JEE Chemistry Classification of Elements and Periodicity in Properties MCQs Set 11

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Multiple Choice Questions

Question 1: Mendeleev's periodic table is based on:
(a) Atomic number
(b) Increasing order of number of protons
(c) Electronic configuration
(d) None of the above
Show Answer & Explanation

Answer: (d) None of the above

Explanation:
1. Mendeleev arranged elements by increasing atomic mass, not atomic number or electronic configuration.
2. So none of the first three options is the basis.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 2: Which of the following is/are Dobereiners triad :- (a) P, As, Sb (b) Cu, Ag, Au (c) Fe, Co, Ni (d) S, Se, Te Correct answer is:
(a) a and b
(b) b and c
(c) a and d
(d) All
Show Answer & Explanation

Answer: (c) a and d

Explanation:
1. A Dobereiner triad has three similar elements with the middle atomic mass close to the mean of the other two.
2. P, As, Sb (31, 75, 122) and S, Se, Te (32, 79, 128) fit.
3. Cu, Ag, Au and Fe, Co, Ni are not triads. So (a) and (d).

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 3: Which are correct match :- (a) Eka silicon – Be (b) Eka aluminium – Ga (c) Eka mangenese – Tc (d) Eka scandium – B?
(a) b, c
(b) a, b, d
(c) a, d
(d) All
Show Answer & Explanation

Answer: (a) b, c

Explanation:
1. Eka aluminium is gallium and eka manganese is technetium, so (b) and (c) are correct.
2. Eka silicon is germanium, not beryllium, and eka boron is scandium.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 4: Atomic wt. of P is 31 and Sb is 120. What will be the atomic wt. of As, as per Dobereiners triad rule:
(a) 151
(b) 75.5
(c) 89.5
(d) Unpredictable
Show Answer & Explanation

Answer: (b) 75.5

Explanation:
1. By the triad rule the middle mass is the mean of the outer two.
2. As = (31 + 120)/2 = 75.5.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 5: The places that were left empty by Mendeleev's were, for:
(a) Aluminium & Silicon
(b) Galium and germinium
(c) Arsenic and antimony
(d) Molybdenum and tungstun
Show Answer & Explanation

Answer: (b) Galium and germinium

Explanation:
1. Mendeleev left gaps for eka aluminium and eka silicon.
2. They were later filled by gallium and germanium.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 6: Which is not anomalous pair of elements in the Medeleev's periodic table:
(a) Ar and K
(b) Co and Ni
(c) Te and I
(d) Al and Si
Show Answer & Explanation

Answer: (d) Al and Si

Explanation:
1. The anomalous pairs, placed against the order of atomic mass, are Ar-K, Co-Ni and Te-I.
2. Al-Si follows the order of increasing mass, so it is not anomalous.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 7: The law of triads is applicable to:
(a) Os, Ir, Pt
(b) Ca, Sr, Ba
(c) Fe, Co, Ni
(d) Ru, Rh, Pt
Show Answer & Explanation

Answer: (b) Ca, Sr, Ba

Explanation:
1. Dobereiner's law holds for groups of three similar elements like Ca, Sr, Ba.
2. Ca (40), Sr (87.6) and Ba (137) have the middle mass close to the mean.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 8: Elements which occupied position in the lother meyer curve, on the peaks, were:
(a) Alkali metals
(b) Highly electro positive elements
(c) Elements having large atomic volume
(d) All
Show Answer & Explanation

Answer: (d) All

Explanation:
1. Peaks of the Lothar Meyer atomic volume curve are the alkali metals.
2. They are highly electropositive and have large atomic volume, so all the statements are correct.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 9: In a period the elements are arranged in:
(a) Decreasing order of nuclear charge
(b) Decreasing order of No. of electrons
(c) Increasing order of nuclear charge
(d) In order of same nuclear charge
Show Answer & Explanation

