Download JEE MCQs for JEE Chemistry: General Principles and Processes Of Isolation Of Elements
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Chapter-wise Objective Questions: General Principles and Processes Of Isolation Of Elements
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Multiple Choice Questions
(a) 50 C, 100 C
(b) 50 C, 200 C
(c) 200 C, 50 C
(d) 100 C, 50 C
Show Answer & Explanation
Answer: (b) 50 C, 200 C
Explanation:
1. Nickel carbonyl forms near 330 K (about 50 degrees Celsius) and decomposes near 470 K (about 200 degrees Celsius).
Teacher's Note:
1. The carbonyl is volatile, leaving impurities behind.
(a) \( \ce{MgCO3 + SiO2 -> MgSiO3 + CO2} \)
(b) \( \ce{3Mn3O4 + 8Al -> 9Mn + 4Al2O3} \)
(c) \( \ce{Cu2S + 2Cu2O -> 6Cu + SO2} \)
(d) \( \ce{Fe2O3 + 3CO -> 2Fe + 3CO2} \)
Show Answer & Explanation
Answer: (b) \( \ce{3Mn3O4 + 8Al -> 9Mn + 4Al2O3} \)
Explanation:
1. The thermite (aluminothermic) process reduces a metal oxide with aluminium powder, releasing a lot of heat.
Teacher's Note:
1. The reaction is used to obtain Mn, Cr, and for welding rails.
(a) Fe
(b) Al
(c) Sn
(d) Zn
Show Answer & Explanation
Answer: (b) Al
Explanation:
1. Aluminium oxide is too stable (very negative \( \Delta G_f \)), so carbon cannot reduce it at practical temperatures.
Teacher's Note:
1. Al is obtained by electrolysis of alumina in cryolite.
(a) self-reduction-s, carbon-p, electrolytic-r, complex formation-q
(b) self-reduction-p, carbon-s, electrolytic-r, complex formation-q
(c) self-reduction-p, carbon-r, electrolytic-s, complex formation-q
(d) self-reduction-q, carbon-s, electrolytic-r, complex formation-p
Show Answer & Explanation
Answer: (b) self-reduction-p, carbon-s, electrolytic-r, complex formation-q
Explanation:
1. Copper glance self-reduces, haematite is reduced by CO/C, Al is electrolysed, and silver is leached with cyanide and displaced by zinc.
Teacher's Note:
1. These are the four main routes of extraction.
(a) \( \ce{TiCl4 + 2Mg -> Ti + 2MgCl2} \) : Kroll
(b) \( \ce{ZrI4 -> Zr + 2I2} \) : Van Arkel
(c) \( \ce{Ni(CO)4 -> Ni + 4CO} \) : Mond
(d) \( \ce{Ag2CO3 -> 2Ag + CO2 + 1/2 O2} \) : Van Arkel
Show Answer & Explanation
Answer: (d) \( \ce{Ag2CO3 -> 2Ag + CO2 + 1/2 O2} \) : Van Arkel
Explanation:
1. Heating silver carbonate is simple thermal decomposition. Van Arkel refers to decomposition of a volatile metal iodide on a hot filament.
Teacher's Note:
1. Mond (Ni) and Van Arkel (Ti, Zr) are vapour phase refining methods.
(a) 2
(b) 4
(c) 5
(d) 3
Show Answer & Explanation
Answer: (d) 3
Explanation:
1. Cuprite \( \ce{Cu2O} \), cassiterite \( \ce{SnO2} \) and chromite \( \ce{FeCr2O4} \) are oxides. Carnallite is a chloride, cinnabar HgS, chalcocite \( \ce{Cu2S} \) and chalcopyrite sulphides, calamine and cerussite carbonates.
Teacher's Note:
1. Group ores by anion before learning their extraction.
(a) Na2SO4
(b) KCl
(c) NaOH
(d) NaCN
Show Answer & Explanation
Answer: (c) NaOH
Explanation:
1. Hot concentrated NaOH dissolves alumina as sodium aluminate, leaving iron oxide and silica behind: \( \ce{Al2O3 + 2NaOH + 3H2O -> 2Na[Al(OH)4]} \).
