CBSE Class 10 Mathematics Pair of Linear Equation In Two Variables Worksheet Set D

Read and download free pdf of CBSE Class 10 Mathematics Pair of Linear Equation In Two Variables Worksheet Set D. Download printable Mathematics Class 10 Worksheets in pdf format, CBSE Class 10 Mathematics Chapter 3 Linear Equations Worksheet has been prepared as per the latest syllabus and exam pattern issued by CBSE, NCERT and KVS. Also download free pdf Mathematics Class 10 Assignments and practice them daily to get better marks in tests and exams for Class 10. Free chapter wise worksheets with answers have been designed by Class 10 teachers as per latest examination pattern

Chapter 3 Linear Equations Mathematics Worksheet for Class 10

Class 10 Mathematics students should refer to the following printable worksheet in Pdf in Class 10. This test paper with questions and solutions for Class 10 Mathematics will be very useful for tests and exams and help you to score better marks

Class 10 Mathematics Chapter 3 Linear Equations Worksheet Pdf

CASE STUDY 1: Apartments have increasingly become the most supplied property type across cities in India. Their popularity can be attributed to reasons including but not limited to contemporary looks, modern day amenities, in-house maintenance and better security. Inaya is planning to buy a 2BHK apartment and the layout is given below. The design and the measurement has been made such that area bedrooms and kitchen together is 95 sq.m.

""CBSE-Class-10-Mathematics-Pairs-of-Linear-Equations-in-Two-Variables-2

Question. Which pair of linear equations in two variables does describe this situation.
(a) x + y =17, 3x + y = 15
(b) x + y =27, 3x + 4y = 95
(c) 5x + 2y =15, x + 4y = 12
(d) 2x + y =19, x + y = 13
Answer : D

Question. What is the length of the outer boundary of the layout?
(a) 40 m
(b) 54 m
(c) 27 m
(d) 48 m
Answer : B

Question. What is the area of the bedroom 1?
(a) 30m2
(b) 40m2
(c) 55m2
(d) 35m2
Answer : A

Question. What is the cost of laying tiles in kitchen at the rate of ₹. 100 per sq.m.
(a) ₹.3000
(b) ₹.3250
(c) ₹.3500
(d) ₹.3750
Answer : C

 

Very Short Answer type Questions

Question. State whether or not the lines represented by the equations 𝑥 + 1 = 0 𝑎𝑛𝑑 2𝑥 + 2 = 0 are coincident?
Answer : yes

Question. 2𝑥 + 𝑦 + 9 = 0 ,𝑥 + 3𝑦 + 7 = 0
Answer : 3, 2

Question. For what value of k do the equations 3𝑥 − 𝑦 + 8 = 0 & 𝑏𝑥 − 𝑘𝑦 + 16 = 0 represent coincident lines.
Answer : 
No solution

Question. What is the number of solutions of the pair of equations 𝑥 = 0; 𝑦 = 0?
Answer : (0, 0)

Question. Two positive numbers differ by 3 and their product is 54. Find the no.s
Answer : 
A = 3, b = 1

Question. Sum of two numbers is 35 and their difference is 13, find the numbers
Answer : 24, 11

Question. What is the value of ‘a’ for which the equations 𝑦 = 𝑥 𝑎𝑛𝑑 𝑦 = 𝑎𝑥 have infinitely many solutions
Answer : 1

Question. Find the value of ‘p’ for which the pair of linear equations 2𝑝𝑥 + 3𝑦 = 7: 2𝑥 + 𝑦 = 6 has exactly one solution
Answer : P ≠ 3

Question. Express ‘y’ in terms of ‘x’ of the equation. 3𝑥 + 5𝑦 = 11. check whether (3,4) satisfies the given equation or not.
Answer : 
= 𝑦 + 2 / 3

Question. Write whether the following pair of linear equations is consistent or not.
Answer : consistent

 

Short Answer type Questions

Question. What number must be added to each of the numbers, 5, 9, 17, 27 to make the numbers in proportion ?
Answer : Four numbers are in proportion if
First × Fourth = Second × Third.
Let x be added to each of the given numbers to make the numbers in proportion. Then,
(5 + x) (27 + x) = (9 + x) (17 +x)
=> 135 + 32x + x2 = 153 + 26x + x2
=> 32x – 26x = 153 – 135
=> 6x = 18
=> x = 3
 

Question. Solve: 99𝑥 + 101𝑦 = 499: 101𝑥 + 99𝑦 = 501
Answer : 
Add two given equations
𝑥+𝑦 = 5 (1)
𝑆𝑢𝑏𝑡𝑟𝑎𝑐𝑡 𝑡𝑤𝑜 𝑔𝑖𝑣𝑒𝑛 𝑒𝑞𝑢𝑎𝑡𝑖𝑜𝑛𝑠
𝑥– 𝑦 = 1 (2)
(1) + (2)
2𝑥 = 6
𝑥 = 3
𝑆𝑢𝑏 𝑥 =3 𝑖𝑛 (1) 𝑦 = 2

