CBSE Class 10 Mathematics Probability Worksheet Set G

Read and download free pdf of CBSE Class 10 Mathematics Probability Worksheet Set G. Students and teachers of Class 10 Mathematics can get free printable Worksheets for Class 10 Mathematics Chapter 15 Probability in PDF format prepared as per the latest syllabus and examination pattern in your schools. Class 10 students should practice questions and answers given here for Mathematics in Class 10 which will help them to improve your knowledge of all important chapters and its topics. Students should also download free pdf of Class 10 Mathematics Worksheets prepared by school teachers as per the latest NCERT, CBSE, KVS books and syllabus issued this academic year and solve important problems with solutions on daily basis to get more score in school exams and tests

Worksheet for Class 10 Mathematics Chapter 15 Probability

Class 10 Mathematics students should refer to the following printable worksheet in Pdf for Chapter 15 Probability in Class 10. This test paper with questions and answers for Class 10 will be very useful for exams and help you to score good marks

Class 10 Mathematics Worksheet for Chapter 15 Probability

 

 Probability

Q.- One card is drawn from a well shuffled pack of 52 cards. The probability of getting an ace is 
a. 1/52
b.1/13
c.4/13
d.2/13
 
Ans-  b. 1/13
 
Explanation: Number of possible outcomes = 4
Number of Total outcomes = 52
∴Probability of getting an ace = 4/52=1/13
 
Q.- The king, queen and jack of clubs are removed from a deck of 52 cards and the remaining cards are shuffled. A card is drawn from the remaining cards. The probability of getting a king is 
a. 4/52
b.3/52
c.3/49
d.4/49
 
Ans- c. 3/49
 
Explanation: K , Q , J of clubs i.e 3 cards are removed , therefore remaining
cards = 52 - 3 = 49
3 kings are left in the pack
Number of possible outcomes = 3
Number of total outcomes = 52 – 3 = 49
Required Probability = 3/49
 
Q.-  Two dice are thrown simultaneously. The probability that the sum of the numbers appearing on the dice is 1 is 
a. 3
b. 0
c. 2
d. 1
 
Ans- b. 0
 
Explanation: Elementary events are
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
∴ Number of Total outcomes = 36
And Number of possible outcomes (sum of numbers appearing on die is 1) = 0
∴ Required Probability =0/30
 
Q.- Tickets numbered from 1 to 20 are mixed up and a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 7?
 
Ans- Total number of tickets = 20
{1,2,3....20}
Favourable outcomes (tickets with number as a multiple of 3 or 7)={3,6,9,12,15,18,7,14}
Therefore,number of favourable cases to the event=8
Required probability = 8/20=2/5
 
Q.- A letter is chosen at random from the letters of the word ASSASSINATION. Find the probability that the letter chosen is an 
i. vowel
ii. consonant
 
Ans- There are 13 letters in the word 'ASSASSINATION out of which one letter can be chosen in 13 ways.
Total number of elementary events = 13
 
i. There are 6 vowels in the word 'ASSASSINATION'. So, there are 6 ways of selecting a vowel.
∴ Probability of selecting a vowel = 6/13
 
ii. We have,
Probability of selecting a consonant
= 1- Probability of selecting a vowel = 1-6/13=7/13
 
Q.- Peter throws two different dice together and finds the product of the two numbers obtained. Rina throws a die and squares the number obtained. Who has the better chance to get the number 25?
 
Ans- The person having higher probability of getting the number 25 has the better chance.
When a pair of dice is thrown, there are 36 elementary events which are as follows:
(1, 1) , (1, 2), (1,3), (1,4), (1,5), (1, 6)
(2, 1) , (2, 2), (2,3), (2,4),(2,5), (2, 6)
(3,1) , (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1) , (4,2), (4,3),(4,4), (4,5), (4,6)
(5,1) , (5,2), (5,3), (5,4), (5,5), (5,6)
(6, 1), (6, 2),(6, 3), (6, 4), (6, 5), (6, 6)
Therefore, the product of numbers on two dice can take values 1, 2, 3, ..., 36.
We observe that the product of two numbers on two dice will be 25 if both the dice show number 5. Therefore,there is only one elementary event, viz., (5, 5), which is favourable for getting 25.
p1 = Probability that Peter throws 25= 1/36
Rina throws a die on which she can get any one of the six numbers 1, 2, 3, 4, 5, 6 as an outcome. If she gets number 5 on the upper face of the die thrown, then the square of the number is 25.
p2 = Probability that the square of number obtained is  25= 1/36
Therefore, p2 > p1. Therefore, Rina has better chance to get the
 
