JEE Chemistry Organic Chemistry Some Basic Principles and Techniques Notes Set 05

Official JEE Chemistry Revision Material: JEE Chemistry Organic Chemistry Some Basic Principles and Techniques Notes Set 05

Explore reliable concept summaries and revision materials through the JEE Chemistry Organic Chemistry Some Basic Principles and Techniques Notes Set 05. Tailored for JEE learners, utilizing these notes for Chemistry Organic Chemistry ensures thorough preparation and strengthens core academic definitions before final evaluations.

Chapter-wise Concept Summaries: Organic Chemistry

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Purification of Organic Compounds

1. Simple distillation: used when the liquid has non-volatile impurities or the boiling points of the components differ by about 80 K or more. Examples: chloroform (334 K) and aniline (457 K); ether (308 K) and toluene (384 K).
2. Fractional distillation: used when the boiling points differ by only about 10 K or less; a fractionating column is used. Examples: crude oil fractions, acetone (329 K) and methanol (338 K).
3. Distillation under reduced pressure (vacuum distillation): used for liquids that decompose below their boiling point, for example glycerol, and for concentrating sugar juice.
4. Steam distillation: used for substances that are immiscible with water and steam volatile, for example aniline, nitrobenzene, bromobenzene, turpentine oil and o-nitrophenol.

Qualitative Analysis: Detection of Elements

1. Carbon and hydrogen: heat the compound with dry copper(II) oxide. Carbon gives CO2, which turns lime water milky; hydrogen gives water, which turns anhydrous \( CuSO_4 \) blue.
2. Lassaigne's test: the compound is fused with sodium metal, plunged into water and filtered. The covalent elements become ionic: \( Na + C + N \to NaCN \), \( 2Na + S \to Na_2S \), \( Na + X \to NaX \). The filtrate is the sodium fusion extract.
3. Nitrogen: boil the extract with \( FeSO_4 \), then add \( FeCl_3 \) and acidify; \( Na_4[Fe(CN)_6] \) gives Prussian blue, \( Fe_4[Fe(CN)_6]_3 \).
4. Sulphur: with lead acetate (acidified with acetic acid) a black precipitate of PbS forms; with sodium nitroprusside a violet colour forms.
5. If both N and S are present, sodium thiocyanate NaSCN forms and gives a blood red colour with \( FeCl_3 \) (no Prussian blue); an excess of sodium in the fusion decomposes it to NaCN and \( Na_2S \).
6. Halogens: boil the extract with conc. \( HNO_3 \) to expel \( H_2S \) and HCN, then add \( AgNO_3 \): AgCl white and soluble in ammonia; AgBr pale yellow and sparingly soluble; AgI yellow and insoluble.
7. Phosphorus: oxidise with \( Na_2O_2 \) to phosphate, then warm with conc. \( HNO_3 \) and ammonium molybdate to get a canary yellow precipitate of ammonium phosphomolybdate.

Quantitative Analysis: Formulae

Let W be the mass of the organic compound in grams.
1. Carbon and hydrogen (Liebig's method): the compound burns in excess \( CuO \); water is absorbed by anhydrous \( CaCl_2 \) and \( CO_2 \) by KOH solution. \[ \%C = \frac{12}{44}\times\frac{m_{CO_2}}{W}\times100,\qquad \%H = \frac{2}{18}\times\frac{m_{H_2O}}{W}\times100 \] 2. Nitrogen by Dumas method: nitrogen is collected over water; correct its volume to STP, using pressure minus aqueous tension. 22400 mL of N2 at STP weigh 28 g. \[ \%N = \frac{28}{22400}\times\frac{V_{STP}\,(mL)}{W}\times100 \] 3. Nitrogen by Kjeldahl's method: the nitrogen is converted to ammonium sulphate, ammonia is liberated with alkali and absorbed in a known volume of standard acid. \[ \%N = \frac{1.4\times N\times V}{W} \] where N is the normality of the acid and V is the volume of acid (mL) neutralised by ammonia. The method does not work for nitro, azo and azoxy compounds or for nitrogen in a ring (pyridine).
4. Halogens by Carius method: the compound is heated with fuming nitric acid and \( AgNO_3 \); the silver halide formed is weighed. \( \%X = \dfrac{\text{atomic mass of X}}{\text{molar mass of AgX}}\times\dfrac{m_{AgX}}{W}\times100 \).
5. Sulphur by Carius method: it is oxidised to sulphuric acid and precipitated as \( BaSO_4 \). \( \%S = \dfrac{32}{233}\times\dfrac{m_{BaSO_4}}{W}\times100 \).
6. Phosphorus is precipitated as magnesium pyrophosphate \( Mg_2P_2O_7 \): \( \%P = \dfrac{62}{222}\times\dfrac{m}{W}\times100 \). Oxygen is usually found by difference.

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Key Concepts and Summary for JEE Chemistry Organic Chemistry

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