JEE Chemistry Haloalkanes and Haloarenes MCQs Set 07

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Multiple Choice Questions

Question 1: Which of the following is not present in a Grignard reagent?
(a) Methyl group
(b) Magnesium
(c) Halogen
(d) -COOH group
Show Answer & Explanation

Answer: (d) -COOH group

Explanation:
1. A Grignard reagent \( \ce{RMgX} \) would be destroyed by acidic groups like -COOH, so it cannot contain one.

Teacher's Note:
1. Grignard reagents need dry ether and are destroyed by water, alcohols and any acidic hydrogen.
2. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.

Question 2: Which halide would be expected to have the lowest reactivity?
(a) Propyl chloride
(b) Propyl iodide
(c) Isopropyl chloride
(d) Isopropyl bromide
Show Answer & Explanation

Answer: (c) Isopropyl chloride

Explanation:
1. The C-Cl bond is stronger than C-Br or C-I, so the chlorides are less reactive; and the secondary chloride is hindered towards SN2 and less able to ionise than the bromide, so isopropyl chloride is the least reactive here.

Teacher's Note:
1. SN1 follows carbocation stability (3 degree > 2 degree > 1 degree), while SN2 is fastest for the least crowded carbon.
2. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.

Question 3: Chlorobenzene is
(a) Less reactive than benzyl chloride
(b) More reactive than ethyl bromide
(c) Nearly as reactive as methyl chloride
(d) More reactive than isopropyl chloride
Show Answer & Explanation

Answer: (a) Less reactive than benzyl chloride

Explanation:
1. The C-Cl bond in chlorobenzene has partial double-bond character (resonance, sp2 carbon), so it is much less reactive than alkyl or benzyl halides.

Teacher's Note:
1. Aryl and vinyl halides are inert in ordinary nucleophilic substitution because the C-X bond has partial double-bond character.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 4: The reactivities of methyl chloride, propyl chloride and chlorobenzene are in the order
(a) Methyl chloride > propyl chloride > chlorobenzene
(b) Propyl chloride > methyl chloride > chlorobenzene
(c) Methyl chloride > chlorobenzene > propyl chloride
(d) Chlorobenzene > propyl chloride > methyl chloride
Show Answer & Explanation

Answer: (a) Methyl chloride > propyl chloride > chlorobenzene

Explanation:
1. For SN2, methyl > primary alkyl (less steric hindrance); chlorobenzene is least reactive.

Teacher's Note:
1. SN1 follows carbocation stability (3 degree > 2 degree > 1 degree), while SN2 is fastest for the least crowded carbon.
2. Haloform and carbylamine reactions are tests; know the reagent, the product and the observation.

Question 5: Carbylamine is liberated when ...... is heated with chloroform and alcoholic potash
(a) An aldehyde
(b) A primary amine
(c) A secondary amine
(d) A phenol
Show Answer & Explanation

Answer: (b) A primary amine

Explanation:
1. The carbylamine reaction (isocyanide test) is specific to primary amines.

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Question 6: Salicylic acid can be prepared by a Reimer-Tiemann type reaction by treating phenol with
(a) Methyl chloride in the presence of anhydrous aluminium chloride
(b) Carbon dioxide under pressure in sodium hydroxide solution
(c) Carbon tetrachloride and sodium hydroxide
(d) Sodium nitrite and a few drops of concentrated sulphuric acid
Show Answer & Explanation

Answer: (c) Carbon tetrachloride and sodium hydroxide

Explanation:
1. With \( \ce{CCl4} \) in place of \( \ce{CHCl3} \) the intermediate \( \ce{-CCl3} \) group is hydrolysed to -COOH, giving salicylic acid.

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.

Question 7: Grignard reagent is prepared by the reaction between
(a) Zinc and alkyl halide
(b) Magnesium and alkyl halide
(c) Magnesium and alkane
(d) Magnesium and aromatic hydrocarbon
Show Answer & Explanation

Answer: (b) Magnesium and alkyl halide

Explanation:
1. \( \ce{RX + Mg ->[dry ether] RMgX} \).

