JEE Chemistry Coordination Compounds MCQs Set 34

Chemistry Objective Questions and Answers: Coordination Compounds

Explore reliable objective questions for Coordination Compounds tailored for JEE learners. Utilizing these Chemistry multiple-choice formats ensures thorough preparation and strengthens problem-solving speed for upcoming school assessments.

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Access the complete set of multiple-choice questions for Coordination Compounds below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.

Multiple Choice Questions

Question 1: The most stable ion is:
(a) [Fe(C2O4)3]3-
(b) [FeCl6]3-
(c) [Fe(SCN)6]3-
(d) [Fe(H2O)6]3+
Show Answer & Explanation

Answer: (a) [Fe(C2O4)3]3-

Explanation:
1. The oxalate is a chelating ligand, so its Fe3+ complex has the largest formation constant.
2. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 2: Which of the following does not have optical isomers?
(a) [Co(en)3]Cl3
(b) [Co(NH3)3Cl3]
(c) [Co(en)(NH3)2Cl2]Cl
(d) All have optical isomers
Show Answer & Explanation

Answer: (b) [Co(NH3)3Cl3]

Explanation:
1. fac- and mer-[Co(NH3)3Cl3] each have a plane of symmetry.
2. The other two are chiral in the cis arrangement.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 3: The hybridisation and geometry of [Fe(CO)4]2- are:
(a) sp3d, trigonal bipyramidal
(b) sp3, tetrahedral
(c) dsp2, square planar
(d) sp3, trigonal bipyramidal
Show Answer & Explanation

Answer: (b) sp3, tetrahedral

Explanation:
1. Fe in this ion is Fe(-II) with 3d10.
2. The 4s and 4p orbitals hybridise to sp3, giving a tetrahedral shape.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 4: When 0.1 mol of CoCl3(NH3)5 is treated with excess AgNO3, 0.2 mol of AgCl is obtained. The conductivity of the solution corresponds to:
(a) 1:3 electrolyte
(b) 1:2 electrolyte
(c) 1:1 electrolyte
(d) 3:1 electrolyte
Show Answer & Explanation

Answer: (b) 1:2 electrolyte

Explanation:
1. Two chloride ions per formula precipitate, so the complex is [Co(NH3)5Cl]Cl2.
2. It gives one complex cation and two Cl-, a 1:2 electrolyte.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 5: Which of the following shows optical isomerism?
(a) [Cu(NH3)4]2+
(b) [ZnCl4]2-
(c) [Cr(C2O4)3]3-
(d) [Co(CN)6]3-
Show Answer & Explanation

Answer: (c) [Cr(C2O4)3]3-

Explanation:
1. Tris-chelate octahedral complexes are chiral.
2. The others are square planar, tetrahedral or Ma6, which have mirror planes.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 6: Pick the poor electrolyte among the following complexes in solution:
(a) K2[PtCl6]
(b) [Co(NH3)3(NO2)3]
(c) K4[Fe(CN)6]
(d) [Co(NH3)4]SO4
Show Answer & Explanation

Answer: (b) [Co(NH3)3(NO2)3]

Explanation:
1. [Co(NH3)3(NO2)3] is a neutral complex and does not ionise.
2. The others dissociate into several ions.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 7: CuSO4 solution reacts with excess KCN solution to form:
(a) Cu(CN)2
(b) K2[Cu(CN)4]
(c) K3[Cu(CN)4]
(d) K[Cu(CN)2]
Show Answer & Explanation

Answer: (c) K3[Cu(CN)4]

Explanation:
1. Cu2+ is reduced to Cu+ by CN- (cyanogen forms).
2. With excess KCN, Cu+ forms the stable tetracyanocuprate(I), K3[Cu(CN)4].
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 8: The number of ions formed on dissolving one molecule of FeSO4·(NH4)2SO4·6H2O in water is:
(a) 4
(b) 5
(c) 3
(d) 6
Show Answer & Explanation

Answer: (b) 5

Explanation:
1. It is a double salt that dissociates completely.
2. Fe2+, 2NH4+ and 2SO42- give 5 ions.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 9: EDTA is a ........... ligand:
(a) Monodentate
(b) Hexadentate
(c) Bidentate
(d) Tridentate
Show Answer & Explanation

Answer: (b) Hexadentate

Explanation:
1. EDTA has four carboxylate O and two N donor atoms, six donor atoms in all.
2. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 10: Among [Ni(CN)4]2-, [NiCl4]2- and [Ni(CO)4], which statement is correct?
(a) [Ni(CN)4]2- is square planar, while [NiCl4]2- and [Ni(CO)4] are tetrahedral
(b) [NiCl4]2- is square planar, while [Ni(CN)4]2- and [Ni(CO)4] are tetrahedral
(c) [Ni(CO)4] is square planar, while the other two are tetrahedral
(d) None of these
Show Answer & Explanation

