Analytical Reasoning Aptitude MCQ Questions with Answers Set 01

Answer: (c) D

Explanation:
1. Games fixed directly: A - Cricket, B - Golf, E - Tennis. Professions fixed: D - Auditor, E - Banker.
2. C and D share Hockey and Basketball; D does not play Hockey, so D plays Basketball and C plays Hockey.
3. The Engineer plays Hockey, so C is the Engineer. A and B are left with Doctor and Advocate; B is not an Advocate, so B is the Doctor and A is the Advocate.
4. So the Basketball player is D, the Auditor.

Teacher's Note:
1. Build a grid of persons against professions and games, and mark every direct fact first before making deductions.
2. When only two persons are left for two slots, one negative clue is enough to fix both of them.

Answer: (a) B

Explanation:
1. Games fixed directly: A - Cricket, B - Golf, E - Tennis. Professions fixed: D - Auditor, E - Banker.
2. C and D share Hockey and Basketball; D does not play Hockey, so D plays Basketball and C plays Hockey.
3. The Engineer plays Hockey, so C is the Engineer. A and B are left with Doctor and Advocate; B is not an Advocate, so B is the Doctor and A is the Advocate.
4. Therefore the Doctor is B.

Teacher's Note:
1. Build a grid of persons against professions and games, and mark every direct fact first before making deductions.
2. When only two persons are left for two slots, one negative clue is enough to fix both of them.

Answer: (b) Advocate

Explanation:
1. Games fixed directly: A - Cricket, B - Golf, E - Tennis. Professions fixed: D - Auditor, E - Banker.
2. C and D share Hockey and Basketball; D does not play Hockey, so D plays Basketball and C plays Hockey.
3. The Engineer plays Hockey, so C is the Engineer. A and B are left with Doctor and Advocate; B is not an Advocate, so B is the Doctor and A is the Advocate.
4. Therefore A is the Advocate.

Teacher's Note:
1. Build a grid of persons against professions and games, and mark every direct fact first before making deductions.
2. When only two persons are left for two slots, one negative clue is enough to fix both of them.

Answer: (d) C

Explanation:
1. Games fixed directly: A - Cricket, B - Golf, E - Tennis. Professions fixed: D - Auditor, E - Banker.
2. C and D share Hockey and Basketball; D does not play Hockey, so D plays Basketball and C plays Hockey.
3. The Engineer plays Hockey, so C is the Engineer. A and B are left with Doctor and Advocate; B is not an Advocate, so B is the Doctor and A is the Advocate.
4. Therefore C plays Hockey.

Teacher's Note:
1. Build a grid of persons against professions and games, and mark every direct fact first before making deductions.
2. When only two persons are left for two slots, one negative clue is enough to fix both of them.

Answer: (c) Engineer

Explanation:
1. Games fixed directly: A - Cricket, B - Golf, E - Tennis. Professions fixed: D - Auditor, E - Banker.
2. C and D share Hockey and Basketball; D does not play Hockey, so D plays Basketball and C plays Hockey.
3. The Engineer plays Hockey, so C is the Engineer. A and B are left with Doctor and Advocate; B is not an Advocate, so B is the Doctor and A is the Advocate.
4. Therefore C is the Engineer.

Teacher's Note:
1. Build a grid of persons against professions and games, and mark every direct fact first before making deductions.
2. When only two persons are left for two slots, one negative clue is enough to fix both of them.

Answer: (a) Neetu

Explanation:
1. Trilok and Jayanth have sons (Gagan, Sumanth) and are the accountant and the lawyer; Venkat and Murali have daughters (Neetu, Teena) and are the sales executive and the doctor.
2. Gagan is not Jayanth's son, so Gagan is Trilok's son and Sumanth is Jayanth's. Sumanth's father is not the accountant, so Jayanth is the lawyer and Trilok the accountant.
3. Teena is not Murali's daughter, so Teena is Venkat's and Neetu is Murali's. Neetu is not the doctor's daughter, so Murali is the sales executive and Venkat the doctor.
4. The sales executive is Murali, whose child is Neetu.