Teacher's Note:
1. Grignard reagents need dry ether and are destroyed by water, alcohols and any acidic hydrogen.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 8: War gas is formed from
(a) \( \ce{PH3} \)
(b) \( \ce{C2H2} \)
(c) Zinc phosphate
(d) Chloropicrin
Show Answer & Explanation

Answer: (d) Chloropicrin

Explanation:
1. Chloropicrin, \( \ce{CCl3NO2} \), is a tear/war gas; it is made from the chlorination/nitration of chloroform or picric acid.

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.

Question 9: What happens when \( \ce{CCl4} \) is treated with \( \ce{AgNO3} \)?
(a) \( \ce{NO2} \) will be evolved
(b) A white precipitate of AgCl will be formed
(c) \( \ce{CCl4} \) will dissolve in \( \ce{AgNO3} \)
(d) Nothing will happen
Show Answer & Explanation

Answer: (d) Nothing will happen

Explanation:
1. \( \ce{CCl4} \) is covalent and does not give Cl- ions, so no precipitate forms.

Teacher's Note:
1. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.
2. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.

Question 10: If we use pyrene (\( \ce{CCl4} \)) in the Reimer-Tiemann reaction in place of chloroform, the product formed is
(a) Salicylaldehyde
(b) Phenolphthalein
(c) Salicylic acid
(d) Cyclohexanol
Show Answer & Explanation

Answer: (c) Salicylic acid

Explanation:
1. The trichloromethyl group introduced ortho to OH is hydrolysed to COOH.

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.

Question 11: The bad-smelling substance formed by the action of alcoholic caustic potash on chloroform and aniline is
(a) Phenyl isocyanide
(b) Nitrobenzene
(c) Phenyl cyanide
(d) Phenyl isocyanate
Show Answer & Explanation

Answer: (a) Phenyl isocyanide

Explanation:
1. Carbylamine reaction: \( \ce{C6H5NH2 + CHCl3 + 3KOH -> C6H5NC + 3KCl + 3H2O} \).

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Haloform and carbylamine reactions are tests; know the reagent, the product and the observation.

Question 12: Ethylidene chloride on treatment with aqueous KOH gives
(a) Ethylene glycol
(b) Acetaldehyde
(c) Formaldehyde
(d) None
Show Answer & Explanation

Answer: (b) Acetaldehyde

Explanation:
1. \( \ce{CH3CHCl2} \) hydrolyses to the unstable gem-diol, which loses water to give \( \ce{CH3CHO} \).

Teacher's Note:
1. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Question 13: The reaction \( \ce{C2H5I + C5H11I + 2Na -> C2H5-C5H11 + 2NaI} \) is called
(a) Hoffmann's reaction
(b) Dow's reaction
(c) Wurtz's reaction
(d) Riemer-Tiemann's reaction
Show Answer & Explanation

Answer: (c) Wurtz's reaction

Explanation:
1. Coupling of two alkyl halides with sodium in dry ether is the Wurtz reaction.

Teacher's Note:
1. Wurtz coupling joins two alkyl groups with sodium in dry ether; fluorides do not react and mixed halides give a mixture of alkanes.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Question 14: The dehydrobromination of 2-bromobutane gives \( \ce{CH3CH=CHCH3} \). The product is
(a) Hofmann product
(b) Saytzeff product
(c) Hoffmann-Saytzeff product
(d) Markownikoff product
Show Answer & Explanation

Answer: (b) Saytzeff product

Explanation:
1. The more substituted alkene (2-butene) is the Saytzeff product.

Teacher's Note:
1. Alcoholic KOH eliminates HX to give the more substituted alkene (Saytzeff rule); aqueous KOH substitutes.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 15: Ethylene difluoride on hydrolysis gives
(a) Glycol
(b) Fluoroethanol
(c) Difluoroethanol
(d) Freon
Show Answer & Explanation

Answer: (a) Glycol

Explanation:
1. Both F atoms (on different carbons, \( \ce{FCH2CH2F} \)) are replaced by OH: ethylene glycol.

Teacher's Note:
1. Haloform and carbylamine reactions are tests; know the reagent, the product and the observation.
2. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.