Answer: (a) [Ni(CN)4]2- is square planar, while [NiCl4]2- and [Ni(CO)4] are tetrahedral

Explanation:
1. Strong field CN- pairs the d8 electrons, giving dsp2 square planar.
2. Weak field Cl- gives sp3 tetrahedral, and Ni(0) in Ni(CO)4 is d10, sp3 tetrahedral.
3. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 11: What is the most likely structure of CrCl3·6H2O if one third of its total chlorine is precipitated by adding AgNO3 to its aqueous solution?
(a) CrCl3·6H2O
(b) [Cr(H2O)Cl3]·(H2O)3
(c) [CrCl2(H2O)4]Cl·2H2O
(d) [CrCl(H2O)5]Cl2·H2O
Show Answer & Explanation

Answer: (c) [CrCl2(H2O)4]Cl·2H2O

Explanation:
1. One of three Cl is ionisable, outside the coordination sphere.
2. The other two are bound to Cr, with four water molecules also coordinated.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 12: The colour of [Ti(H2O)6]3+ is due to:
(a) Transfer of an electron from one Ti to another
(b) Excitation of an electron from d to d
(c) Intramolecular vibration
(d) None of these
Show Answer & Explanation

Answer: (b) Excitation of an electron from d to d

Explanation:
1. Ti3+ is d1.
2. The single electron is promoted from t2g to eg, a d-d transition absorbing visible light.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 13: Which statement is not correct in the case of the [Co(NH3)6]3+ complex?
(a) It is octahedral in shape
(b) It involves d2sp3 hybridisation
(c) It has diamagnetic nature
(d) All are correct
Show Answer & Explanation

Answer: (d) All are correct

Explanation:
1. Co3+ (d6) with strong field NH3 is low spin: t2g6, no unpaired electrons.
2. The complex is octahedral with d2sp3 hybridisation and is diamagnetic, so none of the first three statements is wrong.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 14: Which ion is paramagnetic?
(a) [Ni(H2O)6]2+
(b) [Fe(CN)6]4-
(c) [Ni(CO)4]
(d) [Ni(CN)4]2-
Show Answer & Explanation

Answer: (a) [Ni(H2O)6]2+

Explanation:
1. Ni2+ is d8 with two unpaired electrons in the octahedral aqua complex.
2. The other three are diamagnetic: Fe2+ low spin, Ni(0) d10, and square planar Ni2+.
3. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 15: For which transition metal ions are low spin complexes possible?
(a) Rh3+
(b) Pt2+
(c) Ru2+
(d) All are correct
Show Answer & Explanation

Answer: (d) All are correct

Explanation:
1. 4d and 5d metal ions have large Δo, so low spin complexes are formed readily.
2. Rh3+, Pt2+ and Ru2+ all fall in this group.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 16: Which ligand produces a high crystal field splitting (a strong field ligand)?
(a) CO
(b) NO2-
(c) CN-
(d) All of these
Show Answer & Explanation

Answer: (d) All of these

Explanation:
1. CO, NO2- and CN- lie at the strong field end of the spectrochemical series.
2. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 17: Which order is correct in the spectrochemical series of ligands?
(a) Cl- < F- < C2O42- < NO2- < CN-
(b) CN- < C2O42- < Cl- < NO2- < F-
(c) C2O42- < F- < Cl- < NO2- < CN-
(d) F- < Cl- < NO2- < CN- < C2O42-
Show Answer & Explanation

Answer: (a) Cl- < F- < C2O42- < NO2- < CN-

Explanation:
1. The series in increasing field strength is I- < Br- < Cl- < F- < OH- < C2O42- < H2O < NH3 < en < NO2- < CN- < CO.
2. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 18: K3[CoF6] is a high spin complex. What is the hybrid state of Co in this complex?
(a) sp3d
(b) sp3d2
(c) d2sp3
(d) dsp2
Show Answer & Explanation

Answer: (b) sp3d2

Explanation:
1. Co3+ (d6) with weak field F- stays high spin and uses the outer 4d orbitals.
2. Hybridisation is sp3d2.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 19: The structure of iron pentacarbonyl is:
(a) Square planar
(b) Trigonal bipyramidal
(c) Triangular
(d) Octahedral
Show Answer & Explanation

Answer: (b) Trigonal bipyramidal

Explanation:
1. Fe(CO)5 has 5 sigma bonds, with dsp3 hybridisation.
2. This gives a trigonal bipyramidal shape.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 20: Ruthenium carbonyl is:
(a) Ru(CO)4
(b) Ru(CO)5
(c) Ru(CO)8
(d) Ru(CO)6
Show Answer & Explanation