Answer: (c) Increasing order of nuclear charge

Explanation:
1. Modern periods arrange elements in increasing order of nuclear charge (atomic number).
2. Each period starts from an alkali metal.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 10: Which of the following statement is wrong:
(a) 2nd period contain 8 elements
(b) 3rd period contains 18 elements
(c) 1st period contains two non metals
(d) In p–block, metal, nonmetal and metalloids are present
Show Answer & Explanation

Answer: (b) 3rd period contains 18 elements

Explanation:
1. The third period contains 8 elements (Na to Ar), not 18.
2. The other statements are correct.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 11: Which statement is wrong for the long form of periodic table:
(a) Number of periods are 7 and groups 18
(b) No. of valence shell electrons in a period are same
(c) IIIrd B group contains 32 elements
(d) Lanthanides and actinides are placed in same group
Show Answer & Explanation

Answer: (b) No. of valence shell electrons in a period are same

Explanation:
1. The number of valence electrons increases from 1 to 8 across a period, so it is not the same.
2. The other statements are true: 7 periods, 18 groups, and group 3 holds 32 elements.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 12: Among the Lanthanides the one obtained by synthetic method is:
(a) Lu
(b) Pm
(c) Pr
(d) Ce
Show Answer & Explanation

Answer: (b) Pm

Explanation:
1. Promethium (Z = 61) has no stable isotope and is made artificially.
2. Lu, Pr and Ce occur naturally.

Teacher's Note:
1. Learn what Dobereiner, Newlands and Mendeleev each proposed, with one example. Remember the anomalous pairs and the eka elements.
2. Revise the trend with two or three examples.

Question 13: Which of the following set of elements belongs to same period:
(a) Zn, Cd, Hg
(b) Fr, Ra, U
(c) K, Ca, Ag
(d) None
Show Answer & Explanation

Answer: (b) Fr, Ra, U

Explanation:
1. Fr (87), Ra (88) and U (92) are all in the 7th period.
2. Zn, Cd, Hg are in different periods and so are K, Ca, Ag.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 14: The element with atomic number Z = 115 will be placed in:
(a) 7th period, IA group
(b) 8th period, IVA group
(c) 7th period, VA group
(d) 6th period, VB group
Show Answer & Explanation

Answer: (c) 7th period, VA group

Explanation:
1. Z = 115 has 7s² 5f¹⁴ 6d¹⁰ 7p³, so it is in the 7th period and group 15 (VA).

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 15: What is the electronic configuration of the element with atomic number 108?
(a) [Rn] 5f¹⁴ 6d⁶ 7s²
(b) 6f¹⁴ 7d⁸ 7s²
(c) [Rn] 5f¹⁴ 6d⁸ 7s⁰
(d) [Xe] 4f¹⁴ 5d⁸ 6s²
Show Answer & Explanation

Answer: (a) [Rn] 5f¹⁴ 6d⁶ 7s²

Explanation:
1. Hassium (Z = 108) is [Rn] 5f¹⁴ 6d⁶ 7s².
2. Rn core has 86 electrons, plus 14 + 6 + 2 = 22 gives 108.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 16: In 6th period of the modern periodic table, electronic energy levels are in the order:
(a) 6s, 4f, 5d, 6p
(b) 6s, 6p, 4f, 5d
(c) 4f, 5d, 6s, 6p
(d) None
Show Answer & Explanation

Answer: (a) 6s, 4f, 5d, 6p

Explanation:
1. In the sixth period the orbitals fill in the order 6s, 4f, 5d, 6p.
2. This gives 2 + 14 + 10 + 6 = 32 elements.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 17: Out of first 100 elements no. of elements having electrons in 3d orbital (in their complete electronic configuration) are:
(a) 80
(b) 100
(c) 40
(d) 60
Show Answer & Explanation

Answer: (a) 80

Explanation:
1. Electrons in 3d appear from scandium (Z = 21) onwards.
2. From 21 to 100 there are 80 elements.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 18: The older IUPAC systematic name of the element placed after Db (Z = 105) in the periodic table is:
(a) Un nil pentium
(b) Un un nilium
(c) Un nil hexium
(d) Un nil quadium
Show Answer & Explanation

Answer: (c) Un nil hexium

Explanation:
1. Z = 106 has the old systematic name unnilhexium (un = 1, nil = 0, hex = 6).
2. It follows Db (105).