Question 16: Benzyl chloride when oxidised by \( \ce{Pb(NO3)2} \) (aq) gives
(a) Benzoic acid
(b) Benzaldehyde
(c) Benzene
(d) None
Show Answer & Explanation

Answer: (b) Benzaldehyde

Explanation:
1. Mild oxidation of the CH2Cl group gives \( \ce{C6H5CHO} \).

Teacher's Note:
1. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Question 17: \( \ce{CCl4} \) cannot give a precipitate with \( \ce{AgNO3} \) due to
(a) Formation of complex with \( \ce{AgNO3} \)
(b) Evolution of \( \ce{Cl2} \) gas
(c) Chloride ion is not formed
(d) \( \ce{AgNO3} \) does not give silver ion
Show Answer & Explanation

Answer: (c) Chloride ion is not formed

Explanation:
1. \( \ce{CCl4} \) is covalent and does not furnish Cl- ions in solution.

Teacher's Note:
1. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 18: On heating \( \ce{CHCl3} \) with aqueous NaOH, the product is
(a) \( \ce{CH3COONa} \)
(b) \( \ce{HCOONa} \)
(c) Sodium oxalate
(d) \( \ce{CH3OH} \)
Show Answer & Explanation

Answer: (b) \( \ce{HCOONa} \)

Explanation:
1. \( \ce{CHCl3 + 4NaOH -> HCOONa + 3NaCl + 2H2O} \).

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 19: Ethyl bromide reacts with lead-sodium alloy to form
(a) Tetraethyl lead
(b) Tetraethyl bromide
(c) Both (a) and (b)
(d) None of the above
Show Answer & Explanation

Answer: (a) Tetraethyl lead

Explanation:
1. \( \ce{4C2H5Br + 4Na/Pb -> (C2H5)4Pb + 4NaBr + 3Pb} \), the antiknock compound.

Teacher's Note:
1. Haloform and carbylamine reactions are tests; know the reagent, the product and the observation.
2. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.

Question 20: Ethyl bromide reacts with silver nitrite to form
(a) Nitroethane
(b) Nitroethane and ethyl nitrite in equal amounts
(c) Ethyl nitrite
(d) Ethane
Show Answer & Explanation

Answer: (a) Nitroethane

Explanation:
1. Covalent AgNO2 attacks through N, giving nitroethane as the main product (KNO2 would give the nitrite ester).

Teacher's Note:
1. Ionic cyanide and nitrite attack through C and O/N respectively differently from the covalent silver salts: KCN gives nitriles, AgCN isocyanides, KNO2 nitrites and AgNO2 nitro compounds.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Question 21: Which of the following reactions leads to the formation of chloretone?
(a) \( \ce{CHCl3 + CH3COCH3} \)
(b) \( \ce{CCl4 + acetone} \)
(c) \( \ce{CHCl3 + KOH} \)
(d) \( \ce{CHCl3 + HNO3} \)
Show Answer & Explanation

Answer: (a) \( \ce{CHCl3 + CH3COCH3} \)

Explanation:
1. Chloroform adds to acetone in the presence of base to give chloretone, \( \ce{(CH3)2C(OH)CCl3} \).

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.

Question 22: \( \ce{CH3CH2CH2Br + KOH(alc.) ->} \) product. The product is
(a) \( \ce{CH3-CH=CH2} \)
(b) \( \ce{CH3-CH2-CH3} \)
(c) (a) and (b) both
(d) None of these
Show Answer & Explanation

Answer: (a) \( \ce{CH3-CH=CH2} \)

Explanation:
1. Alcoholic KOH brings about dehydrobromination giving propene.

Teacher's Note:
1. Alcoholic KOH eliminates HX to give the more substituted alkene (Saytzeff rule); aqueous KOH substitutes.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 23: Identify X and Y in \( \ce{C2H5Br ->[X] product ->[Y] C3H7NH2} \)
(a) X = KCN, Y = \( \ce{LiAlH4} \)
(b) X = KCN, Y = \( \ce{H3O+} \)
(c) X = \( \ce{CH3Cl} \), Y = \( \ce{AlCl3/HCl} \)
(d) X = \( \ce{CH3NH2} \), Y = \( \ce{HNO2} \)
Show Answer & Explanation

Answer: (a) X = KCN, Y = \( \ce{LiAlH4} \)

Explanation:
1. \( \ce{C2H5Br + KCN -> C2H5CN} \), then reduction with \( \ce{LiAlH4} \) gives \( \ce{C3H7NH2} \) (propylamine).