Answer: (b) Ru(CO)5

Explanation:
1. Ru (4d75s1) has 8 valence electrons.
2. Five CO donate 10 electrons to reach 18, so the stable carbonyl is Ru(CO)5.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 21: Which of the following is a double salt?
(a) Carnallite
(b) Mohr's salt
(c) Alum
(d) All are correct
Show Answer & Explanation

Answer: (d) All are correct

Explanation:
1. Carnallite KCl·MgCl2·6H2O, Mohr's salt FeSO4·(NH4)2SO4·6H2O and alum K2SO4·Al2(SO4)3·24H2O all give the ions of their component salts in solution.
2. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 22: Carbon donor ligands are strong ligands and usually form low spin complexes. Among the complexes given, the high spin complex is:
(a) [Fe(CN)6]3-
(b) [Fe(CN)6]4-
(c) [Fe(C2O4)3]3-
(d) None of these
Show Answer & Explanation

Answer: (c) [Fe(C2O4)3]3-

Explanation:
1. Cyanide complexes of iron are low spin.
2. The oxalate ligand binds through oxygen and is weaker, so [Fe(C2O4)3]3- is high spin.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 23: The compound [CoCl2(NH3)2(en)]+ can show:
(a) Linkage isomerism
(b) Coordination isomerism
(c) Optical isomerism
(d) Ionisation isomerism
Show Answer & Explanation

Answer: (c) Optical isomerism

Explanation:
1. It is of type M(AA)a2b2.
2. The cis arrangement of the two Cl is chiral, so optical isomers exist. No ambidentate ligand or counter ion is involved.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 24: The colour of the halogens is due to:
(a) Polarisation
(b) HOMO to LUMO transition
(c) Charge transfer
(d) d-d transition
Show Answer & Explanation

Answer: (b) HOMO to LUMO transition

Explanation:
1. Halogens absorb visible light, promoting an electron from the highest occupied pi* orbital to the lowest unoccupied sigma* orbital.
2. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 25: For which of the following species does d-d transition not account for the colour?
(a) Cr2O72-
(b) CrO42-
(c) CrO2Cl2
(d) All of the above
Show Answer & Explanation

Answer: (d) All of the above

Explanation:
1. Cr is +6 (d0) in all three, so no d-d transition is possible.
2. Their colours arise from ligand to metal charge transfer.
3. Answer: (d)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 26: Which of the following ions is not coloured?
(a) [Ni(DMG)2]
(b) [Co(SCN)4]2-
(c) [Al(OH)4]-
(d) [Fe(H2O)5(SCN)]2+
Show Answer & Explanation

Answer: (c) [Al(OH)4]-

Explanation:
1. Al3+ has no d electrons, so there is no d-d or ordinary charge transfer in the visible region.
2. The other three are coloured complexes of transition metals.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 27: Which of the following compounds is coloured and paramagnetic?
(a) KMnO4
(b) AgI
(c) CuSO4·5H2O
(d) [Ni(CN)4]2-
Show Answer & Explanation

Answer: (c) CuSO4·5H2O

Explanation:
1. Cu2+ (d9) has one unpaired electron and a d-d transition gives the blue colour.
2. KMnO4 is coloured but diamagnetic (Mn(VII), d0).
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 28: AgBr and AgI are coloured because of:
(a) d-d transition
(b) Charge transfer
(c) Polarisation of halide by metal ion
(d) HOMO to LUMO transition
Show Answer & Explanation

Answer: (c) Polarisation of halide by metal ion

Explanation:
1. Ag+ is d10, so no d-d transition occurs.
2. The large halide ions are polarised by Ag+, which shifts absorption into the visible region.
3. Answer: (c)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 29: Na2S forms a violet complex when it reacts with:
(a) Brown ring complex
(b) Sodium nitroprusside
(c) K4[Fe(CN)6]
(d) Hypo solution
Show Answer & Explanation

Answer: (b) Sodium nitroprusside

Explanation:
1. S2- reacts with Na2[Fe(CN)5NO] to give violet Na4[Fe(CN)5NOS].
2. This is the standard test for sulphide ion.
3. Answer: (b)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

Question 30: Which is used in cancer chemotherapy?
(a) Cis-platin
(b) Zeise's salt
(c) Both 1 and 2
(d) None of these
Show Answer & Explanation

Answer: (a) Cis-platin

Explanation:
1. Cis-platin, cis-[Pt(NH3)2Cl2], binds to DNA and stops cancer cell division.
2. Zeise's salt has no such use.
3. Answer: (a)

Teacher's Note:
1. Work through each option against the rule or structure involved before choosing. Remember the exceptions your textbook lists.

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