Teacher's Note:
1. Cyanide is used for Ag and Au, and NaOH for bauxite.
(a) coagulation
(b) absorption
(c) sedimentation
(d) adsorption
Show Answer & Explanation
Answer: (d) adsorption
Explanation:
1. The pine oil and collectors adsorb on the ore particles, which attach to air bubbles and rise.
Teacher's Note:
1. Adsorption of the collector on the sulphide surface makes it water repellent.
(a) \( \ce{2Ag + 2HCl + [O] -> 2AgCl + H2O} \)
(b) \( \ce{2Zn + O2 -> 2ZnO} \)
(c) \( \ce{2ZnS + 3O2 -> 2ZnO + 2SO2} \)
(d) \( \ce{MgCO3 -> MgO + CO2} \)
Show Answer & Explanation
Answer: (d) \( \ce{MgCO3 -> MgO + CO2} \)
Explanation:
1. Decomposition of a carbonate on heating without much air is calcination; (c) is roasting.
Teacher's Note:
1. Calcination of dolomite gives MgO and CaO.
(a) X
(b) Y
(c) none
(d) Z
Show Answer & Explanation
Answer: (b) Y
Explanation:
1. In self-reduction the metal compound itself acts as the reducing agent, which happens in (Y): \( \ce{PbS + 2PbO -> 3Pb + SO2} \).
Teacher's Note:
1. X and Z use an external reductant (carbon or CO).
(a) Mg
(b) Na
(c) Cu
(d) Ag
Show Answer & Explanation
Answer: (d) Ag
Explanation:
1. Silver (and gold) dissolve as dicyano complexes.
Teacher's Note:
1. Cyanide complexation is for noble metals.
(a) transition metals
(b) highly electronegative elements
(c) noble metals
(d) highly electropositive elements
Show Answer & Explanation
Answer: (d) highly electropositive elements
Explanation:
1. Very electropositive metals (Na, K, Mg, Al) have stable compounds and need electrical energy to reduce them.
Teacher's Note:
1. Strong chemical reductants cannot reduce these ions.
(a) the change of \( \Delta G \) with pressure
(b) the change of \( \Delta G \) with temperature
(c) the change of \( (\Delta G-T\Delta S) \) with temperature
(d) the change of \( \Delta H \) with temperature
Show Answer & Explanation
Answer: (b) the change of \( \Delta G \) with temperature
Explanation:
1. It is a plot of the standard free energy of formation of oxides (per mole of oxygen) against temperature.
Teacher's Note:
1. A metal whose line lies lower on the diagram can reduce the oxide of any metal whose line is higher.
(a) \( \ce{Cu2I2} \)
(b) \( \ce{CuI2} \)
(c) \( \ce{K2[CuI4]} \)
(d) none of these
Show Answer & Explanation
Answer: (a) \( \ce{Cu2I2} \)
Explanation:
1. Copper(II) oxidises iodide to iodine and itself becomes copper(I) iodide, a white precipitate.
Teacher's Note:
1. \( \ce{2Cu^{2+} + 4I^- -> Cu2I2 + I2} \).
(a) (i), (ii) and (iii) only
(b) (ii) and (iv) only
(c) (i) and (iv) only
(d) (i), (ii), (iii) and (iv)
Show Answer & Explanation
Answer: (a) (i), (ii) and (iii) only
Explanation:
1. Coke burns, oxide is reduced and limestone forms slag; sublimation does not occur.
Teacher's Note:
1. These happen in different zones of the furnace.
(a) electro-refining
(b) hydrometallurgy
(c) zone refining
(d) electrometallurgy
Show Answer & Explanation
Answer: (b) hydrometallurgy
Explanation:
1. This is leaching followed by displacement, e.g. gold and silver cyanide complexes with zinc.
Teacher's Note:
1. Hydrometallurgy uses aqueous solutions.
(a) \( \ce{Al2O3 + 2NaOH -> 2NaAlO2 + H2O} \)
(b) \( \ce{HgS + O2 -> Hg + SO2} \)
(c) \( \ce{CuCO3.Cu(OH)2 -> 2CuO + CO2 + H2O} \)
(d) \( \ce{AgNO3 + NaCl -> AgCl + NaNO3} \)
Show Answer & Explanation
Answer: (c) \( \ce{CuCO3.Cu(OH)2 -> 2CuO + CO2 + H2O} \)
Explanation:
1. Calcination is heating in absence or limited supply of air to drive off volatile matter (CO2 and water here).
Teacher's Note:
1. Roasting needs excess air; calcination does not.
(a) 4
(b) 3
(c) 2
(d) 5
Show Answer & Explanation
Answer: (b) 3
Explanation:
1. Hg (cinnabar), Cu (copper glance) and Pb (galena) are obtained by self-reduction.
Teacher's Note:
1. Zn, Fe and Sn use carbon, and Al and Mg are electrolytic.
(a) Dow process
(b) Hall-Heroult process
(c) complex formation with cyanide and displacement by zinc (MacArthur-Forrest process)
(d) Hoop's process
Show Answer & Explanation
Answer: (c) complex formation with cyanide and displacement by zinc (MacArthur-Forrest process)
Explanation:
1. Argentite is leached with NaCN in air to form \( \ce{Na[Ag(CN)2]} \), then silver is displaced by zinc.
Teacher's Note:
1. Air is passed to oxidise the sulphide ion produced.
(a) metal oxide
(b) metal silicate
(c) metal nitrate
(d) metal carbonate
Show Answer & Explanation
Answer: (b) metal silicate
Explanation:
1. An acidic gangue (silica) combines with a basic flux, or basic oxide with silica, to give silicate slag such as \( \ce{CaSiO3} \) or \( \ce{FeSiO3} \).
Teacher's Note:
1. Gangue + flux gives slag.
(a) Zone refining
(b) Van Arkel
(c) Poling
(d) Cupellation
Show Answer & Explanation
Answer: (b) Van Arkel
Explanation:
1. Formation of a volatile iodide and its decomposition on a hot filament is the Van Arkel method.
Teacher's Note:
1. It is used for ultra pure Ti and Zr.
(a) Siderite
(b) Magnetite
(c) Galena
(d) Malachite
Show Answer & Explanation
Answer: (c) Galena
Explanation:
1. Galena, PbS, is a sulphide.
Teacher's Note:
1. Sulphide ores are floated using pine oil.
(a) it is endothermic
(b) entropy increases
(c) all of these are correct
(d) to make \( \Delta G^\circ \) negative the temperature must be high enough so that \( T\Delta S^\circ>\Delta H^\circ \)
Show Answer & Explanation
Answer: (c) all of these are correct
Explanation:
1. Gas is produced (entropy rises), bonds are broken (endothermic), and \( \Delta G=\Delta H-T\Delta S \) becomes negative at high T.
Teacher's Note:
1. This explains why oxides of noble metals decompose on heating.
(a) sulphide and carbonate ores
(b) carbonate and hydroxide ores
(c) carbonate and oxide ores
(d) carbonate and sulphide ores
Show Answer & Explanation
Answer: (d) carbonate and sulphide ores
Explanation:
1. The gas that turns lime water milky and does not reduce permanganate is \( \ce{CO2} \), so X is a basic carbonate (malachite). Y gives \( \ce{SO2} \) (reduces iodate) and the metal by self-reduction, so Y is a sulphide (copper glance).
Teacher's Note:
1. Greenish blue flame indicates copper.
(a) 3
(b) 5
(c) 4
(d) 7
Show Answer & Explanation
Answer: (b) 5
Explanation:
1. II and III are correct, I and IV are wrong (cyanide is for Au and Ag; zone refining gives pure Ge).
Teacher's Note:
1. Sum = 2 + 3 = 5.
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