Chemistry Objective Questions and Answers: Aldehydes Ketones and Carboxylic Acids
Access targeted multiple-choice questions for Aldehydes Ketones and Carboxylic Acids designed to align with the latest JEE academic syllabus for JEE Chemistry. These objective practice sets help students evaluate their conceptual understanding and improve exam readiness.
Download Aldehydes Ketones and Carboxylic Acids MCQs with Answers
Access the complete set of multiple-choice questions for Aldehydes Ketones and Carboxylic Acids below. This focused format allows students to isolate specific topics for thorough review and uninterrupted practice alongside official JEE textbooks.
Multiple Choice Questions
(a) HCONH2
(b) CH3CONH2
(c) HCOONH4
(d) HCHO + NH3
Show Answer & Explanation
Answer: (a) HCONH2
Explanation:
1. Formamide is the amide of formic acid, HCONH2.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) nucleic acids
(b) amino acids
(c) fatty acids
(d) none of these
Show Answer & Explanation
Answer: (c) fatty acids
Explanation:
1. These are long-chain carboxylic acids found in fats and oils, that is, fatty acids.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) HCOOH
(b) CH3COOH
(c) CH3CH2COOH
(d) CH3CH2CH2COOH
Show Answer & Explanation
Answer: (b) CH3COOH
Explanation:
1. Ethanoic acid has two carbons, so it is acetic acid, CH3COOH.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) HCHO
(b) HCOOH
(c) CH3CHO
(d) CH3COOH
Show Answer & Explanation
Answer: (d) CH3COOH
Explanation:
1. Vinegar is a dilute aqueous solution (about 4 to 8 per cent) of acetic acid.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) Aspirin
(b) Benzoic acid
(c) Picric acid
(d) Salicylic acid
Show Answer & Explanation
Answer: (c) Picric acid
Explanation:
1. Picric acid is 2,4,6-trinitrophenol and has only a phenolic OH.
2. The other three contain COOH.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) CH3COOH
(b) HCOOH
(c) C6H5COOH
(d) CH3CH2COOH
Show Answer & Explanation
Answer: (a) CH3COOH
Explanation:
1. The acid in vinegar is acetic acid.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) C6H5CHO
(b) C6H6
(c) C6H5COOH
(d) C6H5OH
Show Answer & Explanation
Answer: (d) C6H5OH
Explanation:
1. Carbolic acid is the old name of phenol, C6H5OH.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) ClCH2COOH
(b) C6H5COOH
(c) CD3COOH
(d) CH3CH2COOH
Show Answer & Explanation
Answer: (a) ClCH2COOH
Explanation:
1. The -I effect of Cl stabilises the carboxylate ion most.
2. Deuterium or alkyl groups do not increase acidity.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) ethyl acetate
(b) acetic anhydride
(c) acetamide
(d) acetyl chloride
Show Answer & Explanation
Answer: (d) acetyl chloride
Explanation:
1. Reactivity towards nucleophiles: RCOCl > (RCO)2O > RCOOR > RCONH2.
2. Cl- is the best leaving group.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) CH3CH2OH
(b) C2H6
(c) CH3CH=NOH
(d) CH3COOH
Show Answer & Explanation
Answer: (d) CH3COOH
Explanation:
1. Primary nitroalkanes are hydrolysed by hot 85% sulphuric acid to the carboxylic acid with the same number of carbons (and hydroxylamine).
2. So nitroethane gives acetic acid.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) formyl chloride
(b) acetyl chloride
(c) methyl chloride
(d) propionyl chloride
Show Answer & Explanation
Answer: (a) formyl chloride
Explanation:
1. PCl5 replaces the OH of the carboxyl group by Cl.
2. Formyl chloride is unstable and soon decomposes to CO and HCl.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) CH3COOH + SOCl2
(b) CH3COOH + PCl3
(c) CH3COONa + PCl3
(d) CH3COOH + CH3OH
Show Answer & Explanation
Answer: (a) CH3COOH + SOCl2
Explanation:
1. CH3COOH + SOCl2 → CH3COCl + SO2 + HCl.
2. Both by-products escape as gases, leaving a clean product.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) LiAlH4
(b) N-bromosuccinimide
(c) Al(OC2H5)3
(d) Zn-Hg/HCl
Show Answer & Explanation
Answer: (c) Al(OC2H5)3
Explanation:
1. Two molecules of an aldehyde with aluminium ethoxide give an ester, for example 2 CH3CHO → CH3COOC2H5.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) methyl alcohol is oxidised with potassium permanganate
(b) calcium acetate is distilled with calcium formate
(c) acetaldehyde is oxidised with potassium dichromate and sulphuric acid
(d) glycerol is heated with sulphuric acid
Show Answer & Explanation
Answer: (c) acetaldehyde is oxidised with potassium dichromate and sulphuric acid
Explanation:
1. CH3CHO → CH3COOH on oxidation.
2. Methanol gives formic acid, calcium acetate with formate gives acetaldehyde and glycerol with sulphuric acid gives acrolein.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) ethanol
(b) methanol
(c) ethanal
(d) methanal
Show Answer & Explanation
Answer: (a) ethanol
Explanation:
1. Acetobacter in air oxidises ethanol to acetic acid.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) HCOONa
(b) C2H2O4
(c) HCOOH
(d) CH3COOH
Show Answer & Explanation
Answer: (a) HCOONa
Explanation:
1. Carbon monoxide combines with NaOH at about 200°C and high pressure to give sodium formate.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) amine
(b) alcohol
(c) ester
(d) amide
Show Answer & Explanation
Answer: (c) ester
Explanation:
1. RCOOH + CH2N2 → RCOOCH3 + N2, a mild methylation giving the methyl ester.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) an acid
(b) an aldehyde
(c) a ketone
(d) ethanol
Show Answer & Explanation
Answer: (a) an acid
Explanation:
1. Hydration of ethyne gives acetaldehyde (A).
2. Oxidation of acetaldehyde gives acetic acid (B).
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) a carbonium ion intermediate
(b) a carbene intermediate
(c) a carbanion intermediate
(d) a free radical intermediate
Show Answer & Explanation
Answer: (b) a carbene intermediate
Explanation:
1. Chloroform with base gives dichlorocarbene, :CCl2, the electrophile that attacks the phenoxide ring.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) CH3CH2NH2
(b) CH3CN
(c) HCONH2
(d) CH3CONH2
Show Answer & Explanation
Answer: (d) CH3CONH2
Explanation:
1. A = CH3CN; B = CH3COOH; C = CH3COONH4.
2. Heating ammonium acetate loses water to give acetamide, D = CH3CONH2.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) CH3CN
(b) CH3OH
(c) C2H5OH
(d) C2H5NH2
Show Answer & Explanation
Answer: (a) CH3CN
Explanation:
1. Nitriles hydrolyse to carboxylic acids: CH3CN → CH3COOH + NH3.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) benzaldehyde
(b) benzoic acid
(c) CO2 and H2O
(d) none of these
Show Answer & Explanation
Answer: (b) benzoic acid
Explanation:
1. Strong oxidising agents take a primary alcohol all the way to the carboxylic acid: C6H5CH2OH → C6H5COOH.
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
(a) chlorophenol
(b) chlorotoluene
(c) chlorobenzene
(d) benzyl chloride
Show Answer & Explanation
Answer: (d) benzyl chloride
Explanation:
1. Benzyl chloride has a single side-chain carbon bearing the halogen, and vigorous oxidation converts it to C6H5COOH.
2. Chlorotoluene would give chlorobenzoic acid.
Teacher's Note:
1. Count carbons before and after the reaction to avoid mistakes in chain-length changes.
2. Check whether the reagent is a reducing, oxidising or dehydrating agent before choosing the product.
(a) (CH3)2C(OH)CN and (CH3)2C(OH)COOH
(b) (CH3)2C(OH)CN and (CH3)2C(OH)2
(c) (CH3)2C(OH)CN and (CH3)2CHCOOH
(d) (CH3)2C(OH)CN and (CH3)2C=O
Show Answer & Explanation
Answer: (a) (CH3)2C(OH)CN and (CH3)2C(OH)COOH
Explanation:
1. Acetone with HCN or NaCN gives the cyanohydrin A.
2. Acid hydrolysis converts CN to COOH, giving 2-hydroxy-2-methylpropanoic acid.
Teacher's Note:
1. Eliminate options by checking functional groups on both sides of the reaction.
2. Only one option will have the correct functional group and carbon skeleton.
(a) two moles of ethyl alcohol
(b) formic anhydride
(c) acetic anhydride
(d) two moles of methyl cyanide
Show Answer & Explanation
Answer: (c) acetic anhydride
Explanation:
1. P2O5 removes one molecule of water from two molecules of acid.
2. The product is acetic anhydride, (CH3CO)2O.
Teacher's Note:
1. Revise the physical properties such as hydrogen bonding and boiling points together with the chemistry.
2. Compare similar compounds in pairs when you are asked to rank them.
(a) calcium acetate is heated with conc. H2SO4
(b) calcium formate is heated with calcium acetate
(c) glycerol is heated with oxalic acid at 110°C
(d) acetaldehyde is oxidised with K2Cr2O7 and H2SO4
Show Answer & Explanation
Answer: (c) glycerol is heated with oxalic acid at 110°C
Explanation:
1. Oxalic acid with glycerol at 110°C gives glyceryl oxalate, which loses CO2 to give glyceryl monoformate, hydrolysed to formic acid.
Teacher's Note:
1. Learn the reactivity order of acid derivatives: acyl chloride, anhydride, ester, amide.
2. Most questions of this type are solved by recalling the standard reagent and product pair.
(a) CHCl3
(b) SOCl2
(c) PCl3
(d) PCl5
Show Answer & Explanation
Answer: (a) CHCl3
Explanation:
1. SOCl2, PCl3 and PCl5 all convert COOH to COCl.
2. Chloroform is not a chlorinating agent for this.
Teacher's Note:
1. Always link acid strength to the stability of the carboxylate ion.
2. Electron-withdrawing groups increase acidity and electron-donating groups decrease it.
(a) benzoic acid
(b) phenylacetic acid
(c) phthalic acid
(d) acetic acid
Show Answer & Explanation
Answer: (c) phthalic acid
Explanation:
1. Both methyl groups are oxidised to COOH, giving phthalic acid (as its anhydride under vapour-phase conditions).
Teacher's Note:
1. Note the name reaction and write its equation once in your notebook.
2. Such one-step recall questions are common in the JEE and NEET style papers.
Free study material for Chemistry
Aldehydes Ketones and Carboxylic Acids Objective Questions & Solutions for JEE Chemistry
Download Multiple Choice Questions: Aldehydes Ketones and Carboxylic Acids (JEE Chemistry)
Review structured objective questions for JEE Chemistry Aldehydes Ketones and Carboxylic Acids. Built according to official JEE guidelines, these MCQ sets support daily revision and core concept reinforcement.
Concept Clarification for Aldehydes Ketones and Carboxylic Acids
Each question includes structured solution keys mapped directly to standard JEE textbooks, helping students evaluate their reasoning and correct mistakes early in their revision.
Additional Study Resources for JEE Chemistry
Wrap up your chapter revision by testing your knowledge against standard question formats. Everything on our platform is provided free of charge.
FAQs
You can get most exhaustive JEE Chemistry Aldehydes Ketones And Carboxylic Acids MCQs Set 15 for free on StudiesToday.com. These MCQs for JEE Chemistry are updated for the 2026-27 academic session as per JEE examination standards.
Yes, our JEE Chemistry Aldehydes Ketones And Carboxylic Acids MCQs Set 15 include the latest type of questions, such as Assertion-Reasoning and Case-based MCQs. 50% of the JEE paper is now competency-based.
By solving our JEE Chemistry Aldehydes Ketones And Carboxylic Acids MCQs Set 15, JEE students can improve their accuracy and speed which is important as objective questions provide a chance to secure 100% marks in the Chemistry.
Yes, Chemistry MCQs for JEE have answer key and brief explanations to help students understand logic behind the correct option as its important for 2026 competency-focused JEE exams.
Yes, you can also access online interactive tests for JEE Chemistry Aldehydes Ketones And Carboxylic Acids MCQs Set 15 on StudiesToday.com as they provide instant answers and score to help you track your progress in Chemistry.