CBSE Class 11 Chemistry VBQs P Block Elements

CBSE Class 11 Chemistry VBQs P Block Elements read and download in pdf. Value Based Questions come in exams for Chemistry in Class 11 and are easy to learn and helpful in scoring good marks. You can refer to more chapter wise VBQs for Class 11 Chemistry and also get latest topic wise very useful study material as per latest NCERT book for Class 11 Chemistry and all other subjects for free on Studiestoday designed as per latest Class 11 CBSE, NCERT and KVS syllabus and examination pattern

VBQ for Class 11 Chemistry Chapter 11 The p Block Elements

Class 11 Chemistry students should refer to the following value based questions with answers for Chapter 11 The p Block Elements in Class 11. These VBQ questions with answers for Class 11 Chemistry will come in exams and help you to score good marks

Chapter 11 The p Block Elements VBQ Questions Class 11 Chemistry with Answers

Question. The correct order of atomic radii in group 13 elements is
(a) B < Al < In < Ga < Tl
(b) B < Al < Ga < In < Tl
(c) B < Ga < Al < Tl < In
(d) B < Ga < Al < In < Tl 
Answer. D

Question. AlF3 is soluble in HF only in presence of KF. It is due to the formation of
(a) K3[AlF3H3]
(b) K3[AlF6]
(c) AlH3
(d) K[AlF3H]
Answer. B

Question. The stability of +1 oxidation state among Al, Ga, In and Tl increases in the sequence
(a) Al < Ga < In < Tl
(b) Tl < In < Ga < Al
(c) In < Tl < Ga < Al
(d) Ga < In < Al < Tl
Answer. A

Question. Aluminium(III) chloride forms a dimer because aluminium
(a) belongs to 3rd group
(b) can have higher coordination number
(c) cannot form a trimer
(d) has high ionization energy. 
Answer. B

Question. Which one of the following elements is unable to form MF63– ion?
(a) Ga
(b) Al
(c) B
(d) In 
Answer. C

Question. The tendency of BF3, BCl3 and BBr3 to behave as Lewis acid decreases in the sequence
(a) BCl3 > BF3 > BBr3
(b) BBr3 > BCl3 > BF3
(c) BBr3 > BF3 > BCl3
(d) BF3 > BCl3 > BBr3 
Answer. B

Question. Boron compounds behave as Lewis acids, because of their
(a) ionisation property
(b) electron deficient nature
(c) acidic nature
(d) covalent nature. 
Answer. B

Question. Boric acid is an acid because its molecule
(a) contains replaceable H+ ion
(b) gives up a proton
(c) accepts OH– from water releasing proton
(d) combines with proton from water, molecule.
Answer. C

Question. Which of the following structure is similar to graphite?
(a) B4C
(b) B2H6
(c) BN
(d) B 
Answer. C

Question. The type of hybridisation of boron in diborane is
(a) sp3-hybridisation
(b) sp2-hybridisation
(c) sp-hybridisation
(d) sp3d2-hybridisation.
Answer. A

Question. Which of the following statements about H3BO3 is not correct?
(a) It has a layer structure in which planar BO3 units are joined by hydrogen bonds.
(b) It does not act as proton donor but acts as a Lewis acid by accepting hydroxyl ion.
(c) It is a strong tribasic acid.
(d) It is prepared by acidifying an aqueous solution of borax.
Answer. C

Question. Which of the following is incorrect statement ?
(a) SnF4 is ionic in nature.
(b) PbF4 is covalent in nature.
(c) SiCl4 is easily hydrolysed.
(d) GeX4 (X = F, Cl, Br, I) is more stable than GeX2.
Answer. B

Question. Which of the following species is not stable?
(a) [SiCl6]2–
(b) [SiF6]2–
(c) [GeCl6]2–
(d) [Sn(OH)6]2–
Answer. A

Question. It is because of inability of ns2 electrons of the valence shell to participate in bonding that
(a) Sn2+ is oxidising while Pb4+ is reducing
(b) Sn2+ and Pb2+ are both oxidising and reducing
(c) Sn4+ is reducing while Pb4++ is oxidising
(d) Sn2+ is reducing while Pb4+ is oxidising.
Answer. D

Question. Which of the following oxidation states are the most characteristic for lead and tin respectively?
(a) +2, +4
(b) +4, +4
(c) +2, +2
(d) +4, +2 
Answer. A

Question. Carbon and silicon belong to (IV) group. The maximum coordination number of carbon in commonly occurring compounds is 4, whereas that of silicon is 6. This is due to
(a) availability of low lying d-orbitals in silicon
(b) large size of silicon
(c) more electropositive nature of silicon
(d) both (b) and (c). 
Answer. A

Question. Which of the following does not show electrical conduction?
(a) Diamond
(b) Graphite
(c) Potassium
(d) Sodium 
Answer. A

Question. Percentage of lead in lead pencil is
(a) 80
(b) 20
(c) zero
(d) 70 
Answer. C

Question. In graphite, electrons are
(a) localised on each C-atom
(b) localised on every third C-atom
(c) spread out between the structure
(d) present in antibonding orbital. 
Answer. C

