CBSE Class 11 Mathematics Permutations And Combinations Worksheet Set D

Read and download free pdf of CBSE Class 11 Mathematics Permutations And Combinations Worksheet Set D. Students and teachers of Class 11 Mathematics can get free printable Worksheets for Class 11 Mathematics Chapter 7 Permutations and Combinations in PDF format prepared as per the latest syllabus and examination pattern in your schools. Class 11 students should practice questions and answers given here for Mathematics in Class 11 which will help them to improve your knowledge of all important chapters and its topics. Students should also download free pdf of Class 11 Mathematics Worksheets prepared by school teachers as per the latest NCERT, CBSE, KVS books and syllabus issued this academic year and solve important problems with solutions on daily basis to get more score in school exams and tests

Worksheet for Class 11 Mathematics Chapter 7 Permutations and Combinations

Class 11 Mathematics students should refer to the following printable worksheet in Pdf for Chapter 7 Permutations and Combinations in Class 11. This test paper with questions and answers for Class 11 will be very useful for exams and help you to score good marks

Class 11 Mathematics Worksheet for Chapter 7 Permutations and Combinations

Question. The number of divisors of 9600 including 1 and 9600 are:
a. 60
b. 58
c. 48
d. 46
Answer : C

Question. The number of ways of painting the faces of a cube with six different colours is:
a. 1
b. 6
c. 6!
d. 9C2
Answer : A, D

Question. Sanjay has 10 friends among whom two are married to each other. She wishes to invite 5 of the them for a party. If the married couple refuse to attend separately, the number of different ways in which she can invite five friends is:
a. 8C5
b. 2 × 8C3
c. 10C5 – 2 × 8C4
d. none of these
Answer : B, C

Question. There are n seats round a table marked 1,2,3,…n. The number of ways in which m(≤n) persons can takes seats is:
a. nPm
b. nCm x (m - 1)
c. nCm × m!
d. n-1pm-1
Answer : A, C

Question. The number of ways in which 10 candidates A1, A2,…, A10 can be ranked, so that A1 is always above Ais:
a. 10!/2
b. 8! × 10C2
c. 10p2
d. 10p2
Answer : 

Question. In a class tournament when the participants were to play one game with another, two class players fell ill, having played 3 games each. If the total number of games played is 84, the number of participants at the beginning was:
a. 15
b. 30
c. 6C2
d. 48
Answer : A, C

Question. The number of ways of distributing 10 different books among 4 students (S1 − S4 ) such that S and 2 get 2 books each and S3 and S4 get books each is:
a. 12600/
b. 25200
c. 10C4
D. 10!/2!2!3!3!
Answer : B, D

Question. The number of ways to select 2 numbers from {0,1,2,3,4}  such that the sum of the squares of the selected numbers is divisible by 5 are: (repetition of digits is allowed)
a. 9C1
b. 9C8
c. 9
d. 7
Answer : A, B, C

Question. The number of ways of arranging seven persons (having A, B, C and D among them) in a row so that A, B, C and D are always in order A–B–C–D (not necessarily together) is:
a. 210
b. 5040
c. 6 × 7C4
d. 7C3
Answer : A, C, D

Question. Total number of ways of giving at least one coin out of three 25 paise and two 50 pasise coins to a beggar is:
a. 32
b. 12
c. 11
d. 12P1 – 1
Answer : C, D

Question. If α = x1 x2 x3 and β = y1 y2 y3 be two three digits numbers, the number of pairs of α and β can be formed so thatα can be subtracted fromβ without borrowing is:
a. 2!10!10!
b. (45)(55)2
c. 32. 53 .112
d. 136125
Answer : B, C, D

Assertion and Reason

Note: Read the Assertion (A) and Reason (R) carefully to mark the correct option out of the options given below:
a. If both assertion and reason are true and the reason is the correct explanation of the assertion.
b. If both assertion and reason are true but reason is not the correct explanation of the assertion.
c. If assertion is true but reason is false.
d. If the assertion and reason both are false.
e. If assertion is false but reason is true.

Question. Assertion: The number of ways of distributing 10 identical balls in 4 distinct boxes such that no box is empty is 9C3
Reason: The number of ways of choosing 3 places from 9 different place is 9C
3
Answer : B

Question. Assertion: If p is a prime, the exponent of p in n! is [n/p] + [n/p2] + [n/p3] +......
Reason: where [x] denotes the greatest integer ≤ x.

Answer : A

Question. Assertion: A student is allowed to select at most n books from a collection of (2n +1) books. If the total number of ways in which he can select at least one book is 255, thenn = 3.

Answer : D

Question. If the number of ways of selecting n coupons out of an unlimited number of coupons bearing the letters A, T, C so that they cannot be used to spell to the used CAT is 189, then Σn2 must be:
Answer : 127

Question. The letters of the word PATNA are arrange in all possible ways as in a dictionary, then rank of the word PATNA from last is:
Answer : 19

Question. The number of integral solutions of a + b + c = 0, a ≥ −5, b ≥ −5, c ≥ −5 must be:
Answer : 136

Question. Let n1 < n2 < n3 < n4 < n5 be positive integers such that n1 + n2 + n3 + n4 + n5 = 20. The number of such distinct arrangements 1 2 3 4 5 (n1, n2 ,n3, n4, n5) is:
Answer : 7

Question. Let n ≥ 2 be an integer. Taken n distinct points on a circle and join each pair of points by a line segment. Colour the line segment joining every pair of adjacent points by blue and the rest by red. If the number of red and blue line segments are equal, then the value of n is
Answer : 5

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CBSE Class 11 Mathematics Chapter 7 Permutations and Combinations Worksheet

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Worksheet for Mathematics CBSE Class 11 Chapter 7 Permutations and Combinations

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Chapter 7 Permutations and Combinations worksheet Mathematics CBSE Class 11

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Chapter 7 Permutations and Combinations CBSE Class 11 Mathematics Worksheet

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