Teacher's Note:
1. Split the people into groups first (fathers of sons vs fathers of daughters); it halves the possibilities at once.
2. Use each negative clue inside its small group, where a single 'not' immediately fixes the pairing.

Answer: (d) Trilok - accountant

Explanation:
1. Trilok and Jayanth have sons (Gagan, Sumanth) and are the accountant and the lawyer; Venkat and Murali have daughters (Neetu, Teena) and are the sales executive and the doctor.
2. Gagan is not Jayanth's son, so Gagan is Trilok's son and Sumanth is Jayanth's. Sumanth's father is not the accountant, so Jayanth is the lawyer and Trilok the accountant.
3. Teena is not Murali's daughter, so Teena is Venkat's and Neetu is Murali's. Neetu is not the doctor's daughter, so Murali is the sales executive and Venkat the doctor.
4. So Gagan's father is Trilok, the accountant.

Teacher's Note:
1. Split the people into groups first (fathers of sons vs fathers of daughters); it halves the possibilities at once.
2. Use each negative clue inside its small group, where a single 'not' immediately fixes the pairing.

Answer: (c) Jayanth and Trilok

Explanation:
1. Trilok and Jayanth have sons (Gagan, Sumanth) and are the accountant and the lawyer; Venkat and Murali have daughters (Neetu, Teena) and are the sales executive and the doctor.
2. Gagan is not Jayanth's son, so Gagan is Trilok's son and Sumanth is Jayanth's. Sumanth's father is not the accountant, so Jayanth is the lawyer and Trilok the accountant.
3. Teena is not Murali's daughter, so Teena is Venkat's and Neetu is Murali's. Neetu is not the doctor's daughter, so Murali is the sales executive and Venkat the doctor.
4. Sumanth's father is Jayanth and Gagan's father is Trilok; if the boys are cousins, Jayanth and Trilok are brothers.

Teacher's Note:
1. Split the people into groups first (fathers of sons vs fathers of daughters); it halves the possibilities at once.
2. Use each negative clue inside its small group, where a single 'not' immediately fixes the pairing.

Answer: (d) Venkat - doctor

Explanation:
1. Trilok and Jayanth have sons (Gagan, Sumanth) and are the accountant and the lawyer; Venkat and Murali have daughters (Neetu, Teena) and are the sales executive and the doctor.
2. Gagan is not Jayanth's son, so Gagan is Trilok's son and Sumanth is Jayanth's. Sumanth's father is not the accountant, so Jayanth is the lawyer and Trilok the accountant.
3. Teena is not Murali's daughter, so Teena is Venkat's and Neetu is Murali's. Neetu is not the doctor's daughter, so Murali is the sales executive and Venkat the doctor.
4. So Teena's father is Venkat, the doctor.

Teacher's Note:
1. Split the people into groups first (fathers of sons vs fathers of daughters); it halves the possibilities at once.
2. Use each negative clue inside its small group, where a single 'not' immediately fixes the pairing.

Answer: (d) Tuesday

Explanation:
1. A needs a holiday just before it, so A cannot be on Monday; it is not on Tuesday either.
2. Exactly two programmes (holiday not counted) must lie between A and C. Trying A on Thursday or Saturday leaves only one programme between A and C, so A is on Wednesday with Tuesday a holiday.
3. Then C is on Saturday, E and D take Thursday and Friday (E before D), and B is on Monday: B, holiday, A, E, D, C.

Teacher's Note:
1. Place the most restricted item first (here A, which drags a holiday with it), then fit the others around it.
2. Read counting conditions carefully: a holiday is not a programme, so it is not counted in 'between' conditions.

