JEE Chemistry Basic Inorganic Nomenclature MCQs Set 04

Practice MCQs for JEE Chemistry Basic Inorganic Nomenclature

Access targeted multiple-choice questions for Basic Inorganic Nomenclature designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.

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Multiple Choice Questions

Question 1: The name of \( \ce{Cu2S} \) is
(a) cupric sulphide
(b) copper sulphate
(c) cuprous sulphide
(d) cuprous sulphite
Show Answer & Explanation

Answer: (c) cuprous sulphide

Explanation:
1. Two Cu^+ ions and one \( \ce{S^2-} \): copper(I) or cuprous sulphide.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 2: The name of \( \ce{Co(ClO3)3} \) is
(a) cobalt(III) chlorate
(b) cobalt(II) chlorate
(c) cobalt(III) chlorite
(d) cobalt(III) perchlorate
Show Answer & Explanation

Answer: (a) cobalt(III) chlorate

Explanation:
1. \( \ce{ClO3^-} \) is chlorate; three of them imply Co(III).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 3: The name of \( \ce{Mg3(BO3)2} \) is
(a) magnesium metaborate
(b) magnesium orthoborate
(c) magnesium borite
(d) magnesium pyroborate
Show Answer & Explanation

Answer: (b) magnesium orthoborate

Explanation:
1. \( \ce{BO3^3-} \) is the (ortho)borate ion.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 4: The name of \( \ce{Na2MnO4} \) is
(a) sodium permanganate
(b) sodium manganite
(c) sodium manganese oxide
(d) sodium manganate
Show Answer & Explanation

Answer: (d) sodium manganate

Explanation:
1. \( \ce{MnO4^2-} \) is manganate; \( \ce{MnO4^-} \) is permanganate.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 5: The name of \( \ce{Mg3(AsO3)2} \) is
(a) magnesium orthoarsenite
(b) magnesium orthoarsenate
(c) magnesium metaarsenite
(d) magnesium arsenide
Show Answer & Explanation

Answer: (a) magnesium orthoarsenite

Explanation:
1. \( \ce{AsO3^3-} \) comes from the -ous acid, so it is an -ite.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 6: The name of \( \ce{FeAsO4} \) is
(a) ferrous arsenate
(b) ferric arsenite
(c) ferric orthoarsenide
(d) ferric orthoarsenate (iron(III) arsenate)
Show Answer & Explanation

Answer: (d) ferric orthoarsenate (iron(III) arsenate)

Explanation:
1. \( \ce{AsO4^3-} \) is arsenate, so Fe is +3.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 7: The name of \( \ce{Hg2I2} \) is
(a) mercuric iodide
(b) mercurous iodide
(c) mercury iodate
(d) mercurous iodite
Show Answer & Explanation

Answer: (b) mercurous iodide

Explanation:
1. \( \ce{Hg2^2+} \) with \( \ce{I^-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 8: The name of \( \ce{HgCl2} \) is
(a) mercurous chloride
(b) mercury chlorate
(c) mercuric chloride
(d) mercuric chlorite
Show Answer & Explanation

Answer: (c) mercuric chloride

Explanation:
1. \( \ce{Hg^2+} \) is mercuric.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 9: The formula of hypoiodous acid is
(a) \( \ce{HIO} \)
(b) \( \ce{HIO2} \)
(c) \( \ce{HIO3} \)
(d) \( \ce{HIO4} \)
Show Answer & Explanation

Answer: (a) \( \ce{HIO} \)

Explanation:
1. Hypo-, -ous: the lowest oxoacid, HIO.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 10: The formula of periodic acid is
(a) \( \ce{HIO3} \)
(b) \( \ce{HIO4} \)
(c) \( \ce{HIO2} \)
(d) \( \ce{HI} \)
Show Answer & Explanation

Answer: (b) \( \ce{HIO4} \)

Explanation:
1. Per- means one more O than iodic acid (\( \ce{HIO3} \)).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Learn the suffix pattern first: -ic acid gives -ate, -ous acid gives -ite, and hypo-/per- prefixes carry over to the anion.

Question 11: The formula of magnesium nitride is
(a) \( \ce{Mg3N2} \)
(b) \( \ce{MgN} \)
(c) \( \ce{Mg2N3} \)
(d) \( \ce{Mg3N} \)
Show Answer & Explanation

Answer: (a) \( \ce{Mg3N2} \)

Explanation:
1. Mg^2+ and N^3-: criss-cross gives \( \ce{Mg3N2} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 12: The formula of iron(III) sulphide is
(a) \( \ce{FeS} \)
(b) \( \ce{Fe3S2} \)
(c) \( \ce{Fe2S3} \)
(d) \( \ce{FeS3} \)
Show Answer & Explanation

Answer: (c) \( \ce{Fe2S3} \)

Explanation:
1. Fe^3+ and S^2-: \( \ce{Fe2S3} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 13: The formula of stannous chloride is
(a) \( \ce{SnCl4} \)
(b) \( \ce{Sn2Cl} \)
(c) \( \ce{SnCl} \)
(d) \( \ce{SnCl2} \)
Show Answer & Explanation

Answer: (d) \( \ce{SnCl2} \)

Explanation:
1. Stannous is Sn(II).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 14: The formula of potassium ozonide is
(a) \( \ce{K2O2} \)
(b) \( \ce{KO3} \)
(c) \( \ce{KO2} \)
(d) \( \ce{K2O} \)
Show Answer & Explanation