Teacher's Note:
1. Ionic cyanide and nitrite attack through C and O/N respectively differently from the covalent silver salts: KCN gives nitriles, AgCN isocyanides, KNO2 nitrites and AgNO2 nitro compounds.
2. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.

Question 24: 1-Chlorobutane reacts with alcoholic KOH to form
(a) 1-Butene
(b) 2-Butene
(c) 1-Butanol
(d) 2-Butanol
Show Answer & Explanation

Answer: (a) 1-Butene

Explanation:
1. Alcoholic KOH causes E2 elimination; from a primary halide the product is the terminal alkene.

Teacher's Note:
1. Alcoholic KOH eliminates HX to give the more substituted alkene (Saytzeff rule); aqueous KOH substitutes.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Question 25: Which of the following reactions gives \( \ce{H2C=C=C=CH2} \)?
(a) \( \ce{CH2Br-CBr=CH2} \) with Zn/\( \ce{CH3OH} \)
(b) \( \ce{HC#C-CH2-COOH} \) with \( \ce{Ag2CO3} \) at 40°C
(c) \( \ce{CH2Br-C#C-CH2Br} \) with Zn, heat
(d) \( \ce{2CH2=CH-CH2I} \) with Na
Show Answer & Explanation

Answer: (c) \( \ce{CH2Br-C#C-CH2Br} \) with Zn, heat

Explanation:
1. Zn removes the two Br atoms from 1,4-dibromobut-2-yne, creating cumulene \( \ce{CH2=C=C=CH2} \).

Teacher's Note:
1. Chloroform, DDT, BHC and chloropicrin are asked repeatedly: memorise their preparations and uses.
2. Remember the ambident nucleophiles: KCN gives nitriles, AgCN gives isocyanides, KNO2 gives nitrites, AgNO2 gives nitroalkanes.

Question 26: Chlorobenzene on fusing with solid NaOH gives
(a) Benzene
(b) Benzoic acid
(c) Phenol
(d) Benzene chloride
Show Answer & Explanation

Answer: (c) Phenol

Explanation:
1. Dow-type substitution gives sodium phenoxide, which on acidification gives phenol.

Teacher's Note:
1. Aryl and vinyl halides are inert in ordinary nucleophilic substitution because the C-X bond has partial double-bond character.
2. Haloform and carbylamine reactions are tests; know the reagent, the product and the observation.

Question 27: DDT can be prepared by reacting chlorobenzene (in the presence of conc. \( \ce{H2SO4} \)) with
(a) \( \ce{Cl2} \) in UV light
(b) Chloroform
(c) Trichloroacetaldehyde
(d) Acetaldehyde
Show Answer & Explanation

Answer: (c) Trichloroacetaldehyde

Explanation:
1. Chloral (trichloroacetaldehyde) condenses with two molecules of chlorobenzene.

Teacher's Note:
1. DDT is made from chloral and chlorobenzene with conc. sulphuric acid; it is a persistent insecticide.
2. Separate substitution (aqueous KOH, AgCN, KCN) from elimination (alcoholic KOH) before reading the options.

Question 28: When phenol is treated with \( \ce{CHCl3} \) and NaOH, the product obtained would be mainly
(a) Salicylaldehyde
(b) p-Hydroxybenzaldehyde
(c) Both (a) and (b)
(d) Chloretone
Show Answer & Explanation

Answer: (c) Both (a) and (b)

Explanation:
1. Reimer-Tiemann formylation goes ortho (major) and para (minor), giving both aldehydes.

Teacher's Note:
1. Chloroform is oxidised by air and light to poisonous phosgene, so it is stored in dark, full bottles with a little ethanol.
2. Chlorobenzene and vinyl chloride are unreactive because the C-Cl bond has partial double-bond character.

Practice MCQs for JEE Chemistry Haloalkanes and Haloarenes

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