Q.- A ticket is drawn from a bag containing 100 tickets numbered from 1 to 100. The probability of getting a ticket with a number divisible by 10 is 
a.3/10
b.1/10
c.4/10
d.1/5
 
Ans- b. 1/10
 
Explanation: Number of possible outcomes = {10, 20, 30, 40, 50, 60, 70, 80, 90, 100} = 10
Number of Total outcomes = 100
∴ Required Probability 10/100=1/10
 
Q.- 3 rotten eggs are mixed with 12 good ones. One egg is chosen at random. The probability of choosing a rotten egg is 
a. 1/15
b. 4/5
c. 1/5
d. 2/5
 
Ans-c. 1/5
 
Explanation: Number of possible outcomes = 3
Number of Total outcomes = 15
Required Probability = 3/15=1/15
 
Q.- A letter of English alphabets is chosen at random. The probability that the letter chosen is a vowel is 
a. 2/26
b.4/26
c.1/26
d.5/26
 
Ans- d. 5/26
 
Explanation: We know that "A, E, I, O, U" are vowels
Number of vowels = 5
Number of possible outcomes = 5
Number of total outcomes = 26
Required Probability = 5/26
 
Q.- If S is the sample space of a random experiment, then P(S) = 
a.1/4
b.1/8
c. 1
d. 0
 
Ans-c. 1
Explanation: If S is the sample space of a random experiment, then P(S) = 1

 

More Question-

CONSTRUCTIONS

Key Points

1. Division of a line segment in the given ratio.

2. Construction of triangles:-

a. When three sides are given.

b. When two sides and included angle given.

c. When two angles and one side given.

d. Construction of a right angled triangle.

3. Construction of triangle similar to a given triangle as per given scale factor.

4. Construction of tangents to a circle.

EXPECTED LEARNING OUTCOMES

1. Correct use of Mathematical instruments.

2. Drawing a line segment and an angle as per the given data.

3. To divide the given line segment in the given ratio accurately.

4. Neatness and accuracy in drawing.

5. The concept of similar triangles.

6. To Construct a triangle as per the conditions given.

7. To construct similar triangle to a given triangle as per the given ratio.

8. To know that when the ratio is a proper fraction then the similar triangle lies inside the given

Triangle and when improper then the similar triangle lies outside the given triangle.

9. To construct tangents to a circle from an external point given.

CONCEPT MAP

CONSTRUCTIONS

DIVISION OF A LINE SEGMENT

CONSTRUCTION OF A TANGENT TO A CIRCLE

CONSTRUCT SIMILAR TRIANGLES AS PER GIVEN RATIO

KNOWLEDGE OF BASIC PROPORTIONALITY THEOREM

When given ratio is proper fraction the similar triangle lies inside the given triangle

Two triangles are similar if their corresponding sides are proportion

LEVEL – I

1. Draw a line segment AB=8cm and divide it in the ratio 4:3.

2. Divide a line segment of 7cm internally in the ratio 2:3.

3. Draw a circle of radius 4 cm. Take a point P on it. Draw tangent to the given circle at P.

4. Construct an isosceles triangle whose base is 7.5 cm and altitude is 4.2 cm.

5. Draw a line segment of length 9 cm. and divide it in seven equal parts.

LEVEL –II

1. Construct a triangle of sides 4cm, 5cm and 6cm and then a triangle similar to it whose sides are 2/3 of the corresponding sides of the first triangle. (CBSE 2013)

2. Construct a triangle similar to a given ΔABC such that each of its sides is 2/3rd of the corresponding sides of ΔABC. It is given that AB=5cm BC=6cm and AC=7cm. Also write the steps of construction.