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 19: The electronic configuration of the element with atomic number 109 if discovered will be:
(a) (n–1)d⁷ ns²
(b) (n–1)d⁹ ns²
(c) nd⁷ ns²
(d) (n–1)d⁵ ns² np²
Show Answer & Explanation

Answer: (a) (n–1)d⁷ ns²

Explanation:
1. Z = 109 is [Rn] 5f¹⁴ 6d⁷ 7s², so the valence configuration is (n - 1)d⁷ ns².

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 20: The element having electronic configuration 4f¹⁴ 5d⁰ 6s² belongs to:
(a) d–block, 12th group
(b) f–block, III B group
(c) f–block, 14th group
(d) s–block, 2nd group
Show Answer & Explanation

Answer: (b) f–block, III B group

Explanation:
1. 4f¹⁴ 5d⁰ 6s² is ytterbium, an f-block element of group 3 (IIIB), as lanthanides are placed in group 3.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 21: Element with the electronic configuration given below, belong to which group in the periodic table 1s², 2s² 2p⁶, 3s² 3p⁶ 3d¹⁰, 4s² 4p⁶ 4d¹⁰, 5s² 5p³:
(a) 3rd
(b) 5th
(c) 15 th
(d) 17th
Show Answer & Explanation

Answer: (c) 15 th

Explanation:
1. The last shell is 5s² 5p³, so the group is 10 + 2 + 3 = 15.
2. The element is antimony (Z = 51).

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 22: 4d³ 5s² configuration belongs to which group:
(a) IIA
(b) IIB
(c) V B
(d) III B
Show Answer & Explanation

Answer: (c) V B

Explanation:
1. 4d³ 5s² gives 5 valence electrons in d and s.
2. The element is Nb in group V B (group 5).

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 23: From atomic number 58 to 71, elements are placed in ;-:
(a) 5th period and III A group
(b) 6th period and III B group
(c) separate period and group
(d) 7th period and IV B group
Show Answer & Explanation

Answer: (b) 6th period and III B group

Explanation:
1. Atomic numbers 58 to 71 are the lanthanides (4f series).
2. They are in the 6th period and group III B.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 24: Which of the following match is correct:
(a) Last natural element – Cf
(b) General electronic configuration of IA group – ns²
(c) Inert gas elements lie in 2nd – 6th period
(d) Typical elements – 3rd period elements
Show Answer & Explanation

Answer: (d) Typical elements – 3rd period elements

Explanation:
1. Typical elements are the elements of the third period.
2. The last natural element is U, group IA is ns¹, and He (1st period) is also a noble gas.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 25: The electronic configurations of elements X and Z are 1s² 2s² 2p⁶ 3s² 3p⁵ and 1s² 2s² 2p⁵ respectively. The position of X with respect to Z in the periodic table is:
(a) Just below Z
(b) Just above Z
(c) Left to the Z
(d) right to the Z
Show Answer & Explanation

Answer: (a) Just below Z

Explanation:
1. X (1s² 2s² 2p⁶ 3s² 3p⁵) is chlorine and Z (1s² 2s² 2p⁵) is fluorine.
2. Both are in group 17, with Cl just below F.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

Question 26: Which of the following sequences contains the atomic numbers of only representative elements (noble gases excluded)?
(a) 55, 12, 18, 53
(b) 13, 33, 54, 83
(c) 3, 33, 53, 87
(d) 22, 33, 55, 66
Show Answer & Explanation

Answer: (c) 3, 33, 53, 87

Explanation:
1. Representative elements (excluding noble gases) are s⁻ and p-block elements of groups 1, 2 and 13 to 17.
2. 3, 33, 53, 87 are Li, As, I and Fr.
3. The other sets contain noble gases (Ar, Xe) or d⁻ and f-block elements.

Teacher's Note:
1. Count the shells and valence electrons to find period and group. The block is decided by the subshell that receives the last electron.
2. Revise the trend with two or three examples.

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