Answer: (b) \( \ce{KO3} \)

Explanation:
1. Ozonide is \( \ce{O3^-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 15: The formula of potassium peroxide is
(a) \( \ce{KO2} \)
(b) \( \ce{KO3} \)
(c) \( \ce{K2O2} \)
(d) \( \ce{KO} \)
Show Answer & Explanation

Answer: (c) \( \ce{K2O2} \)

Explanation:
1. Peroxide is \( \ce{O2^2-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 16: The formula of barium permanganate is
(a) \( \ce{BaMnO4} \)
(b) \( \ce{Ba(MnO4)2} \)
(c) \( \ce{Ba2MnO4} \)
(d) \( \ce{Ba(MnO3)2} \)
Show Answer & Explanation

Answer: (b) \( \ce{Ba(MnO4)2} \)

Explanation:
1. Permanganate is \( \ce{MnO4^-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 17: The formula of vanadium(III) phosphate is
(a) \( \ce{V3(PO4)} \)
(b) \( \ce{V2(PO4)3} \)
(c) \( \ce{V3PO4} \)
(d) \( \ce{VPO4} \)
Show Answer & Explanation

Answer: (d) \( \ce{VPO4} \)

Explanation:
1. \( \ce{V^3+} \) with \( \ce{PO4^3-} \) gives 1:1.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 18: The formula of ferric sulphate is
(a) \( \ce{Fe2(SO4)3} \)
(b) \( \ce{FeSO4} \)
(c) \( \ce{Fe3(SO4)2} \)
(d) \( \ce{Fe(SO4)3} \)
Show Answer & Explanation

Answer: (a) \( \ce{Fe2(SO4)3} \)

Explanation:
1. Fe^3+ and \( \ce{SO4^2-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 19: The formula of magnesium hydrogenphosphite is
(a) \( \ce{Mg(HPO3)2} \)
(b) \( \ce{Mg(H2PO3)2} \)
(c) \( \ce{MgHPO3} \)
(d) \( \ce{MgHPO4} \)
Show Answer & Explanation

Answer: (c) \( \ce{MgHPO3} \)

Explanation:
1. \( \ce{HPO3^2-} \) with \( \ce{Mg^2+} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 20: The formula of ammonium hyponitrite is
(a) \( \ce{NH4NO2} \)
(b) \( \ce{(NH4)2N2O3} \)
(c) \( \ce{NH4N2O2} \)
(d) \( \ce{(NH4)2N2O2} \)
Show Answer & Explanation

Answer: (d) \( \ce{(NH4)2N2O2} \)

Explanation:
1. Hyponitrite is \( \ce{N2O2^2-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 21: The formula of indium(I) chloride is
(a) \( \ce{InCl3} \)
(b) \( \ce{In2Cl} \)
(c) \( \ce{InCl} \)
(d) \( \ce{InCl2} \)
Show Answer & Explanation

Answer: (c) \( \ce{InCl} \)

Explanation:
1. In(I) means a +1 charge.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 22: The formula of calcium metaborate is
(a) \( \ce{Ca(BO2)2} \)
(b) \( \ce{CaBO2} \)
(c) \( \ce{Ca(BO3)2} \)
(d) \( \ce{Ca3(BO3)2} \)
Show Answer & Explanation

Answer: (a) \( \ce{Ca(BO2)2} \)

Explanation:
1. Metaborate is \( \ce{BO2^-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 23: The formula of aluminium hydrogenphosphite is
(a) \( \ce{AlHPO3} \)
(b) \( \ce{Al(H2PO3)3} \)
(c) \( \ce{Al2(HPO3)3} \)
(d) \( \ce{Al(HPO3)3} \)
Show Answer & Explanation

Answer: (b) \( \ce{Al(H2PO3)3} \)

Explanation:
1. \( \ce{H2PO3^-} \) is dihydrogen phosphite; three needed for Al^3+.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 24: The formula of chromium(III) oxide is
(a) \( \ce{CrO3} \)
(b) \( \ce{Cr3O2} \)
(c) \( \ce{CrO2} \)
(d) \( \ce{Cr2O3} \)
Show Answer & Explanation

Answer: (d) \( \ce{Cr2O3} \)

Explanation:
1. Cr^3+ and O^2-.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 25: The formula of rubidium superoxide is
(a) \( \ce{RbO2} \)
(b) \( \ce{Rb2O2} \)
(c) \( \ce{RbO3} \)
(d) \( \ce{Rb2O} \)
Show Answer & Explanation

Answer: (a) \( \ce{RbO2} \)

Explanation:
1. Superoxide is \( \ce{O2^-} \).
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 26: The formula of caesium iodide is
(a) \( \ce{Cs2I} \)
(b) \( \ce{CsI2} \)
(c) CsI
(d) \( \ce{Cs2I3} \)
Show Answer & Explanation

Answer: (c) CsI

Explanation:
1. Cs^+ and I^-.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

Question 27: The formula of calcium phosphide is
(a) \( \ce{CaP} \)
(b) \( \ce{Ca2P3} \)
(c) \( \ce{Ca3P} \)
(d) \( \ce{Ca3P2} \)
Show Answer & Explanation

Answer: (d) \( \ce{Ca3P2} \)

Explanation:
1. Ca^2+ and P^3-.
2. Only this option agrees with the working above, so it is the correct choice.

Teacher's Note:
1. Write the cation first, put the charges as subscripts crosswise, then cancel any common factor.

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