Download JEE MCQs for JEE Chemistry: Biomolecules
Access targeted multiple-choice questions for Biomolecules designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Chapter-wise Objective Questions: Biomolecules
Navigate directly to the 50 objective questions for Biomolecules using the digital viewer below. Each practice set includes verified answer keys, allowing students to instantly cross-check their work and identify areas requiring further revision.
Multiple Choice Questions
(a) maintains blood sugar level
(b) acts as an oxygen carrier in the blood
(c) forms antibodies and offers resistance to diseases
(d) acts as a catalyst for biological reactions
Show Answer & Explanation
Answer: (b) acts as an oxygen carrier in the blood
Explanation:
1. Haemoglobin is a conjugated protein containing iron in its haem group.
2. Iron binds oxygen reversibly, so it carries oxygen from lungs to tissues.
Teacher's Note:
1. Blood sugar is controlled by insulin, antibodies are immunoglobulins and catalysts are enzymes.
2. Match each protein with its function to avoid confusion.
(a) Bile acids
(b) Adrenaline
(c) Insulin
(d) Cortisone
Show Answer & Explanation
Answer: (c) Insulin
Explanation:
1. Insulin lowers blood glucose by promoting its conversion into glycogen in the liver and muscles.
2. Glucagon does the opposite job.
Teacher's Note:
1. Insulin is a peptide hormone made of two chains joined by disulphide bridges.
2. Its deficiency causes diabetes mellitus.
(a) hydrogen bonds
(b) ether bonds
(c) peptide bonds
(d) dipeptide bonds
Show Answer & Explanation
Answer: (a) hydrogen bonds
Explanation:
1. The alpha-helix is a secondary structure.
2. It is held by hydrogen bonds between the C=O of one amino acid and the N-H of the fourth amino acid ahead of it in the chain.
Teacher's Note:
1. Peptide bonds build the primary structure, not the helix.
2. Hydrogen bonds are the key forces in secondary structure.
(a) Thioether
(b) Thiol
(c) Thioester
(d) Thiolactone
Show Answer & Explanation
Answer: (b) Thiol
Explanation:
1. The amino acid cysteine has a thiol (-SH) group.
2. Two -SH groups are oxidised to form a -S-S- disulphide bridge between chains or parts of a chain.
Teacher's Note:
1. Disulphide links help hold the tertiary structure.
2. Hair keratin is rich in them, which is why perming works by breaking and re-forming them.
(a) phospholipids
(b) proteins
(c) fats
(d) carbohydrates
Show Answer & Explanation
Answer: (a) phospholipids
Explanation:
1. The membrane is a phospholipid bilayer with embedded proteins.
2. Phospholipids form the main structural framework.
Teacher's Note:
1. Heads are hydrophilic and tails hydrophobic, so they arrange as a bilayer in water.
2. Proteins and carbohydrates are present in smaller amounts.
(a) alpha-Keratin
(b) Haemoglobin
(c) Ribonuclease
(d) Adenine
Show Answer & Explanation
Answer: (a) alpha-Keratin
Explanation:
1. Keratin is a fibrous protein, and fibrous proteins are insoluble in water.
2. Haemoglobin and ribonuclease are globular proteins, which are soluble.
Teacher's Note:
1. Fibrous proteins (keratin, collagen, myosin) are structural.
2. Globular proteins (enzymes, haemoglobin, insulin) are soluble.
(a) 3rd
(b) 4th
(c) 1st
(d) 2nd
Show Answer & Explanation
Answer: (d) 2nd
Explanation:
1. Ribose in RNA has an OH at C-2.
2. 2-Deoxyribose in DNA lacks the OH at C-2, which is the difference.
Teacher's Note:
1. The extra 2-OH makes RNA more reactive and easier to hydrolyse.
2. That is why DNA is the stable store of genetic information.
(a) Cytosine
(b) Thymine
(c) Quinoline
(d) Adenine
Show Answer & Explanation
Answer: (c) Quinoline
Explanation:
1. DNA contains adenine, guanine, cytosine and thymine.
2. Quinoline is a heterocyclic compound and not a nucleic acid base.
Teacher's Note:
1. RNA has uracil in place of thymine.
2. Learn the two purines (A, G) and three pyrimidines (C, T, U).
(a) alpha-amino acid
(b) gamma-amino acid
(c) amino acid synthesised in the body
(d) beta-amino acid
Show Answer & Explanation
Answer: (a) alpha-amino acid
Explanation:
1. One NH2 group sits on the carbon next to COOH, so it is an alpha-amino acid.
2. The second amino group is on the side chain.
3. Lysine is essential, so it is not made in the body.
Teacher's Note:
1. Proteins are made only of alpha-amino acids.
2. Lysine is basic because it has two amino groups and one carboxyl group.
(a) van der Waals forces
(b) disulphide linkages (together with hydrogen bonds)
(c) electrostatic forces of attraction
(d) none of these
Show Answer & Explanation
Answer: (b) disulphide linkages (together with hydrogen bonds)
Explanation:
1. Fibrous proteins have parallel chains held together by hydrogen bonds and disulphide bonds.
2. Among the given options, disulphide linkage is correct.
Teacher's Note:
1. Fibrous proteins are insoluble in water.
2. Keratin and collagen are common examples.
(a) amylose
(b) amylopectin
(c) cellulose
(d) glucose
Show Answer & Explanation
Answer: (b) amylopectin
Explanation:
1. Both glycogen and amylopectin are branched polymers of alpha-D-glucose.
2. They have alpha-1,4 links in chains and alpha-1,6 links at the branches.
3. Glycogen is more highly branched.
Teacher's Note:
1. Glycogen is called animal starch.
2. It is stored in liver and muscles.
(a) Glucose
(b) Mannose
(c) Galactose
(d) Fructose
Show Answer & Explanation
Answer: (c) Galactose
Explanation:
1. Glucose, mannose and fructose differ only at C-1 and C-2, and these two carbons become part of the osazone.
2. So all three give the same osazone.
3. Galactose differs at C-4, so it gives a different osazone.
Teacher's Note:
1. Osazone formation uses carbons 1 and 2 only.
2. Epimers at C-2 and the corresponding ketose give the same osazone.
(a) glucose
(b) fructose
(c) ethyl alcohol
(d) both glucose and fructose
Show Answer & Explanation
Answer: (d) both glucose and fructose
Explanation:
1. Invertase hydrolyses sucrose into equal amounts of D-glucose and D-fructose.
2. The mixture is called invert sugar because the rotation changes from dextro to laevo.
Teacher's Note:
1. Sucrose is dextrorotatory (+66.5 degrees).
2. The product is laevorotatory since fructose (-92.4 degrees) rotates more than glucose (+52.5 degrees).
(a) Vitamin B1
(b) Vitamin B2
(c) Vitamin B6
(d) Vitamin B12
Show Answer & Explanation
Answer: (d) Vitamin B12
Explanation:
1. Water-soluble vitamins are generally excreted and need regular supply.
2. Vitamin B12 is an exception and is stored in the liver.
Teacher's Note:
1. Vitamins A, D, E and K are fat soluble and stored.
2. B12 is the water-soluble vitamin that can be stored.
(a) i, ii and iii
(b) i, ii and iv
(c) i and iii
(d) i, ii, iii and iv
Show Answer & Explanation
Answer: (d) i, ii, iii and iv
Explanation:
1. Starch, cellulose and glycogen are polymers of glucose.
2. Dextrins are shorter polysaccharide chains obtained by partial hydrolysis of starch.
3. So all four are polysaccharides.
Teacher's Note:
1. Polysaccharides give many monosaccharide units on hydrolysis.
2. Starch, cellulose and glycogen are the main three.
(a) Fehling's solution
(b) Tollens' reagent
(c) both of these
(d) none of these
Show Answer & Explanation
Answer: (c) both of these
Explanation:
1. Cellulose is a non-reducing polysaccharide with glycosidic links between all anomeric carbons except one terminal end, which is negligible.
2. So it gives no test with Fehling's or Tollens' reagent.
Teacher's Note:
1. Reducing tests need a free hemiacetal group in appreciable amount.
2. Large polymers practically do not respond.
(a) Fructose
(b) Maltose
(c) Sucrose
(d) Glucose
Show Answer & Explanation
Answer: (c) Sucrose
Explanation:
1. In sucrose the anomeric carbons of glucose and fructose are both used in the glycosidic bond.
2. So there is no free hemiacetal or hemiketal group, and it is non-reducing.
Teacher's Note:
1. A free hemiacetal group makes a sugar reducing.
2. Sucrose is the standard non-reducing disaccharide.
(a) which can be synthesised in the body
(b) which have more amino groups than carboxyl groups
(c) which have equal numbers of amino and carboxyl groups
(d) none of these
Show Answer & Explanation
Answer: (a) which can be synthesised in the body
Explanation:
1. Amino acids that the body can make are non-essential.
2. Those that must come from the diet are essential.
Teacher's Note:
1. Essential amino acids include valine, leucine, lysine and tryptophan.
2. The classification has nothing to do with the number of functional groups.
(a) Serine
(b) Lysine
(c) Threonine
(d) Tryptophan
Show Answer & Explanation
Answer: (a) Serine
Explanation:
1. Lysine, threonine and tryptophan have to be supplied by the diet.
2. Serine can be made in the body, so it is non-essential.
Teacher's Note:
1. Remember essential ones for adults with the name PVT TIM HALL.
2. Serine, glycine, alanine and others are non-essential.
(a) Fibrous
(b) Globular
(c) both fibrous and globular
(d) none of these
Show Answer & Explanation
Answer: (c) both fibrous and globular
Explanation:
1. The tertiary structure is the overall folding of the chain.
2. It can be fibrous (rod-like) or globular (spherical).
Teacher's Note:
1. Tertiary structure is stabilised by disulphide bridges, hydrogen bonds and ionic forces.
2. Hydrophobic interactions also help.
(a) silk
(b) collagen
(c) haemoglobin
(d) all of these
Show Answer & Explanation
Answer: (c) haemoglobin
Explanation:
1. Haemoglobin is folded into a compact spherical shape and is water soluble.
2. Silk fibroin and collagen are fibrous.
Teacher's Note:
1. Albumin, insulin and enzymes are also globular.
2. Globular proteins are soluble in water.
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Biomolecules Objective Questions & Solutions for JEE Chemistry
About Biomolecules MCQs for JEE Chemistry
Test your conceptual understanding of Biomolecules with these targeted multiple-choice questions. Designed in alignment with the latest JEE curriculum for JEE Chemistry, these problem sets build accuracy and prepare students for objective exams.
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FAQs
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