Question. Anu’s father is three times as old as Anu. After five years, his age will be two and half times as old as Anu. Represent this situation algebraically only.
Answer : 

𝐿𝑒𝑡 𝐴𝑛𝑢’𝑠 𝑎𝑔𝑒 = 𝑥
𝐹𝑎𝑡ℎ𝑒𝑟’𝑠 𝑎𝑔𝑒 = 𝑦
𝑥 = 3𝑦
𝑦+5 =(2X1/2 )( 𝑥+5)
2𝑦 + 10 = 5𝑥+25
5𝑥 – 2𝑦 = 15

Question. Solve the pair of linear equations by elemination method:
i. 𝑥 – 𝑦 + 1 = 0
ii. 4𝑥 + 3𝑦 – 10 = 0
Answer : 

(2) × 4 →
4x – 4y + 4 = 0
4x + y – 6 = 0
5y – 10 = 0
y = 2
x = 1

Question. The difference between two numbers is 26 and one number is three times the other. Find them.
Answer : Let the numbers be x and y.
Difference of two numbers is 26.
i.e., x – y = 26 ....(1)
One number is three times the other.
i.e., x = 3y ....(2)
Putting x = 3y in (1), we get
3y – y = 26
=> 2y = 26
=> y = 13
Putting y = 13 in (2), we get
x = 3 × 13 = 39
Hence, the numbers are x = 39 and y = 13.
Problems Based on Ages
 
Question. Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.
Answer : Let the age of father = x years.
And the sum of the ages of his two children
= y years
According to the question
Father’s age = 3 × (sum of the ages of his two
children)
=> x = 3y                        ....(1)
After 5 years 
Father’s age = (x + 5) years
sum of the ages of his two childrens
= y + 5 + 5 = y + 10
[Age of his each children increases by 5 years]
According to the question,
After 5 years
Father’s age = 2 × (sum of ages of his two children)
=> x + 5 = 2 × (y + 10)
=> x + 5 = 2y + 20
=> x – 2y = 15                ....(2)
Putting x = 3y from (1) in (2), we get
3y – 2y = 15
=> y = 15 years
And x = 3y
=> x = 3 × 15 = 45
=> x = 45 years

Question. Four chairs and three tables cost 2100/- and 5 chairs and 2 tables cost 1750/-. Find the cost of a chair and table respectively
Answer : 
Let the cost of 1 chair be x /- and that of table be y/-
Then by given condition,
4x + 3y = 2100 ……………..(i)
5x + 2y = 1750 …………..(ii)
Solving x = 150/- and y = 500/-
Cost of one chair = 150 /- and cost of 1 table = 500/-

Question. Determine the values of a and b for which the following system of linear equations have infinite solutions
2𝑥 − (𝑎 − 4)𝑦 = 2𝑏 + 1 ;
4𝑥 − (𝑎 − 1) 𝑦 = 5𝑏 − 1
Answer : 
A pair of linear equation has infinitely many solutions, if a1/a2 = b1/b2 = c1/c2
Therefore 2/4 = − a − 4/ − (a − 1) = 2b + 1/5b − 1
Solving, a = 7 and b = 3

Question. Solve by elimination:
a. 𝑥 − 𝑦 + 1 = 0 𝑎𝑛𝑑 4𝑥 + 3𝑦 − 10 = 0
b. 3𝑥 − 4𝑦 = 15 𝑎𝑛𝑑 2𝑥 – 2𝑦 = 8
Answer : 
(i) x = 1, y = 2
(ii) x = 1, y = -3

Question. Yash scored 40 marks in a test, receiving 3 marks for each correct answer and losing 1 mark for each wrong answer. Had 4 marks been awarded for each correct answer and 2 marks been deducted for each wrong answer, then Yash would have scored 50 marks. How many questions were there in the test?
Answer : 
Let right answer questions attempt by Yash be x wrong answer questions be y
Then, 3x – y = 40………….(i)
4x - 2y = 50 …………(ii)
Solving we get x = 15, y = 5
Total number of questions in the test = x + y = 15 + 5 = 20

Question. The age of the father is twice the sum of the ages of his 2 children. After 20 years, his age will be equal to the sum of the ages of his children. Find the age of the father
Answer : 
Let the present ages of children be x years and y years respectively.
Present age of father is twice the sum of ages of his 2 children = 2(x + y) ………..(i)
Then by question,
(x + 20) + (y + 20) = 2(x + y) + 20
x + y + 40 = 2x + 2y + 20
x + y = 20
Putting (x + y) in (i),
2(x + y) = 2 × 20 = 40

CBSE Class 10 Mathematics Pair of Linear Equation In Two Variables Worksheet Set D

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