JEE Chemistry General Principles and Processes of Isolation of Elements MCQs Set 11

Chemistry Objective Questions and Answers: General Principles and Processes Of Isolation Of Elements

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Multiple Choice Questions

Question 1: Which of the following pairs of metals is purified by the Van Arkel method?
(a) Ga and In
(b) Zr and Ti
(c) Ag and Au
(d) Ni and Fe
Show Answer & Explanation

Answer: (b) Zr and Ti

Explanation:
1. Van Arkel method converts the metal to a volatile iodide on heating with \(\ce{I2}\)
2. The iodide is then decomposed on a hot tungsten filament to give pure metal
3. It is used for ultra-pure metals such as Zr and Ti

Teacher's Note:
1. Van Arkel is used for metals that form volatile iodides and are contaminated with oxygen and nitrogen, such as Ti and Zr.

Question 2: Which of the following elements is present as the impurity to the maximum extent in pig iron?
(a) Manganese
(b) Carbon
(c) Silicon
(d) Phosphorus
Show Answer & Explanation

Answer: (b) Carbon

Explanation:
1. Pig iron contains about 4 percent carbon
2. Silicon, phosphorus, manganese and sulphur are present only to a smaller extent

Teacher's Note:
1. The carbon in pig iron makes it brittle. It is removed to give wrought iron and steel.

Question 3: List I shows reactions involved in the metallurgy of lead and List II shows names of processes. Match List I with List II and select the correct code.
P: \(\ce{PbS + 2PbO ->[\Delta] 3Pb + SO2}\)
Q: \(\ce{PbS + 3/2 O2 ->[\Delta] PbO + SO2}\)
R: \(\ce{PbCO3 ->[\Delta] PbO + CO2}\)
S: \(\ce{PbO + C ->[\Delta] Pb + CO}\)
1 Smelting, 2 Self reduction, 3 Calcination, 4 Roasting
(a) P-2, Q-3, R-4, S-1
(b) P-2, Q-4, R-3, S-1
(c) P-4, Q-2, R-1, S-3
(d) P-4, Q-3, R-2, S-1
Show Answer & Explanation

Answer: (b) P-2, Q-4, R-3, S-1

Explanation:
1. P: PbS reduces PbO without any added reducing agent, so it is self reduction (2)
2. Q: sulphide is heated in air to give oxide: roasting (4)
3. R: carbonate decomposes by heating without air: calcination (3)
4. S: oxide is reduced by carbon: smelting (1)

Teacher's Note:
1. Calcination = heating a carbonate or hydroxide ore without air; roasting = heating a sulphide ore in excess air; smelting = reducing the oxide with carbon at high temperature.

Question 4: Which of the following conversions involves calcination and carbon reduction?
(a) \(\ce{ZnCO3 -> Zn}\)
(b) \(\ce{PbS -> PbO}\)
(c) \(\ce{Cu2S -> Cu}\)
(d) \(\ce{CaCO3 -> Ca}\)
Show Answer & Explanation

Answer: (a) \(\ce{ZnCO3 -> Zn}\)

Explanation:
1. \(\ce{ZnCO3 ->[\Delta] ZnO + CO2}\) is calcination
2. \(\ce{ZnO + C -> Zn + CO}\) is carbon reduction
3. \(\ce{PbS -> PbO}\) is only roasting, \(\ce{Cu2S -> Cu}\) is auto-reduction after roasting and \(\ce{CaCO3 -> Ca}\) needs electrolysis

Teacher's Note:
1. Carbonate ores are first calcined to the oxide, and then the oxide is reduced by carbon (for metals like Zn, Fe, Pb).

Question 5: Zone refining is used for refining which of the following metals?
(a) Ge
(b) Cu
(c) Ni
(d) Ti
Show Answer & Explanation

Answer: (a) Ge

Explanation:
1. Zone refining gives ultra-pure materials
2. It works because impurities are more soluble in the melt than in the solid
3. It is used for semiconductors such as Ge, Si, Ga and B

Teacher's Note:
1. Zone refining is used for semiconductor-grade materials. Ni is refined by the Mond process and Ti by the Van Arkel method.

Question 6: Which of the following is a copper ore?
(a) Haematite
(b) Magnetite
(c) Iron pyrite
(d) Azurite
Show Answer & Explanation

Answer: (d) Azurite

Explanation:
1. Haematite (\(\ce{Fe2O3}\)), magnetite (\(\ce{Fe3O4}\)) and iron pyrite (\(\ce{FeS2}\)) are ores of iron
2. Azurite, \(\ce{Cu(OH)2.2CuCO3}\), is an ore of copper

Teacher's Note:
1. Common ores of copper are copper pyrites, malachite, azurite, cuprite and copper glance.

General Principles and Processes Of Isolation Of Elements Objective Questions & Solutions for JEE Chemistry

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