Practice MCQs for JEE Chemistry Organic Chemistry Some Basic Principles and Techniques
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Multiple Choice Questions
(a) 6
(b) 4
(c) 3
(d) 5
Show Answer & Explanation
Answer: (b) 4
Explanation:
1. The two methyl groups can be at 1,1; 1,2; 1,3 and 1,4 positions.
2. That gives 4 positional isomers (stereoisomers are not counted).
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 5
(b) 3
(c) 4
(d) 2
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. The chlorine atoms can be at 1,2,3; 1,2,4 or 1,3,5 positions.
2. Hence 3 isomers.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 1
(b) 3
(c) 2
(d) 4
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. The ethers are CH\(_3\)OCH\(_2\)CH\(_2\)CH\(_3\), CH\(_3\)OCH(CH\(_3\))\(_2\) and C\(_2\)H\(_5\)OC\(_2\)H\(_5\).
2. So there are 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 2
(b) 5
(c) 3
(d) 4
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. The secondary amines are N-methylpropan-1-amine, N-methylpropan-2-amine and N-ethylethanamine.
2. So there are 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 5
(b) 2
(c) 3
(d) 4
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. They are 2-methylpentan-2-ol, 3-methylpentan-3-ol and 2,3-dimethylbutan-2-ol.
2. So there are 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 9
(b) 10
(c) 8
(d) 6
Show Answer & Explanation
Answer: (b) 10
Explanation:
1. Alkenes: pent-1-ene, pent-2-ene, 2-methylbut-1-ene, 3-methylbut-1-ene, 2-methylbut-2-ene (5).
2. Cycloalkanes: cyclopentane, methylcyclobutane, ethylcyclopropane, 1,1-dimethylcyclopropane, 1,2-dimethylcyclopropane (5).
3. Total 10.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 1
(b) 4
(c) 3
(d) 2
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. CH\(_2\)=CH-CH\(_2\)Cl, CH\(_3\)-CH=CHCl and CH\(_3\)-CCl=CH\(_2\) are the acyclic isomers.
2. So there are 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 1
(b) 4
(c) 2
(d) 3
Show Answer & Explanation
Answer: (a) 1
Explanation:
1. The only cyclic ketone is cyclopropanone.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 2
(b) 3
(c) 4
(d) 1
Show Answer & Explanation
Answer: (a) 2
Explanation:
1. The ring is cyclopropane with two chlorines: 1,1-dichlorocyclopropane and 1,2-dichlorocyclopropane.
2. The number of structural isomers is 2.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 7
(b) 9
(c) 6
(d) 8
Show Answer & Explanation
Answer: (a) 7
Explanation:
1. Hex-1-yne, hex-2-yne, hex-3-yne, 3-methylpent-1-yne, 4-methylpent-1-yne, 4-methylpent-2-yne and 3,3-dimethylbut-1-yne.
2. Total 7.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 4
(b) 3
(c) 6
(d) 7
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. Anthracene has three types of hydrogen (positions 1, 2 and 9, with 1/4/5/8 equivalent, 2/3/6/7 equivalent and 9/10 equivalent).
2. So there are 3 monochloro derivatives.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 3
(b) 2
(c) 4
(d) 5
Show Answer & Explanation
Answer: (a) 3
Explanation:
1. 1,2,3-, 1,2,4- and 1,3,5-tribromobenzene.
2. Total 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 10
(b) 9
(c) 7
(d) 8
Show Answer & Explanation
Answer: (b) 9
Explanation:
1. DU = (2C + 2 + N - H)/2 = (18 + 2 + 4 - 6)/2 = 9.
Teacher's Note:
1. Each N adds one to the hydrogen-equivalent count.
(a) 6
(b) 8
(c) 7
(d) 5
Show Answer & Explanation
Answer: (a) 6
Explanation:
1. Penta-1,2-diene, penta-1,3-diene, penta-1,4-diene, penta-2,3-diene, 3-methylbuta-1,2-diene and 2-methylbuta-1,3-diene.
2. Total 6.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 4
(b) 3
(c) 6
(d) 5
Show Answer & Explanation
Answer: (a) 4
Explanation:
1. Ethylbenzene and the o-, m- and p-xylenes.
2. Total 4.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 4
(b) 2
(c) 3
(d) 5
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. 1,2,3,4-; 1,2,3,5- and 1,2,4,5-tetramethylbenzene.
2. Total 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 7
(b) 10
(c) 9
(d) 8
Show Answer & Explanation
Answer: (c) 9
Explanation:
1. Formates of the four butyl groups (4), acetates of propyl and isopropyl (2), ethyl propanoate (1), and methyl butanoate and methyl 2-methylpropanoate (2).
2. Total 9.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 1
(b) 3
(c) 2
(d) 4
Show Answer & Explanation
Answer: (c) 2
Explanation:
1. Butan-1-ol and 2-methylpropan-1-ol.
2. Total 2.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 4
(b) 5
(c) 6
(d) 3
Show Answer & Explanation
Answer: (a) 4
Explanation:
1. Butan-1-ol, butan-2-ol, 2-methylpropan-1-ol and 2-methylpropan-2-ol.
2. Total 4.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 6
(b) 4
(c) 3
(d) 5
Show Answer & Explanation
Answer: (c) 3
Explanation:
1. The free positions 1/4, 5/8 and 6/7 are equivalent in pairs.
2. So there are 3 distinct isomers.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 14
(b) 10
(c) 8
(d) 12
Show Answer & Explanation
Answer: (b) 10
Explanation:
1. Naphthalene has two types of position (alpha and beta).
2. The distinct dinitro isomers are 1,2; 1,3; 1,4; 1,5; 1,6; 1,7; 1,8; 2,3; 2,6 and 2,7, i.e. 10.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 8
(b) 12
(c) 14
(d) 10
Show Answer & Explanation
Answer: (b) 12
Explanation:
1. The known count of dibromobiphenyl positional isomers is 12 (six with both Br on the same ring and six with one on each ring).
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 8
(b) 7
(c) 6
(d) 5
Show Answer & Explanation
Answer: (b) 7
Explanation:
1. Aldehydes: pentanal, 2-methylbutanal, 3-methylbutanal, 2,2-dimethylpropanal (4).
2. Ketones: pentan-2-one, pentan-3-one, 3-methylbutan-2-one (3).
3. Total 7.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
(a) 2
(b) 3
(c) 4
(d) 5
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. They are 2-methylheptane, 3-methylheptane and 4-methylheptane.
2. Total 3.
Teacher's Note:
1. Write out every possible structure systematically and avoid counting any twice.
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Organic Chemistry Some Basic Principles and Techniques Objective Questions & Solutions for JEE Chemistry
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