Answer: (b) Wednesday

Explanation:
1. A needs a holiday just before it, so A cannot be on Monday; it is not on Tuesday either.
2. Exactly two programmes (holiday not counted) must lie between A and C. Trying A on Thursday or Saturday leaves only one programme between A and C, so A is on Wednesday with Tuesday a holiday.
3. Then C is on Saturday, E and D take Thursday and Friday (E before D), and B is on Monday: B, holiday, A, E, D, C.

Teacher's Note:
1. Place the most restricted item first (here A, which drags a holiday with it), then fit the others around it.
2. Read counting conditions carefully: a holiday is not a programme, so it is not counted in 'between' conditions.

Answer: (d) B, A, E, D, C

Explanation:
1. A needs a holiday just before it, so A cannot be on Monday; it is not on Tuesday either.
2. Exactly two programmes (holiday not counted) must lie between A and C. Trying A on Thursday or Saturday leaves only one programme between A and C, so A is on Wednesday with Tuesday a holiday.
3. Then C is on Saturday, E and D take Thursday and Friday (E before D), and B is on Monday: B, holiday, A, E, D, C.

Teacher's Note:
1. Place the most restricted item first (here A, which drags a holiday with it), then fit the others around it.
2. Read counting conditions carefully: a holiday is not a programme, so it is not counted in 'between' conditions.

Answer: (d) Divya

Explanation:
1. Rohit forces Chetan into the team.
2. One of Anup or Bhavya must also be there, so both faculty places are filled by Chetan and Anup/Bhavya.
3. No faculty place is left, so Divya cannot be selected.

Teacher's Note:
1. Turn each 'if ... then' condition into a quick check and test every option against all of them.
2. In 'exactly one of two' conditions, one member of the pair always takes a fixed slot, which leaves very little room for others.

Answer: (a) Usha

Explanation:
1. Two faculty (Bhavya, Divya) are already in, so the fourth member is a student.
2. Tanuja is ruled out because Bhavya is in; Rohit is ruled out because he needs Chetan, and no faculty place is left.
3. The fourth member is Usha.

Teacher's Note:
1. Turn each 'if ... then' condition into a quick check and test every option against all of them.
2. In 'exactly one of two' conditions, one member of the pair always takes a fixed slot, which leaves very little room for others.

Answer: (b) Anup and Chetan

Explanation:
1. The two students must then be Rohit and Tanuja.
2. Rohit requires Chetan; Tanuja rules out Bhavya, so Anup must be the Anup/Bhavya member.
3. The faculty pair is Anup and Chetan.

Teacher's Note:
1. Turn each 'if ... then' condition into a quick check and test every option against all of them.
2. In 'exactly one of two' conditions, one member of the pair always takes a fixed slot, which leaves very little room for others.

Answer: (d) Fourth

Explanation:
1. L must come immediately before M.
2. M is 5th, so L is 4th; slots 4 and 5 are both in the afternoon, so the lunch break does not separate them.

Teacher's Note:
1. Draw six slots with a break between slots 3 and 4; a 'block' of two can never straddle that break.
2. Place fixed-end items (first or last) and blocks before the free items.

Answer: (c) K is fourth

Explanation:
1. N cannot be last (O is 6th), so N is first.
2. The L-M block cannot use slots 3-4 (lunch break) and slots 4-5 are blocked by P, so L-M take slots 2-3.
3. The only slot left, 4th, goes to K.

Teacher's Note:
1. Draw six slots with a break between slots 3 and 4; a 'block' of two can never straddle that break.
2. Place fixed-end items (first or last) and blocks before the free items.

Answer: (d) None of the cars is parked in slot number 5

Explanation:
1. Slot 3 is red, so blue (next to white in 2) must be in slot 1.
2. Green and maroon go into slots 4, 5, 6 without being adjacent, so they take 4 and 6.
3. Slot 5 is therefore empty.

Teacher's Note:
1. With five cars in six slots, track the empty slot as if it were a sixth item.
2. For 'must be true' questions, look for one arrangement that breaks an option; the option no arrangement can break is the answer.