Question. Which of the following types of forces bind together the carbon atoms in diamond?
(a) Ionic
(b) Covalent
(c) Dipolar
(d) van der Waals 
Answer. B

Question. Which of the following is an insulator?
(a) Graphite
(b) Aluminium
(c) Diamond
(d) Silicon 
Answer. C

Question. Identify the correct statements from the following :
(A) CO2(g) is used as refrigerant for ice-cream and frozen food.
(B) The structure of C60 contains twelve six carbon rings and twenty five carbon rings.
(C) ZSM-5, a type of zeolite, is used to convert alcohols into gasoline.
(D) CO is colourless and odourless gas.
(a) (A), (B) and (C) only
(b) (A) and (C) only
(c) (B) and (C) only
(d) (C) and (D) only
Answer. D

Question. Which of the following compounds is used in cosmetic surgery?
(a) Silica
(b) Silicates
(c) Silicones
(d) Zeolites
Answer. C

Question. Which of these is not a monomer for a high molecular mass silicone polymer?
(a) Me3SiCl
(b) PhSiCl3
(c) MeSiCl3
(d) Me2SiCl2
Answer. A

Question. The basic structural unit of silicates is
(a) SiO32–
(b) SiO42–
(c) SiO
(d) SiO44– 
Answer. D

Question. Which statement is wrong?
(a) Beryl is an example of cyclic silicate.
(b) Mg2SiO4 is orthosilicate.
(c) Basic structural unit in silicates is the SiO4 tetrahedron.
(d) Feldspars are not aluminosilicates.
Answer. D

Question. Name the two types of the structure of silicate in which one oxygen atom of [SiO4]4– is shared?
(a) Linear chain silicate
(b) Sheet silicate
(c) Pyrosilicate
(d) Three dimensional
Answer. C

Question. The straight chain polymer is formed by
(a) hydrolysis of CH3SiCl3 followed by condensation polymerisation
(b) hydrolysis of (CH3)4Si by addition polymerisation
(c) hydrolysis of (CH3)2SiCl2 followed by condensation polymerisation
(d) hydrolysis of (CH3)3SiCl followed by condensation polymerisation. 
Answer. C

Question. Which of the following anions is present in the chain structure of silicates?
(a) (Si2O52–)n
(b) (SiO32–)n
(c) SiO44–
(d) Si2O76– 
Answer. B

Question. Which one of the following statements about the zeolite is false?
(a) They are used as cation exchangers.
(b) They have open structure which enables them to take up small molecules.
(c) Zeolites are aluminosilicates having three dimensional network.
(d) Some of the SiO44– units are replaced by AlO45–and AlO69– ions in zeolites. 
Answer. D

Question. The substance used as a smoke screen in warfare is
(a) SiCl4
(b) PH3
(c) PCl5
(d) acetylene
Answer. A


Question. One of the elements of group 13 was not known at that time when Mendeleev gave his periodic table. This element has some interesting properties much different from other elements of this group.

Now answer the following questions:

(i) Name the element which was not known at Mendeleev’s time.
Answer: 
Gallium

(ii) Mention its interesting properties.
Answer:
 It can melt at 303 K but it does not boil up to 2676 K.

(iii) Give its one use.
Answer: 
Used as semi-conductor.

Question. Kevlar is a nylon obtained by condensation polymerisation of 1,4- diaminobenzene and 1,4- benzenedicarboxylic acid. Its fibre is five times stronger than steel and hence are used for making bullet- proof vests. There are two compounds of boron which are also used for making bullet-proof vests.

Now answer the following questions:

(i) Name the two compounds of boron used for making bullet-proof vests and how are they prepared?
Answer: 
Boron nitride (BN) and Boron carbide (B4C)​​​​​​
B2O3(s) + 2NH3à 2 BN (s) + 3H2(g) (At 1173 K)
2 B2O3(s) + 7 C (s) –Electric furnace --> B4(s) + 6CO (g) (At 1873 K)

(ii) What are the advantages of using boron based compounds over Kevlar?
Answer: 
Boron has high ability to absorb neutrons and hence these two boron compounds can act as protective shield against radioactive radiations.

Please click the link below to download CBSE Class 11 Chemistry VBQs p Block Elements.

Chapter 01 Some Basic Concepts of Chemistry
CBSE Class 11 Chemistry VBQs Basic Concepts Of Chemistry
Chapter 03 Classification of Elements and Periodicity in Properties
CBSE Class 11 Chemistry VBQs Classification Of Elements And Periodicity
Chapter 04 Chemical Bonding and Molecular Structure
CBSE Class 11 Chemistry VBQs Chemical Bonding And Molecular Structure
Chapter 10 The s Block Elements
CBSE Class 11 Chemistry VBQs S Block Elements
Chapter 11 The p Block Elements
CBSE Class 11 Chemistry VBQs P Block Elements
Chapter 12 Organic Chemistry Some Basic Principles and Techniques
CBSE Class 11 Chemistry VBQs Some Basic Concept In Organic Chemistry
Chapter 14 Environmental Chemistry
CBSE Class 11 Chemistry VBQs Environmental Chemistry

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CBSE Class 11 Chemistry Chapter 11 The p Block Elements VBQs

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