Mg > Be > Sr
(c) Ca < Mg < Be < Sr
(d) Mg < Ca < Sr < Be
Show Answer & Explanation
Answer: (c) Ca < Mg < Be < Sr
Explanation:
1. Densities: Ca 1.55, Mg 1.74, Be 1.85, Sr 2.6 g/cm3
Teacher's Note:
1. Density does not vary regularly.
(a) it is a strong oxidising agent
(b) it can be extracted by electrolysis of aqueous solution
(c) its density is lower than K
(d) it is easily oxidised
Show Answer & Explanation
Answer: (d) it is easily oxidised
Explanation:
1. Na is a strong reducing agent, so it is easily oxidised
2. It is obtained from molten NaCl, and its density is higher than K
Teacher's Note:
1. Alkali metals are reducing agents.
(a) ammoniated electrons
(b) metal amide formation
(c) liberation of NH3 gas
(d) cluster formation of metal ions
Show Answer & Explanation
Answer: (d) cluster formation of metal ions
Explanation:
1. Concentrated solutions form metal ion clusters
2. The solution is bronze and diamagnetic
Teacher's Note:
1. Dilute solutions are blue.
(a) formation of NH3 gas
(b) formation of metal amide
(c) cluster formation of metal ions
(d) formation of metal nitrate
Show Answer & Explanation
Answer: (b) formation of metal amide
Explanation:
1. M + NH3 slowly gives MNH2 + H2
2. The amide formation removes the solvated electrons
Teacher's Note:
1. The reaction is slow without a catalyst.
(a) Al
(b) Ca
(c) Be
(d) Li
Show Answer & Explanation
Answer: (c) Be
Explanation:
1. Be + 2NaOH + 2H2O gives Na2[Be(OH)4] + H2
2. Be is amphoteric
Teacher's Note:
1. Al is not an s-block element.
(a) Ba
(b) Ca
(c) Mg
(d) Be
Show Answer & Explanation
Answer: (c) Mg
Explanation:
1. Melting points (K): Be 1560, Ca 1115, Ba 1000, Mg 923
2. Mg is the lowest
Teacher's Note:
1. Group 2 melting points are irregular.
(a) NaOH, Na2O, Li2O
(b) Na2CO3, Na2O2, Li2O
(c) Na2O, Li3N, NH3
(d) Na2O, Li2O, Li3N
Show Answer & Explanation
Answer: (d) Na2O, Li2O, Li3N
Explanation:
1. Na gives mainly Na2O (and Na2O2), Li gives Li2O and also Li3N with the nitrogen of air
Teacher's Note:
1. Dry air has no CO2 or moisture in effect.
(a) Na2O
(b) BaO2
(c) RbO2
(d) KO2
Show Answer & Explanation
Answer: (b) BaO2
Explanation:
1. BaO2 contains the peroxide ion
2. RbO2 and KO2 are superoxides
Teacher's Note:
1. Peroxide ion is O2 2-.
(a) a, b, c
(b) a, b, d
(c) c, d, e
(d) all
Show Answer & Explanation
Answer: (b) a, b, d
Explanation:
1. Metallic character, ionic radius and density generally increase down the group
2. Melting point and ionisation energy decrease
Teacher's Note:
1. Check each property separately.
(a) Li, Be
(b) Cs, Fr
(c) Be, Mg
(d) Ba, Ra
Show Answer & Explanation
Answer: (c) Be, Mg
Explanation:
1. Be and Mg have very high excitation energies
2. So they give no flame colour
Teacher's Note:
1. Others give characteristic colours.
(a) Al + NaOH
(b) Zn + NaOH
(c) Mg + NaOH
(d) LiH + H2O
Show Answer & Explanation
Answer: (c) Mg + NaOH
Explanation:
1. Mg is not amphoteric and does not react with NaOH
2. The others produce H2
Teacher's Note:
1. Zn and Al are amphoteric.
(a) high ionisation energy
(b) high electronegativity
(c) high charge density
(d) low ionisation potential
Show Answer & Explanation
Answer: (d) low ionisation potential
Explanation:
1. Large, low-ionisation cations (K, Rb, Cs) stabilise the large O2-
2. So they form superoxides
Teacher's Note:
1. Large cations stabilise large anions.
(a) LiHCO3
(b) CaCO3
(c) NaHCO3
(d) Na2CO3
Show Answer & Explanation
Answer: (a) LiHCO3
Explanation:
1. LiHCO3 exists only in solution
2. Bicarbonates of the others are stable solids
Teacher's Note:
1. Li shows anomalous behaviour.
(a) it becomes paramagnetic
(b) the solution turns blue due to solvated electrons
(c) it becomes diamagnetic
(d) the solution becomes conducting
Show Answer & Explanation
Answer: (c) it becomes diamagnetic
Explanation:
1. Dilute solutions are paramagnetic because of free solvated electrons
2. So 'it becomes diamagnetic' is not true
Teacher's Note:
1. Concentrated solutions may be diamagnetic, but it is not a general statement.
(a) low electronegativity
(b) one electron in the outermost orbit
(c) smaller atomic radii
(d) low ionisation energy
Show Answer & Explanation
Answer: (d) low ionisation energy
Explanation:
1. Low ionisation energy lets the outer electron be excited by the flame
2. The emission appears as colour
Teacher's Note:
1. Excitation needs little energy.
(a) K+
(b) Zn2+
(c) Ni2+
(d) Al3+
Show Answer & Explanation
Answer: (a) K+
Explanation:
1. KOH is a strong base and highly soluble
2. Others are sparingly soluble or amphoteric
Teacher's Note:
1. Alkali metal hydroxides dissolve freely.
(a) quick lime
(b) nitrolim
(c) limestone
(d) plaster of Paris
Show Answer & Explanation
Answer: (a) quick lime
Explanation:
1. CaO + H2O gives Ca(OH)2
Teacher's Note:
1. The process is exothermic.
(a) liberating CO2
(b) giving out water
(c) combining with water
(d) changing into CaCO3
Show Answer & Explanation
Answer: (c) combining with water
Explanation:
1. CaSO4.1/2H2O + 3/2 H2O gives CaSO4.2H2O (gypsum), which sets hard
Teacher's Note:
1. Setting is hydration.
(a) Li2CO3
(b) Na2CO3
(c) K2CO3
(d) Cs2CO3
Show Answer & Explanation
Answer: (a) Li2CO3
Explanation:
1. Li+ is small and polarises CO3 2- strongly
2. Li2CO3 decomposes to Li2O and CO2
Teacher's Note:
1. Stability rises down the group.
(a) Li
(b) Na
(c) K
(d) Ba
Show Answer & Explanation
Answer: (c) K
Explanation:
1. K, Rb and Cs form superoxides
2. Li gives oxide, Na gives peroxide
Teacher's Note:
1. Large cations stabilise the superoxide.
(a) Li2CO3 decomposes into oxides while other alkali carbonates are thermally stable
(b) LiCl is predominantly covalent
(c) Li3N is stable
(d) all of these
Show Answer & Explanation
Answer: (d) all of these
Explanation:
1. All three show lithium's anomalous behaviour due to small size and high polarising power
Teacher's Note:
1. Li resembles Mg (diagonal relationship).
Free study material for Chemistry
Practice MCQs for JEE Chemistry S Block Elements
Chapter MCQs with Answers for JEE Chemistry
Review structured objective questions for JEE Chemistry S Block Elements. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.
Expert Practice Material for JEE Chemistry
Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
Complete Your Chapter Revision
Follow up your worksheet practice by attempting the interactive online Chemistry MCQ test for this chapter to evaluate your execution speed. All platform resources are free to access.
FAQs
You can get most exhaustive JEE Chemistry S Block Elements MCQs Set 04 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.
Yes, our JEE Chemistry S Block Elements MCQs Set 04 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Chemistry S Block Elements MCQs Set 04, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.
Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Chemistry S Block Elements MCQs Set 04 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.