Answer: (d) 5

Explanation:
1. If maroon is in 5, green cannot be in 4 or 6, so green is in 1 or 2.
2. The slots left (from 1, 2, 4, 6) then contain no two adjacent free slots for blue and white.
3. Maroon fits in 1, 2 or 4 (for example blue-white in 4-5, green in 6 with maroon in 1), but never in 5.

Teacher's Note:
1. With five cars in six slots, track the empty slot as if it were a sixth item.
2. For 'must be true' questions, look for one arrangement that breaks an option; the option no arrangement can break is the answer.

Answer: (a) 1

Explanation:
1. Maroon cannot be in 1 (next to green in 2), so maroon is in 4, 5 or 6.
2. Blue and white need two adjacent slots: 4-5 (maroon 6) or 5-6 (maroon 4).
3. In every case slot 1 stays empty.

Teacher's Note:
1. With five cars in six slots, track the empty slot as if it were a sixth item.
2. For 'must be true' questions, look for one arrangement that breaks an option; the option no arrangement can break is the answer.

Answer: (d) One of the cars is parked in slot number 6.

Explanation:
1. If slot 6 were empty, the four cars would occupy 1, 2, 4, 5, which form two adjacent pairs (1-2 and 4-5).
2. Blue-white would take one pair and green-maroon would be forced into the other pair, making them adjacent, which is not allowed.
3. So slot 6 is always occupied; the other options fail, e.g. blue 1, white 2, green 4, empty 5, maroon 6.

Teacher's Note:
1. With five cars in six slots, track the empty slot as if it were a sixth item.
2. For 'must be true' questions, look for one arrangement that breaks an option; the option no arrangement can break is the answer.

Answer: (a) Archana

Explanation:
1. Chandrika has long hair, so she does not write letters and therefore lives in Mysore.
2. Archana calls the dancer, so Archana is not the dancer; Chandrika lives in Mysore, not Goa. So Bhargavi is the dancer in Goa.
3. The remaining city, Pune, belongs to Archana, and the sister in Pune is married to Tushar.
4. So Archana lives in Pune.

Teacher's Note:
1. Chain the clues: a fact about one sister (long hair) often leads through two or three clues to her city.
2. Some clues are only colour (fairness, phone bills); identify and ignore them quickly.

Answer: (d) Data incomplete

Explanation:
1. Chandrika has long hair, so she does not write letters and therefore lives in Mysore.
2. Archana calls the dancer, so Archana is not the dancer; Chandrika lives in Mysore, not Goa. So Bhargavi is the dancer in Goa.
3. The remaining city, Pune, belongs to Archana, and the sister in Pune is married to Tushar.
4. Tushar is Archana's husband; Chandrika's husband is Ranjit or Sailesh, and no clue decides between them, so the data is incomplete.

Teacher's Note:
1. Chain the clues: a fact about one sister (long hair) often leads through two or three clues to her city.
2. Some clues are only colour (fairness, phone bills); identify and ignore them quickly.

Answer: (b) Bhargavi

Explanation:
1. Chandrika has long hair, so she does not write letters and therefore lives in Mysore.
2. Archana calls the dancer, so Archana is not the dancer; Chandrika lives in Mysore, not Goa. So Bhargavi is the dancer in Goa.
3. The remaining city, Pune, belongs to Archana, and the sister in Pune is married to Tushar.
4. So the dancer is Bhargavi.

Teacher's Note:
1. Chain the clues: a fact about one sister (long hair) often leads through two or three clues to her city.
2. Some clues are only colour (fairness, phone bills); identify and ignore them quickly.