3. Draw a pair of tangents to a circle of radius 4cm, which are inclined to each other at an angle of 600. (CBSE 2013)

4. Draw a circle of radius 5cm. From a point 8cm away from its centre construct the pair of tangents to the circle and measure their lengths.

5. Construct a triangle PQR in which QR=6cm, Q=600 and R=450. Construct another triangle similar to ΔPQR such that its sides are 5/6 of the corresponding sides of ΔPQR.

6. Draw a line segment AB= 7.5cm and locate a point P on AB such that AP= 3/7 AB. Give justification of the construction.

LEVEL-III

1. Draw a circle with centre O and radius 3.5cm. Take a horizontal diameter. Extend it to both sides to point P and Q such that OP=OQ=7cm. Draw tangents PA and QB, one above the diameter and the other below the diameter. Is PA||BQ.

2. Construct a Δ ABC in which AB = 6 cm, ∠A = 30° and ∠B = 60°. Construct another ΔAB’C’ similar to ΔABC with base AB’ = 8 cm. (CBSE 2015)

3. Draw a right triangle ABC in which B=900, AB=5cm, BC=4cm, then construct another triangle A’BC’ whose sides are 5/3 times the corresponding sides of ΔABC. Is the new triangle also a right triangle?

4. Draw a line segment AB of length 8 cm. Taking A as centre, draw a circle of radius 4 cm and taking B as centre, draw another circle of radius 3 cm. Construct tangents to each circle from the centre of the other circle.

5. Draw a line segment AB of length 7 cm. Using ruler and compasses, find a point P on AB such that AP/AB = 3/5. (CBSE 2011)

6. Construct an isosceles triangle whose base is 8 cm. and altitude 4 cm. and then construct another triangle whose sides are ¾ times the corresponding sides of the isosceles triangle. (CBSE 2011)

7. ABC is a right triangle in which AB=5.4 cm, BC= 7 cm and <B = 900.Draw BD perpendicular on AC and a circle through B, C, D. Construct a pair of tangents from A to this circle.

8. Construct a triangle ABC in which AB=5cm,<B=600and altitude CD=3 cm. Construct a triangle PQR similar to ΔABC such that each side of ΔPQR is 1.5 times that of the corresponding sides of ΔABC.

9. Construct a tangent to a circle of radius 3.5 from a point on the concentric circle of radius 6.5 cm and measure its length. Also, verify the measurement by actual calculation.

Self-Evaluation

1.Draw a line segment of length 7 cm. Find a point P on it which divides it in the ratio 3:5.

2. Draw an isosceles triangle ABC in which AB=AC=6 cm and BC=5 cm. Construct a triangle PQR similar to ΔABC in which PQ=8 cm. Also justify the construction.

3.Two line segments AB and AC include an angle of 600where AB=5 cm and AC=7 CM. Locate points P and Q on AB and AC respectively such that AP=3/4 AB and AQ=1/4 AC. Join P and Q and measure the length PQ.

4. Draw a triangle ABC in which AB=4 cm, BC=6 cm and AC=9 cm. Construct a triangle similar to ΔABC with scale factor 3/2. Justify your construction.

5.Draw a pair of tangents to a circle of radius 4.5 cm, which are inclined to each other at an angle of 450.

6.Draw a line segment AB of length 7 cm. Taking A as centre, draw a circle of radius 3 cm and taking B as centre another circle of radius 2.5 cm. Construct tangents to each circle from the centre of the other circle.

Value Based Question

(1) Two trees are to be planted at two positions A and B in the middle of a park and the third tree is to be planted at a position C in such a way that AC: BC= 3:4. How it can be done? What value is indicated from the above action?

(2) Draw a circle of radius 5 cm. Draw tangents from the end points of its diameter. What do you observe?

Please click the link below to download CBSE Class 10 Mathematics Probability Worksheet Set G

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