JEE Chemistry Hydrogen MCQs Set 08

Download JEE MCQs for JEE Chemistry: Hydrogen

Explore reliable objective questions for Hydrogen tailored for JEE learners. Utilizing these Chemistry multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

Chapter-wise Objective Questions: Hydrogen

Access the complete set of multiple-choice questions for Hydrogen below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.

Multiple Choice Questions

Question 1: The hydride ion H- is a stronger base than the hydroxide ion. Which of the following reactions will occur if NaH is dissolved in water?
(a) H-(aq) + H2O(l) → H3O+(aq)
(b) H-(aq) + H2O(l) → OH-(aq) + H2(g)
(c) H-(aq) + H2O(l) → no reaction
(d) None of these
Show Answer & Explanation

Answer: (b) H-(aq) + H2O(l) → OH-(aq) + H2(g)

Explanation:
1. H- is a stronger base than OH-, so it takes a proton from water.
2. NaH + H2O → NaOH + H2.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 2: Hydrogen peroxide is reduced by:
(a) Ozone
(b) Barium peroxide
(c) Acidic solution of KMnO4
(d) Lead sulphide
Show Answer & Explanation

Answer: (d) Lead sulphide

Explanation:
1. PbS + 4H2O2 → PbSO4 + 4H2O: H2O2 is the oxidising agent, so it is itself reduced.
2. Ozone, BaO2 and acidified KMnO4 oxidise or are oxidised by H2O2, and H2O2 acts as a reducing agent towards them.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 3: Water softening by Clarke's process uses:
(a) Calcium bicarbonate
(b) Sodium bicarbonate
(c) Potash alum
(d) Calcium hydroxide
Show Answer & Explanation

Answer: (d) Calcium hydroxide

Explanation:
1. Clarke's method removes temporary hardness by adding the calculated amount of slaked lime, which precipitates CaCO3 and Mg(OH)2.
2. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 4: Which of the following isotopes of hydrogen is radioactive?
(a) 1H1
(b) 1H2
(c) 1H3
(d) Both 1H2 and 1H3
Show Answer & Explanation

Answer: (c) 1H3

Explanation:
1. Tritium (1H3) is a beta emitter with a half-life of about 12.3 years.
2. Protium and deuterium are stable.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 5: Which reaction is not used in the preparation of H2?
(a) Zn + NaOH
(b) Mg + NaOH
(c) Al + NaOH
(d) Be + NaOH
Show Answer & Explanation

Answer: (b) Mg + NaOH

Explanation:
1. Zn, Al and Be are amphoteric and react with NaOH liberating H2.
2. Mg is not amphoteric and does not react with NaOH.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 6: Which of the following is the water gas shift reaction?
(a) CO + H2O → CO2 + H2
(b) C + H2O → CO
(c) CO + O2 → CO2
(d) CO + H2 → CH3OH
Show Answer & Explanation

Answer: (a) CO + H2O → CO2 + H2

Explanation:
1. In the water-gas shift reaction carbon monoxide reacts with steam over a catalyst to give more hydrogen: CO + H2O → CO2 + H2.
2. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 7: Which of the following cannot be oxidised by H2O2?
(a) Na2SO3
(b) PbS
(c) KI
(d) O3
Show Answer & Explanation

Answer: (d) O3

Explanation:
1. Na2SO3, PbS and KI are all oxidised by H2O2.
2. Ozone is a stronger oxidising agent and is reduced by H2O2 instead: H2O2 + O3 → H2O + 2O2.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 8: Which of the following reactions represents the oxidising property of H2O2?
(a) KMnO4 + H2SO4 + H2O2 → K2SO4 + MnSO4 + H2O + O2
(b) K3[Fe(CN)6] + KOH + H2O2 → K4[Fe(CN)6] + H2O + O2
(c) PbO2 + H2O2 → PbO + H2O + O2
(d) None of these
Show Answer & Explanation

Answer: (d) None of these

Explanation:
1. In all three reactions H2O2 is oxidised to O2, i.e. it acts as a reducing agent.
2. So none shows the oxidising property.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 9: Calgon, used as a water softener, is:
(a) Na6P6O18
(b) Na4P6O18
(c) Na6P4O18
(d) Na6P5O10
Show Answer & Explanation