Answer: (b) Housewife

Explanation:
1. Roopa is not a lecturer, auditor or doctor, so she is a housewife. The auditor is married to the sales executive, who is not Madhurima's or Chandana's husband, and Sahana is not an auditor, so Kanchana is the auditor, married to the sales executive.
2. The lecturer is not Chandana, Sahana or Roopa, so Madhurima is the lecturer, married to the naval officer.
3. Chandana, Sahana and Roopa share the doctor, advocate and architect husbands; Sahana and Roopa cannot have the architect, so Chandana's husband is the architect.
4. The same-profession couple must be doctor-doctor, so Sahana is the doctor married to the doctor; Roopa (housewife) has the advocate and Chandana is a housewife.

Teacher's Note:
1. Keep two separate grids (wife's profession and husband's profession) and link them only through the 'married to' clues.
2. A clue like 'one couple has the same profession' only works for a profession that appears on both lists; here that is doctor.

Answer: (b) Architect - Chandana

Explanation:
1. Roopa is not a lecturer, auditor or doctor, so she is a housewife. The auditor is married to the sales executive, who is not Madhurima's or Chandana's husband, and Sahana is not an auditor, so Kanchana is the auditor, married to the sales executive.
2. The lecturer is not Chandana, Sahana or Roopa, so Madhurima is the lecturer, married to the naval officer.
3. Chandana, Sahana and Roopa share the doctor, advocate and architect husbands; Sahana and Roopa cannot have the architect, so Chandana's husband is the architect.
4. The same-profession couple must be doctor-doctor, so Sahana is the doctor married to the doctor; Roopa (housewife) has the advocate and Chandana is a housewife.

Teacher's Note:
1. Keep two separate grids (wife's profession and husband's profession) and link them only through the 'married to' clues.
2. A clue like 'one couple has the same profession' only works for a profession that appears on both lists; here that is doctor.

Answer: (c) Madhurima

Explanation:
1. Roopa is not a lecturer, auditor or doctor, so she is a housewife. The auditor is married to the sales executive, who is not Madhurima's or Chandana's husband, and Sahana is not an auditor, so Kanchana is the auditor, married to the sales executive.
2. The lecturer is not Chandana, Sahana or Roopa, so Madhurima is the lecturer, married to the naval officer.
3. Chandana, Sahana and Roopa share the doctor, advocate and architect husbands; Sahana and Roopa cannot have the architect, so Chandana's husband is the architect.
4. The same-profession couple must be doctor-doctor, so Sahana is the doctor married to the doctor; Roopa (housewife) has the advocate and Chandana is a housewife.

Teacher's Note:
1. Keep two separate grids (wife's profession and husband's profession) and link them only through the 'married to' clues.
2. A clue like 'one couple has the same profession' only works for a profession that appears on both lists; here that is doctor.

Answer: (a) Sahana

Explanation:
1. Roopa is not a lecturer, auditor or doctor, so she is a housewife. The auditor is married to the sales executive, who is not Madhurima's or Chandana's husband, and Sahana is not an auditor, so Kanchana is the auditor, married to the sales executive.
2. The lecturer is not Chandana, Sahana or Roopa, so Madhurima is the lecturer, married to the naval officer.
3. Chandana, Sahana and Roopa share the doctor, advocate and architect husbands; Sahana and Roopa cannot have the architect, so Chandana's husband is the architect.
4. The same-profession couple must be doctor-doctor, so Sahana is the doctor married to the doctor; Roopa (housewife) has the advocate and Chandana is a housewife.

Teacher's Note:
1. Keep two separate grids (wife's profession and husband's profession) and link them only through the 'married to' clues.
2. A clue like 'one couple has the same profession' only works for a profession that appears on both lists; here that is doctor.

Answer: (a) B was born in 1990

Explanation:
1. With A in 1992, the S-K pair (2 years apart) can be 1991-1993 or 1993-1995.
2. Only B or S can be the oldest (K, M, H are younger than someone). If S were 1990, K would be 1992, A's year, so S is not 1990.
3. So B was born in 1990 in every valid case; M and H vary.

Teacher's Note:
1. Write the six years 1990-1995 as slots; 'younger' means a later year.
2. Place the pair with a fixed gap (K two years after S) in every possible way and reject cases that break the other clues.

Answer: (b) M was born in 1994

Explanation:
1. A is younger than K and A is 1992 or 1993; K = S + 2, so K is at least 1992, giving K 1992 and A 1993.
2. Then S is 1990, B is 1991, and H and M take 1994 and 1995 in either order.
3. So M could be 1994 or 1995: 'M was born in 1994' need not be true.

Teacher's Note:
1. Write the six years 1990-1995 as slots; 'younger' means a later year.
2. Place the pair with a fixed gap (K two years after S) in every possible way and reject cases that break the other clues.

Answer: (c) K was born in 1994

Explanation:
1. K is two years younger than S, so K was born in 1994.
2. Then A is 1993, B (older than K and M) is 1990, M is 1991, H is 1995.

Teacher's Note:
1. Write the six years 1990-1995 as slots; 'younger' means a later year.
2. Place the pair with a fixed gap (K two years after S) in every possible way and reject cases that break the other clues.

Answer: (d) Thursday at Shyam's house

Explanation:
1. Neetu rules out Latha's house and Kirthi rules out Neetu's house, so the meeting must be at Shyam's house.
2. Maya rules out Tuesday and Friday, so Thursday at Shyam's house is the only fit.

Teacher's Note:
1. List each person's restriction as a rule about place, day or another person, then strike out members one by one.
2. 'Can attend only if X attends' means X's absence removes that person too; watch such chain reactions.

Answer: (b) The meeting is at Latha's house

Explanation:
1. Shyam attends only when Kirthi and Maya attend, so Kirthi is present.
2. Kirthi cannot attend at Neetu's house, and it is not at Shyam's house, so it is at Latha's house.

Teacher's Note:
1. List each person's restriction as a rule about place, day or another person, then strike out members one by one.
2. 'Can attend only if X attends' means X's absence removes that person too; watch such chain reactions.

Answer: (d) The meeting is held at Shyam's house

Explanation:
1. Maya's presence rules out Tuesday and Friday.
2. Kirthi's presence rules out Neetu's house.
3. A meeting at Shyam's house remains possible (Tom's absence only removes Ram).

Teacher's Note:
1. List each person's restriction as a rule about place, day or another person, then strike out members one by one.
2. 'Can attend only if X attends' means X's absence removes that person too; watch such chain reactions.

Answer: (b) 2

Explanation:
1. Out: Tom (unable), Ram (needs Tom), Maya (Tuesday), Kirthi (Neetu's house), and Shyam (needs Kirthi and Maya).
2. Only Latha and Neetu can attend, so the maximum is 2.

Teacher's Note:
1. List each person's restriction as a rule about place, day or another person, then strike out members one by one.
2. 'Can attend only if X attends' means X's absence removes that person too; watch such chain reactions.

Answer: (c) Seventh

Explanation:
1. Pinks are at 1, 2 and 10, so positions 5-9 hold white, two blues and two greens.
2. The blue pair cannot touch green; it must sit at 8-9 (next to pink at 10) with white at 7 as a buffer from the greens.
3. Order: P P G G G G W B B P, so white is 7th.

Teacher's Note:
1. Write positions 1-10, fix the given colours, and note which colours may never be neighbours.
2. The blue pair cannot touch green, so it must be bordered by white or pink; use that to locate it quickly.

Answer: (c) Sixth

Explanation:
1. Blue at 4 cannot have green at 5, and pink cannot be next to white; the second blue must be at 5 (position 3 is pink).
2. Position 6 cannot be green (next to blue) or pink, so it is white.
3. Order: P G P B B W G G G P, so white is 6th.

Teacher's Note:
1. Write positions 1-10, fix the given colours, and note which colours may never be neighbours.
2. The blue pair cannot touch green, so it must be bordered by white or pink; use that to locate it quickly.