Answer: (a) Na6P6O18

Explanation:
1. Calgon is sodium hexametaphosphate, Na6P6O18 (also written Na2[Na4(PO3)6]).
2. It holds Ca2+ and Mg2+ in a soluble complex.
3. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 10: Which of the following is not present in clear hard water?
(a) Mg(HCO3)2
(b) CaCl2
(c) MgSO4
(d) MgCO3
Show Answer & Explanation

Answer: (d) MgCO3

Explanation:
1. MgCO3 is insoluble in water, so it cannot be dissolved in clear hard water.
2. The other three salts are soluble and cause hardness.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 11: What is formed when calcium carbide reacts with heavy water?
(a) C2D2
(b) CaD2
(c) Ca2D2O
(d) CD2
Show Answer & Explanation

Answer: (a) C2D2

Explanation:
1. CaC2 + 2D2O → Ca(OD)2 + C2D2.
2. The deuterium from heavy water ends up in deuterated ethyne.
3. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 12: The adsorption of hydrogen by metals is called:
(a) Dehydrogenation
(b) Hydrogenation
(c) Occlusion
(d) Absorption
Show Answer & Explanation

Answer: (c) Occlusion

Explanation:
1. The uptake of gases, especially hydrogen, by metals such as Pd and Pt is called occlusion.
2. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 13: An ionic compound is dissolved simultaneously in heavy water and simple water. Its solubility is:
(a) Higher in heavy water
(b) Lesser in heavy water
(c) The same in both
(d) Lesser in simple water
Show Answer & Explanation

Answer: (b) Lesser in heavy water

Explanation:
1. Heavy water has a lower dielectric constant and stronger intermolecular bonding, so ionic salts dissolve less in it.
2. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 14: Hydrogen can be obtained by mixing steam and water gas at 673 K in the presence of Fe2O3 and Cr2O3. This process is called:
(a) Nelson's process
(b) Serpeck's process
(c) Bosch's process
(d) Parke's process
Show Answer & Explanation

Answer: (c) Bosch's process

Explanation:
1. This is the water-gas shift step of Bosch's process: CO + H2O → CO2 + H2.
2. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 15: Which of the following hydrides is electron precise?
(a) B2H6
(b) NH3
(c) H2O
(d) CH4
Show Answer & Explanation

Answer: (d) CH4

Explanation:
1. In CH4 the number of electrons is exactly enough to form normal two-centre bonds with all four hydrogens.
2. B2H6 is electron deficient and NH3 and H2O are electron rich.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 16: The compound that gives H2O2 on treatment with dilute H2SO4 is:
(a) PbO2
(b) BaO2·8H2O
(c) MnO2
(d) TiO2
Show Answer & Explanation

Answer: (b) BaO2·8H2O

Explanation:
1. BaO2·8H2O + H2SO4 → BaSO4 + H2O2 + 8H2O.
2. This is a classical laboratory preparation of H2O2.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 17: Which of the following equations depicts the oxidising nature of H2O2?
(a) 2MnO4- + 6H+ + 5H2O2 → 2Mn2+ + 8H2O + 5O2
(b) 2Fe3+ + 2H+ + H2O2 → 2Fe2+ + 2H2O + O2
(c) 2I- + 2H+ + H2O2 → I2 + 2H2O
(d) 2KIO4 + H2O2 → 2KIO3 + H2O + O2
Show Answer & Explanation

Answer: (c) 2I- + 2H+ + H2O2 → I2 + 2H2O

Explanation:
1. In the iodide reaction H2O2 is reduced to water while I- is oxidised to I2.
2. In the other three options H2O2 is oxidised to O2, i.e. it acts as a reducing agent.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 18: Which of the following equations depicts the reducing nature of H2O2?
(a) 2[Fe(CN)6]4- + 2H+ + H2O2 → 2[Fe(CN)6]3- + 2H2O
(b) I2 + H2O2 + 2OH- → 2I- + 2H2O + O2
(c) Mn2+ + H2O2 → Mn4+ + 2OH-
(d) PbS + 4H2O2 → PbSO4 + 4H2O
Show Answer & Explanation

Answer: (b) I2 + H2O2 + 2OH- → 2I- + 2H2O + O2

Explanation:
1. In the iodine reaction H2O2 is oxidised to O2 and I2 is reduced to I-.
2. In the other three options H2O2 is reduced to water, so it acts as an oxidising agent.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Multiple Choice Questions (MCQs) for JEE Chemistry Hydrogen

Download Multiple Choice Questions: Hydrogen (JEE Chemistry)

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FAQs

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